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Understanding the Behavior of `isLicci(I)` in Macaulay2 for Squarefree Monomial Ideals

I am studying Licci squarefree monomial ideals, where the definition is typically given in the polynomial ring localized at the maximal ideal (Licci ideals can be defined more generally in a regular ...
Hola's user avatar
  • 359
2 votes
1 answer
103 views

Is this statement of the Nakayama Lemma incorrect?

In my lecture notes, I found the following proposition. I believe that it is incorrect. Proposition (Nakayama for Local Rings). Let $(R, \mathfrak{m})$ be a commutative local ring with residue field $...
Smiley1000's user avatar
  • 3,275
2 votes
1 answer
97 views

Is $\mathbb C[[x, y]]/(x^3+y^4)$ an integral domain?

The polynomial $x^3+y^4$ is irreducible in $\mathbb C[x, y]$, thus $\mathbb C[x, y]/(x^3+y^4)$ is an integral domain. My question is: Is $\mathbb C[[x, y]]/(x^3+y^4)$ also an integral domain? Further ...
uno's user avatar
  • 1,682
0 votes
1 answer
45 views

Two-dimensional affine quotient singularity modulo a linear element

Let $k$ be a field of characteristic $0$. Let $G$ be a finite subgroup of $GL(2, k)$ such that $\sigma- I_2$ does not have rank $1$ for every $\sigma\in G$. Consider the invariant subring $R := k[[x, ...
uno's user avatar
  • 1,682
3 votes
1 answer
126 views

Socle of the maximal ideal and its square for a local ring with nonzero square of maximal ideal

Let $(R, \mathfrak m, k)$ be a Noetherian local ring such that $\mathfrak m^2\neq 0$. If $\text{Hom}_R(k, \mathfrak m^2)=0$, then is it true that $\text{Hom}_R(k, \mathfrak m)=0$? My thoughts: Since $...
uno's user avatar
  • 1,682
0 votes
1 answer
32 views

Module finite extension of one-dimensional local domain which is PID

Let $R$ be a Noetherian local domain of dimension $1$. Let $R \subseteq B$ be a module finite ring extension such that $B\subseteq Q(R)$. Then clearly, $B \subseteq \overline R$, where $\overline R$ ...
uno's user avatar
  • 1,682
1 vote
1 answer
102 views

Embedding of modules and annihilation by maximal ideal

Let $(R,\mathfrak m, k)$ be a Noetherian local domain of dimension $1$. Let $x\in \mathfrak m$ be such that $\mathfrak m^{n+1}=x\mathfrak m^n$. Let $Y$ be a finitely generated torsion-free $R$-module ...
Snake Eyes's user avatar
2 votes
0 answers
42 views

Localization of profinite integers

Let $p$ be a prime number, $\mathbb{Z}_{(p)}$ the localization of $\mathbb{Z}$ at $p$ and $\widehat{\mathbb{Z}} = \prod_{q\text{ prime}} \mathbb{Z}_q$ the profinite completion of the integers. Is the ...
Henrique Augusto Souza's user avatar
1 vote
0 answers
46 views

Are two-periodic two-generated ideals of Gorenstein local domains self-dual?

Let $I$ be a non-principal ideal of a Gorenstein local domain $R$ such that there is an exact sequence $0\to I \to R^{\oplus 2}\to R^{\oplus 2}\to I\to 0$. Then, must it be true that $I\cong \text{Hom}...
uno's user avatar
  • 1,682
0 votes
1 answer
52 views

Indecomposability of an object, in the bounded derived category of finitely generated modules, whose derived self-Hom is isomorphic to the ring

Let $R$ be a commutative Noetherian local ring. Let $M\in \mathcal D^b(\text{mod } R)$ be such that $\mathbf R \text {Hom}_R(M, M)\cong R$. Then, is $M$ indecomposable in $\mathcal D^b(\text{mod } R)$...
user's user avatar
  • 4,476
4 votes
1 answer
147 views

