Sorry i really dont know how to do this, last resort but to ask. I wanted to add values to the string list. But my code is not working
private List<String> sample = new ArrayList<String>(){"item1","item2","item3"};
asked Mar 9, 2014 at 13:31
2 Answers
Here it is:
List<String> sample = new ArrayList<String>(Arrays.asList("item1", "item2", "item3"));
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Thank you, both of your answer work, i tried very hard to look for a solution on android developer, but i do not know which page to look for. Commented Mar 9, 2014 at 13:44
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Returns a fixed-size list backed by the specified array. (Changes to the returned list "write through" to the array.) This method acts as bridge between array-based and collection-based APIs, in combination with Collection.toArray(). The returned list is serializable and implements RandomAccess. This method also provides a convenient way to create a fixed-size list initialized to contain several elements: List<String> stooges = Arrays.asList("Larry", "Moe", "Curly"); docs.oracle.com/javase/7/docs/api/java/util/Arrays.html Commented Mar 9, 2014 at 13:46
Try,
ArrayList<String> list = new ArrayList<String>() {{
add("item1");
add("item2");
add("item3");
}}
OR
ArrayList<String> list = new ArrayList<String>();
list.add("item1");
list.add("item2");
list.add("item3");
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Thank you for the solution sir, may i ask why is there double quotes,{{}}. Commented Mar 9, 2014 at 13:49
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@lonelearner In the first case we are making an anonymous inner class with an instance initializer (double brace initialization) For More : c2.com/cgi/wiki?DoubleBraceInitialization Commented Mar 9, 2014 at 13:53
private List<String>and answers stipulateArrayList<String>which is another thing. So this is not actually even answered properly. But fulfilled the cause.