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Prove $\sup_{P=(t_0,\dots,t_k)}\sum_{j=1}^k |f(t_j)-f(t_{j-1})|=\sup_{n\in\mathbb N}\sum_{j=1}^{k_n} |f(t_j^n)-f(t_{j-1}^n)|$

Let $f:[0,1]\rightarrow \mathbb R$ be right continuous $P_n=(0=t_0^n<t_1^n<\dots<t_{k_n}^n=1)$ a sequence of grids with $\max_{1\leq j\leq k_n} |t_j^n-t_{j-1}^n|\to 0 (n\to \infty)$. Show ...
Moritz's user avatar
  • 153
2 votes
1 answer
76 views

Finding the different zeros of a continuous function

I'm working on Spivak's Calculus and am doing Problem 4 of Chapter 8. Here's the problem: Suppose $f$ is continuous on $[a,b]$ and that $f(a) = f(b) = 0$. Suppose also that $f(x_0) > 0$ for some $...
Aryaan's user avatar
  • 353
1 vote
0 answers
50 views

Show that the supremum of a family of continuous functions is lower semicontinuous.

Let $(X, \mathcal{T})$ be a topological space. Consider a family $\{f_i \mid i \in I\}$ of continuous functions $f_i : X \rightarrow \overline{\mathbb{R}}.$ Define $M : X \rightarrow \overline{\mathbb{...
alyosha's user avatar
  • 93
0 votes
0 answers
19 views

IF $\Psi(x) = \inf_{0 \leq s \leq t} \Phi_s(x)$,can we have $\Psi^{-1}(x) = \sup_{0 \leq s \leq t} \Phi_s^{-1}(x)$?

{$\Phi_s(x)$}$0 \leq s \leq t$ is a set of continuous and increasing functions which are uniformly bounded by $[0,1]$.Defind $\Psi(x) = \inf_{0 \leq s \leq t} \Phi_s(x)$,can we have $\Psi^{-1}(x) = \...
saolk aqolvc's user avatar
0 votes
1 answer
51 views

obtain the supremum and infimum of the given set.

Consider the set $E=\{cos \frac{n\pi}{3}+\sin \frac{n\pi}{3}:n\in \mathbb{N}\}$. Then supremum of E and infimum of E is (a) 1 and -1 (b) $\frac{\sqrt{3}}{2}+\frac{1}{2}$ and $\frac{1}{2}-\frac{\sqrt{...
math student's user avatar
  • 1,297
1 vote
0 answers
106 views

What is $\sup\limits_{f \in \mathscr F} \int_{1}^{3} \frac {f(x)} {x}\ dx\ $?

Let $\mathscr F$ be the set of all continuous functions $f : [1,3] \longrightarrow [-1,1]$ such that $\int_{1}^{3} f(x)\ dx = 0.$ Find the value of $$\sup\limits_{f \in \mathscr F} \int_{1}^{3} \frac {...
Akiro Kurosawa's user avatar
1 vote
1 answer
57 views

Find all the values that the expresion $\sum_{cyc} \frac{a}{a+b+d}$ takes.

Let $a,b,c,d \in \mathbb{R}^+$. Find all the values that the expresion $\frac{a}{a+b+d} + \frac{b}{a+b+c} + \frac{c}{b+c+d} + \frac{d}{a+c+d}$ takes. $$\\$$ I had this problem in a test. I found that $...
amkpm90's user avatar
  • 362
0 votes
2 answers
268 views

Is it possible to prove that $|\sup (f+g)| \le |\sup f| + |\sup g|$? [duplicate]

Let C the space of continuous functions $f: [0,1] \to \mathbb R$. How to prove that $|\sup (f+g)| \le |\sup f| + |\sup g|$? I thought that it was a simple consequence of the well-known fact that $\...
Átila Luna's user avatar
1 vote
1 answer
393 views

How can we define the supremum norm on the space of continuous functions if they're not necessarily bounded?

I frequently see the uniform norm described as a norm on the space of continuous functions $C(Y, X)$ where $Y$ is a topological space and $X$ is a metric space, especially in the context of the ...
ajax2112's user avatar
  • 257
1 vote
1 answer
61 views

Is my little proof of lub axiom using (lub axiom in any way)?