Finite map of local rings satisfying certain properties is surjective

$\newcommand{\iM}{\mathfrak{m}}\newcommand{\iN}{\mathfrak{n}}$I'm working on the following exercise and am quite stuck. Let $(A,\iM)$ and $(B,\iN)$ be local rings, and let $f:A\to B$ be a map of local ...
Kenanski Bowspleefi's user avatar
0 votes
1 answer
41 views

Length of quotient ring by power of maximal ideal

Let $(R, \mathfrak{m})$ be a local ring such that $\mathfrak{m}$ is generated by $k$ elements. Then for every $n$, what is the length of the module $R/\mathfrak{m}^n$? We know we have an exact ...
Serge the Toaster's user avatar
0 votes
1 answer
96 views

Is a localization of a local ring local?

I'm trying to answer the following question: " If $R$ is a local ring and $S$ a multiplicative set, is $S^{-1}R$ a local ring?" I found out in this other question that a localization is ...
Silvano_Micele's user avatar
2 votes
1 answer
84 views

Is there a 1-periodic module M over a local non-Cohen Macaulay ring?

As the title states, I am looking for an example of a module $M$ (non-zero and non-free) over a non-Cohen-Macaulay local Noetherian ring $(R,\mathfrak m, k)$ where $M$ is periodic of period one. There ...
Brian Laverty's user avatar
3 votes
0 answers
162 views

Completion of primary ideal is primary

I have the following question. Suppose $(R, \mathfrak{m})$ is a local Noetherian ring, $\mathfrak{a}$ is $\mathfrak{p}$-primary ideal. Is it true that $\hat{\mathfrak{a}}$ is a primary ideal in $\hat{...
abcd1234's user avatar
  • 105
0 votes
0 answers
47 views

Dimension of graded rings

Let $A=\oplus_{i \in N \cup \{0\}} A_i$ be a positively graded ring of dimension $d$ with $A_0=k$ and $k$ is a field. If $B$ is a Noetherian graded subring of $A$. Can we say dimension of $B$ cannot ...
Dgarg12's user avatar
  • 101
0 votes
1 answer
32 views

Minimal generator systems of a finitely generated

Let $A$ a local commutative ring with unity and $M$ an $A$-module. If $M$ is finitely generated, its minimal generator systems have the same cardinal. I am trying to prove this claim in order to use ...
Daniel García's user avatar
1 vote
1 answer
72 views

Cohen--Macaulay rings $R$ of dimension more than $1$ such that $R/\mathfrak p$ is also Cohen--Macaulay for every minimal prime ideal $\mathfrak p$

Let $R$ be a Cohen--Macaulay local ring. If $\dim R=1$, then $R/\mathfrak p$ is also a Cohen--Macaulay ring for every minimal prime ideal $\mathfrak p$ of $R$. It is known that for $\dim R\ge 2$, this ...
Alex's user avatar
  • 435
1 vote
0 answers
56 views

Is there a "minimal free resolution" for non-finitely generated modules?

Let $(R,\mathfrak m)$ be a commutative local ring and $M$ be an $R$-module such that $\mathfrak m^n M=0$ for some $n>0$. Then, does there exist a projective (necessarily free by Kaplansky's theorem)...
strat's user avatar
  • 341
0 votes
0 answers
62 views

Using Nakayama's lemma in non-local ring

Let $R$ be a Noetherian integral domain of dimension one and $\mathfrak{m}$ an ideal such that $\text{dim }\mathfrak{m}/\mathfrak{m}^2=1$ as an $R/\mathfrak{m}$-vector space. The localization of $R$ ...
Navid's user avatar
  • 323
1 vote
1 answer
36 views

Uniformizers in one-dimensional local rings

Suppose that $R$ is a Noetherian ring with unique maximal ideal $\mathfrak{m}$. Further suppose that $\mathfrak{m}/\mathfrak{m}^2$ is a one-dimensional $R/\mathfrak{m}$-vector space. By an application ...
Navid's user avatar
  • 323
2 votes
1 answer
95 views

When is the initial form of a principal ideal generated by the initial form of the original ideal's generator?

