Skip to main content

All Questions

Filter by
Sorted by
Tagged with
1 vote
0 answers
25 views

Why a $\Gamma$ for the general semiaffine group in its notation?

This question is about notation. I often see the general semiaffine group of degree $n$ over a field $K$ written as $A\Gamma L(n,K)$, $\Gamma A(n,K)$, $A\Gamma L_n(K)$, or $\Gamma A_n(K)$... Why the ...
Robin's user avatar
  • 3,990
1 vote
0 answers
39 views

How to Construct a Larger Set of Generators for Sp(2n, q) to Optimize Diameter? [closed]

For the symplectic group Sp(2n, q) over a finite field of order q, I am interested in constructing a set of generators that produces a Cayley graph with a "good diameter." Specifically: By &...
aza's user avatar
  • 19
0 votes
0 answers
47 views

Is the Valentiner Group isomorphic to PGL(3, 4)?

In this answer to a question from a while back, it says that the Valentiner group is isomorphic to $PGL_3(\mathbb{F}_4)$. However, when I implement in sage: ...
FamisherCaterpillar's user avatar
1 vote
0 answers
31 views

The order of a linear profinite group over commutative profinite ring

Recall that one can define the order of a profinite group using the notion of supernatural number. Let $A$ be a commutative profinite ring and let $G$ be a topologically finitely generated closed ...
stupid boy's user avatar
1 vote
1 answer
63 views

No continuous isomorphism from $O_4$ to $O_{3,1}$

I am hoping to show that there is no continuous isomorphism from the orthogonal group $O_4$ to the Lorentz group $O_{3,1}$. My approach so far is to make use of the fact that a matrix $A$ is in $O_{3,...
Jake Khawaja's user avatar
3 votes
1 answer
123 views

The rank of Sylow subgroup of special linear groups over finite fields

Let $p,\ell$ be two primes, and let $\mathbb{F}_{q}$ be a finite field of order $q=p^r$. We define the rank of a finite group $G$ to the smallest cardinality of a generating set for $G$. We denote by $...
stupid boy's user avatar
1 vote
0 answers
43 views

Condition on finitely generated subgroup of $GL_2(\mathbb{Q})$ to be free

I am considering finitely generated subgroup $G=\langle A,B,C\rangle$ of $GL_2(\mathbb{Q})$ such that $A,B,C$ all have the upper triangular form $$A=\begin{pmatrix}a_1 & a_2 \\ 0 & a_3\end{...
Jfischer's user avatar
  • 1,355
2 votes
1 answer
71 views

A generalization of Baumslag-Solitar groups

I am wondering about the following generalization of the group $B_{1,2}=\langle a,b\, |\, bab^{-1}=a^2\rangle$: $$ G_k=\langle a_1,a_2,\ldots,a_{k+1}\, |\, a_{i+1}a_ia_{i+1}^{-1}=a_i^2, i=1,2,\ldots,k\...
QMath's user avatar
  • 427
1 vote
1 answer
84 views

The order of $H = \{X \in \mathrm{GL}_2(\mathbb{Z}_p) \mid \det(X) = 1\}$ with the definition

Let be a prime $p$ and $H = \{X \in \mathrm{GL}_2(\mathbb{Z}_p) \mid \det(X) = 1\}$. I know that the order of a element $g \in \mathrm{GL}_2(\mathbb{Z}_p)$ is the less $k$ such that $g^k = e$, but I ...
Wellington Silva's user avatar
1 vote
1 answer
135 views

Generators for ${\rm SL}_2(\mathbb{Z}/8\mathbb{Z})$ [closed]

Let ${\rm SL}_2(\mathbb{Z}/8\mathbb{Z})$ be the special linear group over the finite ring $\mathbb{Z}/8\mathbb{Z}$. By How to calculate |SL2(Z/NZ)| , we know that the order of the group ${\rm SL}_2(\...
stupid boy's user avatar
2 votes
1 answer
117 views

Prove that every finite subgroup of $SL_2(\mathbb{C})$ is conjugate to a finite subgroup of $SU_2$

I want to prove this proposition. For any finite subgroup $G$ of $SL_2(\mathbb{C})$, I showed that $G$ is unitary with respect to an inner product that we define properly. But I couldn't find the ...
xxyyzz's user avatar
  • 31
2 votes
0 answers
40 views

Showing that two orbit spaces are isomorphic

Consider the following two group actions: $O_n\times Sym_n(\mathbb{R})\rightarrow Sym_n(\mathbb{R})$ Given by $(A,B)\mapsto ABA^{-1}$, where $O_n$ denotes the group of orthogonal matrices and $Sym_n(\...
Asvr_esn's user avatar
  • 167
4 votes
0 answers
125 views

Proving certain triangle groups are infinite

[Cross-posted to MathOverflow] Consider the Von Dyck group $$ G = \langle x,y\mid x^a=y^b=(xy)^c=1\rangle $$ where $a,b,c\ge3$. Because $G$ is infinite and residually finite, it has an infinite family ...
Steve D's user avatar
  • 5,465
5 votes
1 answer
254 views

When is general linear group isomorphic to special linear group?

