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Non-manipulable rules for land rental problems

2015, Research Papers in Economics

We consider land rental problems where there are several communities that can act as lessors and a single tenant who does not necessary need all the available land. A rule should determine which communities become lessors, how much land they rent and at which price. Our first result is a complete characterization of the family of rules that satisfy land monotonicity and non-manipulability under land reassignment. We also define two parametric subfamilies. The first one is characterized by adding a property of weighted standard for two-person. The second one is characterized by adding consistency and continuity.

Non-manipulable rules for land rental problems∗ Alfredo Valencia-Toledo† Juan Vidal-Puga‡ July 14, 2016 Abstract We consider land rental problems where there are several communities that can act as lessors and a single tenant who does not necessary need all the available land. A rule should determine which communities become lessors, how much land they rent and at which price. Our first result is a complete characterization of the family of rules that satisfy land monotonicity and non-manipulability under land reassignment. We also define two parametric subfamilies. The first one is characterized by adding a property of weighted standard for two-person. The second one is characterized by adding consistency and continuity. Keywords— land rental, non-manipulability, land reassignment, land monotonicity, consistency. ∗ Alfredo Valencia-Toledo thanks the Ministry of Education of Peru for its financial sup- port through the grant “Beca Presidente de la República del Programa Nacional de Becas y Crédito Educativo (PRONABEC)”. Juan Vidal-Puga acknowledges financial support from the Spanish Ministerio de Economı́a y Competitividad through grant ECO2014-52616-R. † Research Group in Economic Analysis (RGEA). Universidade de Vigo, Spain. E-mail: [email protected]. ‡ Departamento de Estadı́stica e IO. Universidade de Vigo, Spain. [email protected]. 1 E-mail: vi- 1 Introduction The management of land and natural resources is one of the most critical challenges facing developing countries (Kaye and Yahya, 2012; van der Ploeg and Rohner, 2012). In particular, natural resource exploitation is an industrial activity that has recently been generating conflicts between firms and indigenous communities in many countries in Latin America, Africa and Asia. Examples include Mexico (Tetreault, 2015), Peru (Arellano-Yanguas, 2011), Sierra Leone (Akiwumi, 2014), India (Sarkar, 2015) and Indonesia (Welker, 2009). Another examples appear in Sosa (2011) and Walter and Urkidi (2015). Another two examples, both in Colombia, arise from a restitution problem where two agents have rights over the land (Jaramillo et al., 2014) and from land aggregating for housing and infrastructure (Kominers and Weyl, 2012), respectively. In these land conflicts, there exist rights over the land for each side. For the case of mining activities, Article 10 of the United Nations Declaration on the Rights of Indigenous People defined Free Prior and Informed Consent (FPIC) as the principle that indigenous communities have the right to give or withhold its consent to proposed projects that may affect the land they customarily own, occupy or otherwise use (UN, 2007). On the other hand, the mining firm has an investment and a concession over those lands, or, even if a concession has not been granted yet, the firm may have a profit opportunity high enough to make it possible to compensate the land owners in a fair way (Helwege, 2015). In order to solve these land conflicts, it is fundamental for the planner (e.g. the government) to have all the relevant information about both sides. In many situations, land identification and demarcation may be not clear, as in the case of customary land (Gildenhuys, 2005; Azima et al., 2015). This situation can lead to manipulation by merging or splitting of the communities, due to the fact that they may have incentives to strategically misrepresent their identity in order to influence the final outcome to their own advantage. The study of this kind of manipulation is common in the strategy2 proofness literature in the context of cost sharing (Moulin and Shenker, 2001; Sprumont, 2005; Gómez-Rúa and Vidal-Puga, 2011; Ju, 2013; Massó et al., 2015), resource allocation (Erlanson and Flores-Szwagrzak, 2015), job scheduling (Moulin, 2007, 2008), indivisible object allocation (Sun and Yang, 2003; Svensson, 2009; Morimoto and Serizawa, 2015), assigning problems (Kojima and Manea, 2010), and taxation problems (Ju and Moreno-Ternero, 2011), among others. Splitting and merging proofness have also been deeply studied in bankruptcy problems where an estate E > 0 should be divided among a set of claimants N with claims given by c ∈ RN . Several authors (O’Neill, 1982; Moulin, 1987; Chun, 1988; de Frutos, 1999; Ju, 2003; MorenoTernero, 2006, 2007; Ju et al., 2007) have showed that merging and splitting proofness in bankruptcy problems leads to a proportional share of the estate. See for example Thomson (2003, 2015a). In