how to exclude folders by date with find?

Question

This is "myfolder":

tree -a 'myfolder'
myfolder
├── 20220902
│   ├── filefoo
│   └── filebar
├── 20221001
│   ├── filefoo
│   └── filebar
└── 20221015
    ├── filefoo
    ├── filebar
    └── filexyz
  etc...

my command:

find $folder/$(date +"%Y%m"*) -type f | xargs -I {} awk '/^total:/{sub(".*/", "", FILENAME); print FILENAME" "$NF}' {})

Problem: i need exclude weekends. How do I do it?

PD: I know that in bash/awk it is

%u The weekday as a decimal number (1–7). Monday is day one.

thanks

Update Solved!

I found the answer in stackoverflow HERE

Answer 1

To filter out the weekends, you could format the name of the folder to a date format %u, which signifies the day of the week (by number).

Check out this example:

FOLDER_DATE=$(date -d '20221014' +%u)   #your folder name would go here

if [[ "$FOLDER_DATE" -eq 6 || "$FOLDER_DATE" -eq 7 ]]
then 
  echo "Weekend"
else 
  echo "Not Weekend"
fi