Can $\operatorname{GL}_n(\Bbb F_{q})$ be isomorphic to $\operatorname{SL}_m(\Bbb F_{r})$, where $\Bbb F_q$, $\Bbb F_r$ are finite fields with $q,r$ elements respectively? By considering the center, $$\...
user108580's user avatar
4 votes
1 answer
129 views

Prove that $\operatorname{GL}_n(k)$ and $\operatorname{SL}_n(k)$ cannot be symmetric group?

Problem. Prove that $\operatorname{GL}_n(k)$ and $\operatorname{SL}_n(k)$ cannot be isomorphic to $S_m$, $m\geq 4$ if $k$ is a finite field with at least two elements. I am trying to argue by looking ...
user108580's user avatar
3 votes
0 answers
86 views

Number of homomorphisms from $\Bbb Z_p$ to $\operatorname{GL}_2(\Bbb Z_q)$?

I am trying to count the total possible number of group homomorphisms from $\Bbb Z_p$ to $\operatorname{GL}_2(\Bbb Z_q)$, where $p<q$ are primes and $\Bbb Z_p$ denotes the additive group modulo $p$....
Elementary Only's user avatar
3 votes
1 answer
84 views

Semilinear subgroup $\Gamma L(1,2^n)$ of group $GL(n,2)$

Let $\phi$ be an automorphizm of $\mathbb{F}_{2^n}$ and $a \in \mathbb{F}_{2^n}$. Let's consider a set of functions $\Gamma L(1,2^n) = \{g_{a,\phi} | a\in\mathbb{F}_{2^n}, \phi \in Aut(\mathbb{F}_{2^n}...
Orel_Algebraist's user avatar
-1 votes
1 answer
55 views

why square matrix is group for multipy

There are 4 requirements in order to be group for $$(R^{n*n},*), n\in{N}$$ Closer $ \forall{A,B}\in{R^{n*n}}:A*B\in{R^{n*n}}$ Associativity $\forall{A,B,C}\in{R^{n*n}}:A*(B*C)=(A*B)*C$ Neutral ...
KIM CHANGJUN's user avatar
0 votes
0 answers
47 views

Hyperplanes in $SL_2(\mathbb{R})$ containing conjugacy classes of matrices

Let $SL_2(K)$ be the special linear group of rank 2 over a field $K$, as an affine group scheme cut out by the equation $ad - bc = 1$ in $\mathbb{A}^4_K$. Let $H$ be an arbitrary, homogeneous, ...
kindasorta's user avatar
  • 1,280
4 votes
1 answer
171 views

Are $S^1$ and $O_2(\mathbb{R})$ isomorphic?

Let $S^1 = \{z \in \mathbb{C} | |z| = 1\}$ and $O_2(\mathbb{R}) = \{A \in GL_2(\mathbb{R})|A^TA = I_2 \}$. Is the group $(S^1, \cdot)$ isomorphic to $(O_2(\mathbb{R}), \cdot)$? Prove it. This is a ...
Bernardo Maia's user avatar
4 votes
1 answer
336 views

Why can the Orthogonal group be split up in this way?

In my groups course at university, we’ve spent a while on the orthogonal group, leading up the the conclusion that $$ \mathrm{O}_n = \mathrm{SO}_n \mathbin{\dot{\cup}} \begin{pmatrix} -1 ...
Reuben Price's user avatar
-1 votes
1 answer
65 views

Generation a subgroup of $GL_2(\mathbb{C})$

Let $G$ be a group and let $S$ be a nonempty subset of a group $G$. The subgroup of $G$ generated by $S$, which is denoted by $\langle S\rangle$, is equal to the set of all elements of $G$ that can be ...
Marja's user avatar
  • 67
3 votes
1 answer
178 views

Does a given subset of an infinite group generate a finite or infinite subgroup?

Consider a fixed infinite group, such as $SL(n, \mathbb{R})$. Let $S$ be a given finite subset of the elements of $SL(n, \mathbb{R})$, further suppose that $S$ is closed under inverses. Is there any ...
chaiKaram's user avatar
1 vote
0 answers
403 views

Prove that the quaternion group of order 8 is isomorphic to a subgroup of $SL_2(\mathbb{F_3})$ generated by the following two elements.