this article, we assume that the government or planner seeks to assign a price and amount of land fairly and efficiently, and at the same time, to guarantee non-manipulability by land reassignment. In particular, our work can be seen as part of the theory of mechanism design applied to land rental (see Sen (2007) for an overview). We assume there is a single tenant who can be a mining firm, and several lessors who can be a group of communities. Each community has some available amount of land ci with a reservation price r per unit, that for simplicity we consider equal for all of them. The mining firm needs to rent an optimal amount of adjacent land E, which is a completely divisible object1 . A rule determines, for each land rental problem, a quantity of adjacent land to be rented by each community and a price that the mining firm must pay as a way of compensation. In order to study rules that guarantee non-manipulability, we propose a version of strategy-proofness such that communities should not find it profitable to re-assign the land among them. Also, we propose a version of land monotonicity that assures fairness, in the sense that an increase in the quan1 We use the terms c and E because of their resemblance to bankruptcy problems. 3 tity of available land affects positively the final profits to both sides. Our first result is a complete characterization of the family of rules that satisfy these properties. By adding a property inspired by “standard for two-person” in Hart and Mas-Colell (1989), we characterize a parametric subfamily. Another property is consistency, that states that the rule should behave in a similar way independently of the number of agents involved. This is a classical property in cooperative games (see van den Brink et al. (2013) and Huettner (2015) for two recent applications), and it has also been studied in bankruptcy problems (see Thomson (2008, 2015b) and references herein) and cost sharing problems (see for example Albizuri and Zarzuelo (2007) and Koster (2012)). By adding consistency and continuity we characterize another parametric subfamily of rules. The intersection of both parametric subfamilies singles out two particular rules: one of them optimal for the tenant and the other optimal for the lessors. We organize the paper as follows: In Section 2, we present the model. In Section 3, we study and characterize the family of rules that satisfy land reassignment and land monotonicity. In Section 4, we characterize the family of rules that also satisfy a weighted version of “standard for two-person”. Finally, in Section 5, we characterize the subfamily of rules that satisfy land reassignment, land monotonicity, consistency and continuity. 2 The model Let N+ = {1, 2, . . . } be the set of potential lessors and let N be the set of non-empty finite subsets of N+ . Let N = {1, 2, . . . , n} be a generic set of lessors, and let S be a generic subset of N . Given y ∈ RS , we write P S y(S) = i∈S yi . Given x, y ∈ R , we write x ≤ y when xi ≤ yi for all i ∈ S. Moreover 0S denotes the vector (0, . . . , 0) ∈ RS . We denote the set of nonnegative real numbers as R+ , and the set of positive real numbers as R++ . Let V N = {{i, j} : i, j ∈ N } be the set of all unordered pairs {i, j} over 4 N . The elements of V N are called edges. A network G over N is a subset of V N . We say that G is a connected network when, for all i, j ∈ N , there exists a sequence of different edges {{is−1 , is }}es=1 that satisfy {is−1 , is } ∈ G for all s ∈ {1, 2, . . . , e}, i = i0 and j = ie . We denote the set of all connected networks over N as G N . Given G ∈ G N and S ⊂ N , we denote the restriction of G to S as GS , i.e. GS = {{i, j} ∈ G : i, j ∈ S}. A land rental problem is a tuple (N0 , µ, c, r, G) where N0 = {0} ∪ N is the set of agents with 0 the unique tenant and N the set of lessors, µ : R+ → R is a function that assign to each amount of adjacent land the tenant’s revenue when that amount is rented, c ∈ RN ++ is the vector whose coordinates represent the amount of available land for each lessor, r ∈ R+ is the reservation price per unit of land for lessors, G ∈ G N identifies the lessors whose land is adjacent. Hence, the aggregate profit when the tenant rents l units of adjacent land is µ(l) + (c(N ) − l)r. We normalise µ(0) = 0, and assume that G is a connected network and that there exists a unique E ∈]0, c(N )] such that µ(E) + (c(N ) − E)r is maximum2 on [0, c(N )].3 We then denote K = µ(E) as the optimal profit that the agents can obtain. This implies that K > rE, i.e. there exists benefit of cooperation. Under these conditions, an efficient allocation implies that the amount of rented adjacent land is E and the profit of the tenant is K. Thus, the only relevant parameters of µ are E and K. Furthermore, for convenience we use N instead of N0 . Hence, we denote the land rental problem as (N, K, E, c, r, G) instead of (N0 , µ, c, r, G). Let L be the set of all land rental problems. A feasible agreement is a pair (x, p) ∈ RN + × R+ satisfying x ≤ c and {i ∈ N : xi > 0} a connected component in G, where xi is the land rented by lessor i ∈ N , and p is the price per unit of land. The set of feasible S agreements on a land rental problem L is denoted as AL . Let A = L∈L AL be the set of all potential feasible agreements. Given (x, p) ∈ AL , the utility for tenant and each lessor i ∈ N are 2 3 Since rc(N ) is constant, this condition is equivalent to µ(E) − rE be maximum. This condition holds, for example, when µ is increasing and strictly concave. 