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I'm reading the book Tensor Categories by Etingof, Gelaki, Nikshych, and Ostrik. In Section 2.6 they discuss the monoidal functors between two categories $\mathcal{C}_{G_1}^{\omega_1}(A)$ and $\mathcal{C}_{G_2}^{\omega_2}(A)$, where $G_i$ are finite groups, $A$ a fixed abelian group and $\omega_i \in Z^3(G_i,A)$.

The monoidal category $\mathcal{C}_G^\omega$ consists of the following datum:

  • Objects are given by the fixed finite group $G$, i.e. $\mathrm{ob}(\mathcal{C}_G^\omega) := G$.
  • Morphisms: $\mathrm{Hom}(g,h) = \emptyset $ if $g\neq h$ and $\mathrm{Hom}(g,g) = A$ for the fixed abelian group $A$. (In other words, as a category $\mathcal{C}_G^\omega = \mathrm{B}A^{\amalg G} $).
  • Tensor products on objects is given by multiplication of $G$ and on morphisms by multiplication in $A$.
  • Finally, $\omega \in Z^3(G,A)$ corresponds to the associators.

I think in addition to $f:G_1\rightarrow G_2$ (monoidal on objects) and $\mu:G_1 \times G_1\rightarrow A$ (monoidality isomorphism), a monoidal functor is also specified by an endomorphism $g:A\to A$ that determines how the functor maps morphisms. Also, $$\omega_1 = f^\ast \omega_2 \cdot d_3(\mu)$$ (see (2.31) in [EGNO]) should be changed into

$$g_{*}\omega_1=f^{*}\omega_2\cdot d_3(\mu)\,.$$

Therefore, a monoidal functor from $\mathcal{C}_{G_1}^{\omega_1}$ to $\mathcal{C}_{G_2}^{\omega_2}$ should correspond to a triple $(f,g,\mu)$, instead the mere pair $(f,\mu)$.

Who's correct? Me, the book, or neither?

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  • $\begingroup$ To make the question more accessible, I suggest to either add a link to the book (I think it was online, right?), or wrote down the definition of the categories, what (2.31) is saying and what brings you to your conclusion. $\endgroup$ Commented Nov 7, 2023 at 18:10

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Yes, you are correct in that a monoidal functor $F:\mathcal{C}_{G_1}^{\omega_1}\rightarrow \mathcal{C}_{G_2}^{\omega_2}$ is determined by a triple $(f,g,\mu)$.

In EGNO they consider functors that act trivially on the coefficient group $A$, i.e. $g = \mathrm{id}$ in your example. They explain that in their corrections here.

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