Below is my little proof of lub axiom DEFINITIONS : $A$ be any non empty subset of $\mathbb{R}$ bounded above $B$ be the set of all real upper bounds of $A$ $x \in B\ \Leftrightarrow \forall\ a \in A,...
lorilori's user avatar
  • 556
1 vote
1 answer
289 views

Suppose function $f(x)$ is continuous on $[a,b]$ then the function $\sup_{a\le{t}\le{x}}f(t)$ is also continuous.

In this problem, I need to prove $\sup_{{a}\le{t}\le{x}}f(t)$ is continuous, and I denote this function by $M(x)$. It is obvious that the function $M(x)$ is a non-decreasing function,so I can conclude ...
Donglai's user avatar
  • 11
10 votes
1 answer
417 views

Are inf and sup continuous functionals in general?

Let $X$ be any topological space and $\bar{\mathbb{R}} = [-\infty, \infty]$ with the standard topology. Is it true, in general, that the functionals $$\inf: C(X,\bar{\mathbb{R}}) \to \bar{\mathbb{R}}, ...
psl2Z's user avatar
  • 4,559
5 votes
1 answer
107 views

maximum Fourier coefficient among all bounded real continuous periodic functions

Let $\mathcal C$ be the space of real continuous $2\pi$-periodic functions bounded in absolute value by 1. Can we compute $$c_s := \sup_{f\in\mathcal C} \left|\int_0^{2\pi} e^{-isx}f(x)dx\right|$$ for ...
Exodd's user avatar
  • 11.8k
0 votes
0 answers
157 views

Running supremum of a right-continuous function: prove that $\left\{x\geq 0\left|\sup_{0\leq y\leq x}f(y)\geq K\right.\right\}$ is closed.

Let $f:[0,\infty)\rightarrow\mathbb{R}$ be a right-continuous function. Consider the set $$ E=\left\{x\geq 0\left|\sup_{0\leq y\leq x}f(y)\geq K\right.\right\}, $$ where $K$ is a constant. It is ...
AlmostSureUser's user avatar
2 votes
0 answers
36 views

Maximal inequality for time-continuous martingales: counter-example

The following can be regarded as the generalization of the maximal inequality for time-continuous martingales: Let$ (X_t)_{t \ge 0}$ be a supermartingale with right-continuous sample paths. Then, for ...
kibus's user avatar
  • 124
0 votes
0 answers
44 views

Proving that for $f\in C^2(a,\infty)$ then $\max_{(a,\infty)} |f'(x) |\le 4\max_{(a,\infty)}|f(x)|\max_{(a,\infty)} |f''(x) |$. [duplicate]

Let $f\in C^2(a,\infty)$ and $M_k=\max_{(a,\infty)} |f^{(k)}(x) |$, $k=0,1,2$, prove that $$M_1^2\le 4M_0M_2.$$ Firstly, I know that if $f, g\in C^2(a,\infty)$ so is $fg\in C^2(a,\infty)$. Any hint on ...
unknown's user avatar
  • 401
2 votes
1 answer
133 views

I want to prove $f$ in continuous on $[a,b]$ implies $F(x)=\sup f([a,x])$ is continuous on $[a,b]$?

Goal: I want to prove $f$ in continuous on $[a,b]$ implies $F(x)=\sup f([a,x])$ is continuous on $[a,b]$. Proof: Suppose $f$ in continuous on $[a,b]$. Let $c \in (a,b)$. Let $\epsilon>0$. By the ...
user avatar
1 vote
0 answers
83 views

The measurability of $c$-transform

In my proof of below result, I'm surprised that $f$ has no effect on the measurability of $f^c$. Could you have a check on my attempt? Is there stronger assumption that makes $f^c$ continuous? Let $...
Analyst's user avatar
  • 5,991
0 votes
1 answer
53 views

Prove that $\bar{B}_1(0)=\{f \in \mathcal{C}^{1}([0,1]) | \: \lVert f \rVert_{1,\infty} \leq 1\}$ is relatively compact but not compact [closed]

Define on $\mathcal{C}^{1}([0,1])$ the norm $\lVert f \rVert_{1,\infty} := \lVert f\rVert_{\infty} + \lVert f' \rVert_{\infty}$. Prove that the closed unit ball $\bar{B}_1(0) \subset \mathcal{C}^{1}([...
Paul Joh's user avatar
  • 569
3 votes
1 answer
47 views