5 u0 (x, p) = µ(x(N )) − px(N ) and ui (x, p) = (p − r)xi , respectively. We define a rule as a function ψ : L −→ A that assigns to each problem L = (N, K, E, c, r, G) ∈ L a pair (x, p) = ψ(L) ∈ AL , satisfying: (i) x(N ) = E; (ii) for all α, β > 0, p(N, αK, βE, βc, αβ r, G) = α p(N, K, E, c, r, G) β and x(N, αK, βE, βc, αβ r, G) = βx(N, K, E, c, r, G); (iii) r ≤ p ≤ K . E The first condition (efficiency) says that the amount of land rented is optimal. The second condition (scale invariance) says that the final price and the amount of land rented are independent of changes of scale. The third condition (individual rationality) says that the lessors get at least zero (this is implied by r ≤ p), and under efficiency, the tenant also gets at least zero (this is implied by p ≤ K ). E Under efficiency, the utility of the tenant can be rewritten as u0 (x, p) = K − pE. There exist two special classes of rules: On the one hand, a rule is optimal for tenant when the price is given by p = r. In that case, xi is irrelevant for each i ∈ N , because their payoffs are zero, and so the final payoff allocation is unique. On the other hand, a rule is optimal for lessors when the price is given by p = K . E In the latter case, there are many possible payoff allocations when E < c(N ), all of them giving zero to the tenant. 3 Land reassignment and monotonicity Since there may be no official registration and demarcation of the customary land, the lessors can reach an agreement of reallocating it in order to share extra benefits so created under a rule. Formally, assume N = (N \ S) ∪ S, where N \ S is connected in G and represents the set of lessors that rearrange their land, while S is the set of lessors that do not. Hence, a new land problem arises, with N ′ = (N ′ \ S) ∪ S 6 as the new set of lessors, so that S = N ∩ N ′ . Moreover, the new connected network G′ that determines the adjacent lands should be compatible with G in the sense that GS = G′S and, for all i ∈ S, ∃j ∈ N \ S : {i, j} ∈ G ⇔ ∃j ′ ∈ N ′ \ S : {i, j ′ } ∈ G′ . In this case, we say that G and G′ are S-compatible. For the planner it is not possible to see this customary land situation, and it may be hard to get the outcome that the rule is supposed to attain. In our context manipulation implies that the lessors will benefit by merging or splitting under reallocating their land. Our aim is to fully identify rules that are free from this concern. We formalise this property as follows. Land Reassignment (LR) Given (N, K, E, c, r, G), (N ′ , K, E, c′ , r, G′ ) ∈ L such that ci = c′i for all i ∈ S = N ∩ N ′ , c(N \ S) = c′ (N ′ \ S), and G and G′ are S-compatible, X ui (ψ(N, K, E, c, r, G)) = X ui (ψ(N ′ , K, E, c′ , r, G′ )). i∈N ′ \S i∈N \S If the right-hand side of expression is larger than the left-hand side and the problem is (N, K, E, c, r, G), then lessors in N \S can gain by reallocating their land so that the problem becomes (N ′ , K, E, c′ , r, G′ ). Analogously, if the left-hand side of expression is larger than the right-hand side and the problem is (N ′ , K, E, c′ , r, G′ ), then lessors in N ′ \ S can gain by reallocating their land so that the problem becomes (N, K, E, c, r, G). S is the set of lessors that remain unchanged (S = ∅ is also possible). This property prevents lessors from having incentives for merging or splitting by reallocating their land. The following property says that an increase of the available land, leaving K and E unaffected, is (weakly) beneficial for everyone involved. Land Monotonicity (LM) Given (N, K, E, c, r, G), (N, K, E, c′ , r, G′ ) ∈ L with c ≤ c′ and G ⊆ G′ , 7 (i) u0 (ψ(N, K, E, c, r, G)) ≤ u0 (ψ(N, K, E, c′ , r, G′ )), and (ii) for each i ∈ N , cj = c′j for all j 6= i implies ui (ψ(N, K, E, c, r, G)) ≤ ui (ψ(N, K, E, c′ , r, G′ )). Under this property, the tenant will be weakly better off when there are more available land. Furthermore, when only one lessor has more available land and the rest of lessors remain unchanged, this lessor will be weakly better off. Let F be the set of functions f : [0, 1] → [0, 1] with f (t) ≥ t for all t ∈ [0, 1]. Now, we consider the family of rules defined by p = f ∈ F and xi = ci E c(N ) K f ( rE ) E K for some for all i ∈ N . So, we obtain different rules with different functions f ∈ F. These functions determine the price, whereas the amount of land is always divided proportionally, in line with the known results on invariance under reassignment in cost ans surplus sharing (cf. Theorem 1.1 in Moulin (2002)). Figure 1 represents six examples of these functions. 1 1 f (t) = t 1 f (t) = 1 1 1 (a) 1 (b) f (t) = 1 1 f (t) = 1.4t (c) 1 1 f (t) = t+1 2 1 (d) f (t) f (t) = 1 f (t) = 2t 1 (e) 1 (f) Figure 1: Examples of functions in F that determine six different rules, including an optimal rule for the tenant (a) and an optimal rule for the lessors (b). 