The Problem: Prove that the subgroup of $SL_2(\mathbb{F_3})$ generated by $\begin{pmatrix}0&-1\\1&0\\\end{pmatrix}$ and $\begin{pmatrix}1&1\\1&-1\\\end{pmatrix}$ is isomorphic to the ...
Dick Grayson's user avatar
  • 1,487
2 votes
1 answer
208 views

The general linear group $GL(n, \mathbb{C})$ has no proper subgroup of finite index.

Problem: Show that the general linear group $G = GL(n, \mathbb{C})$ has no proper subgroup of finite index. I wrote down a proof, but not quite sure if it is right, especially about the part about ...
zyy's user avatar
  • 1,103
2 votes
1 answer
366 views

7.5.4 of Stillwell Naive Lie Theory

In section 7.5 of John Stillwell's 'Naive Lie Theory' he constructs a proof of what he calls the 'Tangent space visibility' theorem: that for any path-connected matrix Lie group $G$ with a discrete ...
PlatopusMcJagger's user avatar
4 votes
1 answer
268 views

If every finite quotient group of a finitely generated linear group G is solvable, then G is solvable

For this question, I was able to show that each finite quotient is polycyclic: Suppose $N$ is a normal subgroup of finite index. Then, all subgroups of $G/N$ are finite, so $G/N$ is Noetherian. A ...
Algebro1000's user avatar
1 vote
0 answers
168 views

If every finitely generated subgroup of a linear group G is solvable, then G is solvable

I've been working on this question for a long time now and I still have no idea how to approach it. I tried induction on the dimension of the matrices in G but can't complete the induction step. Any ...
Algebro1000's user avatar
0 votes
0 answers
61 views

Is it true that $F^*\wr S_n$ is a solvable group, when $n\leq 5$?

Let $U$ be a linear space over a division ring $D$, $G_1$ a subgroup of $GL(U)$, and $\Gamma$ a subgroup of a symmetric group $S_k$ on $\{1,\ldots,k\}, k>1$. The cartesian product $U^k=V_1$ can ...
Reza Fallah Moghaddam's user avatar
4 votes
2 answers
199 views

Finding the normalizer of $\left\{ \left(\begin{matrix} x &0 \\0 & y \end{matrix}\right) : x,y\in \mathbb R\setminus\{0\} \right\}$

I'm having some trouble with the following question: Let $G=\text{GL}_2(\mathbb R)$. What are the elements of the set: $$N_G \left( \underbrace{\left\{ \left(\begin{matrix} x &0 \\0 & y \end{...
Eduardo Magalhães's user avatar
3 votes
0 answers
208 views

What are the subgroups of the projective general linear group of degree 3 over a finite field?

I'm investigating something and the question of what the subgroups of $ \text{PGL}(3,\mathbb{F}_p)$ are has come up. I've found this Group Properties Wiki page, but it doesn't contain much useful ...
wwhoss's user avatar
  • 29
2 votes
1 answer
181 views

The Sylow $2$-subgroups of $SL(2,q)$ are not cyclic for $q \equiv 3$ mod $4$?

I'm reading through the free version of the book Finite Groups from Daniel Gorenstein and theorem 8.3 on page 42 caught my attention. I understand the proof so far, but the second page of the proof is ...
Gamer2015's user avatar
  • 121
2 votes
0 answers
104 views

Group action on one-dimensional subspaces

Assume $p=(q^n-1)/(q-1)$ with $p$ prime and let $V:=\mathbb F^n_q$ denote an $n$-dimensional vector space over $\mathbb F_q$. There is a natural action of $PSL(n,q)$ on the $(q^n-1)/(q-1)$ one-...
Paulius Virbalas's user avatar
2 votes
1 answer
588 views

Finding an element of order $p+1$ in $\text{SL}_2(\mathbb{F}_p)$ and Sylow subgroups of $\text{SL}_2(\mathbb{F}_p)$

Let $p$ be a prime number. I am trying to show that $\text{SL}_2(\mathbb{F_p})$ has an order $p+1$ element and use this to show that for every odd prime $q$, the $q$-Sylow subgroup of $\text{SL}_2(\...
Nick's user avatar
  • 645
2 votes
0 answers
401 views

Order of $PSL(n,q)$

Being $F$ the field of order $q$ that linear groups are defined here, there is something I can't understand. I know that $|SL(n,q)| = \dfrac{|GL(n,q)|}{(q-1)}$, and I know that $PSL(n,q) = SL(n,q)/Z(...
Gea5th's user avatar
  • 515
2 votes
1 answer
145 views

why do matrices in orthogonal group have determinant 1 in characteristic 2?

