European Journal of Combinatorics 26 (2005) 417–435
www.elsevier.com/locate/ejc
Automorphisms and regular embeddings of
merged Johnson graphs
Gareth A. Jones
School of Mathematics, University of Southampton, Southampton SO17 1BJ, UK
Received 26 July 2002; accepted 29 January 2004
Available online 15 January 2005
Abstract
The merged Johnson graph J (n, m) I is the union of the distance i graphs J (n, m)i of the
Johnson graph J (n, m) for i ∈ I , where ∅ = I ⊆ {1, . . . , m} and 2 ≤ m ≤ n/2. We find
the automorphism groups of these graphs, and deduce that their only regular embedding in an
orientable surface is the octahedral map on the sphere for J (4, 2)1 , and that they have just six
non-orientable regular embeddings. This yields classifications of the regular embeddings of the line
graphs L(K n ) = J (n, 2)1 of complete graphs, their complements L(K n ) = J (n, 2)2 , and the odd
graphs Om+1 = J (2m + 1, m)m .
© 2004 Elsevier Ltd. All rights reserved.
1. Introduction
A standard problem in topological graph theory is that of determining the regular
embeddings, in orientable or non-orientable surfaces, of a given class of arc-transitive
connected graphs. Here we use the term ‘regular’ in the sense of Coxeter and Moser [7,
Chapter 8], meaning that the map has two specific automorphisms, cyclically permuting
the successive edges around a face and around a vertex meeting that face. This problem
has been solved for several classes of graphs: for instance, the work of Biggs [2] and of
James and the author [19] yields a classification of the orientable regular embeddings of
complete graphs, while their non-orientable regular embeddings are described by James
in [18]. Nedela and Škoviera [26] have obtained similar results for other classes of graphs,
such as cocktail party graphs and dipoles.
E-mail address:
[email protected] (G.A. Jones).
0195-6698/$ - see front matter © 2004 Elsevier Ltd. All rights reserved.
doi:10.1016/j.ejc.2004.01.012
418
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
Here we consider a class of graphs based on the Johnson graphs. The vertices of a
Johnson graph J (n, m) are the m-element subsets of an n-element set (2 ≤ m ≤ n/2),
adjacent if their intersection has m −1 elements. Given a nonempty subset I ⊆ {1, . . . , m},
we define the merged Johnson graph J (n, m) I to be the union of the distance i graphs
J (n, m)i of J (n, m) for all i ∈ I , so two m-element subsets are adjacent in J (n, m) I
if their intersection has m − i elements for some i ∈ I . The graphs J (n, m) I include
many interesting graphs, such as the Johnson graphs J (n, m) = J (n, m)1 , the line graphs
L(K n ) = J (n, 2)1 of the complete graphs, their complements J (n, 2)2 , and the odd graphs
Om+1 = J (2m + 1, m)m .
In Theorem 2 we determine the automorphism group of each graph J = J (n, m) I ,
using the work of Ustimenko-Bakumovskiı̆ [29, 30] and others on overgroups of the
symmetric group Sn in its action on m-element subsets: by considering the orbitals of each
overgroup, we determine the sets I for which it leaves J (n, m) I invariant. We then use
results of Livingstone and Wagner [25] and Kantor [23] on m-homogeneous permutation
groups, and of Zassenhaus [35] and Gorenstein and Hughes [15] on triply transitive
permutation groups, to determine which subgroups of Aut J can act as automorphism
groups of regular embeddings of J . We show in Theorem 10 that there are, up to
isomorphism, just seven such embeddings: these are the well-known octahedral embedding
of J (4, 2)1 = J (4, 2) = L(K 4 ) in the sphere, and six regular embeddings of J (4, 2)1,
J (4, 2)1,2 = K 6 , J (5, 2)1 = L(K 5 ) and Petersen’s graph J (5, 2)2 = L(K 5 ) in nonorientable surfaces; constructions of some of these maps are considered in Section 8. In
fact, not only do almost all of these graphs J have no regular embeddings, we show in
Theorem 14 that most of them have no vertex-transitive embeddings, though in this case
we have not attempted to find a complete classification.
Although this paper uses some quite deep results on finite permutation groups, they are
independent of the classification of finite simple groups, so our methods could be regarded
as ‘elementary’ in some sense. Nevertheless, it would be interesting to investigate a more
combinatorial approach, perhaps replacing permutation groups with association schemes.
For general background on permutation groups, see the book by Dixon and Mortimer [8].
2. Johnson graphs and their mergings
Let N be a finite set of n elements, and let Ω denote the set N {m} of m-element
subsets
M ⊆ N, for some fixed m such that 1 ≤ m ≤ n − 1, so d := |Ω | = mn . The Johnson
graph J (n, m) has vertex-set Ω , with vertices M and M ′ joined by an edge if and only
if |M ∩ M ′ | = m − 1 (see [3, Section 9.1] for a detailed study of the properties of this
graph). The distance between two vertices M and M ′ of J (n, m) is |M\M ′ | = |M ′ \M|,
so J (n, m) has diameter min{m, n − m}. The distance i Johnson graph J (n, m)i , where
0 ≤ i ≤ min{m, n − m}, also has vertex-set Ω , with M and M ′ joined by an edge if
and only if they are at distance i in J (n, m), that is, |M ∩ M ′ | = m − i ; in particular,
J (n, m)1 = J (n, m). For fixed n and m, the graphs J (n, m)i are the orbital graphs for the
action of Sn on Ω , induced by its natural action on N: each J (n, m)i corresponds to the
orbital (or 2-orbit, that is, orbit of Sn on Ω 2 )
Γi = {(M, M ′ ) ∈ Ω 2 | |M ∩ M ′ | = m − i }
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
419
(see [8, Section 3.2] and [27] for orbital graphs). We denote by Γi (M) the set of neighbours
of M in J (n, m)i : these are the subsets M ′ = (M\I1 ) ∪ I2 of N, where I1 and I2 are
i -element subsets of M and of M = N\M, so J (n, m)i has valency
m
n−m
|Γi (M)| =
.
i
i
Included among the graphs J (n, m)i are the complete graphs K n = J (n, 1)1 , the null
(or empty) graphs K n = J (n, 1)0 , the line graphs L(K n ) = J (n, 2)1 of the complete
graphs, and their complements L(K n ) = J (n, 2)2 . In particular, J (5, 2)2 is Petersen’s
graph, and more generally, J (n, m)m is the Kneser graph K (n, m) [3, p. 258], with
J (2m + 1, m)m = Om+1 , the odd graph of valency m + 1 [3, p. 259].
Complementation of subsets M → M induces an isomorphism J (n, m)i ∼
= J (n, n −
m)i (and an ‘outer automorphism’ of the graph when m = n/2), so we may assume
without loss of generality that m ≤ n/2. We will also assume that m ≥ 2 (so n ≥ 4)
since the regular embeddings of complete graphs K n have been completely classified (see
Section 5).
We now consider the connectedness of the graphs J (n, m)i . Since J (n, m)0 is a null
graph, we will assume here that i > 0. In the action of Sn on Ω , the stabiliser of an
m-element subset M ∈ Ω has the form Sm × Sn−m , where the direct factors act naturally
on M and M; for m = n/2 this stabiliser is a maximal subgroup of Sn (see, for instance, [8,
Exercise 5.2.8]), so Sn acts primitively on Ω and hence J (n, m)i is connected for each
i = 1, . . . , m ([8, Theorem 3.2A] and [27]). If m = n/2, however, there is a unique group
between the stabiliser Sm × Sm and Sn , namely the wreath product Sm ≀ S2 , a semidirect
product (Sm × Sm ) : S2 of Sm × Sm by S2 , stabilising the partition {M, M} of N; thus Sn
is imprimitive on Ω , permuting the e = d/2 complementary pairs M and M. In this case,
if we choose g ∈ Sn sending M to some M ′ ∈ Γi (M), then g ∈ Sm ≀ S2 if and only if i = 0
or m; it follows that if 1 ≤ i ≤ m − 1 then Sm ≀ S2 , g = Sn so a result of Glauberman [14]
implies that J (2m, m)i is connected. On the other hand, J (2m, m)m consists of e disjoint
copies of K 2 , one for each pair {M, M }.