8 Theorem 3.1 A rule ψ satisfies LR and LM if and only if there exists f ∈ F  f rE and, when p 6= r, the assigned such that the price is given by p = K E K amount of land is given by xi = ci E c(N ) for all i ∈ N . Proof. (⇐) Let ψ be a rule given by p = when p 6= r, xi = ci E c(N ) K f E rE K  for some f ∈ F and, for all i ∈ N . We will prove that ψ satisfies LR and LM. In order to prove that ψ satisfies LR, let L = (N, K, E, c, r, G) ∈ L, L′ = (N ′ , K, E, c′ , r, G′ ) ∈ L and S = N ∩ N ′ given as the definition of P ∈ [0, 1[. On the one hand, we have LR. Let t = rE i∈N \S ui (ψ(L)) = K    P c(S) ci E K i∈N \S E f (t) − r c(N ) = K (f (t) − t) 1 − c(N ) . Analogously, on the   P ′ (S) other hand, we have i∈N ′ \S ui (ψ(L′ )) = K (f (t) − t) 1 − cc′ (N Since ′) . c(N \ S) = c′ (N ′ \ S) and ci = c′i for all i ∈ S, we have that c(S) = c′ (S) and c(N ) = c′ (N ′ ). Hence the last two expressions coincide. We now prove that ψ satisfies LM. Let L and L′ = (N, K, E, c′ , r, G′ ) ∈ L given as in the definition  E = u0 (ψ(L′ )), of LM. If c ≤ c′ , then, by efficiency, u0 (ψ(L)) = K − K f rE E K hence condition (i) holds. If ci ≤ c′i and cj = c′j for all j ∈ N \ {i} then   cE   c′ E rE K rE i i f ≤ f = ui (ψ (L′ )) for all − r − r ui (ψ(L)) = K E K c(N ) E K c′ (N ) i ∈ N , hence condition (ii) also holds. (⇒) Let ψ be a rule that satisfies LR and LM. For simplicity, we write (x, p) instead of ψ(N, K, E, c, r, G), (x′ , p′ ) instead of ψ(N ′ , K, E, c′ , r, G′ ) and so on. Furthermore, we write ui instead of ui (x, p), u′i instead of ui (x′ , p′ ) and so on. We proceed by series of claims. Claim 3.1 If K = E = 1 and N = {1}, then the price p does not depend on c. Proof. By LM, if c1 ≤ c′1 , then u0 ≤ u′0 . By efficiency, u0 ≤ u′0 can be rewritten as 1 − p ≤ 1 − p′ , hence p ≥ p′ (the higher c1 , the higher p). Analogously, c1 ≤ c′1 implies u1 ≤ u′1 and p ≤ p′ (the higher c1 , the lower p). Therefore, p = p′ .  We define f (t) = p({1}, 1, 1, (1), t, ∅) for all t ∈ [0, 1]. By individual rationality, t ≤ p({1}, 1, 1, (1), t, ∅) ≤ 1 for all t ∈ [0, 1], so f ∈ F. 9 Claim 3.2 If K = E = 1, then p = f (r). Proof. Assume first 1 ∈ / N . By LR, u(N ) = u1 (ψ({1}, 1, 1, (c(N )), r, ∅)). Under Claim 3.1 and efficiency, this is equal to p({1}, 1, 1, (1), r, ∅) − r, hence P u(N ) = f (r) − r. Furthermore, by efficiency, u(N ) = i∈N (p − r)xi = p − r. Therefore, we have p = f (r). Assume now 1 ∈ N . Let i ∈ N+ \N . Under LR, ui (ψ({i}, 1, 1, (c(N )), r, ∅)) = u1 (ψ({1}, 1, 1, (c(N )), r, ∅)) and we proceed as before. Claim 3.3 p =  K f E rE K  . Proof. By scale invariance, p =  . f rE 3.2 we have that p = K E K K p E N, 1, 1, c E   , G , and under Claim , rE K  Therefore, the price is determined by Claim 3.3. Now we focus on the amount of land x. Claim 3.4 If p 6= r and there exist i, j ∈ N such that ci = cj , then xi = xj . Proof. Fix α ∈ N+ \ N . We define (N iα , K, E, ciα , r, Giα ) ∈ L, where N iα = iα iα {i, α}, ciα = {{i, α}}. Since N ∩ N iα = {i}, i = ci , cα = c(N \ {i}), and G then by LR, u(N \ {i}) = uiα (N iα \ {i}). Under Claim 3.3 and p 6= r, we obtain x(N \ {i}) = xiα α . Furthermore, by efficiency x(N \ {i}) + xi = E and iα iα xiα i + xα = E. From these last three equalities we obtain that xi = xi . We iα define (N jα , K, E, cjα , r, Gjα ) ∈ L, where N jα = {j, α}, cjα j = ci = ci = cj , jα iα jα cjα = {{j, α}}. Since N iα ∩ N jα = {α} and ciα α = cα , and G i = cj , by LR, jα ui (xiα , piα ) = uj (xjα , pjα ). Under Claim 3.3 and p 6= r, we obtain xiα i = xj . jα jα Since N jα ∩ N = {j} and cjα α = c(N \ {j}), by LR, uα (x , p ) = u(N \ {j}), and under Claim 3.3 and p 6= r, we obtain xjα α = x(N \ {j}). Furthermore, jα by efficiency we have xjα j + xα = E and xj + x(N \ {j}) = E. So, from these jα iα iα last three equalities we obtain xjα j = xj . Then, from xi = xi , xi = xj and xjα j = xj we get that xi = xj .  Claim 3.5 If N = {i, j}, p 6= r and ci , cj ∈ Q, then xi = cj E . ci+cj 10 ci E ci+cj and xj = Proof. Assume ci = i ai bi aj bj and cj = j i where a and b are non-negative integers. j Let N , N ⊂ N+ \N with N ∩N = ∅, |N i | = ai bj and |N j | = aj bi . We define (N ∗i , K, E, c∗i , r, G∗i ) ∈ L with N ∗i = N i ∪ {j} and c∗i k = 1 bi b j for all k ∈ N i , ∗i i ∗i c∗i = {j} and c∗i (N ∗i \ j) = j = cj , and G = {{k, j} : k ∈ N }. Since N ∩ N ci , by LR, ui = u∗i (N ∗i \ {j}). Under Claim 3.3, this is equivalent to write (p − r)xi = (p − r)x∗i (N ∗i \ {j}). Since p 6= r, xi = x∗i (N ∗i \ {j}). We now define (N ∗ij , K, E, c∗ij , r, G∗ij ) ∈ L with N ∗ij = N i ∪ N j , c∗ij k = all k ∈ N ∗ij c (N ∗ij ∗ij ∗ij ′ i ′ ∗i j 1 bi bj for ∗i = {{k, k } : k ∈ N , k ∈ N }. Since c (N \ {j}) = P aj b i 1 = cj = c∗i \N ), N ∩N = N i and c∗ij (N ∗ij \N i ) = l=1 j , by b i bj , and G j ∗i ∗ij ∗ij ∗ij LR, u∗i \ N i ). Under Claim 3.3, this is equivalent to write (p − j = u (N ∗ij ∗ij ∗ij ∗ij r)x∗i \ N i ). Since p 6= r, x∗i \ N i ) = x∗ij (N j ). j = (p − r)x (N j = x (N On the one hand, by efficiency, xi +xj = E and x∗i (N ∗i \{j})+x∗i j = E. Since ∗ij j ∗ij j xi = x∗i (N ∗i \{j}) and x∗i j = x (N ), we obtain xj = x (N ). On the other ∗ij i ∗ij j hand, by efficiency, x∗i (N ∗i \ {j}) + x∗i j = E and x (N ) + x (N ) = E. ∗ij j ∗ij i Since xi = x∗i (N ∗i \ {j}) and x∗i j = x (N ), we obtain xi = x (N ). We have (N ∗ij , K, E, c∗ij , r, G∗ij ) with N ∗ij ∩ N = ∅ and c∗ij (N ∗ij ) = c(N ). By LR, u∗ij (N ∗ij ) = u(N ). By p 6= r and Claim 3.3, this is equivalent to write x∗ij (N ∗ij ) = x(N ). Under Claim 3.4 and efficiency, we obtain that x∗ij k = E |N ∗ij | = E ai bj +aj bi for all k ∈ N ∗ij . By efficiency and xj = x∗ij (N j ), we have that xi = E − x∗ij (N j ). Under Claim 3.4, this is equivalent to write ∗ij . Since x∗ij xi = E − aj bi x∗ij k = k for each k ∈ N have xi = E − aj b i E ai bj +aj bi = ci E . ci +cj Analogously, E ai bj +aj bi cj E xj = ci+c . j Claim 3.6 If N = {i, j}, p 6= r and cj ∈ Q, then xi = Proof. Assume first ci + cj = E. Then, ci E ci +cj for all k ∈ N ∗ij , we ci E ci +cj = ci and efficiency, xi = ci and xj = cj . Therefore, xi =  ci E ci +cj and xj = cj E ci +cj cj E . ci +cj = cj . By and xj = cj E . ci +cj Assume now ci + cj > E. Let {csi }∞ s=1 be a decreasing sequence of rational numbers that converges to ci . For each s, we take (N, K, E, cs , r, G) ∈ L cs E c E  with cs = (csi , cj ). Under Claim 3.5, we have xs = csi+cj , csj+cj . By LM, i i ui (x, p) ≤ ui (xs , ps ). Under Claim 3.3, this is equivalent to write (p − r)xi ≤ (p − r)xsi . Since p 6= r, this is equivalent to xi ≤ xsi . Under Claim 3.5, 11 this is equivalent to write xi ≤ csi E s ci +cj . Hence, xi ≤ ci E . ci +cj Let {b csi }∞ s=1 be an increasing sequence of positive rational numbers that converges to ci and bs = (N, K, E, b such that L cs , r, G) ∈ L, where b cs = (b csi , cj ). We can find such a sequence because ci > 0 and ci + cj > E. Under Claim 3.5, we have b cs E c E  x bs = bcsi+cj , bcsj+cj . By LM, u bsi ≤ ui . Under Claim 3.3, this is equivalent to i i write (p − r)b xsi ≤ (p − r)xi . Since p 6= r, this is equivalent to x bsi ≤ xi . Under Claim 3.5, this is equivalent to write xi ≤ ci E ci +cj and Since xi = ci E ci +cj ci E , ci +cj we b csi E b csi +cj ci E ci +cj ≤ xi . Hence, iE ≤ xi , we obtain xi = cic+c . By j cj E ci E deduce xj = E − ci +cj = ci +cj . Claim 3.7 If N = {i, j} and p 6= r, then xi = ci E ci +cj ci E = ci +cj ci E xi = ci +cj ≤ xi . Since efficiency, xj = E − xi .  and xj = cj E . ci +cj cj E = ci +cj cj E xj = ci +cj . Proof. Assume first ci + cj = E. Then, ci and cj . By efficiency, xi = ci and xj = cj . Therefore, and Assume now ci + cj > E. Let {csj }∞ s=1 a decreasing sequence of rational numbers that converges to cj . For each s, we take (N, K, E, cs , r, G) ∈ L with cs = (ci , csj ). csj E  s s Under Claim 3.6, we have xs = xi , ci +c s . By LM, uj (x, p) ≤ uj (x , p ). j Under Claim 3.3, this is equivalent to write (p − r)xj ≤ (p − r)xsj . Since p 6= r, this is equivalent to xj ≤ xsj = csj E . ci +csj Hence, xj ≤ cj E . ci +cj Let {b csj }∞ s=1 be an increasing sequence of rational numbers that converges to cj and such bs = (N, K, E, b that L cs , r, G) ∈ L, where b cs = (ci , b csj ). We can find such a sequence because ci > 0 and ci + cj > E. Under Claim 3.6, we have b csj E  x bs = xi , ci +b . By LM, u bsj ≤ uj . Under Claim 3.3, this is equivalent to cs j write (p − r)b xsj ≤ (p − r)xj . Since p 6= r, this is equivalent to x bsj ≤ xj , or b csj E ci +b csj ≤ xj . Hence, cj E . By ci +cj cj E iE = cic+c . ci +cj j obtain xj = xi = E − cj E ci +cj ≤ xj . Since xj ≤ cj E ci +cj and efficiency, xi = E − xj . Since xj = Claim 3.8 If p 6= r, then xi = cj E ci +cj cj E , ci +cj ≤ xj , we we deduce  ci E c(N ) for all i ∈ N . Proof. Let i ∈ N , j ∈ N+ \ N and (N ij , K, E, cij , r, Gij ) ∈ L with N ij = ij ij {i, j}, cij = {{i, j}}. By efficiency, xi = i = ci , cj = c(N \ {i}), and G E − x(N \ {i}). By LR and p 6= r, we have x(N \ {i}) = xij j , so that 12 ij xi = E − xij j . Under Claim 3.7, xj = E− c(N \{i})E ci +c(N \{i}) = cij j E ij ci +cij j . Hence, xi = E − cij j E ij ci +cij j ci E . c(N ) =  Therefore, the amount of land is determined by Claim 3.8.  f We denote ψ as the rule corresponding to f ∈ F that is given by p =  ci E K f rE for all i ∈ N . , and xi = c(N E K ) 4 Weighted standard for two-person We study a property that is inspired on the so called standard for two-person property by Hart and Mas-Colell (1989). This property follows a “divide the surplus equally” idea for two-person situations. In our context, the twoperson case arises when |N | = 1, i.e. the only agents are the tenant and a single lessor. Standard for two-person says that both the tenant and the lessor obtain equal benefit. We formalize this property as follows. Let L2 be the set of land rental problems with a unique lessor. Standard for 2-person (S2) Given L = ({1}, K, E, c, r, ∅) ∈ L2 , u0 (ψ(L)) = u1 (ψ(L)) . Next theorem characterizes the unique rule that satisfies LR, LM and S2. The function that determines this rule is represented in Figure 1(e). Theorem 4.1 A rule ψ satisfies LR, LM and S2 if and only if the price is given by p = K+rE 2E Proof. (⇐) Let ψ be a rule given by p = K+rE 2E f p = for all i ∈ N . ci E c(N ) = 1+t 2 for all i ∈ N . and xi = It is straightforward to check that ψ = ψ with f (t) K+rE . 