The supremum function for ideals is continuous

Let $P$ be a dcpo, $Idl(P)$ be the set of ideals ordered by inclusion, and $f : Idl(P) \to P$ be the function defined by $f(I) = \bigvee I$. Question: How to show that $f$ is Scott-continuous? My ...
Bob's user avatar
  • 1,578
1 vote
1 answer
102 views

A multiple choice question on a function

Let $f(x) = x^2+ {1\over x^2}$ for $x \in (0,\infty)$, then which of the following is/are correct: (a) $f$ is continuous on $(0,\infty)$. (b) $f$ is uniformly continuous on $(0,\infty)$. (c) $f$ ...
Aastha Choudhary's user avatar
0 votes
0 answers
30 views

Hatcher K-Theory continuity of $\alpha \to \inf_{(x,z)\in X \times S^1} \det|\alpha(x,z)|$

Does Hatcher makes an error at page $45$ afirming that $f:\alpha \mapsto \inf_{(x,z)\in X \times S^1} \det|\alpha(x,z)|$ is continuous? I didn't find any reference of continuity of $\inf$ of ...
jacopoburelli's user avatar
-1 votes
1 answer
49 views

Show $\inf\{t\ge0:x(t-)\in B\text{ or }x(t)\in B\}\le T$ iff $x(T)\in B=\bigcap_nB_n$ or $\forall n:\exists s\in[0,T):x(s)\in B_n$

Let $(E,d)$ be a metric space, $x:[0,\infty)\to E$ be càdlàg (right-continuous with left-limits), $x(0-):=x(0)$, $x(t-):=\lim_{s\to t-}x(s)$ for $t>0$, $B\subseteq E$ be nonempty and $$\tau:=\inf\...
0xbadf00d's user avatar
  • 13.9k
0 votes
1 answer
54 views

Why is d' a metric in this case?

If $X$ is a compact space and $Y$ a metric topological space with metric $d$, then $d'(\alpha,\beta) = sup_{x \in X} d(\alpha (x),\beta (x))$ is a metric on $TOP(X,Y)$ $TOP(X,Y)$ denotes the set of ...
123123's user avatar
  • 306
0 votes
0 answers
75 views

Understanding the proof of an extension theorem

I'm studying the proof of the following theorem, but there are two things that I have not been able to understand about the continuity of the function $g$ on the boundary of $A$. (1) Why $\inf_{y \...
Curious's user avatar
  • 551
1 vote
0 answers
33 views

Calculus on the half positive space

Let $n \geq 2$ be an integer, and $J: \mathbf{R}^{n} \longrightarrow \mathbf{R}$ a continuous, coercive and strictly convex fonction. For any real $\delta \geq 0$, we denote by $U_{\delta}=\mathbf{R}^{...
LOVEMATH's user avatar
  • 183
3 votes
1 answer
149 views

Proving that $\sup_{s \in [a,b)}f(s)=\sup_{s \in [a,b)\cap \mathbb{Q}}f(s)$ for right continuous function.

Proposition. Let $[a,b) \subset \mathbb{R},\,a<b$. If $f:[a,b)\to \mathbb{R}$ is right-continuous over $[a,b)$, we have that $$\sup_{s \in [a,b)}f(s)=\sup_{s \in [a,b)\cap \mathbb{Q}}f(s)$$ This ...
Snoop's user avatar
  • 17.1k
0 votes
1 answer
33 views

Continuity in different metrics:

Let $X = C([0,1];\mathbb{R} )$ be space of continuous real valued fns defined on [0,1] equipped with sup metric $d$ given by : $$d(f,g) = sup_{x \in [0,1]} |f(x) - g(x) |$$ Consider map $I: X \...
Amy's user avatar
  • 115
0 votes
2 answers
191 views

If $u$ is rational, can we show $\inf\{t:x(t)\in B\}\le u$ iff $x(s)\in B$ for some rational $s\le u$?