If I is any subset of {1, . . . , m} we define the merged Johnson graph J (n, m) I to be the
edge-union of the graphs J (n, m)i where i ∈ I . Thus J (n, m) I has vertex-set Ω = N {m} ,
with vertices M and M ′ adjacent if and only if |M ∩ M ′ | = m
− i for some i ∈ I . We will
denote the set of neighbours of M in J (n, m) I by Γ I (M) = i∈I Γi (M). The preceding
comments about the connectedness of J (n, m)i show that with the exceptions of J (n, m)∅
and J (2m, m)m , the graphs J (n, m) I are all connected.
3. Automorphism groups of the merged Johnson graphs
Before considering regular embeddings, we need first to determine the automorphism
group of each graph J (n, m) I . In many cases this is already in the literature: for instance,
Whitney’s theorem [32] on automorphisms of line graphs deals with the case J (n, 2)1 =
L(K n ), and further examples are given in [3, Section 9.1], [10] and [24]. Nevertheless, it is
useful to state and prove the full result here. It can be proved by a careful examination of
the structure constants of the Johnson association scheme, and indeed this has been done in
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
certain cases by Klin [24]. However, it is more convenient for us to use the classification of
the overgroups of Sn in Sd ; this was begun by Kalužnin and Klin [22], developed further by
Halberstadt [16], and completed by Ustimenko-Bakumovskiı̆, who summarised his results
in [29] and gave full details in [30]. Skalba [28] has also published a proof (like Halberstadt,
avoiding the hardest case m = n/2), while Faradžev, Klin and Muzichuk have provided a
useful algebraic and combinatorial overview of this topic in [12, Section 3.2].
Since Sn , acting naturally on the n-element set N, has a faithful induced action on the
set Ω = N {m} for each m = 1, . . . , n −1, we will abuse the notation by identifying Snwith
its image in the symmetric group Sd of all permutations of Ω , where d = |Ω | = mn . By
considering the effect on Ω of transposingtwo elements of N, we see that Sn is contained
n−2
in the alternating group Ad if and only if m−1
is even. Any additional overgroups of Sn
in Sd are given by the following result of Ustimenko-Bakumovskiı̆:
Proposition 1 ([29, 30]). The group Sn , acting on Ω for 2 ≤ m ≤ n/2, is maximal in
Sd or Ad if (n, m) = (6, 2), (8, 2), (10, 3), (12, 4), (2m + 1, m) or (2m, m). For these
exceptional pairs (n, m), the overgroups of Sn other than Sd and Ad are as follows:
(6, 2):
(8, 2):
(10, 3):
(12, 4):
(5, 2):
(2m + 1, m):
(2m, m):
S6 < G L 4 (2)
with d = 15,
with d = 28,
S8 < Sp6 (2)
S10 < Sp8 (2)
with d = 120,
−
S12 < O10
(2)
with d = 495,
S5 < S6 < Aut S6
with d = 10,
for m ≥ 3,
Sn < Sn+1
Sn < various imprimitive subgroups of S2 ≀ Se ,
where e = d/2.
In the first six cases, where n > 2m, there is a unique overgroup of Sn of each type
listed. In the last case, where n = 2m, the overgroups are explicitly described in [29]; here
we simply need the fact that they are imprimitive, permuting complementary pairs M and
M, as proved in [29]. To avoid confusion, note that when (n, m) = (12, 4) the overgroup is
not the simple orthogonal group G of order 220.36 .52 .7.11.17, but rather its automorphism
−
group, of twice this order, denoted by G.2 = G O10
(2) in the ATLAS [5, p. 147]; we
−
(2) for this overgroup,
have followed [9, 12, 28, 29] in using the classical notation O10
whereas in the ATLAS and in [8, Appendix B] this notation indicates its simple subgroup
of index 2, which contains A12 but not S12 . The remarks in [28, pp. 159, 172] that this
overgroup is simple appear to be based on a misunderstanding. For a detailed description
of this and many other embeddings of symmetric groups in orthogonal and symplectic
groups, see [9].
we write J = J (n, m) I and A = Aut J . Since J =
For notational simplicity,
J
(n,
m)
we
have
i
i∈I Aut J (n, m)i ≤ A. If I = ∅ or {1, . . . , m} then J is a null
i∈I
or complete graph, so A = Sd ; we will therefore assume that ∅ ⊂ I ⊂ {1, . . . , m}. We
define I ′ = I \{m}, and for any integer k we define k − I = {k − i | i ∈ I }, with asimilar
definition of k − I ′ . We also define I ′′ = m − I ′ . If m = n/2 we define e = (1/2) mn .
Theorem 2. Let J = J (n, m) I where 2 ≤ m ≤ n/2 and ∅ ⊂ I ⊂ {1, . . . , m}, and let
A = Aut J .
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
421
(a) If 2 ≤ m < (n − 1)/2, and J = J (12, 4) I with I = {1, 3} or {2, 4}, then A = Sn ;
this group has rank 1 + m on the vertex-set Ω of J , with orbitals Γ0 , . . . , Γm ⊂ Ω 2 .
−
(b) If (n, m) = (12, 4) with I = {1, 3} or {2, 4}, then A = O10
(2) with orbitals
Γ0 , Γ1 ∪ Γ3 and Γ2 ∪ Γ4 .
(c) If m = (n − 1)/2 and I = m + 1 − I , then A = Sn with orbitals Γ0 , . . . , Γm .
(d) If m = (n−1)/2 and I = m +1− I , then A = Sn+1 with orbitals Γ0 and Γi ∪Γm+1−i
for i = 1, . . . , ⌊(m + 1)/2⌋.
(e) If m = n/2 and I = {m} or {1, . . . , m − 1}, and I ′ = I ′′ , then A = S2 × Sn with
orbitals Γ0 , . . . , Γm .
(f) If m = n/2 and I = {m} or {1, . . . , m − 1}, and I ′ = I ′′ , then A = S2e : Sn with
orbitals Γ0 , Γi ∪ Γm−i for i = 1, . . . , ⌊m/2⌋, and Γm .
(g) If m = n/2 and I = {1, . . . , m − 1} or {m}, then A = S2e : Se = S2 ≀ Se with orbitals
Γ0 , Γ1 ∪ · · · ∪ Γm−1 and Γm .
[The precise nature and action of each group A will be explained within the proof.]
Proof. Thenatural
actions of Sn on N and of A on Ω induce inclusions Sn ≤ A ≤ Sd ,
where d = mn . The graph J is neither complete nor null, so A cannot be doubly transitive,
and hence A Ad since d ≥ 4. For most pairs n and m (see Proposition 1 for details), Sn
is a maximal subgroup of either Sd or Ad , so it follows in these cases that A = Sn , a rank
1 + m group on Ω with orbitals Γ0 , . . . , Γm . We now consider in more detail when this
argument applies, and when additional arguments are required.
We first consider cases (a) and (b) of the theorem, where 2 ≤ m < (n − 1)/2, so that
n ≥ 6. By Proposition 1, the preceding argument deals with all cases where m ≥ 5; it also
deals with the case m = 4 provided n = 12, with m = 3 provided n = 10, and with m = 2
provided n = 6 or 8. When (n, m) = (6, 2), (8, 2) or (10, 3), the overgroups G L 4 (2),
Sp6 (2) and Sp8 (2) are all doubly transitive on Ω , so the same argument gives A = Sn .
−
(2) has rank 3; its orbitals are Γ0 , Γ1 ∪
When (n, m) = (12, 4), however, the overgroup O10
−
Γ3 and Γ2 ∪ Γ4 (see [3, p. 261] or [12, p. 101]), so J (12, 4) I is invariant under O10
(2) only
−
for I = {1, 3} and {2, 4}. Thus A is O10 (2) in these two cases, and S12 otherwise.
