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Questions tagged [additive-categories]

For questions dealing with additive or pre-additive categories.

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Composing with the zero morphism in a pre-additive category

In an pre-additive category $C$ let $X,Y$, and $Z$ be three objects, and let $f:X \to Y$ a morphism. If I compose $f$ with the zero morphism from $Y$ to $Z$ do I get the zero morphism from $X$ to $Z$?
Gheorghe Bucătaru's user avatar
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Ideals in this category of morphisms of additive category [closed]

let's say an additive category is given. What are the ideals(the definition is given in the comments) in the category of its morphisms? I only see these: morphisms $a = (\alpha_0,\alpha_1): g\...
Егор Игнатьев's user avatar
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Additive functor category has a generator

In the Wikipedia page for Grothendieck categories, one example that's given is the category of additive functors from a small additive category $\mathcal C$ to a Grothendieck category $\mathcal A$. ...
zork zork's user avatar
2 votes
1 answer
67 views

On a property of subobjects of infinite direct sums in categories

Let $\mathcal{A}$ be a category with (arbitrary) coproducts (denoted as direct sums), a zero object, and in which monomorphisms are stable under coproducts. I am interested in additive categories, so ...
Martin Brandenburg's user avatar
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Definition of additive category

In the book "Several Complex Variables with Connections to Algebraic Geometry and Lie Groups" I found following definition of additive category: for each ordered pair of objects $A, B$, the ...
M12345's user avatar
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Length of an additive functor is the supremum of lengths over all objects

Let $\mathcal{C}$ be an additive category and $F: \mathcal{C} \to \mathrm{Ab}$ an additive functor. We can define the length of $F$ as usual as the unique length of a composition series $$0=F_n \...
Flynn Fehre's user avatar
3 votes
1 answer
71 views

Equivalence between finitely presented additive functors of projective modules and right modules

Let $R$ be a ring with unity. I want to show the following equivalence of categories $$\operatorname{mod}(\operatorname{Proj} R) \cong \operatorname{Mod} R.$$ Here, $\operatorname{R}$ denotes the ...
Flynn Fehre's user avatar
2 votes
1 answer
58 views

functors preserve isomorphism of direct sum.

In this proof in the Stacks project, it is mentioned that the decomposition of identity morphism of direct sum: ... because the composition $F(A) \oplus F(B) \xrightarrow{\varphi} F(A \oplus B) \...
jhzg's user avatar
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The functor that preserves the direct sum is an additive functor

I am learning about additive categories on the Stacks Project, and I encountered some difficulties in proving that functor that preserves direct sums is an additive functor. There is such a ...
jhzg's user avatar
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1 answer
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Prove that any preadditive category can be embedded into an additive category as a full subcategory

I am trying to prove that any preadditive category $\mathcal{C}$ can be embedded as a full subcategory into an additive category $\mathcal{D}$. Since an additive category is, by definition, a ...
Squirrel-Power's user avatar
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Constructing Shift Functor on Chain Complexes - Alternating Differential

I've got a question pertaining to the construction of the shift functor on the chain complex category Ch$(\mathbf{A})$ (where $\mathbf{A}$ denotes an additive category). It makes perfect sense to me ...
J.G.131's user avatar
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Why Do Additive Categories Need Zero Objects? - Motivation

At the moment, I'm trying to develop intuition behind the derived construction of what is an additive category from the (standard) category definition. (i) It seems natural that a category with the ...
J.G.131's user avatar
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1 vote
1 answer
81 views

In what sense are preadditive categories also enriched categories?

I'm confused about Wikipedia's definition of preadditive categories: In mathematics, specifically in category theory, a preadditive category is another name for an Ab-category, i.e., a category that ...
WillG's user avatar
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Left adjoint of an additive functor between triangulated categories that commute with shift

Let $\mathcal S, \mathcal T$ be triangulated categories and $R: \mathcal S \to \mathcal T$ be an additive functor that commutes with shift. If $L:\mathcal T \to \mathcal S$ is a left adjoint to $R$, ...
Snake Eyes's user avatar
5 votes
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The collection of maps to a (commutative) monoid is a (commutative) monoid, via Eckmann-Hilton

A commutative monoid $M$ has the nice property that given a set $S$, the set of functions $S \to M$ forms a commutative monoid (under pointwise addition). The same statement without any mention of ...
Matthew Niemiro's user avatar
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1 answer
85 views

Does a category where binary products commute with binary coproducts necessarily have biproducts?

Given a category $\mathcal{C}$ with binary products and binary coproducts for which the canonical comparison morphism $(A \times B) + (C \times D) \to (A+C) \times (B + D)$ is an isomorphism for any ...
Geoffrey Trang's user avatar
1 vote
2 answers
76 views

Universal property of additive categories

Keep in mind that I suck at cateogory theory, so please be gentle. The definition of additive categeory that I have is that it is a preadditive category $\mathcal{C}$ with an object $0$ such that End$(...
kubo's user avatar
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Biproduct in arrow category of additive category

Let $\mathcal{A}$ be an additive category and $\text{Arr}(\mathcal{A})$ be its arrow category i.e. the objects are the morphisms in $\mathcal{A}$ and the morphisms from $u:A\to B$ to $v:C\to D$ are ...
user829347's user avatar
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1 vote
1 answer
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On the proof of the Additive Yoneda Lemma

The additive Yoneda lemma says that if you have an $Ab$-enriched category $\mathscr A$ and an additive functor $F:A\rightarrow Ab$, then there is a group isomorphism $$Nat(\mathscr A(A,-),F)\cong F\ A$...
Julián's user avatar
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How does ${f_i}^j=\pi_j\cdot f\cdot \text{in}_i$ construct matrices in additive categories?

