JOURNAI.
OF DlFPEREN’I’IAl~
EQUATlONS
50,
I-1
Y
(1983)
A Free-Boundary
Problem for a
Degenerate Parabolic System
lJkv?rsily
Mathematics Research Center.
qj’ Wisconsin, .bfudison. Wisconsin 53706
AND
R. E. SHOWALTER
Department
R1.M Y.100.
The lJnioersi/,g
qf Mathematics.
OJ’Texas, Austin, Tcxns 78712
Rcccived August 17, 1981
I. INTRC)D~JCTION
We shall be concerned with the first initial-boundary-vaiue
problem for
non-negative solutions of a system of nonlinear partial differential equations
of the form
$w,
I)) ---‘@0(.x,
I) -t-h($& f)
0(x, t)) EJ.f,(x,I)
and a related free-boundary problem of Stefan type. Here d denotes tho
Laplacean in the spatial variable x E IH”, h > 0, and the pair ix, /I’ are
maximal monotone graphs in II? x Ft. If the first equation were to contain the
term .‘ -kd(J(~, t)” with k > 0, then the system (I. 1) would be parabolic. The
situation we consider here with k = 0 is accord,ingly a degenerate parabolic
system,
Although the system (1.1) with the (possibly multi-valued) nonlinear
monotone graphs CY,,4 is of mathematical interest in its own right, we present
in Section 2 an extensive discussion of how such a system arises as a model
of heat conduction in a composite material consisting of two components in
which a change of phase occurs in the second component. This model is
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2
DIBENBDETTO
AND SIIOWAL'I-ER
described by (1.1) with ,8 obtained in the special form P(X) = h-u + .LH(x),
where b > 0, L is the latent heat of fusion and H(.) is the multi-valued
Heaviside step function. Certain models of diffusion through fractured
porous media lead to the same system.
Our results on (1.1) are organized as follows. In Section 3 we prove that
the first initial-boundary-value
problem for (I. 1) is well-posed when the data
satisfy certain integrability conditions and ,8 is defined everywhere on II?. If
the data are non-negative then the solution is likewise non-negative; this
property is essential for the model problem discussed in Section 2. We make
extensive use of the theory of maximal monotone operators in Hilbert space
to which WCrefer to 12. 3 I.
Certain properties of the solution arc obtained when we restrict attention
to the case where ~1 has a lower linear bound and /I = b/ + LH as in the
model problem. In Section 4 we show that if the data arc essentially bounded
then the solution of (1. I ) is essentially bounded. Additional conditions on the
data are shown to imply that 6, and 9 are continuous. In order to obtain
these regularity results we found it very useful to treat the problem as an
equation of evolution rather than to have formulated it as a variational inequality.
In Section 5 we exhibit an explicit lower bound on the first component of
the solution of (1.1). This implies that the set of points where this function is
positive (the positivity set) is non-decreasing with time. Finally, we show
that the positivity set of the first component contains that of the second
component, and an example is given to show that this containment may be
proper.
2. D~PFUSION IN HETEKOGENEOIIS MEDIA
We begin with a mathematical description of diffusion processes within a
medium consisting of two components. A fundamental assumption is that the
first component occurs in small isolated parts that are suspended in the
second component. This situation arises in thermal conduction through
rocky soil, since the rocks arc isolated within the soil. It also occurs in lhe
diffusion of liquid or gas through a porous media that has been fractured,
since the blocks of the medium are isolated from one another by the system
of fissures. Next we shall formulate a free-boundary problem of Stefan type
that results from a change of phase in the second component of the medium.
This arises in the model of heat conduction through the moisture in rocky
soil since the soil moisture may freeze or thaw with a corresponding release
of latent heat; thcrc is no moisture in the rocks. If WCconsider diffusion in a
fractured medium in which the system of fissures is only partially saturated
then we can think of the fissures as containing holes in which a certain
A FREE-BOUNDARY
PROBTXM
3
amount (per volume) of the liquid or gas is trapped and can no longer take
part in the diffusion. Such a diffusion process is formally equivalent to the
preceding heat conduction problem. Finally, we give a weak formulation of
this one-phase Stefan problem for a two-component medium.