2E ci E c(N ) and the amount of land is given by xi = for all t and By Theorem 3.1, ψ satisfies LR and LM. So, we just need to prove that u0 (ψ({1}, K, E, c, r, ∅)) = u1 (ψ({1}, K, E, c, r, ∅)). The left side K+rE E = K−rE . Analogously, the right side 2E 2  K+rE − r x1 . By efficiency, x1 = E, and hence of the equality is equal to 2E we obtain u1 (ψ({1}, K, E, c, r, ∅)) = K−rE . Therefore, the equality holds. 2 of the equality is equal to K − 13 (⇒) Let ψ be a rule that satisfies LR, LM and S2. By Theorem 3.1  ci E f rE and, when, p 6= r, xi = c(N there exists f ∈ F such that p = K E K )  K K+rE rE for all i ∈ N . We need to prove that E f K = 2E or equivalently f (t) = 1+t 2 for t = rE K ∈ [0, 1]. By S2, we have u0 (ψ({1}, 1, 1, (1), t, ∅)) = u1 (ψ({1}, 1, 1, (1), t, ∅)). This is equivalent to 1 − f (t)x1 = (f (t) − t)x1 . By efficiency, x1 = 1, which is equivalent to write 1 − f (t) = f (t) − t. Hence, f (t) = 1+t . 2 Finally, since K > rE, we deduce p 6= r so xi = ci E c(N ) for all i ∈ N.  Next, we generalize the standard for two-person concept in a nonsymmetric way. Notice that S2 determines the final payoffs for two-person problems, forcing both the tenant and the unique lessor to receive the same value. Since tenant and lessor are not symmetric, we can reasonabely allow one side of the market to extract a higher value than the other. In our context, since the rules satisfy efficiency, it is enough to fix the relative payoff between both agents. In particular, a rule satisfies the next property when the payoffs are in the same proportion for every single-lessor problem. Weighted Standard for 2-person (WS2) There exists ω ∈ [0, 1] such that (1 − ω)u0 (ψ(L)) = ωu1 (ψ(L)) for all L = ({1}, K, E, c, r, ∅) ∈ L2 . Next theorem characterizes the parametric subfamily of rules that satisfy LR, LM and WS2. We can see three examples of functions that determine these rules in Figure 1 (a), (b) and (e), respectively. Theorem 4.2 A rule ψ satisfies LR, LM and WS2 if and only if there exists ω ∈ [0, 1] such that the price is given by p = the quantity of land is given by xi = ci E c(N ) K−(K−rE)ω E and, when ω < 1, for all i ∈ N . Proof. (⇐) Fix ω ∈ [0, 1]. Let ψ be a rule given by p = if ω < 1, then xi = ci E c(N ) K−(K−rE)ω E and, for all i ∈ N . By Theorem 3.1, ψ satisfies LR and LM for f (t) = 1 − (1 − t)ω and p = K−(K−rE)ω . E 14 Fix L = ({1}, K, E, c, r, ∅). We just need to prove that (1 −ω)u0 (ψ(L)) = ωu1(ψ(L)). The left side of E = (1 − ω)ω(K − rE). the equality is equal to (1 − ω) K − K−(K−rE)ω E Analogously, the right side of the equality is equal to ω( K−(K−rE)ω − r)x1 . E By efficiency, x1 = E, and hence we obtain ω(1 − ω)(K − rE). Therefore, equality holds. (⇒) Let ψ be a rule that satisfies LR, LM and WS2. Let ω ∈ [0, 1].  By Theorem 3.1, there exists f ∈ F such that p = K f rE and, when E K p 6= r, xi = ci E c(N ) for all i ∈ N . It is clear that ω < 1 implies p 6= r. To see why, notice that p = r implies u1 = 0, whereas u0 + u1 = K − rE > 0, so u0 > 0, and by WS2, (1 − ω)u0 = ωu1 = 0, so (1 − ω)u0 = 0, which implies  = K−(K−rE)ω f rE or, equivalently, ω = 1. We still need to prove that K E K E f (t) = 1 − (1 − t)ω for all t ∈ [0, 1]. Let t = rE K ∈ [0, 1]. By WS2 we have (1 − ω)u0 (ψ({1}, 1, 1, (1), t, ∅)) = ωu1 (ψ({1}, 1, 1, (1), t, ∅)). This is equivalent to (1 − ω)(1 − f (t)x1 ) = ω(f (t) − t)x1 , which by efficiency is equivalent to write (1 − ω)(1 − f (t)) = (f (t) − t)ω. Rearranging terms, we deduce f (t) = 1 − (1 − t)ω.  Notice that, when ω = 1, we obtain an optimal rule for the tenant, and when ω = 0, we obtain an optimal rule for the lessors. Given ω ∈ [0, 1], we denote ψ ω as the rule corresponding to the function ψ f with f (t) = 1−(1−t)ω for all t and xi = ci E c(N ) 1 for all i ∈ N . In particular, ψ 2 is the rule given in Theorem 4.1. 5 Consistency Consistency is a well-known principle. Assume that there exists an agreement on what the right price and land share are, and that some lessors take this price and leave. The tenant and the rest of lessors can proceed in two ways: On the one hand, they can keep the previous price and land share. On the other hand, they can recompute the right price and land share following the same principle as before in the new reduced land renting problem. This new reduced land rental problem is defined as L′ = (N ′ , K ′ , E ′ , c′ , r, G′ ) ∈ L given 15 by N ′ = N \S where S ⊂ N is the set of lessors that leave, K ′ = K −px(S) is the new maximal profit of the tenant, E −x(S) is the amount of land that the N \S tenant still needs in the new reduced land rental problem, c′ = cN \S ∈ R++ is the vector whose coordinates represent the amount of available land, r is the reservation price, which is equal as in the original land rental problem, and G′ identifies the lessors in N ′ whose land is adjacent, directly or through lessors in S. If this procedure always gives the same result for agents in N0 \S as before, we say that ψ is consistent. Consistency For all (N, K, E, c, r, G) ∈ L and S ⊂ N such that GS is a connected network and x(S) < E, for all i ∈ N0′ , ui (ψ (N ′ , K ′ , E ′ , c′ , r, G′ )) = ui (ψ(N, K, E, c, r, G)) where N ′ = N \S, K ′ = K −px(S), E ′ = E−x(S), c′i = ci for all i ∈ N ′ ,  ′ and G′ = GN ′ ∪ {i, j} ∈ V N : ∃k, k ′ ∈ S s.t. {i, k}, {j, k ′ } ∈ G . Next proposition characterizes the second