This deals with cases (a) and (b) of the Theorem. To understand cases (c) and (d),
where m = (n − 1)/2, we need to explain the action of the overgroup Sn+1 on Ω . Let
N ∗ = N ∪ {∞} for some symbol ∞ ∈
/ N, so |N ∗ | = n + 1 = 2(m + 1), and let Φ be
∗
the set of equipartitions of N , by which we mean the unordered partitions {P1 , P2 } of N ∗
with |P1 | = |P2 |, so |P j | = m + 1 for each j . There is a bijection β : Ω → Φ, sending
each M ∈ Ω to the equipartition {M ∪ {∞}, N\M}; its inverse sends each {P1 , P2 } ∈ Φ
to M = P j \{∞}, where j is chosen so that ∞ ∈ P j . The natural action of Sn+1 on N ∗
induces an action on Φ and hence, via β, on Ω ; the restriction of this action to the subgroup
Sn of Sn+1 fixing ∞ agrees with the original action
of Sn on Ω , so we obtain the inclusions
Sn < Sn+1 < Sd . When n = 5, so that d = 52 = 10, we can identify this overgroup S6
with PΣ L 2 (9), acting naturally on the 10 points of the projective line over G F(9), and
this is contained in an additional overgroup PΓ L 2 (9) ∼
= Aut S6 of S5 in S10 .
In its action on Φ (and hence on Ω ), Sn+1 has rank 1 + ⌊(m + 1)/2⌋: for each
i = 0, . . . , ⌊(m + 1)/2⌋, it has an orbit on Φ 2 consisting of those pairs of equipartitions
({P1 , P2 }, {P1′ , P2′ }) of N ∗ such that each of the four intersections P j ∩ Pk′ has size i or
m + 1 − i . Deleting ∞ from whichever sets P j and Pk′ contain it, we see that these pairs of
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
equipartitions correspond under β to the pairs (M, M ′ ) ∈ Ω 2 where |M ∩ M ′ | = i − 1 or
m − i . For i > 0 these therefore form an orbit ∆i = Γm+1−i ∪ Γi of Sn+1 on Ω 2 , a union
of two distinct orbits of Sn unless i = (m + 1)/2 with m odd. With this one exception, the
orbitals Γ1 , . . . , Γm of Sn are thus merged in pairs under the action of Sn+1 . Since all the
overgroups of Sn apart from Sn+1 are doubly transitive on Ω , it follows that A = Sn unless
I = m + 1 − I , in which case A = Sn+1 . This deals with cases (c) and (d).
To deal with the remaining cases, let m = n/2. Since A is an overgroup of Sn in
Sd , not containing Ad , it follows from Proposition 1 that A is an imprimitive subgroup
of S2 ≀ Se , permuting the set Φ consisting of the e = d/2 equipartitions E = {P, P}
of N. First we determine the kernel C = A ∩ B of the action of A on Φ, where B
is the base group S2e of S2 ≀ Se . Each direct factor S2 of B is generated by a permutation t E (E ∈ Φ) of Ω which transposes the
parts P and P of E, while fixing all other
elements of Ω . For any Ψ ⊆ Φ, let tΨ = E∈Ψ t E , so tΨ → Ψ is an isomorphism
between B and the power set of Φ. In particular, let D denote the diagonal subgroup
tΦ ∼
= S2 of B, where tΦ sends every element of Ω to its complement. For each i , if
(P, Q)
∈ Γi then |P ∩ Q| = |P ∪ Q| = 2m − (m + i ) = m − i , so (P, Q) ∈ Γi . Thus
tΦ ∈ i∈I Aut J (n, m)i ≤ A and hence A contains D, Sn = D × Sn ∼
= S2 × Sn .
Suppose first that I ′ = I ′′ (:=m − I ′ ), say i ∈ I but m − i ∈
/ I for some i = m. Let
tΨ ∈ A for some Ψ = ∅, say E = {P, P} ∈ Ψ . If E ′ = {Q, Q} ∈ Φ where (P, Q) ∈ Γi
then since |P ∩ Q| = m − i whereas |P ∩ Q| = i it follows that tΨ must send Q to Q;
thus E ′ ∈ Ψ for all such E ′ , and since J (n, m)i is connected it follows by iterating this
argument that Ψ = Φ. Conversely tΦ ∈ A, so this shows that if I ′ = I ′′ then C = D.
When I ′ = I ′′ , however, we have t E ∈ A for each E ∈ Φ, so C = B.
We now consider the permutation group S = A/C induced by A on Φ. First let n > 4,
so the subgroup Sn of A acts faithfully on Φ, and hence S is an overgroup of Sn in Se . As in
cases (c) and (d), but now replacing n and m with n − 1 and m − 1, by choosing an element
∞ ∈ N we obtain a bijection between the equipartitions {P1 , P2 } ∈ Φ of N and the
(m − 1)-element subsets P j \{∞} of N0 = N\{∞}, where ∞ ∈ P j . The symmetric groups
n−1
on N0 and N then give rise to inclusions Sn−1 < Sn < Se , where e = (1/2) mn = m−1
.
By applying Proposition 1 to the overgroups of Sn−1 in Se we see from the inclusions
Sn ≤ S ≤ Se that S must be Sn , Ae or Se , or possibly Aut S6 = PΓ L 2 (9) if n = 6 (so
e = 10). Apart from Sn for n ≥ 8, these groups are all doubly transitive on Φ, so if S > Sn
then the stabiliser A E in A of an equipartition E = {M, M } ∈ Φ permutes the e − 1
equipartitions E ′ ∈ Φ\{E} transitively. Now A E = D × A M , with D acting trivially on Φ,
so A M is also transitive on Φ\{E} and hence has at most two orbits on Ω \{M, M}.
If A M is transitive on Ω \{M, M }, then A has rank 3, with orbitals Γ0 , Γ1 ∪ · · · ∪ Γm−1
and Γm ; thus I = {1, . . . , m − 1} or {m}, so J is the multipartite graph K 2,...,2 or its
complement (e disjoint copies of K 2 ), and A is the semidirect product B : Se = S2 ≀ Se
as in case (g). If A M has two orbits on Ω \{M, M }, they are transposed by D and hence
each contains the complements of the sets in the other; thus A has rank 4, and Γi (M) and
Γm−i (M) are contained in different orbits of A M for each i , so {1, . . . , m − 1} is partitioned by I ′ and I ′′ . This means that J/D ∼
= K e , so J is an antipodal double cover of K e .
Each triangle K 3 ⊂ K e lifts to either a disjoint pair of triangles or a cycle of length 6 in
J , and since the groups S > Sn listed above are all triply transitive on Φ, every K 3 lifts in
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
423
the same way. If they lift to pairs of triangles then J consists of two disjoint copies of K e ,
and if they lift to cycles, then J is the cocktail party graph K e ⊗ K 2 , that is, the complete
bipartite graph K e,e minus a matching [26]. In either case, A acts imprimitively on Ω , with
two blocks of size e, and hence so does its subgroup Sn . These blocks must be the orbits of
a subgroup of index 2 in Sn , whereas the only such subgroup is An , which acts transitively.
Thus, unless we are in case (g) we have S = Sn , so A = C : Sn ; it then follows from our
earlier investigation of C that A = D × Sn or B : Sn as I ′ = I ′′ or I ′ = I ′′ , giving cases (e)
and (f). The orbitals Γ0 , . . . , Γm of Sn are preserved by D, while B preserves Γ0 and Γm
and transposes the pairs Γi and Γm−i (i = 1, . . . , ⌊m/2⌋), so in each case the orbitals of
A are as stated in the theorem.
We earlier excluded the case n = 2m = 4; here I = {1} or {2}, and J is either the
octahedral graph J (4, 2)1 = J (4, 2) = L(K 4 ) or its complement J (4, 2)2 , three disjoint
copies of K 2 . In either case, it is easily seen that A = S23 : S3 = S2 ≀ S3 , as in case (g).