$ \DeclareMathOperator{\init}{in} \DeclareMathOperator{\gr}{gr} \newcommand{\calO}{\mathcal{O}} $Let $(R,\mathfrak{m})$ be a Noetherian local ring and $\gr_{\mathfrak{m}}(R)=\bigoplus_{i=0}^\infty\...
mbert's user avatar
  • 265
0 votes
1 answer
55 views

Possible inequality of krull dimension of local injection of Noetherian local domains

If $(A, \mathfrak{m}) \hookrightarrow (B, \mathfrak{n})$ is a local injection of Noetherian local domains, do we necessarily have $\dim B \geq \dim A$?
AprilGrimoire's user avatar
1 vote
1 answer
214 views

Finiteness of the intersection multiplicity of plane algebraic curves

Hello guys i am trying to solve excerise 2.7 page 14 from Gathmann notes https://agag-gathmann.math.rptu.de/class/curves-2023/curves-2023-c2.pdf Definition About (a) : Stuck here.Not sure how to ...
oti nane's user avatar
1 vote
1 answer
40 views

How to compute a minimal spanning set and the minimal spanning number of $\Bbb C[x,y]_{(x-1,y-1)}/(x^3-y^2)$?

Let $A=\frac{\mathbb C[X,Y]}{(X^3-Y^2)}$. I am asked to show that $\mathbf m=(\overline X-1,\overline Y-1)$ is a maximal ideal of $A$ which I have shown successfully. Now I am asked to compute the $\...
Kishalay Sarkar's user avatar
3 votes
0 answers
99 views

Is $(I(R:_{Q(R)} I))^n$ generated by $(fI)^n$ as $f$ varies over $(R:_{Q(R)} I)$?

Let $(R, \mathfrak m)$ be a Noetherian local domain of dimension $1$ which is not a UFD. Let $Q(R)$ be the fraction field of $R$. If $I\subsetneq \mathfrak m$ is a non-zero, non-principal ideal of $R$ ...
Alex's user avatar
  • 435
1 vote
0 answers
46 views

How to understand a situation where one can use Nakayama's lemma even when the situation is not Tailor-made.

In commutative algebra we have the following version of Nakayama's Lemma(also calle NAK lemma): NAK Lemma: Let $R$ be a local ring and $\mathbf m$ be the unique maximal ideal of $R$.Let $M$ be a ...
Kishalay Sarkar's user avatar
0 votes
1 answer
78 views

Algebraic properties of the ring of analytic functions on the complex plane

Let $r, R>0$ and $D_{R}=\{z\in\mathbb{C}: \|z\|<R\}$ and $D_{r,R}=\{z\in\mathbb{C}: r<\|z\|<R\}$. Consider the following $\mathcal{R}_{1}:=\mathcal{O}_{R}=\{f:D_{R}\to\mathbb{C}: f\hspace{...
user 987's user avatar
  • 675
1 vote
1 answer
56 views

Dominating rings: $\mathfrak{m}_A=A\cap \mathfrak{m}_B\Longleftrightarrow \mathfrak{m}_A\subset \mathfrak{m}_B$

Exercise $27$ from Atiyah and MacDonald states that if $A,B$ are two local rings, then $B$ is said to dominate $A$ iff $A$ is a subring of $B$ and the maximal ideal $\mathfrak{m}_A$ of $A$ is ...
kubo's user avatar
  • 2,096
-4 votes
1 answer
94 views

Quotients of local rings [closed]

I have the following commutative algebra question. It came up at the time of reading local rings of schemes and their tangent spaces. Let $R$ be a local ring with unique maximal ideal $m$. Then is it ...
KAK's user avatar
  • 275
0 votes
0 answers
81 views

Free module over local ring $R$. [duplicate]

People often say that a module $M$ over a not necessarily neotherian local ring $R$ being projective is flat, and also free. However, some refer to the finitely-generatedness of $M$, i.e. $M$ being ...
Pierre MATSUMI's user avatar
3 votes
1 answer
109 views

Finitely generated torsion-free indecomposable modules over one-dimensional complete local domains are isomorphic to ideal?