parametric subfamily of rules that satisfy LR, LM and consistency. We can see some examples of functions that determine these rules in Figure 1 (a), (b), (d) and (f), respectively. Proposition 5.1 A rule ψ satisfies LR, LM and consistency if and only if there exist α, β ∈ [0, 1] with α ≤ β such that: a) The price is given as follows: a.1) If r = 0, then either p = 0 or p = K E for all L ∈ L. a.2) If r > 0 and rE < αK, then p = αβ r for all L ∈ L. a.3) If r > 0 and rE = αK, then p = αβ r or p = a.4) If r > 0 and rE > αK, then p = K E for all L ∈ L. for all L ∈ L. b) The amount of land when p 6= r is given by xi = 16 K E ci E c(N ) for all i ∈ N. Proof. (⇐) Let α, β ∈ [0, 1] with α ≤ β so that the price and the amount of land are given by a) and b), respectively. Let f ∈ F defined as follows: f (0) ∈ {0, 1}, f (t) = β t α if 0 < t < α, f (α) ∈ {β, 1} if α > 0, and f (t) = 1 if t > α. Then, the price can be written as p = K f ( rE ). E K Hence, by Theorem 3.1, ψ satisfies LR and LM. Let L = (N, K, E, c, r, G) and L′ = (N ′ , K ′ , E ′ , c′ , r, G′ ) given as in the definition of consistency. We will prove that ui (x, p) = ui (x′ , p′ ) for all i ∈ N0 \ S, where (x, p) = ψ(L) and (x′ , p′ ) = ψ(L′ ). Firstly, we prove that p′ = p. We distinguish the following cases: Case 1: r = 0 and p = 0. In this case, f (0) = 0. Hence, p′ = 0 and p = 0. K . In E x(S) K− K E =K E−x(S) E Case 2: r = 0 and p = ′ p = K′ E′ = this case, f (0) = 1. Hence, p′ = K′ . E′ Therefore, = p. Case 3: r > 0, rE < αK and p = β r. α Under a.2), we know that p′ = β r α when r > 0 and rE ′ < αK ′ . Since r > 0, it is enough to check  that rE ′ < αK ′ . Equivalently, r (E − x(S)) < α K − αβ rx(S) . Since rE < αK, it is enough to check that rx(S) ≥ βrx(S). This is trivially true when rx(S) = 0. Otherwise, it is equivalent to check that β ≤ 1, which is true by definition. Case 4: r > 0, rE = αK and p = β r. In this α rE(E−x(S)) K(E−βx(S)) case, p = K β, E so f rE K  = ′ r(E−x(S)) = K− and β ≤ 1, we have that = β. Since rE K K′ βx(S) E rE ′ ≤ rE(E−x(S)) = rE = α. Hence, rE ′ ≤ αK ′ . We will show that K′ K(E−x(S)) K  ′ ′ . We have two sub-cases: First, if rE ′ < αK ′ , then it = αβ rE f rE K′ K′ ′ ′ f rE . Second, if rE ′ = αK ′ , holds by a.2) and the fact that p′ = K E′ K′  (rE=αK) ′ = β. Since rE ′ = αK ′ , we obtain = f (α) = f rE then f rE K′ K (rE=αK) ′ ′ ′ ′ ′ β rE ′ that f rE . Hence, p′ = K f rE = αβ r = = αβ rE = K K′ K′ E′ K′ E′ α K′ K β = p. E  K rE and p = K . Since p = f , we Case 5: r > 0, rE = αK, and p = K E E K E  r(E−x(S)) rE(E−x(S)) rE rE ′ rE deduce f K = 1. Moreover, K ′ = K− K x(S) = K(E−x(S)) = K = α. E  ′ = 1, we deduce Hence, f rE = f (α). Since rE = αK and f rE K′ K K   ′ ′ ′ ′ x(S) K− E f rE = E−x(S) =K = p. = 1. Hence, p′ = K =K f rE K′ E′ K′ E′ E 17 Case 6: rE > αK. In this case, p = when rE ′ > αK ′ . Since K′ E′ = K . Under a.4), E x(S) K− K E = K , E−x(S) E we know that p′ = K′ E′ it is enough to check that rE ′ > αK ′ . This is equivalent to check thatr(E −x(S)) >  . Since x(S) . Equivalently, r (E − x(S)) > αK E−x(S) α K−K E E E − x(S) > 0, this is equivalent to rE > αK, which is true in this case. We check now that ui (ψ(L′ )) = ui (ψ(L)) for all i ∈ N0 \ S. Assume first i ∈ N \ S. We need to prove that (p − r)x′i = (p − r)xi . This is trivially true when p = r. Hence, assume p 6= r. We need to prove  x′i = xi . Since  c(N ) = c(N \ S) + c(S), then x′i = c(Nci\S) (E − x(S)) = c(Nci\S) E − c(S)E = c(N )     c(N )−c(S) \S) ci ci E = c(Nci\S) c(N E = c(N E = xi . Assume now i = 0. c(N \S) c(N ) c(N ) ) We check that u0 (ψ(L′ )) = u0 (ψ(L)), or K ′ − pE ′ = K − pE. By definition, K ′ − pE ′ = (K − px(S)) − p(E − x(S)) = K − pE. (⇒) Let ψ be a rule that satisfies LR, LM and consistency. Under LR  and, f rE and LM, by Theorem 3.1 there exists f ∈ F such that p = K E K when p 6= r, xi = ci E c(N ) for all i ∈ N . Denote L = (N, K, E, c, r, G) and let S ⊂ N with E < x(S) and L′ = (N ′ , K ′ , E ′ , c′ , r, G′ ) be defined as in the definition of consistency. Hence, we have ui (x, p) = ui (x′ , p′ ) for all i ∈ N0 \ S, where (x, p) = ψ(L) and (x′ , p′ ) = ψ(L′ ). In particular, u0 (x, p) = u0 (x′ , p′ ). By definition, this is equivalent to K ′ − p′ E ′ = K − pE, or K − px(S) − p′ (E − x(S)) = K − pE. Since E 6= x(S), we deduce p′ = p. We will prove the existence of α and β with α ≤ β, such that the price is given as in a). Or, equivalently, f (0) ∈ {0, 1}, β f (t) = t if t ∈]0, α[, α f (α) ∈ {β, 1} when α > 0, and (1) f (t) = 1 if t > α. If f (t) = 1 for all t ∈ [0, 1], then α = 0 and β = 1 satisfy (1). Hence, we  can assume that there exists b t such that f b t < 1. Let α = Sup{t : f (t) < 1} 18 and β = Sup{f (t) : f (t) < 1}. Then, f (t) ≥ t for all t implies α, β ∈ [0, 1] and α ≤ β. For each r ∈ [0, 1] and γ ∈]0, 1[, assume L = ({1, 2}, 1, 1, (γ, 1 − γ), r, G) and S = {2}. So, K ′ = K − px2 = 1 − f (r)(1 − γ) and E ′ = E − x2 = γ. Hence, we have L′ = ({1}, 1 − f (r)(1 − γ), γ, (γ), r, ∅).    