JOURNAL
OF MATHEMATICAL
ANALYSIS
AND
Analytic
157, 3 18-336 (1991)
APPLICATIONS
Besov Spaces
KEHE ZHU*
Department of Mathematics, State University
Albany, New York 12222
of New York,
Submitted by C. Foias
Received June 5, 1989
1. INTRODUCTION
Let D be the open unit disk in C and dA the normalized area measure
on D. For 1 < p < +co, the analytic Besov space BP consists of analytic
functionsfon D such that (1 - Izl’)f’(z) is in LP(D, &), where
d&z)
d4z)
=
(,
_
lz12)2
is the Mobius invariant measure on D. The Besov space B, consists
of analytic functions f on D such that f(z) =CT=? anql,(z) with
C,‘=“l [anI < +co, where 1, ED and
VA(Z)
For 1 <p<
zz
A--2
1-Xz’
ZED.
+co, we write
llfllB,= lI(l - Iz12)f’(Z)IlU(di)~
When p = 1, we write
llfll B,= hf { y M: f(z) = F anlni..(z))’
n=l
n=l
Note that B, is also called the Bloch space. I( jl B, is a complete norm
on B,. When 1 < p d +co, 11iI4 is a complete semi-norm on BP. For all
1 d p < +co, 11/IBPis Mobius invariant in the sense that IIf0 cp]IBP= llfll 4
for all f~ B, and cpE Aut(D), the Mobius group of D.
* Research supported by the National Science Foundation.
318
0022-247X/91 $3.00
Copyright
0 1991 by Academic Press, Inc.
All rights of reproduction
in any form reserved.
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ANALYTIC BESOV SPACES
The advantage of the above definition for B, is that I/ IIB, is clearly
Mobius invariant. The disadvantage of this definition is that it makes B,
appear isolated from the other spacesB,. It follows from Theorem A below
that for 1 < p < + 00 an analytic function f(z) on D is in B, if and only if
(1 - IzI *)*f”(z) is in LP(D, &). Thus we see that B, is indeed compatible
with the other B,‘s. In particular, we see that f is in B, if and only if
s
D \f"(Z)I dA(z)< +a.
This characterization for B, can be found in [2], and we will use it
occasionally.
To describe the main results of the paper, we need to use the Bergman
metric of D, which is given by
1
B(z, w)=px
1 + kPz(wl
1 _ ,ql(w),’
z, WED.
For any z E D and Y> 0, let E(z, r) = {w E D: /?(z, w) < Y} and IE(z, r)j be
the (normalized) area of E(z, r). If f is analytic in D, we define the oscillation off at z in the Bergman metric as
o,(.f)(z)=suP{If(z)-f(W)I:
wEE(z, y,).
We’ll also consider the mean oscillation off in the Bergman metric. Let
^
1
fJz) = lqz, r)l I E(;,r)f(w) dA(w),
ZED.
The mean oscillation off at z in the Bergman metric is then defined to be
MQ,(f
^
1
)(z) = ,E(z, r), sE(=,r)If(w) -f,(z)1
dA(w).
For f analytic in D, we’ll let 1f(E(z, r))l denote the (normalized) area of
the image of E(z, Y) under$ The main results of the paper are Theorems A,
B, C, and D.
A. Suppose 1 d p < +CO, m 2 2, P is the Bergman projection
on D, and f is analytic in D, then the following are equivalent:
THEOREM
(1) f+;
(2) f E PLP(D, di,);
(3)
(1 - IZ/2)“‘f(n’)(z)ELP(D, dA).
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KEHE ZHU
Moreover, if 1 < p < +co, then
(4)
jr&
(If(z)-f(w)l”/ll
-Z~14)~4Z)~~(~)<
THEOREM B.
following
If r > 0, 1 < p < +oo, and ,f is analytic
are equivalent:
(1) f ~4,;
(2) MO,(f)
E LV,
(3)
w(f)
(4)
If(E(z, r))l”‘E
THEOREM C.
+a.
in D, then the
d2);
E LP(Q dA);
LP(Q d2).