Let $R$ be a complete local domain of dimension $1$. Let $M$ be a finitely generated torsion-free indecomposable $R$-module. Then, must $M$ be isomorphic to an ideal of $R$? Also clearly, $R$ embeds ...
uno's user avatar
  • 1,682
1 vote
1 answer
86 views

Show that $A[T]/(P(T))$ is a local flat A-algebra where $(A,\mathfrak{m},k)$ is a local ring with $k[T]/(\tilde{P}(T))$ is a simple extension of $k$

Let $(A,\mathfrak{m},k)$ be a (Noetherian) local ring. Let $k[T]/(\tilde{P}(T))$ be a simple field extension of $k$ with $\tilde{P}(T)$ monic and irreducible (and separable). Lift $\tilde{P}(T)$ to ...
Z Wu's user avatar
  • 1,865
1 vote
0 answers
40 views

On the finiteness of certain Zariski closed subsets of the prime spectrum of commutative Noetherian local rings

Let $(R,\mathfrak m)$ be a Noetherian local ring. Let $S,T$ be Zariski closed subsets of $\text{Spec}(R)$ such that if $\mathfrak p\in S, \mathfrak q \in \text{Spec}(R)$ and $\mathfrak p \subsetneq \...
uno's user avatar
  • 1,682
5 votes
0 answers
86 views

On idempotents and local property of $\Lambda \otimes_R R_{\mathfrak p}$ where $\Lambda$ is module finite algebra over commutative local ring $R$

Let $R$ be a commutative Noetherian local ring. Let $\Lambda$ be a module finite associative $R$-algebra. Let $\mathfrak p$ be a prime ideal of $R$. I have the following two questions: (1) If $\...
uno's user avatar
  • 1,682
1 vote
0 answers
89 views

Proving two modules are free based on their direct sum [duplicate]

I have given two modules $M$ and $N$ over a local ring $R$. I also know that $M \oplus N \cong R^n$ for some $n\in \mathbb{N}$. I then have to prove that both $M$ and $N$ are free modules. Since $M \...
MarlonButBetter's user avatar
1 vote
1 answer
72 views

How to express elements of a DVR as power series of the uniformizer?

Let $R$ be a DVR with a fixed uniformizer $t$. My main considering example is the local ring of an algebraic curve over an algebraically closed field $k$, so let's assume $R$ is a $k$-algebra and has ...
S.Gau at Math's user avatar
0 votes
1 answer
71 views

Is a flat extension of DVRs always finite?

Is it true that if $S/\mathbb{Z}_p$ is a flat extension of discrete valuation rings then $S$ is finite over $\mathbb{Z}_p$?
Fraz's user avatar
  • 527
1 vote
0 answers
82 views

Module over a commutative local ring has nonzero homomorphism

The question is from a Persian text book: Let $R$ be a commutative local ring with $1$, and $\mathfrak m$ its maximal ideal. If $M$ is a non-zero module over $R$ prove that $\text{Hom}_R(M,R/\mathfrak ...
Amir Mg's user avatar
  • 136
3 votes
1 answer
92 views

Serre conditions and local isomorphisms

I encountered the following in the introduction of the paper "Duality for Koszul Homology over Gorenstein Rings": I assume it's easy, but why is this fact true? I played with modding out by ...
user2154420's user avatar
  • 1,460
-3 votes
1 answer
107 views

How can I show that if $x$ is a nonunit then $1-x$ is a unit? [duplicate]