The following question is taken from Arrows, Structures and Functors the categorical imperative by Arbib and Manes. $\color{Green}{Background:}$ $\textbf{(1)}$ $\text{Definition 1:}$ A $\textbf{...
Seth's user avatar
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1 vote
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Kernels and cokernels for the category of long exact sequences

I've seen in many places, including Weibel's excellent book, that the category of short exact sequences (in an abelian category) has kernels and cokernels, although it is not abelian. However, I ...
Gabriel Longatto Clemente's user avatar
2 votes
1 answer
182 views

Additive functors as colimits of representable functors

Let $A$ be an additive category. Denote $(A, Ab)$ the category of all additive functors from A to the category of abelian groups. There is well known result that any functor $F \colon C \to Sets$ on a ...
Alex's user avatar
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5 votes
1 answer
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Zero object in additive category

I am new in category theory and I got stuck with this following problem - An additive category $\mathcal{C}$ is a category with $\mathcal{C}(A, B)$ an abelian group for every pair $A, B$ and ...
Chanel Rose's user avatar
3 votes
1 answer
75 views

Maps of complexes are homotopic if and only if a certain diagram exists

$\DeclareMathOperator{\mc}{Mc}$ $\DeclareMathOperator{\diff}{Diff}$ $\DeclareMathOperator{\fct}{Fct}$ $\newcommand{\c}{\mathscr{C}}$I'm trying to understand and prove the following statement : Let $\c$...
t_kln's user avatar
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Weak kernels and cokernels in a triangulated category

Weak kernels and cokernels are defined to be the same as kernels and cokernels but with the requirement of uniqueness removed from their universal properties. I want to prove that each morphism $u:A\...
user829347's user avatar
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2 votes
1 answer
358 views

Examples of preadditive categories that is not additive

We follow the definition of stacks project. So the existence of zero object is not in the definition of preadditive categories. Clearly any ring $R$ (commutative with 1) thought of as a category with ...
Z Wu's user avatar
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6 votes
1 answer
144 views

'Invariants' in a category of modules

I have a commutative unital ring $R$, a full additive subcategory $\mathcal{C}$ of $\text{Mod}_R$ that is closed under isomorphisms and an operation $f \colon \mathrm{Ob}(\mathcal{C}) \to \mathbb{Z}_{\...
user829347's user avatar
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Category of torsion free abelian groups is additive but not abelian

I’m trying to prove that the category of torsion free abelian groups is additive but not abelian… To prove that it is not abelian I’m trying to prove that that the multiplication map φ x2 in Z is not ...
Hey's user avatar
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Additive category without finite limits

I was wondering if they are easy examples of additive categories wherein the equalizer or the pullback do not always exist ?
Sov's user avatar
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1 vote
2 answers
254 views

Canonical morphism $\text{im}(f)\to\text{ker}(g)$ for exact sequence in an abelian category

Let $\mathcal{A}$ be an abelian category. Suppose we have objects $A$, $B$ and $C$, and morphisms $f:A\to B$, $g:B\to C$ with $g\circ f=0$ i.e. is equal to the zero morphism $A\to C$. In order to make ...
user829347's user avatar
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2 votes
1 answer
161 views

Understanding a product of objects as a limit of a discrete diagram

I have read that a product of objects $\{A_i\}_{i\in I}$ in a category $\mathcal{A}$ can be defined as a limit of a discrete diagram i.e. a diagram $D:\mathcal{I}\to\mathcal{A}$ where the only ...
user829347's user avatar
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1 vote
1 answer
124 views

Canonical morphism from coproduct to product in a pointed category

Suppose we have a pointed category $\mathcal{A}$ and a collection $\{A_i\}_{i\in I}$ of objects which have both a product $\prod_iA_i$ and a coproduct $\coprod_iA_i$. The product has projections $\...
user829347's user avatar
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0 votes
0 answers
95 views

Direct sum and short exact sequence, as well as, tensor product and what?

In an abelian category, the notion of direct sum is generalized by the notion of short exact sequence (see split exact sequence). Question: In a monoidal category, can the notion of tensor product be ...
Sebastien Palcoux's user avatar
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1 answer
182 views

A functor that preserves binary coproducts or binary products between additive categories must preserve the zero object?

