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does an exact sequence of filtered complexes induce an exact sequence of spectral sequences

Let $(A_i, d_i, F_i)$ be a filtered differential complex (with bounded filtration) for $i=1,2,3$. Assume we have filtered chain maps $i:A_1\to A_2$ and $j:A_2\to A_3$ such that $$0\to A_1 \overset{i}{\...
Elad's user avatar
  • 3,332
0 votes
1 answer
50 views

Meaning of "quasi-isomorphism" of diagram indexed by the negative integers

I've been given this exercise: Fix a commutative unital ring $R$ and a diagram $$A^\bullet = \cdots \to A_{-2} \to A_{-1}\to A_{0}$$ of objects and maps in $\mathrm{Ch}(R \mathrm{-Mod})$ indexed by ...
Gay Lussac's user avatar
0 votes
1 answer
71 views

Reference for Hurewicz's theorem in algebraic topology

Let me begin by stating that under no circumstances am I an expert in algebraic topology. That being said, some years ago I came across Hurewicz's theorem relating the (co)homology groups to the ...
Prelude's user avatar
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0 votes
1 answer
57 views

Definition of homology group as quotient in chain complex

I am working through some theory about abelian categories and complexes from "An Introduction to Homological Algebra" by Rotman. I don't understand one of the sections which I will explain ...
Flynn Fehre's user avatar
0 votes
1 answer
66 views

Snake Lemma Weibel 1.3.2

I'm reading An introduction to homological algebra by Charles A. Weibel and I'm trying to prove the snake lemma 1.3.2. Using this diagram (don't have enough points to embbed it in my question) it says ...
Jolia's user avatar
  • 130
1 vote
1 answer
95 views

definition of chain homotopy

We can define the notion chain homotopy in the category of chain of $R-$modules. But do we have any definition of chain homotopy in any abelian category? Analogously I can define the notion of chain ...
Ziqiang Cui's user avatar
0 votes
1 answer
124 views

Homology functor preserves coproduct

(I am aware of the existence of this question). Hello, there's a step of a proof that $H_n$ preserves coproducts in an abelian category that I do not understand, despite it looking fairly simple... ...
Julia's user avatar
  • 355
0 votes
0 answers
86 views

Special short exact sequences of chain complexes

For simplicity let's say I am working in the category of chain complexes of $R$ modules. I have a chain map $i:C\rightarrow D$, which I know to be a weak equivalence (i.e. $i_*$ is an isomorphism of ...
Chris's user avatar
  • 4,163
0 votes
0 answers
111 views

Well-definedness of Cohomology

In an abelian category, cohomology can be defined as kernel of a cokernel and cokernel of a kernel, as follows, My problem is why are they the same? I expect this will be some image=coimage type ...
MrPajeet's user avatar
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1 vote
0 answers
56 views

Isomorphism between the hom complexes $\mathrm{Hom}(A,B[n])$ and $\mathrm{Hom}(A,B)[n]$

Let $A$ and $B$ be chain complexes of $k$-modules. Is there an isomorphism or a homotopy equivalence between the hom complexes $\mathrm{Hom}(A,B[n])$ and $\mathrm{Hom}(A,B)[n]$? I tried with the map $...
MaryMoon's user avatar
1 vote
2 answers
145 views

Quasi-isomorphisms are stable under homotopy base change in $\operatorname{Ch}(\mathcal{A})$

Edit: People are commenting that what I'm trying to do follows from "general theory of model categories" or "general theory of categories of fibrant objects". I have no idea at all ...
Elías Guisado Villalgordo's user avatar
2 votes
1 answer
51 views

Factorization of quasi-isomorphism is also a quasi-isomorphism

Let $\mathcal{A}$ be an abelian category, $ X_\bullet \overset{f}{\hookrightarrow} Y_\bullet \overset{g}{\hookrightarrow} Z_\bullet$ be in $Ch(\mathcal{A})$ such that $gf:X_\bullet \hookrightarrow Z_\...
S.Co's user avatar
  • 195
6 votes
2 answers
2k views

Short Exact Sequence of Complexes Induces Long Exact Sequence of Homology Groups

I am following Lang's Algebra on General Homology Theory and wanted to try proving the short exact sequence of complexes $$\require{AMScd} \begin{CD} 0 @>{}>> A @>{f}>> B @>{g}>...
Ryan Shesler's user avatar
  • 1,498
0 votes
1 answer
154 views

Morphism from image to kernel for a complex of objects in an abelian category.

