Consider a screw gauge of 50 divisions on the circular scale. Till now I have used the following method to account for zero error in it.
If $x^{th}$ division on the circular scale coincides with the zero on the main scale , then zero error,$Z$ is given by: $$Z=\begin{cases} x, & \text{if $x$ < 25} \\[2ex] x - 50, & \text{if $x$ > 25} \end{cases}$$
What would be the zero error if $x= 25$, i.e., if 25 divisions coincide with the zero of the main scale? Will it be a positive error or a negative error?
Please note that I am relatively new to experimental Physics.