Suppose f(z) = CT:0 a,z” is analytic in D, then we have
(1) For any 16 p < +co, there is a constant C, > 0 (independent off)
such that
IanId C, Ilf /IBpn--lip,
(2)
n = 1, 2, ... .
There is a constant C > 0 such that
THEOREM D.
For any 1 < p < +oo, there exists a constant C, > 0 such
that
If(z)-f(w)1
GCp Ilf IIBpP(Z,w)“y
for all f E B, and z, w E D, where /I is the Bergman metric and l/p + l/q = 1.
We note that the above results are well-known for the case p = +co. See
[ 1, 3,4]. Actually, this case serves as our main motivation for the paper.
Theorem A will be proved in the next section by a number of lemmas
some of which are of independent interest. We prove Theorem B in Section 3, where several other geometric characterizations for the analytic
Besov spaces are also obtained. Sections 4 and 5 are devoted to the proof
of Theorems C and D, respectively.
The author thanks the referee for a very careful reading of the
manuscript and several insightful comments and suggestions. This work
was done while the author was at the University of Waterloo.
321
ANALYTIC BESOV SPACES
2. ANALYTIC CHARACTERIZATIONS
Recall that the Bergman kernel of D is the function
K(z, w) =
1
(1 -zG)
2’
z, WED.
The Bergman projection is the operator P defined by
P!(z) = j f(w) &, w) dA(w),
ZED.
D
For any LED, let
1 - /q*
k,(z) = (1 _ Xz)2.
It is easy to see that k,(z) = -q;,(z), thus we have the following change of
variable formula
jD.bCPAZ)
dA(z)= jDS(4lk,&)12
dA(z).
Since each cp).is an involution, we also have
This section is devoted to the proof of Theorem A. We break the proof
into several lemmas some of which are of independent interest.
LEMMA
1. Iff
Proof:
Fix any nonnegative integer n and z E D, then
is a polynomial,
ix0
then f E PLP(D, d%)for all 1 ,< p 6 +oo.
(m+ l)z* jD (1 - 1~1’)~w’?V’dA(w)
=(n+l)z”
j~(l-lw~*)‘l~~~“dA(w)
2
=(n+2)(n+3)Z”’
322
KEHE ZHU
It follows that each monomial is in PLP(D, &) for all 1 < p < +oo. Since
the Bergman projection is linear, we see that each polynomial is in
PLP(D, dA) for all 1 <p< +co. 1
LEMMA 2. Suppose m 3 l,f~
. . = f”“‘(O) = 0, then
Proof
L’(D, dA) is analytic, andf(0)
=f’(O)
=
Since f(0) = f’0) = . . = f”“)(O) = 0, the integral
(1- Iw12)“f’“‘(w)dA(w)
g(z)=$S,
$yl-zw)2
converges for all z E D and defines an analytic function g(z) in D. Taking
derivatives n times inside the integral gives
SincefE L’(D, dA), we have (1 - Iz12)“f’“‘(z) E L’(D, dA) [S]. By 7.1.4 of
[6] (and an application of dominated convergence), we have
ZED.
g’“‘(z) = f’“‘(z),
For any 0 <k B m - 1, Taylor expansion shows that
(1 - Iw12)“f’“‘(w)
g’*‘(o)=i!!$!?j
dA(w)=o
-m-k
W
D
Thus we have g’“‘(z) =f’“‘(z)
and gCk’(0)=f’“‘(O) for all 0 d k <m - 1.
Hence f(z) = g(z), completing the proof of Lemma 2. 1
LEMMA 3.
rf 16 p < + a3 and f E B,, then f E PLP(D, dl,).
By Lemma 1, we may as well assume that f(0) =.f’(O) = . . . =
Proof
f ‘4’(O)= 0. By Lemma 2, we have f = Pq with
cp(z)= Cl- Iz12)f’(4
z
ZED.
If 1 < p d +co and f E B,, then cpE LP(D, dA) and hencef E PLP(D, dA).