I'm back again with another basic category theory question. I promise I will get my head around this - one day. Consider a complex (so $f_{n}\circ f_{n-1}=0$), of objects in an abelian category: $$ \...
CoffeeCrow's user avatar
  • 1,647
1 vote
1 answer
159 views

Weibel Lemma 1.6.2.

The following is (a part of) Lemma 1.6.2. from Weibel's Homological Algebra.$\newcommand{\C}[1]{\mathcal{#1}}\DeclareMathOperator{\coker}{coker}\newcommand{\md}[1]{{\left\lvert #1 \right\lvert}}\...
hello's user avatar
  • 396
2 votes
1 answer
726 views

Fundamental Lemma of homological Algebra, what is $H_0f$ supposed to mean?

I am currently attending a lecture in homological algebra, where we discussed the fundamental lemma of homological algebra (i will just cite the relevant part of the theorem): Let $\mathcal{A}$ be an ...
Zest's user avatar
  • 2,486
2 votes
0 answers
88 views

Derived functor of $H^0$

Let $R$ be a commutative unitary ring and $\mathrm{Mod}_R$ be the category of $R$-modules and $C := \mathrm{Ch}_{\geq 0}(\mathrm{Mod}_R)$ be the category of chains of $R$-modules which are zero in ...
Candyblock's user avatar
5 votes
0 answers
652 views

Naturality of connecting homomorphisms

I'm reading Weibel's "An Introduction to Homological Algebra" page by page. I'm confused about theorem 1.3.1: Theorem 1.3.1 Let $0\to A.\xrightarrow{f} B.\xrightarrow{g}C.\to 0$ be a short ...
Z. He's user avatar
  • 514
1 vote
1 answer
68 views

Condition for an element in Ext be zero

Consider an abelian category $\mathcal{A}$ and two objects $A,B$ of $\mathcal{A}$. It is straightforward that an element $\eta \in \text{Ext}^{1}(A,B)$ of the form $0 \to B \xrightarrow{f} X \...
Robert's user avatar
  • 33
2 votes
0 answers
131 views

Can equivalent abelian categories have non-equivalent derived categories?

This is a point of stupid confusion for me. Let $s:\mathcal{A}\to\mathcal{B}$ be an equivalence of abelian categories. Does this functor induce a triangulated equivalence $\overline{s}: \mathbb{D}^b(\...
Patrick Elliott's user avatar
2 votes
0 answers
59 views

On the categorical definition of Chain Homology

I am having trouble with the general definition of Chain homology. Given an Abelian category $\textbf{A}$, I have defined the category of Chain Complexes $\text{Ch}_\bullet(\textbf{A})$ as usual. ...
Anthony's user avatar
  • 1,359
5 votes
1 answer
265 views

Grothendieck category with a generator has injective hulls (envelopes): a subtlety in Freyd's book on abelian category

First, Freyd proves that an object in a Grothendieck category is injective if and only if it has no proper essential extensions. For each object $A$ of the category, he chooses a monomorphism $e_A\...
Jxt921's user avatar
  • 4,648
1 vote
1 answer
121 views

Chain Complex morphism: Arbitrary maps instead of Homomorphism?