Let $q$ be quadratic form on $V=K^n$ where $K$ is a field in characteristic $2$. Let $b(x,y)=q(x+y)-q(x)-q(y)$ be the bilinear form associated to $q$ and set $V^\perp=\{x\in V\mid b(x,y)=0 \text{ for ...
JNS's user avatar
  • 21
-1 votes
1 answer
263 views

Show that $GL(2, \Bbb Q)$ is isomorphic to a subgroup of $GL(3, \Bbb Q)$ [closed]

What should be my approach for this particular question and general approach to prove isomorphism of one group to another ?
Amit Sankhla's user avatar
9 votes
2 answers
201 views

Does $G$ being a subgroup of $GL(n, \mathbb Z/p\mathbb Z)$ for all odd primes $p$ imply it is a subgroup of $GL(n, \mathbb{Z})$?

It is known that any finite subgroup of $GL(n, \mathbb{Z})$ is isomorphic to a subgroup of $GL(n, \mathbb Z/p\mathbb Z)$ for any odd prime $p$ (see here). I am wondering if there is a converse to to ...
Beren Gunsolus's user avatar
2 votes
0 answers
21 views

Reference for $SO_Q$ maximal in $SL_n$

I would like to find a reference for the following fact, which is sort of "well known": Let $Q$ be a positive definite non-degenerate quadratic form in $n$ variables over an algebraically ...
Andrew Musso's user avatar
4 votes
2 answers
613 views

Explicit isomorphism between ${\rm SL}(2,{\Bbb R})$ and ${\rm SU}(1,1)$

I have heard that there exists an isomorphism of real algebraic groups as in the title. I am asking for an explicit isomorphism. Motivation: I need such an isomorphism for a calculation of Galois ...
Mikhail Borovoi's user avatar
0 votes
0 answers
41 views

Generalizations of linear groups

There are quite many general results about finitely generated linear groups (e.g. the Malcev theorem that they are residually finite, the Tits alternative for them, etc.). Since at least in the real ...
user446046's user avatar
0 votes
1 answer
97 views

Show that a complex, compact, abelian linear group is finite (using Liouville's theorem)

I'm trying to solve the following problem from the second chapter of Rossmann's book on Lie groups: This seems like a very interesting result (and a cool application of Liouville's theorem), but I'm ...
GSofer's user avatar
  • 4,458
3 votes
2 answers
963 views

Why is $SL(n, \mathbb{R})$ the kernel of $\det : GL(n, \mathbb{R}) \mapsto\Bbb R^*$?

The special linear group of invertible matrices is defined as the kernel of the determinant of the map: $$\det:GL(n,\mathbb{R}) \mapsto \mathbb{R}^*$$ In my mind the kernel of a linear map is the set ...
mathripper's user avatar
1 vote
1 answer
231 views

Book about linear groups

Please advise a good book about linear groups, their actions (as, for example, PGl acts on projective space, etc.), as well as the relationship between themselves. (ideally if they were considered ...
Ilya's user avatar
  • 464
1 vote
2 answers
2k views

SU(1,1) isomorphic to SL(2,R), but SU(2) is not

I am surprised by the fact that $\mathrm{SU}(1, 1)$ group is isomorphic to $\mathrm{SL}(2, \mathbb{R})$, but $\mathrm{SU}(2)$ is not isomorphic to $\mathrm{SL}(2, \mathbb{R})$. The first statement is ...
Eddward's user avatar
  • 113
2 votes
2 answers
442 views

Confused by quotient group (whats the operation): Show quotient group $GL_n(K)/SL_n(K)$ is abelian.

In my introductory abstract algebra course, the quotient group $G/H$ was defined as $$G/H=\{gH:g\in G\}$$ which is a set of sets. In an exercise, I should show that for the group of invertible ...
Ruben Kruepper's user avatar
2 votes
1 answer
70 views

Group of $2\times2$ matrices that are isomorphic to $SU(2)$

Studying physics I encountered the $SU(2)$ group, in the context in which I use it $SU(2)$ is the group of the $2\times2$ unitary matrices with determinant equal to one. Out of curiosity, I searched ...
SimoBartz's user avatar
  • 333
2 votes
0 answers
506 views

Generators of $SL_2 (F_q)$

I am working on the following problem. Let $\mathbb{F}_q$ be a finite field with $q \neq 9$ elements and $a$ be a generator of the cyclic group $\mathbb{F}_q^{\times}$. Show that $\mathrm{SL}_2(\...
Sato's user avatar
  • 71
1 vote
1 answer
314 views

Small order examples of non-nilpotent finite groups in which every minimal normal subgroup intersects the center nontrivially

I know that $p$-groups have the property, and all nilpotent groups also do. I wanted to have some non-nilpotent examples. Then I checked quasisimple groups, and found every proper normal subgroups of ...
user avatar
-1 votes
1 answer
416 views

conjugacy classes of the special orthogonal group $SO(2)$ [closed]

I'm doing some research in Group Theory and have come across conjugacy classes. In general I can determine the conjugacy classes for most groups. However the conjugacy classes of the special ...
user avatar