Comments. (1) As noted in [3, p. 261] and [12, p. 101], the merging of orbitals Γi in
case (b) of Theorem 2 yields a strongly regular graph on 495 vertices. One can deduce
−
this merging in several ways. One is by considering the actions of S12 and O10
(2) on
the 10-dimensional binary vector space consisting of the even order subsets M ⊆ N
modulo complementation, preserving the quadratic form (1/2)|M| mod (2), with the 4element subsets M ∈ Ω corresponding to the non-zero isotropic vectors. Alternatively,
−
the irreducible constituents of the permutation character of O10
(2) have degrees 1, 154
and 340 [5, p. 147], and the subdegrees |Γi (M)| for S12 on Ω are 1, 32, 168, 224 and
70 for i = 0, . . . , 4; the only rank 3 merging of these subdegrees which satisfies Frame’s
criterion (see [3, Theorem 2.2.4], [13] or [33, Theorem 30.1(A)]) is 1, 32 + 224 = 256,
168 + 70 = 238, so the orbitals of A are Γ0 , Γ1 ∪ Γ3 and Γ2 ∪ Γ4 .
(2) In the proof for case (d), the bijection β can be used to identify J (n, m) I =
J (2m + 1, m) I with the graph whose vertices are the equipartitions of the (n + 1)-element
set N ∗ , adjacent if their parts intersect in i -element sets for some i ∈ I (well-defined
since I = m + 1 − I ). This can be regarded as the distance I graph J (2m + 2, m + 1) I
of the folded Johnson graph (or even graph) J (2m + 2, m + 1) = E m+1 formed from
J (2m + 2, m + 1) by identifying every (m + 1)-element subset of N ∗ with its complement;
it has automorphism group Sn+1 = S2m+2 acting naturally on N ∗ (see [3, Section 9.1C]
or [17, Section 6.2] for details of the even graphs).
4. Preliminary results on permutation groups
In order to apply Theorem 2 to the regular embeddings of the merged Johnson graphs,
we need some further concepts and results on permutation groups. See [8] for full details.
A permutation group G, acting on a set N, is m-homogeneous if its induced action on
N {m} is transitive. The following result [8, Theorem 9.4A] is originally due to Brown [4]:
Proposition 3 ([4]). Let G act on a set N of n elements. If 0 ≤ l ≤ m and l + m ≤ n, then
G has at least as many orbits on N {m} as it has on N {l} . If G is m-homogeneous where
0 < 2m ≤ n + 1 then G is l-homogeneous for all l with 0 < l ≤ m; in particular, G is
transitive on N.
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The next result [8, Theorem 9.4B] is by Livingstone and Wagner [25] and Kantor [23]:
Proposition 4 ([23, 25]). Let G be an m-homogeneous group of degree n, where 3 ≤ m ≤
n/2. Then G is (m − 1)-transitive, and with the following exceptions G is m-transitive:
(a) m = 4 and G = PG L 2 (8) or PΓ L 2 (8) with n = 9, or G = PΓ L 2 (32) with
n = 33.
(b) m = 3 and P S L 2 (q) ≤ G ≤ PΣ L 2 (q) for q ≡ 3 mod (4) with n = q + 1, or
G = AG L 1 (8) or AΓ L 1 (8) with n = 8, or G = AΓ L 1 (32) with n = 32.
There is a similar result for m = 2, but we do not need it here. We also need the
following results about cyclic groups; the proofs, which are straightforward, are omitted.
Lemma 5. Let C be a cyclic permutation group of degree n. If C is m-homogenous where
0 < m < n, then C is transitive and m = 1 or n − 1.
Lemma 6. Let C be a cyclic group, acting on finite sets Ω1 and Ω2 . Then the following
are equivalent:
(a) C is transitive in its induced action on Ω1 × Ω2 ;
(b) C is transitive on Ω1 and Ω2 , and |Ω1 | is coprime to |Ω2 |.
A k-transitive permutation group is sharply k-transitive if the stabiliser of k points
is the identity subgroup [8, Section 7.6]. Zassenhaus [35] has shown that there are just
two families of sharply 3-transitive finite permutation groups, both of them subgroups of
PΓ L 2 (q) acting with degree n = q + 1 on the projective line over G F(q). One such
subgroup is PG L 2 (q), consisting of the Möbius transformations
az + b
(a, . . . , d ∈ G F(q), ad − bc = 0).
(1)
cz + d
If the prime power q is an odd square there is a second sharply 3-transitive subgroup
M2 (q), consisting of the transformations (1) for which ad − bc is a square, together with
the transformations
az + b
(a, . . . , d ∈ G F(q))
z→
cz + d
z→
√
for which ad − bc is a non-square, where z → z = z q is the automorphism of order 2 of
G F(q). The smallest example M2 (9) of this family is M10 , the stabiliser of a point in the
simple Mathieu group M11 of degree 11 [5].
Finally, we need a purely number-theoretic result:
Proposition 7. If 2 ≤ m ≤ n/2, the binomial coefficient mn is not a prime power.
Proof. This is elementary
for m = 2 and 3, and otherwise it follows from a theorem of
Erdős [11] that mn is not a proper power for 4 ≤ m ≤ n − 4 (see also [1, Chapter 3]).
5. Regular maps
Coxeter and Moser [7, Chapter 8] define a map on a surface to be regular if it
has automorphisms cyclically permuting the successive edges around a face and around
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
425
an incident vertex. If M is an orientable regular map then its orientation-preserving
automorphism group G = Aut+ M acts regularly on the directed edges of M. In particular,
G acts transitively on the vertices, and moreover the stabiliser of a vertex is a cyclic
group, acting regularly on the incident edges. Here |G| = 2E where E is the number
of edges of M, whereas in the case of a non-orientable regular map, the automorphism
group G = Aut M has order 4E: again G acts transitively on the vertices, but now their
stabilisers are dihedral groups acting naturally on the incident edges.
A map has type { p, q} if its faces are p-gons and its vertices have valency q. In [6]
and [7], the notation { p, q} also denotes the unique simply connected map of type { p, q};
this is drawn on the sphere, the Euclidean plane or the hyperbolic plane as p−1 + q −1 >
1/2, = 1/2 or < 1/2, and it covers all other maps of this type. The orientation-preserving
automorphism group of { p, q} is the triangle group
∆(q, 2, p) = X, Y, Z | X q = Y 2 = Z p = XY Z = 1,
where X, Y and Z are rotations of the map through 2π/q, π and 2π/ p around a vertex
and the centres of an incident edge and face. The orientable regular maps of type { p, q} are
the quotients M = { p, q}/K , where K is a torsion-free normal subgroup of ∆(q, 2, p);
up to isomorphism, there is one map for each such K , and its orientation-preserving
automorphism group Aut+ M is isomorphic to ∆(q, 2, p)/K .
The full automorphism group of { p, q} is the extended triangle group
∆[q, 2, p] = R0 , R1 , R2 | Ri2 = (R1 R2 )q = (R2 R0 )2 = (R0 R1 ) p = 1,
where R0 , R1 and R2 are reflections preserving an incident edge and face, face and vertex,
and vertex and edge, so that X = R1 R2 , Y = R2 R0 and Z = R0 R1 generate the even
subgroup ∆(q, 2, p) of index 2 in ∆[q, 2, p]. An orientable regular map M is reflexible
(has orientation-reversing automorphisms) if and only if K is normal in ∆[q, 2, p], in
which case its full automorphism group Aut M is isomorphic to ∆[q, 2, p]/K . Nonorientable regular maps of type { p, q} have the form M ∼
= { p, q}/K for normal subgroups
K of ∆[q, 2, p] not contained in ∆(q, 2, p), with Aut M ∼
= ∆[q, 2, p]/K .
We refer to [7, Chapter 8] for further background and notation for regular maps, and
to [20] for their connections with triangle groups. In particular, { p, q}r denotes the map
{ p, q}/K where K is the normal closure of (R0 R1 R2 )r , so that the Petrie polygons (closed
zig-zag paths) have length r ; this map is orientable if and only if r is even. The Petrie dual
of a map embeds the same graph, but has faces and Petrie polygons transposed, the two
maps having the same automorphism group [7, Sections 5.2 and 8.6]; this map operation,
along with others, is considered in more detail in [20, 21, 34]. The notation {5, 5/2} denotes
the great dodecahedron, an orientable regular map of type {5, 5} and genus 4 [6, Section
6.2]; it embeds the graph of the icosahedron {3, 5} with 12 pentagonal faces, each spanning
the neighbours of a vertex, and it has the same automorphism group S2 × A5 as {3, 5}, with
the factor S2 generated by the antipodal automorphism.
