Valid, if leads are kept at ambient temperature at a distance of 10 mm from case
The wording is extremely poor indeed!
What this really means is that the "ambient" temperature is defined as the temperature of the leads 10mm away from the case - whatever that temperature may be when the diode is in thermal equilibrium, i.e. everything has warmed up.
For example, if the leads are soldered into the PCB at a distance exactly 10mm from the case, and there are large copper areas to dissipate the heat, then there won't be a big thermal gradient next to the leads, and the temperature of the copper area immediately adjacent to the lead will be what you need to put into the thermal model as the "ambient" temperature.
It doesn't mean that you'll be expected to somehow heatsink the lead to ambient air 10mm away from the case. It'd be entirely impractical, and it would be easier to get a diode in a thermally superior package and make it dump the heat into the PCB better, or use a diode in a package that's mounted to a heatsink.
Should it be understood that Ir can reach 1 A?
\$I_r\$ is controlled by you (or, rather, the circuit you've designed). It is the reverse current that charges the diode capacitance so that the diode turns off. It is not a leakage current.
If the circuit you've designed cannot provide about 1A of reverse current to turn the diode off, then the diode will stay turned on for much longer than 1.5µs.
The diode is a typical slow rectifier diode. It's not even a good diode for transformer rectifier circuits: it will have lots of cross-conduction as the AC voltage changes polarity. This particular diode is best used for circuits where the current flows in one direction for a long time, e.g. for polarity protection or parallel supply isolation.
Real diodes do not turn off immediately. They always need some charge driven as a reverse current to turn off. This particular diode needs about 1.5µC of reverse charge to turn off from full conduction. \$Q=I\cdot t\$, thus 1A*1.5µs=1.5µC. Or, alternatively, it's equal to charging a 1.5µF capacitor from 0 to 1V.