Let $(E,d)$ be a metric space, $B\subseteq E$ be closed and nomepty, $x:[0,\infty)\to E$, $I:=\{t\ge0:x(t)\in B\}$ and $\tau:=\inf I$. If $I$ is nonempty and $\tau\in I$, then we easily see$^1$ that $$...
0xbadf00d's user avatar
  • 13.9k
1 vote
2 answers
101 views

$a^*$ and $a^{**}$ in wikipedia's proof of IVT

I am following the proof of the IVT on Wikipedia, and have one point of confusion. In the proof they say By the properties of the supremum, there exists some $a^* \in (c-\delta, c]$ that is contained ...
CBBAM's user avatar
  • 6,641
0 votes
0 answers
208 views

Fundamental theorem of calculus for monotone function

Assume $F:(0,1] \to \mathbb{R}$ is given by $F(x) = \int_0^xf(u) du$ where $f:(0,1) \to \mathbb{R}$ is a nonincreasing (not necessarily continuous) function (note that F is real-valued so it is ...
Namch96's user avatar
  • 928
1 vote
0 answers
15 views

Show that $\limsup_{t\to T_0-}\left\|u(t,\;\cdot\;)\right\|_\infty<\infty$ is not possible here

Let $T\in(0,\infty]$ and $\Omega\subseteq\mathbb R^d$ be bounded and open. For $k\in\mathbb N$, let $I_k:=(0,\min(k,T))$, $u_k\in C(\overline{I_k}\times\overline\Omega)$ and $$T_k:=\min\left(\inf\left\...
0xbadf00d's user avatar
  • 13.9k
0 votes
2 answers
182 views

Prove that $\sup_A f = \sup f|_{\mathbb Q\cap A} = \sup f |_{(\mathbb{R} \setminus \mathbb{Q})\cap A}$ [closed]

I was trying to prove something else and this came up. It must be really simple to prove but I am struggling to do it. Let $A$ be a non-empty and compact interval of $\mathbb{R}$ and $f \colon A \to \...
Beatriz de Faria's user avatar
0 votes
1 answer
53 views

If $f$ is continuous, $\sup_{|\lambda|<\omega} |f(\lambda)|=\infty$ then $\lim_{|\lambda| \rightarrow \omega} |f(\lambda)|=\infty$

Suppose that $f:(-\omega,\omega) \rightarrow \mathbb{R}$ is a continuous function, $\omega>0$ and $$\sup_{|\lambda|<\omega} |f(\lambda)|=\infty.$$ Can we conclude that $$\lim_{|\lambda| \...
Math's user avatar
  • 2,413
0 votes
2 answers
65 views

If $M$ is compact, then follows from $\forall x \in M | f(x) < a$ that $\sup_{x\in M} f(x)<a$

Let $(X,d)$ be a metric space, $M\subseteq X$ and $f: M \to \mathbb{R}$ continuous. Show that: If $M$ is compact, then follows from $\forall x \in M | f(x) < a$ that $\sup_{x\in M} f(x)<a$. My ...
Junjiro's user avatar
  • 197
0 votes
1 answer
427 views

Maximum vs supremum of a discontinuous function over a closed bounded set

The statement "Any continuous function must have a maximum on a closed bounded set" is made in these notes. We are looking at a function $f: S\rightarrow \mathbb{R}$. I can see why ...
user1936752's user avatar
  • 1,758
0 votes
1 answer
400 views

Continuity of a supremum function over compact sets

I'm unsure how to formally prove or disprove the following claim. It came up in trying to prove convergence of a gradient descent-style algorithm. I've tried using different definitions of continuity ...
smalldog's user avatar
  • 1,824
0 votes
1 answer
69 views

Picard-Lindelöf to show whether $u'=u^2-u^3$ has unique solution on an interval

This problem is taken from here. Consider the initial value problem: $$ u'=f(u,t)=u^2-u^3$$ $$ u(0)= 2/a>0 $$ $a$ is a small constant. How can I determine wheter a unique solution tom $t=0$ to $t=...
econmajorr's user avatar
0 votes
1 answer
126 views

Supremum and Continuity for function

Let $f$ be continuous on $[a, b]$. Define a function $g$ as follows: $g(a)=f(a)$ and, for $x$ in $(a, b]$ $$g(x)=\sup \{f(y): y \text { in }[a, x]\}$$ Prove that $g$ is monotone increasing and ...
Snowball's user avatar
  • 1,023
-1 votes
1 answer
29 views

If $\tau:=\{t\ge t_0:f(t)\in B\}$, can we show that $f(\min(t,\tau))\not\in B$ for all $t$?