Given two chain complexes $\{ G_i \}$ and $\{ H_i \}$ we usually define a morphism of chain complex as a family of homormophisms $\{ f_i \}$ such that the diagram commutes: $$ \begin{matrix} \dots &...
Siddharth Bhat's user avatar
6 votes
1 answer
233 views

Weibel: spectral sequence of a filtration

Let $$\dots \subseteq F_{p - 1}(C) \subseteq F_p(C) \subseteq F_{p + 1}(C) \subseteq \dots$$ be a filtration of a chain complex in an abelian category. In his book Introduction to Homological Algebra, ...
Jxt921's user avatar
  • 4,648
1 vote
1 answer
380 views

Properties of a middle resolution of a Horseshoe Lemma

I understand the proof of Horseshoe lemma as it is presented in, e.g. Weibel's book. However both Weibel and these notes note an additional property which is at the bottom of my screenshots here: ...
Jxt921's user avatar
  • 4,648
2 votes
1 answer
78 views

Spectral sequence of a filtration: a possible mistake

$\require{AMScd}$The following is taken from these notes by Daniel Murfet. Let $ \cdots \subseteq F^{p + 1}(C) \subseteq F^p(C) \subseteq F^{p - 1}(C) \subseteq \cdots$ be a filtration of a complex $...
Jxt921's user avatar
  • 4,648
2 votes
1 answer
178 views

Exactness in category theory

In MacLane's 'Category Theory for the working mathematician' there is a definition of exactness (page 200): 'A composable pair of arrows $f: a\rightarrow b$ and $g: b\rightarrow c$ is exact at b if ...
S.Farr's user avatar
  • 1,190
1 vote
1 answer
32 views

A complex with prescribed cohomology

Let $\mathcal A$ be an Abelian category (I am happy to assume that $\mathcal A\cong \mathrm{Mod}(R)$ for some ring $R$ if that helps). Given the following long exact sequence in $\mathcal A$ $$ 0\to ...
Simone's user avatar
  • 2,024
3 votes
2 answers
41 views

Are the two morphisms $T^i(C)\to T^{i+1}(A)$ the same for each $i$?

For short exact sequence $0\to A\to B\to C\to 0$, we have $T^i(C)\to T^{i+1}(A)$ such that the long sequence $$0\to T^0(A)\to T^0(B)\to T^0(C)\to T^1(A)\to \cdots$$ is exact. For short exact sequence $...
Born to be proud's user avatar
3 votes
0 answers
108 views

Question on why a particular quasi-isomorphism between complexes doens't have an inverse

My question is on the example below, taken from page 4 of http://www.math.wisc.edu/~andreic/publications/lnPoland.pdf. I'm not familiar enough with this stuff yet to understand why the quasi-...
user avatar
3 votes
1 answer
76 views

Is a "subfunctor generated by x" really a subfunctor?

I am reading Freyd's Abelian Categories, and Essential Lemma 7.12 says: Let $\mathcal{A}$ be an abelian category, and $Ab$ be the category of abelian groups. Let $M \rightarrow E$ be an essential ...
SSF's user avatar
  • 905
15 votes
4 answers
1k views

Homological algebra using nonabelian groups

Can homological algebra be done with nonabelian groups? In particular, can homology or cohomology be defined on chain complexes of nonabelian groups? I know that Abelian categories are the choice ...
Herng Yi's user avatar
  • 3,216
1 vote
1 answer
89 views

Computing Ext for a complex of modules, help with a proof in Stacks Project

I am stuck on a step in the proof of Lemma 15.66.2 here. Let $R$ be a commutative ring with identity and let $K^{\bullet}$ be a complex of $R$-modules. I am stuck on the following sentence: "Choose a ...
Luke's user avatar
  • 3,693
0 votes
1 answer
228 views

How to show a morphism $f^•: A^•\to B^•$ of complexes induce the morphism of cohomology objects $H^i(A^•)\to H^i(B^•)$?