Before considering the regular embeddings of merged Johnson graphs, we need some
results of Biggs [2] and James [18] on regular embeddings of complete graphs.
Proposition 8 ([2]). The complete graph K d has an orientable regular embedding if and
only if d is a prime power.
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
In fact, it is shown in [19] that the only orientable regular embeddings of K d are those
constructed by Biggs, as Cayley maps over the additive group of the field G F(d); they
correspond to the orbits of the Galois group of the field on generators of its multiplicative
group, so there are φ(d − 1)/e such maps, where d = pe for some prime p and φ denotes
Euler’s function.
Proposition 9 ([18]). The only non-orientable regular embeddings of a complete graph
are the antipodal quotients of a dihedron {6, 2} for K 3 , of a cube {4, 3} for K 4 , and of an
icosahedron {3, 5} and a great dodecahedron {5, 5/2} for K 6 . The first three maps have
genus 1, and the fourth has genus 5.
The embeddings in Proposition 9 are isomorphic to the maps {6, 2}3, {4, 3}3, {3, 5}5
and {5, 5}3 discussed in [7, Section 8.6 and Table 8]. The first two maps are the Petrie
duals of the orientable regular embeddings {3, 2} and {3, 3} of K 3 and K 4 (a dihedron and
a tetrahedron); they have automorphism groups D6 ∼
= S2 × S3 and S4 . The last two maps
are Petrie duals of each other, both having automorphism group P S L 2 (5) ∼
= A5 .
6. Regular embeddings of merged Johnson graphs
We now classify the regular embeddings of the graphs J = J (n, m) I ; they are described
in more detail in Section 8. To ensure that J is connected, we will assume that I = ∅,
and also that I = {m} if m = n/2. We denote an orientable or non-orientable compact
connected surface of genus g by Sg+ or Sg− respectively: for instance, S0+ and S1− are the
sphere and the real projective plane.
Theorem 10. Let J = J (n, m) I , where 2 ≤ m ≤ n/2 and ∅ ⊂ I ⊆ {1, . . . , m}, and
I = {m} if m = n/2. Then J has only the following regular embeddings:
(a) the octahedron {3, 4} and its Petrie dual {6, 4}3 , which embed J (4, 2)1 = L(K 4 ) in
S0+ and S4− with automorphism group S2 ≀ S3 ∼
= S2 × S4 ;
(b) the embeddings {3, 5}5 and {5, 5}3 of J (4, 2)1,2 = K 6 in S1− and S5− , which are a
Petrie dual pair of maps arising as the antipodal quotients of an icosahedron {3, 5}
and a great dodecahedron {5, 5/2}, with automorphism group P S L 2 (5) ∼
= A5 ;
(c) a Petrie dual pair of embeddings of type {4, 6} and {5, 6} of J (5, 2)1 = L(K 5 ) in
−
, which are quotients of {4, 6}5 and {5, 6}4 by a central involution, with
S7− and S10
automorphism group S5 ;
(d) the embedding {5, 3}5 of Petersen’s graph J (5, 2)2 = L(K 5 ) in S1− , arising as the
antipodal quotient of a dodecahedron {5, 3}, with automorphism group A5 .
Proof. We use case-by-case analysis, considering the possibilities for A = Aut J in
Theorem 2. First we eliminate a case not covered there. If I = {1, . . . , m} then J = K d .
By Proposition 8, K d has an orientable regular embedding if and only if d is a prime
power, and by Proposition 7 this is never the case if d is a binomial coefficient mn with
9 implies
2 ≤ m ≤ n/2. If K d has
a non-orientable regular embedding then Proposition
that d ≤ 6; since d = mn with 2 ≤ m ≤ n/2, only the case d = 6 = 42 arises here, and
Proposition 9 gives the embeddings described in part (b) of the theorem. We may therefore
assume from now on that I ⊂ {1, . . . , m}, as in Theorem 2.
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
427
Let M be a regular embedding of J , and G its automorphism group (orientationpreserving if M is orientable). Since G acts faithfully on J , it is a subgroup of A acting
transitively on the directed edges, with the stabiliser of a directed edge having order η = 1
or 2 as M is orientable or not. These directed edges can be identified with the pairs
(M, M ′ ) ∈ Γ I = ∪i∈I Γi , so
n m n − m
n!
.
(2)
|G| = η|Γ I | = η
=η
2
i ! (m − i )!(n − m − i )!
m
i
i
i∈I
i∈I
By Theorem 2, there is a subgroup Sn of A consisting of the automorphisms of J
induced by the permutations of N.
Cases (a), (c). Suppose that G ≤ Sn , as must happen in cases (a) and (c) of Theorem 2,
and may happen in other cases, so we can study G through its action on N. Since Sn has
orbitals Γ0 , . . . , Γm ⊂ Ω 2 , it follows that if |I | > 1 then G cannot be transitive on Γ I ,
contradicting the regularity of M. Hence |I | = 1, so J = J (n, m)i for some i = 1, . . . , m.
The stabiliser G M in G of each vertex M ∈ Ω of M is a cyclic or dihedral group,
permuting the neighbours of M in its natural representation, so it contains a cyclic subgroup
G ∗M of index η = 1 or 2 permuting the neighbours regularly. The setwise stabiliser G M
of each m-element subset M ⊂ N therefore has a cyclic subgroup G ∗M of index η acting
regularly on those m-element subsets M ′ ⊂ N such that |M ∩ M ′ | = m − i . These are
the sets M ′ = (M\I1 ) ∪ I2 , where I1 and I2 are i -element subsets of M and M, so G ∗M
acts regularly on the ordered pairs (I1 , I2 ) of such subsets. By Lemma 6, it follows that the
cyclic group G ∗M induces transitive groups G 1 and G 2 of coprime orders on the i -element
subsets of M and of M. By Lemma 5, this transitivity condition on the cyclic group G 1
forces i = 0, 1, m − 1 or m, and the condition on G 2 forces i = 0, 1, n − m − 1 or n − m.
Since we are assuming that i = 0, the only possibilities are therefore
(i)
(ii)
(iii)
(iv)
(v)
i
i
i
i
i
= 1, or
= m − 1 = n − m − 1, or
= m − 1 = n − m, or
= m = n − m − 1, or
= m = n − m.
In case (i), G 1 and G 2 are regular cyclic groups of orders m and n − m; since these
orders are coprime, m and n are coprime. In (ii), n = 2m and i = m − 1, so G 1 and G 2 are
both regular cyclic groups of order m, contradicting the coprimality of their orders. In (iii)
we have n = 2m − 1, contradicting our assumption that m ≤ n/2. We have excluded
case (v) since J (2m, m)m is not connected for m ≥ 2. This leaves case (i), where J is a
Johnson graph J (n, m) with gcd(n, m) = 1, and case (iv), where n = 2m + 1 and i = m,
so that J = J (2m + 1, m)m is an odd graph Om+1 . In cases (i) and (iv), Eq. (2) gives
n
ηn!
|G| = η
,
(3)
m(n − m) =
(m − 1)!(n − m − 1)!
m
and
|G| = η
n
η(2m + 1)!
.
(m + 1) =
m
m!2
(4)
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
A second consequence of the regularity of M is that G acts transitively on the vertices
of J , that is, on the m-element subsets of N, so it acts on N as an m-homogeneous
permutation group. Since m ≤ n/2, Proposition 4 implies that G is m-transitive if m ≥ 5;
the set-wise stabiliser G M of an m-element set M ⊂ N then acts on M as Sm , and hence
cannot be cyclic or dihedral, so m ≤ 4. We now consider such values of m in turn.
If m = 4 then Proposition 4 shows that G is 4-transitive, giving a similar contradiction,
unless G = PG L 2 (8) or PΓ L 2 (8) with n = 9, or G = PΓ L 2 (32) with n = 33. These
groups have orders 9.8.7, 9.8.7.3 and 33.32.31.5, whereas by Eq. (3) the groups G in
case (i) have orders 9.8.7.5η and 33.32.31.5.29η for (n, m) = (9, 4) and (33, 4); similarly
in case (iv), where (n, m) = (9, 4), Eq. (4) gives |G| = 9.7.5.2η, so these exceptions do
not arise.