Let $t_0\in\mathbb R$, $f:[t_0,\infty)\to\mathbb R$ be continuous, $B\subseteq\mathbb R$, $I:=\{t\ge t_0:f(t)\in B\}$, $\tau:=\inf I$ and $$g(t):=f(\min(t,\tau))\;\;\;\text{for }t\ge t_0.$$ If$^1$ $f(...
0xbadf00d's user avatar
  • 13.9k
0 votes
2 answers
85 views

continuity, supremum/infimum

I came across this but I'm still struggling to understand the concept fully. Specifically, how do we know $\text{lub}\{f(x)\mid a-\epsilon<x<a+\epsilon\}-\text{glb}\{f(x)\mid a-\epsilon<x<...
cosmicflair's user avatar
1 vote
1 answer
82 views

Continuity of Functions defined from a supremum

Let $\overline{\Omega}\subset\mathbb{R}^{N}$ be a compact set and $T<\infty$. Assume $f : \overline{\Omega}\times(0,T)\to\mathbb{R}$ is continuous and sastifies (A) $\forall x\in\overline{\Omega}, \...
Evan William Chandra's user avatar
1 vote
1 answer
43 views

Continous functions and supremum

this might be a very trivial questions that can be answered by pointing to a theorem or lemma, but I have trouble remembering something clearly. Give a continuous function $f(x)$ with $x\in \mathbb{R}^...
KingDingeling's user avatar
1 vote
1 answer
52 views

Finding infimum and proving continuity of a function

Let $f : [a,b] \to\mathbb R$ and for every $x \in [a,b]$ there exists $y \in [a,b]$ such that $|f(y)| < \frac12|f(x)|$. Find $\inf\{|f (x)| : x \in [a, b]\}$, and show that $f$ is not continuous on ...
Tushita Pandey's user avatar
0 votes
1 answer
169 views

Is $\sup\{ \max\{f(x)\}\} = \sup\{f(x)\}$?

In some problem from my differential equations course, I stated that, given $f(x)$ a continuous function defined in a compact set $K$, $$\sup_{x\in K} \{ \max_{x\in K}\{f(x)\}\} = \sup_{x\in K}\{f(x)\}...
Alejandro Bergasa Alonso's user avatar
3 votes
2 answers
299 views

Spivak Rising Sun Lemma

Suppose that all points of $(a,b)$ are shadow points, that is $\forall x \in (a,b) \space \exists y\space(y>x \mbox{ and } f(y)>f(x))$. For all $x\in(a,b)$, prove that $f(x)\leq f(b)$. let $A=\{...
super.t's user avatar
  • 726
0 votes
1 answer
129 views

On Suprema and limits

Let be $f:I\to\mathbb{R}$ a continuous function, $[x,x_0]\subseteq I$ and $M:=\sup\{f(y)\mid y\in[x,x_0]\}$. Show that the supremum attains the value of $f(x_0)$ when $x\to x_0$. My original idea was ...
Philipp's user avatar
  • 4,799
0 votes
0 answers
81 views

Prove the following for the monotonic function $f$ on $[0,1]$ satisfying $f \left (\frac {1} {4} \right ) f \left (\frac {3} {4} \right ) \lt 0.$

If $f : [0,1] \longrightarrow \Bbb R$ be a monotonic function with $f \left (\frac {1} {4} \right ) f \left (\frac {3} {4} \right ) \lt 0.$ Let $\sup \{x \in [0,1]\ \big |\ f(x) \lt 0 \} = \alpha.$ ...
Anil Bagchi.'s user avatar
  • 2,932
1 vote
2 answers
63 views

Show that the following is uniformly convergent

Show that if the function $f: R \to R$ is uniformly continuous, then the sequence $f_{n}(x) = f(x + \frac{1}{n})$ converges uniformly. I know that f(x + 1/n) approaches f(x) as $n \to \infty$. I feel ...
Nolan P's user avatar
  • 1,136
-1 votes
2 answers
26 views

Could I define the supremum of a function, given that that function is not continuous?

Starting from a function $f(x)$ which is not continuous on $\mathbb{R}$, it that possible to "define" objects like $\sup\limits_x f(x)$, $x\in\mathbb{R}$?
Strictly_increasing's user avatar