Let $\mathscr C$ be a Abelian category, how to show a morphism $\varphi^•: A^•\to B^•$ of complexes induce the morphism of cohomology objects $H^i(A^•)\to H^i(B^•)$? $A^•:\qquad \cdots\to A^{i-1}\...
Born to be proud's user avatar
2 votes
1 answer
50 views

Injective objects in a category

Let $C$ be a category and $x\in$ Ob$(C)$. Assume that $I\in$ Ob$(C)$ is injective in $C$, and there are morphisms $f:x\rightarrow I,~ g:I\rightarrow x$ such that $gf =1_x$. Is it true that $x$ is ...
Cdse We's user avatar
  • 63
1 vote
1 answer
971 views

Exact additive functor preserves homology

Let $R$ and $A$ be rings, $T:{}_{R}\text{Mod}\rightarrow {}_A\text{Mod}$ be an exact additive functor and $(C_\bullet,d_\bullet)$ a chain complex in ${}_{R}\text{Mod}$. Prove that $$H_n(TC_\bullet,...
Walter Simon's user avatar
4 votes
1 answer
203 views

Non-trivial extensions with trivial connecting homomorphism in long exact sequence?

Let $X$ be a smooth projective curve over an alg. closed field $k$. Consider an exact sequence of locally free sheaves: $$0 \to \mathcal{E}_1 \to \mathcal{E}_2 \to \mathcal{E}_3 \to 0$$ This ...
Saal Hardali's user avatar
  • 4,899
1 vote
1 answer
76 views

If an object of an abelian category is split in the derived category, then must it be split?

Let $\mathcal{A}$ be an abelian category, and $A\in\mathcal{A}$ an object. Let $D(\mathcal{A})$ be its derived category, and let $A'$ denote the image of $A$ in $D(\mathcal{A})$. If $A' = B'\oplus C'$ ...
user avatar
1 vote
1 answer
120 views

A particular exact sequence in an abelian category

Let $\mathcal{A}$ be an abelian category and let $(X^\bullet, d^\bullet)$ be a chain complex in $\mathcal A$. I want to show that there exists an exact sequence $$0\to \text{im}(d^{i-1})\to \ker(d^i)\...
user72870's user avatar
  • 4,212
2 votes
1 answer
176 views

Homotopy of chain complexes (category theoretic proof)

I know the usual proof of the fact that if a morphism between chain complexes $f$ is homotopic to zero then it induces the $0$ map on cohomology. I was wondering if there is an easy proof of this ...
Abellan's user avatar
  • 3,795
3 votes
0 answers
49 views

An alternative of projective dimension in triangulated categories

Does anybody know anything about an alternative of the notion of projective dimension (defined in abelian categories with enough projective objects) in triangulated categories?
Nick's user avatar
  • 31
1 vote
0 answers
134 views

Easy characterization of Cohomology in an Abelian Category

It should be quite an easy question and probably there's also a certain degree of intrinsic silliness in it, but still... Let $\mathcal{C}$ be an abelian category and let $C(\mathcal{C})$ be the ...
Marco Vergura's user avatar
0 votes
1 answer
150 views

Are the hom sets in the category of varieties abelian groups?

This is supposedly (though I know of the proof bud haven't read it) for the Hom sets of noetherian schemes. Since every variety can be thought of as a noetherian scheme then it seems right... when ...
ABIM's user avatar
  • 6,828
42 votes
3 answers
2k views

Why do universal $\delta$-functors annihilate injectives?

Let $\mathcal{A}$ and $\mathcal{B}$ be abelian categories. Suppose $\mathcal{A}$ has enough injectives, and consider a universal (cohomological) $\delta$-functor $T^\bullet$ from $\mathcal{A}$ to $\...
Zhen Lin's user avatar
  • 93.3k
29 votes
2 answers
3k views

Meaning of "efface" in "effaceable functor" and "injective effacement"

I'm reading Grothendieck's Tōhoku paper, and I was curious about the reasoning behind the terms "effaceable functor" and "injective effacement". I know that in English, to efface something means ...
Zev Chonoles's user avatar
42 votes
3 answers
5k views

How to define Homology Functor in an arbitrary Abelian Category?

In the Category of Modules over a Ring, the i-th Homology of a Chain Complex is defined as the Quotient Ker d / Im d where d as usual denotes the differentials, indexes skipped for simplicity. How ...
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