Now let m = 3. In case (i) we have |G| = n(n − 1)(n − 2)(n − 3)η/2. Since G is
transitive on adjacent pairs (M, M ′ ) it is transitive on 4-element subsets M ∪ M ′ ⊂ N,
that is, 4-homogeneous on N. Hence G is 3-transitive by Proposition 4, leading to a
similar contradiction in the orientable case. In the non-orientable case, where η = 2, G
is 4-transitive since the exceptions in Proposition 4 have the wrong orders, and hence
G is sharply 4-transitive. By a theorem of Jordan [8, Theorem 7.6A], the only sharply
4-transitive finite groups are S4 , A6 and the Mathieu group M11 , acting naturally. We can
eliminate S4 since n ≥ 2m = 6, and A6 and M11 since their subgroups G M , of order 18
and 48, are not dihedral. In case (iv) we have n = 2m + 1 = 7 and |G| = 140η. Now G is
3-homogeneous and hence 3-transitive, since the exceptions in Proposition 4 do not have
degree 7. This is impossible, since |G| is coprime to 3.
This leaves the case m = 2. In case (iv), putting n = 5 gives J = J (5, 2)2 , Petersen’s
graph. Since |G| = 30η = 30 or 60, the only possible subgroup G ≤ S5 is G = A5
with η = 2, so M is non-orientable. Since J has valency 3, G is an epimorphic image of
the triangle group ∆[3, 2, p] where p (the face-valency) is the order of an element of A5 .
Since |∆[3, 2, p]| < |A5 | for p < 5, the only possibility is p = 5, so M is covered by
the dodecahedron {5, 3}. Now ∆[3, 2, 5] ∼
= S2 × A5 , so the only normal subgroup with
quotient A5 is the centre S2 , generated by the antipodal automorphism of {5, 3}; thus M
is the antipodal quotient {5, 3}/S2 = {5, 3}5 of {5, 3} [7, Section 8.6 and Table 8], as in
part (d).
We may therefore assume that we are in case (i), so J = J (n, 2)1 = L(K n ) with n
odd. The pairs (M, M ′ ) ∈ Γ1 can be identified with the ordered triples (x, y, z) of distinct
elements of N, where M = {x, y} and M ′ = {y, z}; in the orientable case, G permutes
these regularly and is therefore sharply 3-transitive on N. As shown by Zassenhaus [35],
it follows that n = q + 1 for some prime power q, and G is either PG L 2 (q), or
M2 (q) with q an odd square (see Section 4); since n is odd we have G = PG L 2 (q),
so G M ∼
= Dq−1 which is non-cyclic since q = n − 1 ≥ 2m − 1 = 3, and we obtain
no orientable regular embeddings. In the non-orientable case, G is 3-transitive on N
with 3-point stabilisers of order 2. Here G M (∼
=D2(n−2) ∼
= S2 × Dn−2 ) acts naturally as
D2(n−2) on the set Γ1 (M) of neighbours of M, which can be identified with M × M,
so it must act as S2 on M and as Dn−2 on M. Since n is odd, the subgroup of G fixing
x, y ∈ M and z ∈ M therefore acts semiregularly on the remaining n − 3 points of
M, so the subgroup of G fixing any four points in N is trivial. A theorem of Gorenstein
and Hughes [15] states that if a finite group G is 3-transitive but not sharply 3-transitive,
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
429
with trivial 4-point stabilisers, then G = A6 , M11 or PΓ L 2 (2 f ) ( f prime), all acting
naturally. Here |G| = 2n(n − 1)(n − 2), so by comparing orders we see that G =
PΓ L 2 (22 ) = S5 with n = 5, giving J = J (5, 2)1 = L(K 5 ). Since J has valency 6,
any non-orientable regular embedding has type { p, 6} for some p, and thus has the form
M = { p, 6}/K where K is the kernel of an epimorphism ∆ = ∆[6, 2, p] → S5 . Such
epimorphisms correspond to triples of elements ri ∈ S5 (images of the generators Ri
of ∆) which satisfy the relations of ∆ and generate S5 . Since Ri2 = 1, and S5 is not
a dihedral group, each ri must be an involution, and thus a transposition or a double
transposition. At least one ri must be a transposition, for otherwise r0 , r1 , r2 ≤ A5 .
Since the degree 5 is prime, and a primitive group containing a transposition must be the
symmetric group, it follows that r0 , r1 and r2 generate S5 if and only if they generate a
transitive group. By a rather tedious case-by-case analysis, which we omit, we then find
that the only epimorphisms ∆ → S5 are given by the following three mappings of the
generators Ri (i = 0, 1, 2), where a, . . . , e is an arbitrary permutation of 1, . . . , 5:
(ac), (ad)(bc), (de);
Ri → ri = (ac)(de), (ad)(bc), (de);
(ab)(de), (ac), (ad)(be).
In each of these three cases, the various epimorphisms differ only by automorphisms
of S5 , so they have the same kernel K and hence correspond to a single regular map M.
The element Z = R0 R1 maps to a permutation z = r0r1 = (abcd), (abcde) or (abc)(de)
of order p = 4, 5 or 6 respectively, so M has type {4, 6}, {5, 6} or {6, 6}. If M is to
be an embedding of J then z must induce a p-cycle on Ω forming a closed path in J ,
the boundary of a z-invariant face of M. In the first two cases, such a cycle is given by
(ab, bc, cd, da) or (ab, bc, cd, de, ea), and in each case the different choices of a, . . . , e
give the faces of a regular embedding of J . In the third case, however, the only 6-cycle of z
on Ω is (ad, be, cd, ae, bd, ce), with consecutive vertices not adjacent, so the 1-skeleton of
M is not J (it is, in fact, the multigraph formed by doubling the edges of Petersen’s graph
J (5, 2)2 ). In the first and second cases, R0 R1 R2 is mapped to (abced) or (abce), so the
Petrie polygons have length 5 or 4; since the orientation-reversing elements (R0 R1 R2 )5
and (R0 (R1 R2 )2 )3 lie in K , both maps are non-orientable. They have |S5 |/12 = 10
vertices, |S5 |/4 = 30 edges, and |S5 |/2 p = 15 or 12 faces, so they have genus 7 or
10 respectively. Because of their types and Petrie lengths, they are quotients of the regular
maps {4, 6}5 and {5, 6}4, which are Petrie duals of each other with automorphism group
S2 × S5 [7, Table 8]; being regular, with automorphism group S5 , they must be isomorphic
to {4, 6}5/S2 and {5, 6}4/S2 , and they form a Petrie dual pair as described in part (c) of
the theorem. This deals with all cases where G ≤ Sn , and in particular it covers cases (a)
and (c) of Theorem 2, where A = Sn .
−
Case (b). In Theorem 2(b), where (n, m) = (12, 4), we have A = O10
(2); the valency of
−
J is 256 or 238 as I = {1, 3} or {2, 4}, and there are no elements of these orders in O10
(2)
(see [5, p. 147] for its simple subgroup of index 2), so J has no regular embeddings.
By Theorem 2 we may therefore assume that m = (n − 1)/2 with I = m + 1 − I , or
m = n/2, as in cases (d) to (g) of Theorem 2; we may also assume that G Sn , since we
dealt with subgroups G ≤ Sn earlier, under cases (a) and (c).
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
Case (d). Suppose that m = (n − 1)/2 and I = m + 1 − I , as in Theorem 2(d), so
A = Sn+1 . Then m ≥ 3, for if m = 2 then I = {1, 2}, against our earlier assumption.