Iff EBi, then
f(Z)=
y anV2n(z)
I, = 1
323
ANALYTIC BESOV SPACES
for a sequence {An} in D and C,:=“, la,/ < +co. It is easy to compute that
f”(Z) = -2 :cr an/in (:_;;$
II= I
By 1.4.10 of [6], there is a constant C>O such that
jD(1- lz12)2
If”(z)1
4z)=s,If”(Z)1
d‘e)
62 +f I% Cl- IW~J:
,ly;,3
n
,z = 1
II=1
By Lemma 2, we have S = PCJJwith
q(z) = (1 - Izl*)*fw
22*
in L’(D, dll). This completes the proof of Lemma 3. 1
LEMMA 4.
The operator T defined by
Tf(z) = (1 - 1~1~)
jDfIl”~z$;’
is bounded on LP(D, d;l) for all 1 < p < + CO.
Proof:
l<p<
By 1.4.10 of [6], T is bounded on L”(D).
+oc and l/p+l/q=l.
Let
1
El=-+-
2q
3
P’
1
&l
&*=-+-
Assume that
2
4’
then we have E, + c2= 3, qE2> 2, and pc, > 3. By Hiilder’s inequality, we
have
324
KEHE ZHU
Since qc2 > 2, 1.4.10of [6] implies that there is a constant C, > 0 such that
c
dA(w)
ID
d
11 -zzw/qc2
(1
_
YIP
)2):yF-2
for all ZE D. Since E, + .s2= 3 and l/p + l/q = 1, it is easy to see that
1 - (qE2- 2)/q = F, -2/p. It follows that
ITf(z)l”<
C,(l - Iz12)P@
IS( p dA(w)
sD 11- ZWlPC’
for all z ED. Applying Fubini’s theorem, we get
jD IV(z)lp WI
6 C, j”DIf(
p dA(w) i, “l;!?;;:;4
dA(z).
Since pcl - 4 > - 1, 1.4.10 of [6] implies that there exists another constant
C, > 0 such that
(1 - IzJ2)PQ-4
c2
D I 1 - ZWlP”’ dA(z)6 (1 -jut\‘)’
1
for all w E D. This implies that
j I?‘f(z)lp4z)~C,C,
D
jD If(w)l”d4w),
completing the proof of Lemma 4. 1
COROLLARY.
Proof.
If 1 < p d + cc and f E PLP(D, dA), then f E BP.
Suppose cpE LP(D, dll) and f = Pep, then for any z E D, we have
Differentiating under the integral sign and then multiplying the result by
(1 - lzl*), we get
By Lemma 4, we have (1 - lzl*)f)(z)~
When p = 1, we have
f”(z)
= 6
LP(D, dE,) for all 1 <p<
!:,,l;y;;;, dA(w)
+co.
325
ANALYTIC BESOV SPACES
and
=6 j
Icp(w)l dA(w)< +a.
I
D
We have proved the equivalence of (I) and (2) in Theorem A.
LEMMA 5.
Suppose a > 1 and T, is the operator defined by
Tnf(z) = (I-
Iz12YjD :,(~z;I::,,.
Then T, is bounded on L,(D, dA) for all 1 6 p d +CO.
Proof:
c, Ilfli,.
By 1.4.10 of [6], there is a constant C, >O such that IlT,/I, d
On the other hand, 1.4.10 of [6] gives another constant C, > 0
such that
sD ITxf(z)l W)d
I, If(w)1 dA(w) jD (l;+;r;22dA(z)
d
c2
If(
sD
(1
Mw)
-
(,i2)’
=
C2
jD If(w)ld~(w).
By interpolation [S], T, is bounded on LP(D, d;l) for all 1 < p < + CO. 1
Remark.
The referee pointed out that
Cl- lz12Y If(w)I dA(w)
IT,f(z)l d t1 _ lzlIm-~ .rD ll-zWl3
.
Thus Lemma 5 follows from the proof of Lemma 4 in the case 1 < p < +a,
and hence interpolation is not needed for the proof of Lemma 5.
COROLLARY.
Suppose 1 6 p 6 + co and m 3 2, then f E PLP(D, dA) if and
only [f (1 - /z12)*f (M)(z) E LP(D, dA).
