How to disable "just my code" setting in VSCode debugger?

Question

When starting my project in the debugger (C# .NET Core), it states it's debugging "just my code".

I want to also debug the libraries, and can't see a setting to disable this anywhere in VSCode.

Is it possible to disable?

Answer 1

Just adding "justMyCode": false to launch.json doesn't work. You need to add a separate config in launch.json like below. FYI each {} represents a config.

"configurations": [
        {
           .... # existing config
        },
        {
            "name": "Debug Unit Test",
            "type": "python",
            "request": "test",
            "justMyCode": false,
        }
    ]

As pointed out in here

Answer 2

For this you need to change the launch.json file. Inside the launch.json file you have to set "justMyCode" to false.

As described here. (I was pointed to that link through this post on the Visual Studio Code site.)

Answer 3

VSCode 1.60 was complaining about the "request": "test" method suggested by others.

But I did have to add a new section below my existing configuration to get "justMyCode": false to work.

Here is what worked for me:

{
    // Use IntelliSense to learn about possible attributes.
    // Hover to view descriptions of existing attributes.
    // For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
    "version": "0.2.0",
    "configurations": [
        

        {
            "name": "Python: Current File",
            "type": "python",
            "request": "launch",
            "program": "${file}",
            "console": "integratedTerminal",
            "args": [
                "blah",
                "whatever"
            ]
        },
        {
            "name": "Python: Debug Unit Tests",
            "type": "python",
            "request": "launch",
            "purpose": ["debug-test"],
            "console": "integratedTerminal",
            "justMyCode": false,
        }
    ]
}

The purpose addition appears to be important.

I found the correct approach documented here: https://code.visualstudio.com/docs/python/testing#_debug-tests

Answer 4

I added the "justMyCode": false" setting to launch.json and it still didn't stop at breakpoints in external library code. What was even more confusing: It did work for once and then suddenly it didn't anymore.

Then I found out: If you are in the "Run and Debug (SHIFT+CMD+D)"-tab and select your configuration there and click the green triangle / "Start Debugging (F5)" it works! However, if I click "Debug Python File" in the upper right corner it does not stop in external library code!

Answer 5

If you're specifically debugging Python unit tests, adding "justMyCode": "false" to your normal config won't do, you'll need to add another in your launch.json with "request": "test":

        {
            "name": "Debug Unit Test",
            "type": "python",
            "request": "test",
            "justMyCode": false,
        },

Source: Github Microsoft/vscode-python Issue #7131

Answer 6

As of 2022, VS Code no longer seems to have an “Open launch.json” shortcut in its command palette, but it still prompts you to edit launch.json to set "justMyCode" to false. The solution that worked for me was:

• create a directory called .vscode in the root of the repository
• create a file called launch.json in the .vscode directory
• put this text in the file:

{
    "version": "0.2.0",
    "configurations": [
        {
            "name": "Debug Unit Test",
            "type": "python",
            "request": "test",
            "justMyCode": false,
        }
    ]
}

There will be an error message under the word "test" saying that "test" is not a valid value, and that "attach" would be valid. However, it doesn't work for me if I change "test" to "attach". If the "version" field isn't there, it doesn't work and VS Code raises an error saying launch.json is missing a field.

Answer 7

This works for me, it's plain and simple. Basically,

1. just set "justMyCode": false
2. Then debug by pressing the debugger button at the bottom panel, instead of the top right corner.

Here's the main source. https://github.com/microsoft/debugpy/issues/795#issuecomment-1310846015

Answer 8

If you are using vscode on mac, press shift+command+p, search for Open'launch.json' (if you don't have the file, create it in the .vscode directory in the project), open an editor you want, and add the following JSON object to the file :

{
            "name": "Python: Debug Unit Tests",
            "type": "python",
            "request": "launch",
            "purpose": ["debug-test"],
            "console": "integratedTerminal",
            "justMyCode": false,
}

Reopen your vscode and now you can put breakpoints on lines that are imported or you have not written.

Answer 9

In the documenentation of Visual Studio Code they have a section "Skipping uninteresting code".

VS Code Node.js debugging has a feature to avoid source code that you don't want to step through (AKA 'Just My Code').
This feature can be enabled with the skipFiles attribute in your launch configuration. skipFiles is an array of glob patterns for script paths to skip.

In your launch.json file you have to add (or any other file you want to skip):

  "skipFiles": [
    "${workspaceFolder}/node_modules/**/*.js",
    "${workspaceFolder}/lib/**/*.js"
  ]

Answer 10

None of the fiddling with launch.json worked for me. I had to tick the "Allow setting breakpoints in any files" box in the Settings:

Answer 11

Recently, even I faced this issue where the VS code was not taking the latest launch.json (one with 'justMycode: false'). So, I had to perform the following steps.

1. Instead of running a debugger from the Top right group menu of the editor, I ran it from below status bar as shown in the below picture

Click here to see the screenshot of the status bar

2. Once clicked on this option a pop-up appears asking which launch.json you want to run your debugging with, as shown below.

Click here to see the screenshot of the pop-up menu

You can click on launch.json here to edit the configuration file and now the debugger opens with the selected launch.json and 'justtMycode:false' setting will be applied.

Answer 12

I added in the configurations part as below:

"configurations": [
    {
        "name": "Python: Curent File",
        "type": "python",
        "request": "launch",
        "program": "${file}",
        "console": "integratedTerminal",
        "justMyCode": false,
    }
],

Answer 13

It took me a while to understand where the file needs to be and what exactly needs to be inside it. So here's what I've got for others to enjoy:

The launch.json file is not in the root of your project, it needs to be in .vscode/launch.json instead. And for new VSCode versions, once you open that file from that location, you can get warnings on issues in the file, and also automatically add sections to it.

For me, at the end the contents of the file is this:

{
    "configurations": [
        {
            "name": "Python: Current File",
            "type": "python",
            "request": "launch",
            "program": "${file}",
            "console": "integratedTerminal",
            "justMyCode": false
        },
    ]
}

This allows me to enter (F11) other libs when I run a custom code in debug mode for Python.

Answer 14

I merged the previous answers and the below setting works for me (vscode 1.75.0).

"launch": {
    "configurations": [
        {
            "name": "Debug Unit Test",
            "type": "python",
            "request": "launch",
            "purpose": "debug-test",
            "justMyCode": false,
            "program": "${file}",
        }
    ],
},

Answer 15

One can set

{
    ...
    "debugpy.debugJustMyCode": false
    "jupyter.debugJustMyCode": false // for jupyter cells
}

in settings.json in one or both of the User and Workspace settings files. It also works for jupyter cells.

This is the most reliable and consistent solution for me.

Answer 16

The following worked for me:

1. Set "justMyCode": false
2. Then press debug button dropdown and select "Debug using launch.json"