Since Sn+1 has orbitals Γ0 and Γi ∪ Γm+1−i , it follows from the transitivity of G on
directed edges, and the condition I = m + 1 − I , that either I = {i, m + 1 − i } for
some i = (m + 1)/2 or I = {(m + 1)/2}. As in the proof of Theorem 2, we can identify
the vertex-set Ω with the set Φ of equipartitions of N ∗ = N ∪ {∞}, two equipartitions
being adjacent if their parts intersect in sets with cardinality in I . Since G acts transitively
on Φ, either it is transitive on the (m + 1)-element subsets of N ∗ , or it has two orbits on
them, each consisting of the complements of the subsets in the other. If G is transitive on
(m + 1)-element subsets then by Proposition 4 it is (m + 1)-transitive on N ∗ , since the
exceptions to 4-transitivity do not have degree 8. The stabiliser of an (m + 1)-element
set therefore acts on it as Sm+1 , with m + 1 ≥ 4, so the stabiliser of the corresponding
equipartition is not cyclic or dihedral, a contradiction. Thus G has two orbits on (m + 1)element subsets. Since complementary sets are in different orbits, the stabiliser G E of an
equipartition E = {M, M } preserves its parts M and M. If I = {i, m + 1 − i } with
i = (m + 1)/2 then the adjacent equipartitions E ′ correspond to the ordered pairs of i element subsets I1 ⊂ M and I2 ⊂ M, with E ′ = {(M\I1 ) ∪ I2 ), I1 ∪ (M\I2 )}, so the
cyclic group G ∗E of index η in G E must permute such pairs regularly. However, this is
impossible by Lemma 6, since the actions of G ∗E on the i -element subsets of M and of M
have the same degree. We may therefore assume that I = {i } where i = (m + 1)/2. Since
i = 0, 1, m or m + 1, Lemma 5 implies that G ∗E has at least two orbits on the i -element
subsets I1 ⊆ M, and similarly for i -element subsets I2 ⊆ M, so it has at least (2×2)/2 = 2
orbits on equipartitions E ′ = {(M\I1 ) ∪ I2 ), I1 ∪ (M\I2 )} adjacent to E. This contradicts
the regularity of M, so we have covered all cases in Theorem 2 where m < n/2, leaving
cases (e) to (g).
Now let m = n/2, so A acts imprimitively on Ω , permuting the set Φ consisting of the
e = d/2 equipartitions {M, M } of Ω . Then G also acts imprimitively, and G M fixes the
vertices M and M of J . Since G M acts transitively on the neighbours of M, and since we
are assuming that I = {m}, it follows that M is not a neighbour; thus m ∈
/ I , so I ′ = I .
Case (e). Suppose that I ′ = I ′′ , so A = D : Sn = S2 × Sn by Theorem 2(e). The orbitals
Γ0 , . . . , Γm of A are invariant under G, and since G M is transitive on the neighbours of
M, it follows that |I | = 1, say I = {i } where i = m/2. Since we are also assuming that
G Sn , the subgroup H := G ∩ Sn has index 2 in G. If H is transitive on directed edges
then it is regular on them, and since H ≤ Sn , our earlier arguments (applied to H rather
than G) show that we are in case (i) with m and n coprime, or case (iv) with m = (n −1)/2,
each contradicting m = n/2. Hence H has two orbits on directed edges, transposed by D,
so either H has two orbits on vertices, with H M transitive on the neighbours of each
M ∈ Ω , or H is transitive on vertices, with H M having two orbits on neighbours. In
the first case, since the neighbours of M are the sets M ′ = (M\I1 ) ∪ I2 , where I1 and I2
∗ must act transitively on ordered
are i -element subsets of M and M, the cyclic group H M
pairs (I1 , I2 ) of such sets. This is impossible by Lemma 6, since the representations of H M
on subsets I1 and I2 have the same degree. We may therefore assume that H is transitive
on vertices, so H acts as an m-homogeneous group on N. Since i = m/2 we have m ≥ 3,
so Proposition 4 implies that H is m-transitive on N since the exceptions to m-transitivity
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
431
for m = 3 or 4 do not have degree n = 6 or 8. Thus H M acts on M as Sm , and since H M
is cyclicordihedral
it follows that m = 3 and η = 2. Then n = 6 and i = 1 or 2, so
|G| = η 63 31 32 = 360; thus H has order 180 and is therefore a subgroup of index 4 in
S6 , which is impossible by the simplicity of A6 , so case (e) is eliminated.
Case (f). Suppose that I ′ = I ′′ and I = {1, . . . , m − 1}, so m ≥ 4. By Theorem 2(f),
A = S2e : Sn , where the direct factors of the normal subgroup B = S2e are generated by the
transpositions t E corresponding to the equipartitions E ∈ Φ of N, and the complement
Sn is induced by the permutations of N. The orbitals of A are Γ0 , Γi ∪ Γm−i (i =
1, . . . , ⌊m/2⌋) and Γm , so the transitivity of G M on the neighbours of M, together with
the condition I = m − I , gives I = {i, m − i } where 1 ≤ i < m/2 or I = {i } where
i = m/2. If M ′ is a neighbour of M then so is its complement, so G M acts imprimitively
on these neighbours, permuting complementary pairs. Under the natural epimorphism
A → Sn given by the action on Φ, the image of G ∗M is a cyclic subgroup H of Sn (acting
naturally on N) which preserves the equipartition E = {M, M } and acts transitively on the
equipartitions E ′ adjacent to E (those with parts M ′ satisfying |M ∩ M ′ | ∈ m − I = I );
thus H has at most two orbits on the neighbours of M, and if there are two then each
consists of the complements of the sets in the other orbit. These neighbours are the sets
M ′ = (M\I1 ) ∪ I2 , and their complements if i < m/2, where I1 and I2 are i -element
subsets of M and M. Now either H preserves M and M, or it transposes them. First
suppose that it preserves them. If i < m/2 then H must be transitive on ordered pairs
of i -element subsets I1 ⊂ M and I2 ⊂ M, which is impossible by Lemma 6 since the
actions on i -element subsets of M and M have the same degree. If i = m/2 then H
must have at most two orbits on ordered pairs (I1 , I2 ), so it is transitive on the i -element
subsets of at least one of M and M; since H is cyclic, Lemma 5 gives i = 1 and hence
m = 2, which contradicts the fact that m ≥ 4. The other possibility is that H transposes
M and M, so it acts on the set ∆ of all i -element subsets I1 ⊂ M or I2 ⊂ M. It must be
transitive on ∆, for if it had distinct orbits ∆1 and ∆2 on ∆, it would have at least three
orbits on sets M ′ = (M\I1 ) ∪ I2 , namely those with I1 , I2 both in ∆1 , both in ∆2 , or
one in each. Hence the subgroup of index 2 in H , which leaves M and M invariant, acts
transitively on the i -element subsets of each of these sets, so Lemma 5 gives i = 1 since
1 ≤ i ≤ m/2 < m − 1. Thus we can identify ∆ with N, so a generator h of H permutes
N in a single cycle of length n = 2m ≥ 8. It follows that H has at least three orbits on
neighbours M ′ = (M\I1 ) ∪ I2 of M, since sets of the form M ′ = (M\{x}) ∪ {xh j } must
be in different orbits for j = 1, 3 and 5. This is a contradiction, so case (f) of Theorem 2
is dealt with.
Case (g). Let I = {1, . . . , m − 1}, so Theorem 2(g) gives A = S2e : Se = S2 ≀ Se , a
group which acts imprimitively on Ω by permuting the set Φ of complementary pairs
E = {M, M} ⊂ Ω . It follows that G M fixes M and M and acts imprimitively on the
remaining vertices M ′ of J , again permuting complementary pairs. These d − 2 vertices
M ′ are the neighbours of M, and are therefore permuted regularly by G ∗M , so if g is a
generator of G ∗M then g (d−2)/2 is an involution fixing M and M and transposing all other
complementary pairs. This is the element tΨ of the base group B = S2e of S2 ≀ Se , where
Ψ = Φ\{E}; as M ranges over Ω the elements tΨ generate a subgroup of index 1 or 2 in B
as e is even or odd, so |G ∩ B| is divisible by 2e−1 . Since G M acts transitively on Ω \{E},
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
G induces a doubly transitive group G/(G ∩ B) of degree e on Φ, so e(e − 1) divides the
index |G : G ∩ B| and hence |G| is divisible by 2e−1 e(e − 1). However, J has d vertices
of valency d − 2, so |G| = ηd(d − 2) = 4ηe(e − 1) ≤ 8e(e − 1) and hence e ≤ 4.