1−f (r)(1−γ)  rγ K′ rE rE ′ ′ . f f f = f (r) and p = = So, p = K E K E′ K′ γ 1−f (r)(1−γ) Since p′ = p, from the last two expressions, we have   rγ f (r)γ f = for all r ∈ [0, 1] and γ ∈]0, 1[. (2) 1 − f (r)(1 − γ) 1 − f (r)(1 − γ) In particular, for r = 0, we have f (0) = f (0)γ 1−f (0)(1−γ) for all γ. If f (0) 6= 0, then γ = 1 − f (0)(1 − γ) for all γ, or equivalently, (1 − f (0))γ = 1 − f (0) for all γ, which implies that f (0) = 1. Hence f (0) ∈ {0, 1}. This is the first line of (1). For t > α, we have f (t) = 1. This is the fourth line of (1). For each r ∈]0, 1[, we define F r (δ) = rδ 1−f (r)(1−δ) ∈ [0, r] for all δ ∈]0, 1]. If f (r) < 1, then F r is a strictly increasing and continuous function, and its inverse is given by Gr (t) = (1−f (r))t r−f (r)t ∈]0, 1[ for all t ∈]0, r]. Given t ∈]0, r] and r ∈]0, 1[ such that f (r) < 1,  rGr (t) f (t) = f (F (G (t))) = f 1 − f (r)(1 − Gr (t)) f (r)Gr (t) (2) = 1 − f (r)(1 − Gr (t)) r r  (r))t f (r) (1−f f (r) r−f (r)t =  t. = (1−f (r))t r 1 − f (r) 1 − r−f (r)t Assume α > 0. Then we can fix r ∈]0, 1[ such that f (r) < 1. Hence, f (t) t = f (r) r where θ = for all t ∈]0, r]. We will prove that f (t) = θt for all t ∈]0, α[, f (r) . r For all t ∈]0, α[, there exists r′ > t such that f (r′ ) < 1 and f (r ′ ) . If t < r, we can take r′ = r, thus f (t) = θ. If t ≥ r, then r′ r′ t ′ ) = f (r = θ. Hence, f (t) = θt for all t ∈]0, α[. We will prove thus f (r) r r′ θ = αβ , or equivalently rβ = αf (r). We have two cases: f (t) t = 19 > r, that Case I. If f (α) = 1, then β = Sup{f (t) : t ∈]0, α[} = Sup{θt : t ∈]0, α[} = θα. Hence, θ = αβ . Case II. If f (α) < 1, then f (α) α = θ, so that f (t) = θt for all t ∈]0, α] and β = Sup{f (t) : t ∈]0, α]} = Sup{θt : t ∈]0, α]} = θα. Hence, θ = αβ . Then, the second line of (1) is satisfied. From Case I and Case II we can deduce f (α) ∈ {β, 1}. This is the third line of (1).  Given α, β ∈ [0, 1] with α ≤ β, we define ψ α,β as the rule corresponding to the function given in Proposition 5.1 with f (0) = 0, f (α) = β and such that the amount of land is given by xi = ci E c(N ) for all i ∈ N . Next property says that small changes in the land rental problem should not cause large changes in the chosen allocation. Continuity The price p and the amount of land x are continuous functions on L. The rules that satisfy LR, LM, consistency and continuity constitute a particular subfamily of rules from the one determined in Proposition 5.1 and it is characterized in the next theorem. We can see some examples of functions that determine these rules in Figure 1 (a), (b) and (f), respectively. Theorem 5.1 A rule ψ satisfies LR, LM, consistency and continuity if and only if there exists α ∈ [0, 1] such that: a) p=  r α K E and if rE < αK if rE ≥ αK b) xi = ci E for all i ∈ N. c(N ) 20 Proof. (⇐) Let α ∈ [0, 1] such that the price and amount of land are given by a) and b) respectively. Part a) can be written as p = f ∈ F given as f (t) = t α K f ( rE ) E K with if t < α and f (t) = 1 if t ≥ α. Hence, by Proposition 5.1, ψ satisfies LR, LM and consistency. To prove it that satisfies continuity we still need to check that p is continuous at the points where rE = αK. Equivalently, limrE→αK + xi = ci E c(N ) r α = K , E which holds trivially. Moreover, for all i ∈ N also determines a continuous function. (⇒) Under LR, LM and consistency, by Proposition 5.1 there exist α, β ∈ [0, 1] with α ≤ β such that the price is given as in part a) of Proposition 5.1, and the amount of land when p 6= r, is given by xi = By adding continuity, we will prove that p = rE ≥ αK. Moreover, xi = ci E c(N ) r α ci E c(N ) for all i ∈ N . if rE ≤ αK and p = K E if for all i ∈ N . In this sense, we have that p is a continuous functions in ]0, α[∪]α, 1]. We still need to prove the following cases: i) If r = 0, by continuity, p = limt→0 αβ t = 0 = αt . ii) If rE = αK, by continuity, αβ r = We need to prove that xi = ci E c(N ) K . E Then, β = Kα rE = 1. for all i ∈ N when p = r. Let Lt = (N, K, E, c, rt , G) ∈ L with limt→∞ rt = 0 and rt > 0 for all t. Therefore, xti = ci E c(N ) for all t ∈ [0, 1]. Then, under continuity of the land function, xi = limr→0 ci E c(N ) = ci E . c(N )  Notice that the functions provided in Theorem 5.1 are those ψ α,β with β = 1. In particular, ψ 0,1 = ψ 0 (rule ψ ω when ω = 0) is a rule optimal for the tenant and ψ 1 (rule ψ ω when ω = 1) is a rule optimal for the lessors. These two rules are the only ones that belong to both parametric subfamilies defined at Theorem 4.2 and Theorem 5.1, respectively. Both rules are characterized in the next proposition. We can see the functions that determine these rules in Figure 1 (a) and (b), respectively. Proposition 5.2 ψ 0 and ψ 1 are the only rules that satisfy LR, LM, WS2, consistency and continuity. 21 Proof. It is straightforward to check that both ψ 0 and ψ 1 satisfy these properties. Let ψ be a rule that satisfies these properties. We will prove that ψ is either ψ 0 or ψ 1 . On the one hand, by Theorem 5.1, there exists α ∈ [0, 1] such that p = K E when rE = αK. On the other hand, by Theorem 4.2, there exists ω ∈ [0, 1] such that p = we have K E = K−(K−rE)ω , E K−(K−rE)ω E for all r. Hence, given r = αK , E or (K − rE)ω = 0. There are two possibilities: On the one hand, ω = 0 which gives ψ = ψ 0 . On the other hand, K = rE and rE = αK imply K = αK. Since K > 0, we deduce α = 1 which gives ψ = ψ 1,1 = ψ 1 .  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