I'm attempting to clean up a file with arbitrary element names that looks like:
<root>
<nodeone>
<subnode>with stuff</subnode>
</nodeone>
<nodeone>
<subnode>with other stuff</subnode>
</nodeone>
<nodeone>
<subnode />
</nodeone>
</root>
into a file that looks like:
<root>
<nodeone>
<subnode>with stuff</subnode>
</nodeone>
<nodeone>
<subnode>with other stuff</subnode>
</nodeone>
</root>
You can see that all of "nodeone" that had the empty children disappeared. I've used a solution that removes the empty <subnode>
, but keeps the <nodeone>
. The desired result is that both of those elements are removed.
My current attempt at a solution (which does precisely nothing) is:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="node()|@*">
<xsl:call-template name="backwardsRecursion">
<xsl:with-param name="elementlist" select="/*/node/*[normalize-space()]"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="backwardsRecursion">
<xsl:param name="elementlist"/>
<xsl:if test="$elementlist">
<xsl:apply-templates select="$elementlist[last()]"/>
<xsl:call-template name="backwardsRecursion">
<xsl:with-param name="elementlist" select="$elementlist[position() < last()]"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
<xsl:template match="/*/node/*[normalize-space()]">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
XSLT is not something I use terribly often, so I'm a bit lost.