ProoJ The “if” part follows from Lemmas 1 and 2. To seethe “only if”
part, let f = Pep with q E LP(D, d;l). Then differentiating under the integral
sign gives
The desired result now follows from the above lemma. m
326
KEHE ZHU
This completes the proof of the equivalence of (l), (2), and (3) in
Theorem A.
LEMMA 6.
Zf 1~ p < +m and f is analytic in D, then f E B, ij’ and only
if
is
D D
ProoJ
If(z)-f(w)l”
)l-nq4
dA(z) dA(w) < +m.
If g E L’(D, dA) is analytic, then Taylor expansion shows that
g’(O)= 2 jD $g(w) - g(O))Mw).
By Holder’s inequality, we have
Ig’(O)1’ 6 2’ jD Ig(w)- g(O)1
pWw).
Replace g by f 0cp=,then
Using Fubini’s theorem and a chage of variable, we get
s
D
(1 -l4’)”
If'(z)l"d4z)
=2p!*,!“D
‘f’;‘~+-;;“p
dA(z) d/l(w).
This proves the “if” part of the lemma.
On the other hand, by Theorem A of [S], there is a constant C> 0
(depending only on p) such that
is
DD
If(z)-f(w)lpd~(Z)dA(w)
ll-z+14
=~DW)~D
If~cp,(w)-ff(z)lPdNw)
327
ANALYTIC BESOV SPACES
Since (focp,)’ (w)=f’((~Aw)) d(w) and (1 - 14’) Id(w)I = 1- Iv,(w)l*,
we have
ss
If(z) -f(w)l p &(=) dA(w)
D *
(1-zW14
4 z1JD
(1 GCJD
I~z(~~~)l’YIf’(cP,(w))l” dA(w)
= c j di(z) j (1 - lwl’)” If’(W)IP Ikl(W)12dA(w)
D
D
= c jD Cl- Iwl’)” If’(~~)l”~4W) I, lly~;14
= c jD (1- [WI’)” If’(w)“&(w).
This proves the “only if” part of Lemma 6. 1
This completes the proof of Theorem A. We remark that the following
are equivalent norms on B, for 1 < p < +a:
(1) lIfllBp+ If(O
(2) llfll = I.m)l + If’(O)+ ... + If’“- “(O)l
+ lltl- Iz12~‘~f~“~~z~llLP(di)~
Ilfll =inf(IIgll,~,,:f=~g);
c4) /tf /I = If(O)I + &, SD(If(z) -fcw)l "/I 1 - zw14)
&4(z) &l(w)]?
(3)
3. GEOMETRIC CHARACTERIZATIONS
Recall that p is the Bergman metric on D and for z E D, r > 0,
E(z, r) = {w E D: fi(z, w) < r}.
If f is a function on D, then the oscillation off
metric is
o,(.f)(z)=supfIf(z)-f(w)l:
at z in the Bergman
wEE(z, r)>,
and the mean oscillation off at z in the Bergman metric is
1
1
M~r(fNz) = ,E(z, r), sE(;,r)If(w)-.Ixz)l
dA(W)>
328
KEHE ZHU
where?Jz) is the averaging function defined by
For any open set E c D and any bounded function
dist(f, H”(E))=sup(I
f(z)-g(z)l:zEE,
f on E, we write
gEH”(E)}.
The main purpose of this section is to prove Theorem B. In the process of
the proof, we’ll obtain several other characterizations of the analytic Besov
spaces.We need the following well-known estimates (see [4] for example):
(1) There is a constant C > 0 (depending only on r) such that
1
C I&
C
r)l
6 IUw)12 6 IE(z, ).),
for all z E D and w E E(z, Y).
(2) There is a constant C > 0 (depending only on Y) such that
lfcz,l6--j IE(z, r)l ,q;,r) IfCw)' dA(w)
for all analytic functions
f and z E D.