Since e = 2m
m /2 with m ≥ 2 we must have m = 2 and e = 3, so J = J (4, 2)1 with
A = S23 : S3 = D × S4 . In the orientable case we have |G| = 24, so |A : G| = 2, and
of the three subgroups of index 2 in A, only one is transitive on directed edges and has
cyclic vertex-stabilisers, namely the rotation group G = ∆(4, 2, 3) ∼
= S22 : S3 ∼
= S4 of
the octahedral map {3, 4} on the sphere [7, Section 4.2]. Now M has type { p, 4} where
p is the order of an element of G, so p ≤ 4. One easily checks that the only possible
epimorphisms ∆(4, 2, p) → G are the isomorphisms where p = 3, so M = {3, 4} with
full automorphism group ∆[4, 2, 3] = A = S2 × S4 as in part (a). In the non-orientable
case we have |G| = 48, so G = A and hence p ≤ 4 or p = 6. It is easily seen that
there is an epimorphism ∆[4, 2, p] → A with kernel K ∆(4, 2, p) only when p = 6.
Now A has a single conjugacy class of elements of order 6, each a cyclic permutation of
the consecutive vertices of a Petrie polygon of {3, 4}. These must therefore form the four
faces of M, so M is the Petrie dual {6, 4}3 of {3, 4}, a non-orientable map of genus 4, as
in part (a).
The following three results are special cases of Theorem 10. Putting m = 2 and i = 1,
and using Proposition 9 for L(K 3 ) ∼
= K 3 , we have:
Corollary 11. The only regular embeddings of L(K n ) for n ≥ 3 are:
(a) the dihedron {3, 2} on S0+ and its Petrie dual {6, 2}3 = {6, 2}/S2 on S1− for n = 3,
(b) the octahedron {3, 4} on S0+ and its Petrie dual {6, 4}3 on S4− for n = 4, and
−
(c) the Petrie dual pair {4, 6}5 /S2 on S7− and {5, 6}4/S2 on S10
for n = 5.
Putting i = m = 2, we have:
Corollary 12. The only regular embedding of L(K n ) for n ≥ 5 is the embedding {5, 3}5 =
{5, 3}/S2 of Petersen’s graph L(K 5 ) in S1− .
Similarly, putting i = m = (n − 1)/2:
Corollary 13. The only regular embedding of an odd graph Om+1 of valency m + 1 ≥ 3
is the embedding {5, 3}5 = {5, 3}/S2 of Petersen’s graph O3 in S1− .
7. Vertex-transitive embeddings
For most of the merged Johnson graphs J = J (n, m) I , the arguments used to prove
Theorem 10 actually yield a stronger result, that J has no vertex-transitive embeddings.
The critical point is that for any map, regular or not, the automorphisms fixing a vertex
form a cyclic or dihedral group.
Theorem 14. Let J = J (n, m) I where 5 ≤ m < (n − 1)/2 and ∅ ⊂ I ⊂ {1, . . . , m}.
Then J has no vertex-transitive embeddings in orientable or non-orientable surfaces.
Proof. Given such an embedding, its automorphism group G is a subgroup of A = Aut J
which acts transitively on Ω . By Theorem 2(a), the conditions on m imply that A = Sn ,
G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
433
so G is an m-homogenous permutation group on N. Since m ≥ 5, Proposition 4 implies
that G is m-transitive, so the stabiliser G M of a vertex M induces Sm on the subset M and
cannot therefore be cyclic or dihedral.
This argument can be extended to the case 4 = m < (n − 1)/2, provided one avoids
−
the values n = 12 and 33, where the groups G = O10
(2) and PΓ L 2 (32) are exceptions
in Theorem 2 and Proposition 4 respectively. It also applies if 5 ≤ m = (n − 1)/2 and
I = m + 1 − I , since Theorem 2(c) again gives A = Sn .
8. Constructions
Some of the maps of higher genus appearing in Theorem 10 may be unfamiliar, so here
we give rather more detailed constructions for them.
There is an epimorphism θ : ∆[5, 2, 4] → {±1} × S5 ∼
= S2 × S5 given by
R0 → −(35),
R1 → −(25)(43),
R2 → −(12)(35),
which extends the epimorphism ∆(5, 2, 4) → S5 given by
X → (12345),
Y → (12),
Z → (2543),
so as in Section 5, the kernel K of θ corresponds to an orientable reflexible map M =
{4, 5}/K of type {4, 5} with Aut M ∼
= S2 × S5 . Having 120/5 = 24 vertices, 120/2 = 60
edges and 120/4 = 30 faces, M has Euler characteristic −6 and hence genus 4. Since
the image −(123)(45) of R0 R1 R2 has order 6, M is a quotient of {4, 5}6 , and since
Aut{4, 5}6 ∼
= S2 × S5 [7, Table 8] these two maps are isomorphic. Now M and its dual
M′ = {5, 4}6 project onto regular maps M/S2 and M′ /S2 with automorphism group S5
on the surface S4+ /S2 = S5− , and the duals of their Petrie duals {6, 5}4/S2 and {6, 4}5 /S2
are the maps {5, 6}4/S2 and {4, 6}5/S2 in Theorem 10(c). Alternatively, these maps can
be obtained directly from M′ /S2 and M/S2 by applying Wilson’s ‘opposite’ operation
[20, 21, 34]: this transposes vertices and Petrie polygons, while preserving edges and faces,
by cutting a map along its edges and then rejoining adjacent faces with reversed orientation.
The inverse image of S2 × A5 under θ is a triangle group ∆[5, 2, 5], the subgroup of
index 2 in ∆[5, 2, 4] generated by the reflections R0′ = R0 R1 R0 , R1′ = R2 and R2′ = R1 .
Since this contains K there is a reflexible map N = {5, 5}/K of type {5, 5} on S4+ , with
automorphism group S2 × A5 . This is the great dodecahedron {5, 5/2}, isomorphic as a map
to its dual, the small stellated dodecahedron {5/2, 5} [6, Sections 6.2 and 6.6], and N /S2
is the map {5, 5}3 on S5− appearing in Theorem 10(b). One can construct M = {4, 5}6
from N by adding edges joining each of the twelve vertices of N to the centres of its five
incident faces, and then deleting the edges of N ; thus the maps in Theorem 10(c) can also
be obtained from N , with their extra automorphisms induced by the self-duality of N .
Alternatively, one can construct conformal models of M and N . The surface group K
acts as a group of isometries of the hyperbolic plane, and the quotient space is a Riemann
surface of genus 4 isomorphic to Bring’s curve, the complex projective variety B ⊂ P4 (C)
given by 5j =1 z kj = 0 (k = 1, 2, 3). The conformal automorphisms of B form a group
S5 , permuting the homogeneous coordinates z j ; this commutes with the anticonformal
involution induced by complex conjugation, and together they generate the isometry group
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G.A. Jones / European Journal of Combinatorics 26 (2005) 417–435
Iso B = S2 × S5 of the hyperbolic 2-manifold B. The map M can be drawn on B, with
Aut M = Iso B, by taking the vertices, edge-centres and face-centres to be the images
under S5 of the points [1, ζ, ζ 2 , ζ 3 , ζ 4 ], [1, 1, α, β, γ ] and [0, 1, i, −1, −i ] fixed by X, Y
and Z , where ζ and i are primitive 5th and 4th roots of unity, and α, β, γ are the roots of
the polynomial z 3 + 2z 2 + 3z + 4. These vertices form two orbits under A5 , consisting of
the vertices and face-centres of N , while its edge-centres are the face-centres of M. The
edges of M and N are the images under S5 and A5 of line-segments on B fixed by the
reflections
R2 : [z 1 , z 2 , z 3 , z 4 , z 5 ] → [z 2 , z 1 , z 5 , z 4 , z 3 ]
and
R2′ : [z 1 , z 2 , z 3 , z 4 , z 5 ] → [z 1 , z 5 , z 4 , z 3 , z 2 ].
The connections between Bring’s curve and the small stellated dodecahedron {5/2, 5}
are explored in detail by Weber in [31], developing earlier ideas of Kepler and Klein.
Acknowledgements
The author is grateful to Mikhail Klin, David Singerman, Vasyl Ustimenko, and several
anonymous referees for a number of very helpful comments.
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