Auto unzip of password-protected rar files in python

Question

recently started to learn python and there was a problem .... I need to unzip the rar file, which is password protected, but the password is written in the file name, which is in the archive. And so ~ 300 times. How, with what and where can this be implemented? For example, there is an archive 383442389.rar, it has two files, pass-1337643656.data (the name contains the archive password) and the following archive)

Answer 1

I'm not sure of all the context of your question, but I will try to answer you.

1. You said that you need to unzip a file .rar, but that is not possible, if the file is .rar you need to unrar

2. If you need just to unzip a .zip

something like that should work

from zipfile import ZipFile
with ZipFile('test1.zip', 'r') as myzip:
    myzip.extractall(pwd='<password>')

3. In the case of .rar

pip install rarfile (installed only in python 3)

from rarfile import RarFile
with RarFile('test2.rar', 'r') as myrar:
    myrar.extractall(pwd='<password>')

4. you mention that the password comes in the .rar like a name of file
   • pass-1337643656.data
   • you can list the names of the files using

RarFile.namelist() Return a list of archive members by name.

So you can extract the password using split

s = 'pass-1337643656.data'
s.split('-')[1].split('.')[0]
print(s)

'1337643656'

you can use also a regular expression to extract that

Conclusion.

A complete solution using .rar could be

from rarfile import RarFile
with RarFile('test2.rar', 'r') as myrar:
    file_names = myrar.namelist()
    pass_file = list(filter(lambda k: 'pass' in k, l))[0]
    pass = pass_file.split('-')[1].split('.')[0]
    myrar.extractall(pwd=pass)

Reference.

• https://python-unrar.readthedocs.io/en/v0.3/rarfile.html
• https://www.w3schools.com/python/ref_string_split.asp
• Filtering a list of strings based on contents
• https://docs.python.org/2/library/zipfile.html
• Unzipping files in Python