We state the main results of the section as
THEOREM 7. If r > 0, 1~ p < +CXI, and f is analytic in D, then the
following are equivalent (note that in some casesfunctions are ident$ed with
their values at z):
(1) fEBp;
(2)
MO,(f) E LV,
(3)
(4)
If(E(z, r))11i2ELPP, di);
C&i,r) If’(w)12 d4w)l”2 E LPP, d2);
SE(w)If "(w)I dA(w) E LP(D, dA);
diWIEcz,,,, H”(E(z, r))) E LP(D, dA);
o,(f)ELVX
dA);
IE(z, rj1-l jEcz,rjIf(w)-f(z)I dA(w)ELP(D,dA).
(5)
(6)
(7)
(8)
dJ%);
ProoJ The theorem will be proved in the following orders: (1) o (2) o
(7)--V); (l)-(5);
and (l)-=-(3)-(3)-(4)-(6).
ANALYTIC
BESOV
SPACES
329
We begin with the inequality
Replace .f by f - f{z), then
for all analytic f and z, WED. If w E E(z, v), then E(w, r) c E(z, 2r) and
there is another constant C2 > 0 such that
It follows that
for all z E D. Choose a constant C > 0 such that
C2
G c Ik,(N
IJW, WI
2
for all z E D and w E E(z, 2r), Since each lk,(w)l’dA(w)
measure, we have
is a probability
This proves the implication
(1) + (7) by Lemma 6 (and a change of
variable).
The implication (7) => (8) is obvious from the observation that
409:157'2-3
330
KEHE ZHLJ
That (8) implies (2) follows from the inequality
=-
2
Im 4 I I ‘q:,r)
If(w) -mi
~40
By Taylor expansion and the symmetry of E(0, Y), we have
s’(O)=Cj
E(O.
r)
a4
d-0)
for all analytic function g in D, where C > 0 is some constant independent
of g (but dependent on r). Replace g by g - A and crack in the absolute
values, then
I g(w) - 4 Mw)
for all analytic g and all complex numbers A. Replace g by fo cp; and A by
.ih), then
(1- lz12)V-WI G c j
w, r)
If%04
-m
d4w).
Changing the variable in the above integral and using the fact that
cp,VW, r)) = JW, 4, we get
(1 - Izl’) If’(Z)I Q c j
IS(w) -“M
E(;,r)
Choose another constant C’>O such that
c Ikwl’~
C’
,E(z, r)l
for all z ED and w E E(z, Y) then
(1 - IA21 I.fWl G C’MWfk)
Ik(w)l’ Ww).
ANALYTIC
BESOV
SPACES
331
for all analytic f and z E D. This proves that (2) implies (l), and we have
completed the proof of the equivalences of (l), (2), (7) and (8).
Next we prove the equivalence of (1) and (5). By a change of variable,
) lf”(W)l dA(w) = I,(o,r) If”(cpAw))l lk(w)12 dA(w).
sE(-,r
Since E(0, Y) is a Euclidean disk with center 0 and radius less than 1
(depending on Y only), there is a constant C> 0 such that 1 ,< C( 1 - Iwl’)’
for all M’E E(0, r). Thus
s
I.f”(~~)l dA(w) < c j
If”(P4w))l (1 - 142)2 lkb412 Mw)
E(:.r)
E(0.r)
=Cj
uo.r)
If”(cP,(w))l (1 - I4&4’)‘~~(w)
6 c sD If”(cPAw))l Cl- I~‘04’)‘~~(w)
= c [ If”(W)\ (1 - Iwl’)2 ~k;(w)~‘liA(w).
JD
then (1 - I~l~)~f”(w) is bounded in D, which implies that
If .fEB,,,
jE(z,rj If”(w)1 &I(w) is bounded in z since each lk,(w)12d,4(w) is a
probably measure. Moreover, if 1 d p < +cc, then Holder’s inequality
implies that
D
If”(W)lP (1 - lw12)2pIk,(W)l’dA(~~),
and Fubini’s theorem gives
~dE.(z)~Cp~D(l-~M;‘)~~lf”(w)~“drl(w).
I.f”(W)l &l(w)
1
Therefore, (1) implies (5) by Theorem A.