That is the question. If I have a functor $F:\mathcal{A}\to\mathcal{B}$ between additive categories such that either $F(A)\oplus F(B)\to F(A\oplus B)$ is an isomorphism for all $A,B\in\mathcal{A}$, ...
Elías Guisado Villalgordo's user avatar
1 vote
1 answer
165 views

Canonical group structure on hom-sets in an additive category

I am trying to understand why a given category (without any extra structure) is either abelian or not abelian i.e. why the definition can be expressed in such a way that there is no need to add any ...
user829347's user avatar
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2 votes
1 answer
232 views

Can $\mathbf{Rng}$ be made into a pre-additive category?

Question: Can $\mathbf{Rng}$ be made into a pre-additive category? Rngs are just rings, without the requirement of an identity. Accordingly, we do not require rng homomorphisms to preserve the ...
stoic-santiago's user avatar
1 vote
0 answers
281 views

Shift/translation functor in a triangulated category

I'm trying to get to grips with triangulated categories at the moment. According to Wikipedia, the shift/translation functor of a triangulated category $\mathcal{C}$ is an "additive automorphism (...
user829347's user avatar
  • 3,538
2 votes
0 answers
520 views

Additive and preadditive categories

I have been attempting to make sense additive categories recently. I outline my current understanding below and would be very grateful if you could let me know if I have made a mistake, since I am not ...
user829347's user avatar
  • 3,538
5 votes
1 answer
278 views

Alternate Definition of Quotient Category

A quotient category is usually (at least from most sources I had seen) defined by something like $\mathcal C/\sim$ for some equivalence relation $\sim$, for example in this post. I am wondering if one ...
SummerAtlas's user avatar
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2 votes
1 answer
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Prove that additive functor preserves products and coproducts

Let $\cal A,B$ be additive categories and $F:\cal A\rightarrow B$ be an additive functor. Show that $F$ preserves products and coproducts. Since product and coproduct of a pair $A,B$ of objects in an ...
Maxim Nikitin's user avatar
1 vote
2 answers
58 views

$p_Ai_B=0$ and $p_Bi_A=0$ in additive category

Let $\cal A$ be an additive category. Then for any $A,B\in\textrm{Ob}(\cal A)$ the direct sum $A\oplus B$ is both their product and their coproduct. Let $i_A:A\rightarrow A\oplus B$ and $i_B:B\...
Maxim Nikitin's user avatar
4 votes
1 answer
154 views

Category of Abelian group pairs is not Abelian

Consider the category of pairs $(X,Y)$ where $X,Y$ are Abelian groups such that $X\subseteq Y$. I want to show that this category is not Abelian. I have checked that this category is additive, and ...
SummerAtlas's user avatar
  • 1,052
4 votes
1 answer
103 views

In a additive tensor category, End(1) ,where 1 is a unit object, is a commutative ring

I am reading Tannakian categories by Deligne and Milne. The question is this : Let (C,#) is an additive tensor category and (1,e) is an identity object then R= End(1) which acts on each object of X, ...
Parth's user avatar
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2 votes
1 answer
98 views

Canonical morphism is always monic and epic?

I'm reading Manin & Gelfand's book Methods of Homological Algebra and I came to something I can't prove after several tries. It's on page 113, II.5.11.(b) Commentary on the Axiom A4 (of Abelian ...
DrinkingDonuts's user avatar
1 vote
1 answer
127 views

Is there a version of Short Five Lemma in any Exact Category?

It is well known that Short five Lemma (https://en.m.wikipedia.org/wiki/Short_five_lemma) holds in any abelian category. My question is: Does a version of Short five Lemma also hold in exact category? ...
Snake Eyes's user avatar
1 vote
1 answer
159 views

Weibel Lemma 1.6.2.

The following is (a part of) Lemma 1.6.2. from Weibel's Homological Algebra.$\newcommand{\C}[1]{\mathcal{#1}}\DeclareMathOperator{\coker}{coker}\newcommand{\md}[1]{{\left\lvert #1 \right\lvert}}\...
hello's user avatar
  • 396
1 vote
1 answer
87 views

Existence of sum/intersection of abelian (resp. additive) categories

Let $\mathcal{C}$ and $\mathcal{D}$ be abelian (resp. additive) categories. Does there exist a smallest abelian (resp. additive) category $\mathcal{C}+\mathcal{D}$, s.t. $\mathcal{C}$ and $\mathcal{D}$...
Bipolar Minds's user avatar
1 vote
1 answer
286 views

What is the internal hom functor for vector spaces?

I am wondering what the explicit definition of the internal hom functor $[X,\_]$ (described in this answer), for the category of vector spaces $\text{Vect}$ (over, say, the field of real numbers) is. ...
Richard Southwell's user avatar
3 votes
2 answers
214 views

Image of a morphism in a category with zero object, equalizers and coequalizers

Let’s assume that $\mathcal{C}$ is a category which has a zero object and equalizer and coequalizer of all the morphisms exist (so we have kernels and cokernels). Then, is it true that for an ...
Pouya Layeghi's user avatar
1 vote
2 answers
121 views

On a special kind of $R$-linear functor from an $R$-linear additive category [closed]

Let $R$ be a Commutative Noetherian ring, let $\mod (R)$ be the category of finitely generated $R$-modules. Let $\mathcal C \subseteq \mod(R)$ be an $R$-linear (https://stacks.math.columbia.edu/tag/...
uno's user avatar
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