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7 votes
Accepted

Function that satisfies $f(x-f(x))=f(x)$

This solution is due to a colleague o'mine. Let $g_n(x):\equiv x - n f(x)$. As you have noticed, we have $f(g_n(x))\equiv f(x)$, $\forall n\in\mathbb N$. Lemma. The function $g_n:\mathbb R\to\mathbb ...
Alma Arjuna's user avatar
  • 5,643
4 votes

Why is a function not differentiable at the end-points of its domain?

Is there a source telling you that you can't say $x^2$ on $[0,8]$ is differentiable at the endpoints? The way you pose the question makes me suspect you are studying the Mean Value Theorem, which is ...
KCd's user avatar
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2 votes
Accepted

Continuity of point to set mapping

Let $N$ be a neigbhorhood of $\bar x$ such that $\text{cl}(\Omega(N))$ is compact, where $\Omega(N) := \bigcup_{x\in N} \Omega(x)$. Because the sequence $x_k \to \bar x$, it is eventually inside $N$, ...
Paul Sinclair's user avatar
2 votes

Help with proving that a function is increasing and continuous

What I write here might not be the simplest way to handle this, but I would think of it like this. First, if $\phi$ is monotone increasing, we can prove that $\phi(x^-) = \sup \{\phi(y) : y < x\}$ ...
George Coote's user avatar
  • 1,925
2 votes
Accepted

Help with proving that a function is increasing and continuous

Let $x\in [0,1)$ and let $\epsilon>0$. By the continuity of $f$, there exists $\delta>0$ such that $|f(x)-f(y)|<\epsilon$, whenever $y\in (x-\delta,x+\delta)$. We are going to show that $|\...
Medo's user avatar
  • 3,548
1 vote

Help with proving that a function is increasing and continuous

I'd use the definition. Let $\varepsilon >0$. You need to show that exists $\delta>0$ such that $\forall x\in(a-\delta,a+\delta), x\neq a$ we have $\varphi(x)\in(\varphi(a)-\varepsilon,\varphi(a)...
SwitchArio's user avatar
1 vote

Help with proving that a function is increasing and continuous

A way, f because it is continuous in [0,1] has a maximum in $x_0$ then $\varphi (x)=f(x_0), \ if \ x \ \in [x_0,1]$, then $ \varphi $ is continuous in $(x_0,1]$ for being constant.$\varphi$ is right ...
josmat's user avatar
  • 58
1 vote
Accepted

Why is a locally Hölder continuous and bounded function pointwise Hölder continuous?

Let $f$ be $\alpha-$Holder continuous on $D$. I will assume that $D$ is a domain. Let $x_{0}\in D$. There exists $\delta>0$ such that $B_{\delta}(x_{0})$, the ball centered at $x_{0}$ with radius $\...
Medo's user avatar
  • 3,548

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