On the other hand, we can find a constant C > 0 (depending on r only)
such that
C
If “(ZII 6 lE(z,
sE(-,r,I.f”(W)l dA(w)
for ail z E D and all analytic J: Since lE(z, r)l - (1 - 1~1~)~for any fixed
r > 0, we can find another constant C’ > 0 such that
I f”(w)l dA(w).
E(;,r)
(1 - \z12)2I.f”(Z)l d C’ 1
Thus (5) implies (1) by Theorem A.
332
KEHE ZHU
Finally we prove the equivalences of (1 ), (3), (4), and (6). That (4)
implies (3) is clear, because IE(Z,rjlf’(w)12 &t(w) is the area of f(E(z, r))
counting multiplicity. By the proof for the case p = +co in [3], there are
constants C, > 0 and C’, > 0 such that
(1 - lzl’) If’(z)1 <Cl dist(flE(z,r),H”(E(z, r)))GC2 If(Q, ~))l”~.
Thus we have (4)=> (3)9 (6) 5 (1). It remains to show that (1) implies
(4).
First we note that
l/2
1
IfW12dA(w) < JE(z, r)ySup{If’(w)l:
If
w
E E(z, v), then E(w, r) c E(z, 2r)
and
IE(w, r)l
WEE(Z, Y)].
is comparable to
I%, r)l, thus
If’(w)l 9 ,,E: r), s,,,.,, Is’(u)I dA(u)
<-
c2
If’(U)1 Mu)
IEk r)l sE(z.Zr)
for all w E E(z, Y). It follows that
I)
[i EC:,
If’ba2
dA(w)
1’2f c, (E(z, r)l Ii2
E(-2 , If’(~)l dA(u)
I% r)l s -, r
1
for all z E D. Since IE(z, r)/ ‘j2 is comparable to (1 - IWI’) and jE(z, r)] ’ is
comparable to Ik,(w)l’ for all ZE D and w E E(z, r), we can find a constant
C > 0 such that
d C i (lD
1~1~)If’(w)1 Ik(w)12 MM))
for all z E D. The implication (1) + (4) now follows easily from an
application of the Cauchy-Schwarz inequality (note that lkz(w)12 d(w) is
a probability measure for each z E D) and Fubini’s theorem. This completes
the proof of Theorem 7. 1
ANALYTIC
333
BESOV SPACES
4. TAYLOR COEFFICIENTSOF FUNCTIONS IN B,
In this section, we estimate the growth of the Taylor coefficients of
functions in the analytic Besov spacesB,. The main result of the section is
Theorem C in the Introduction. For convenience of reference, we restate
the theorem as
THEOREM
8.
Suppose f(z) = Cz=x0 a,,z” is analytic in D, then we have
(1) For all 1 <p<
+a,
there is a constant C,>O
n = 1, 2, ... .
I4 GCp lIfllBpn-“p~
(2)
with
There is a constant C > 0 such that
+cr 14 6 C IlfllB,.
,t=0
Proof: Since the Bloch space B, contains all the other Besov spaces,
we may as well assume that f E B,. In this case, we have
a,z=(n+l)~~(l-l;i2)f’(~)in~1dA(z),
n = 1, 2, ... .
a,,=f(n+l)J
n = 2, 3, ... .
(l-~z~2)2f”(z)~‘*-2dA(z),
D
It follows from the first equation above and Holder’s inequality that if
1 <p< +co, then
Ia,/ <(n+
1) jD (1 - lz12) If’(z)/
Izlnp’ (l-
1~1’)~dl(z)
l/Y
<(n+
1) IIf II4
Izl(n-‘)q (1 - IzI*)~~d(z)
j
i
D
I
for all n = 1, 2, .... where l/p + l/q = 1. Using polar coordinates and
r-functions, we can easily get
By Stirling’s formula,
Q(n-l)q+2)
T((n+l)q+l)-n24
1
(n-t
+co).
334
KEHE ZHU
Therefore we can find a constant C > 0 such that
?Y
bnl GC IIfIlBJ~+ 1) p&
(
n = 1, 2, ...
