New answers tagged acceleration
3
votes
Why is Kinetic energy not an explicit function of acceleration?
His main question was that acceleration is also a property of a moving body so why is Kinetic energy which keeps track of energy associated with motion doesn't include the acceleration explicitly?
...
4
votes
Why is Kinetic energy not an explicit function of acceleration?
This is just another "why is this thing not the definition I think it is?" question. The thing we define to be kinetic energy is a function of speed. If you want to get to the heart of the ...
4
votes
Why is Kinetic energy not an explicit function of acceleration?
Most high school students have seen the kinematic equations. Specifically
$$v^2 = v_0^2 + 2ad$$
This is the explicit equation that shows $\Delta v^2$ is directly proportional to acceleration.
If you ...
5
votes
Why is Kinetic energy not an explicit function of acceleration?
Kinetic energy is not a generic property of a moving body. It is a property defined in such a way as to satisfy some essential relations directly originating from Newtonian Mechanics.
In particular, ...
3
votes
Why is Kinetic energy not an explicit function of acceleration?
There is one assumption made in the way he framed the question:
His main question was that acceleration is also a property of a moving body so why is Kinetic energy which keeps track of energy ...
3
votes
Why is Kinetic energy not an explicit function of acceleration?
Kinetic energy is not an explicit function of acceleration. However, a change in kinetic energy depends on acceleration.
The change in kinetic energy for a system of particles, which is a function of ...
5
votes
Can you directly feel the effect of gravity, or only opposing forces?
You are almost completely right.
What we do not and cannot feel is a uniform gravitational force. By “uniform” here I mean in the sense of general relativity where the force of gravity is just a ...
0
votes
Variation of $g(t)$
I think you are struggling with the differences between implicit and explicit time dependence, which was well explained here.
It is true that, since $r=r(t)$ and generally $g=g(r)$, we think about $g$ ...
3
votes
Accepted
Need help in understanding Tangential Acceleration
Derivatives speak to the instantaneous behavior at a point. It is possible to have a 1st derivative that is non-zero and a 2nd derivative that is 0 at a point. They're simply measuring two different ...
0
votes
Why is F = ma and not mv?
So, in theory, if that object now hits u in the head, it’s the momentum that hurts, not the force. Physicists? Did I get that right?
No. What causes injuries is not a simple matter. However it is ...
2
votes
Why is F = ma and not mv?
no, you don't have it right. If a ball ($m$) has momentum $\vec p_i$ hits you in the head, that collision takes time $\Delta t$. If the ball bounces away with momentum $\vec p_f$, then the momentum ...
3
votes
Is it ever possible that the object is moving with a velocity such that its rate of change of speed is not constant but acceleration is constant?
In general if $v$ denotes the velocity, the rate of change of speed is
\begin{align*}\frac{\text{d}|v|}{\text{d}t} &= \frac{\text{d}}{\text{d}t} \sqrt{ \left< v, v \right> } \\&= \frac{1}...
6
votes
Is it ever possible that the object is moving with a velocity such that its rate of change of speed is not constant but acceleration is constant?
Yes, this happens all the time. Fire a gun, or throw a ball, or do just about anything that involves making something move. And ignore things like air resistance, curvature of the earth and so on.
...
9
votes
Is it ever possible that the object is moving with a velocity such that its rate of change of speed is not constant but acceleration is constant?
Prelude - a (hopefully) fun but counterintuitive geometrical fact
A nice fact which may be a bit counterintuitive, is that if you have a square with diagonal length $\ell$ and this length varies in ...
26
votes
Is it ever possible that the object is moving with a velocity such that its rate of change of speed is not constant but acceleration is constant?
Hint: In the projectile motion (without drag) the acceleration $\vec{a}=\frac{d\vec{v}}{dt}$ is constant. However $\frac{d|\vec{v}|}{dt}$ is not constant, since it is negative when the projectile is ...
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