Let $R$ be a commutative local ring. I want to show that then $x\in R$ is not a unit implies $1-x$ is a unit. My idea was the following: Since $R$ is a local ring we can chose $\mathfrak{m}$ to be ...
Summerday's user avatar
  • 297
1 vote
1 answer
70 views

On pushforward functor and freeness of modules

Let $R$ be a commutative Noetherian ring. Given an $R$-module $M$ and a ring homomorphism $\phi:R\to R$, let $\phi^* M$ be the $R$-module whose underlying abelian group is the same as $M$ but the $R$-...
Alex's user avatar
  • 435
0 votes
0 answers
111 views

Betti numbers of associated graded ring

Let $(R,\mathfrak{m})$ be a (not necessarily commutative) local ring with commutative residue field $k$. Define it's betti numbers as $$\beta_i(R):=\dim_k\mathrm{Tor}^i_R(k,k).$$ The associated graded ...
Ben's user avatar
  • 1,270
3 votes
0 answers
114 views

Is the ring of formal power series a localization of some non local ring at prime ideals?

Consider $F = K[[x]],$ the formal series over field $K.$ We know that $K$ is a local ring with maximal ideal $(x).$ Does there exist a non local ring $R$ and prime ideal $p$ such that $R_p = K[[x]]?$ ...
Melon_Musk's user avatar
1 vote
1 answer
55 views

Do we have $\bigcap_{1\leq i\leq r}(\mathfrak{m}^n+\mathfrak{p}_i)=\mathfrak{m}^n$ in a local ring, where $\mathfrak{p_i}$ are the minimal primes?

$\newcommand{\cO}{\mathcal{O}}\newcommand{\fm}{\mathfrak{m}}\newcommand{\fp}{\mathfrak{p}}$ Let $(\cO,\fm)$ be a Noetherian reduced local ring, essentially of finite type over an algebraically closed ...
imtrying46's user avatar
  • 2,839
1 vote
0 answers
89 views

Finiteness of the homology of the Koszul complex

Let $A$ be a local noetherian commutative ring, let $x_1, \dots, x_r$ be elements of the maximal ideal of $A$, $I$ the ideal that they generate, $M$ a $A$-module of finite type such that $M/IM$ is of ...
Plafonddeplatre's user avatar
1 vote
0 answers
73 views

A sort of "minimal presentation " for a local ring essentially of finite type over a field

Let $k$ be a field of characteristic $0$. Let $(R,\mathfrak m)$ be a local ring essentially of finite type over $k$ (https://stacks.math.columbia.edu/tag/07DR). Then, $R$ is the homomorphic image of ...
strat's user avatar
  • 341
1 vote
0 answers
78 views

$1$-dimensional reduced local ring $R$ such that $(R:_{Q(R)} \overline R)$ is non-zero and consists of zero-divisors

This question is motivated by If $(R:_{Q(R) } S)$ is non-zero, then does $(R:_{Q(R) } S)$ contain a non-zero-divisor? (and a now deleted comment on it). Namely: Does there exist a one-dimensional ...
Muni's user avatar
  • 65
0 votes
1 answer
78 views

Quotient of the polynomial ring over a local noetherian ring is finitely generated?

I am going through these lecture notes, and I am confused about the proof of Corollary 10.10 there. Corollary 10.10. Let $A$ be a local noetherian domain with maximal ideal $\mathfrak{p}$, let $g \in ...
Kyaw Shin Thant's user avatar
2 votes
1 answer
106 views

If $M\cong N \oplus k^{\oplus a}$, where $a=\dim_k \dfrac{soc(M)}{soc(M)\cap \mathfrak m M }$, then $k$ is not a direct summand of $N$?

Let $M$ be a finitely generated module over a commutative Noetherian local ring $(R,\mathfrak m, k)$ such that $M\cong N \oplus k^{\oplus a}$, where $a=\dim_k \dfrac{soc(M)}{soc(M)\cap \mathfrak m M }$...
feder's user avatar
  • 105

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