3
>
Since l/p + l/q = 1, we have 2 - l/q = 1 + l/p. It follows that there is a
constant C,>O with
bnl Q cp IlfllEp-‘i”
for all n=l,2,....
This proves (1) for l<p<
+co. The case p= +cc is
trivial from the first formula for a,. Moreover, it is clear that C, = 2.
To prove the case p = 1 in (1 ), we use the second formula for a, :
a,=&+l)
j (1 -~z~2)2,f”(Z)Zn~*dA(Z),
n = 2, 3, ... .
D
Elementary calculus shows that the maximum of (n + 1) Iz\~-~ (1 - 1~1’)~
in D is
(n+ 1) (s)(np2)‘2
(5)
which is clearly less than 16/n. Since jn If”(z)1 &t(z) is dominated by
/If IIB, (see the proof of Lemma 3), we can find a constant C > 0 such that
(a , <c IlfllB,
n --. n
for all n b 2. The case n = 1 is easy (point evaluations of derivatives of
functions are bounded linear functionals on the analytic spaces). This
proves (1).
Part (2) also follows from the second formula for a,:
un=; (n+ 1) JD (1 - lz~2)2f”(z)Z~~* &t(z).
We have
nF* l%l <;j:
(I- lz12)’ If”(Z)l dA(z) +cx(n+ 1) 14n-2
n=2
G 2 sD If”(Z)l dA(z)
ANALYTIC BESOV SPACES
335
f IIB,.Since la01+ la,] is dominated by I/f IIB,, the
which is dominated by 11
desired result in (2) now follows. This finishes the proof of Theorem 8. 1
Remark. The above result for p = + so is well-known, see [l]
example. The casep = 1 in (1) is also well-known, see [2].
for
5. GROWTH OF FUNCTIONS IN BP
Finally in this section we prove Theorem D, a Lipschitz type estimate for
functions in the analytic Besov spaces.
THEOREM
9. For any 1 6 p < +CD, there exists a constant C, > 0 such
that
If(z)-f(w)1
GC, Ilf IIB,,P(ZT
wry
for all f E B, and z, w E D, where /? is the Bergman metric and l/p + l/q = 1.
Proof: If p = + co, then q = 1 and the desired result is well-known (with
C, = l), see [3] for example. When p = 1, then q = +cc and the desired
result is obvious by the definition of the norm ((f jlB,. So we now assume
1 < p < +GO. Since both II 1)4 and /I are Mobious invariant, it suffices to
prove that there is a constant C, such that
If(z)-f(O)1 G c, II.fIIBJm z)“y
for all f E B, and all z E D.
By Taylor expansion, we have
for all f E B, and z E D. It is easy to find a constant C, > 0 (see Lemma 15
of [7]) such that
If(z)-f(O)1
ss,
(1 -lwl’)
If'(w)l
,w, ,1 -zu’12
d c, s (lD
dA(w)
Iw12) If’(w)1 dA(w)
II
-zzw(’
= C, jD Cl- b12) If'(w)1 'I,_'!;~'d&v,.
336
KEHE ZHU
Applying HGlder’s inequality, we get
By 1.4.10 of [6],
s
(l- lw12Y2 dA(w)-~log
D
(l-zW12Y
2
1+ IZI
--/?(O,
z)
1 - lzl
(lzl + 1 -).
Thus there are constants 6 E (0, 1) and C2 > 0 such that
If(z) -“m)l G c2 IIf IIBPPa ZP
for allfEBp and 6 < Iz/ < 1.
The case IzI < 6 can be deduced from Theorem C. In fact, if f(z) =
CcT0 u,zn, then Theorem C gives a constant C3 > 0 such that
If(z)-f(O)1 6 y I4 l4”6C,
IlfllB,, y lZl”n-l’P
?I=1
n=l
fC3 llfllB&b&
Ilf llBpIzl
+
Ilf IIBpB(O~
z)l’y
Ilf 113lW&
for all f~ B, and IzI < 6. This completes the proof of Theorem 9. [
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