Consider the conduction of heat through a heterogeneous medium G c. II:“>
consisting of two components. As our first model for such a process we take
the system of equations in the region 12 = C x (0, co),
I
(I $ - kAt9 + k(8 - w) =./;,
where H and cp arc the temperatures in the first and second components,
respectively. Each is a function of position x E G and time t > 0 and is
obtained at a point x by averaging the temperature of the corresponding
component in a neighborhood which contains a sufficiently large number of
pieces of both components. The constants (I, b are specific heats of the
respective components, k is the conductivity of the lirst, the conductivny of
the second component is normalized to unity, an.d the positive number h is
related to the surface area common to the two components. Thus h is a
measure of the homogeneity of the material. The system (2.1) is just a pair
of classical heat conduction equations together with a linear coupling to
model the simplest cxchangc between components. Our basic assumption
that the lirst component occurs in small parts isolated by the second
component implies that k = 0 in (2.1). That is, the particles of the first.
component may store heat (u > 0) or may exchange with the surrounding
second component (h > 0), but they cannot pass heat directly to other firstcomponent particles (k = 0). This is the sense in which the system (2. E) is
degenerafe ,uar-crbolic.
Suppose there is a solid-liquid phase change in the second component at
the temperature cp= 0. We consider here the (one-phase) situation whereln
(n > 0 everywhere. The region fl is separated into a conducting region IL.,
where CJ>
> 0 and a non-conducting region a,, where ip = 0; these correspond
to completely melted and partially frozen parts, respectively. ‘WC need not
assume that Q, consists exclusively of ice but only that it is a mixture of ice
and water in thermal equilibrium at the melting temperature. At each point
(x, t) of 12 we introduce the fraction of water, ((s, t); note that c E f-Q?) in
R, where I!(.) is the maximal monotone Heaviside graph given by H(.s) == 1
for s > 0, f-f(O) = IO, 11. and M(s) = 0 for s ( 0. The two regions arc
separated at time t by an interface S(l). If we let n be the unit normal on
4
Dl HENEDETTO
AND
SHOWALTER
S(t) directed towards Q, and V be the speed of S(t) along n, then we obtain
the condition
av
-=-LV(l-<)
an
on s(t),
where i-iv/an = V, . n is the heat flux across S(t) and (1 - 5) is the fraction
of ice. Moreover, if N = (N,, N, ,..., N,, N,) denotes the unit normal on the
interface S = U { (S(l), t)}, we find that (2.2) is equivalent to
V,a, . (N, ,..., NJ = LN,( 1 .-- r).
(2.3)
Each of (2.2) and (2.3) is called the interface or free-boundary condition.
It is worthwhile to recall the simple experiment in which one applies a
uniform heat source of intensity F to a unit volume of ice at temperature
q = 0. The temperature remains at zero until L units of heat have been
added. During this period there is a fraction < of water coexisting with the
ice and 5 increases at a constant rate F/L. When all the ice has melted, r = 1
and the temperature (o begins to rise at the rate F/b. The constants L. and b
arc the latent heat and specific heat, respectively. We can summarize the
above by stating that the rate of increase of the internal energy or enthalpJ>
ZI= bq + .Lr is given by F. Later we shall see that not only is enthalpy the
natural variable to determine the state of the process but that it is
mathematically the proper variable by which to describe the evolution of the
process.
We can now formulate our problem. With the notation above we seek a
triple of non-negative real-valued functions I!?,w, l on Q which satisfy the
following:
r
a g
+ h(6r -
cp) =f,
and
t E H(v),
in
R,
(2.5)
b+lp+h(++S,
in
a+,
(2.6)
$+Lv(I-e;)=O
on
S,
P-8 1
rp=o
on
aGx(O,co),
(2.9)
r
A FREE-BOUNDARY
PROBLEM
5
The data consist of the strictly positive numbers U, h, h, I, and the: nonnegative functions f,, Js on R and O,), qo, to on G For which we assume
5,,(x) E WV”C~)) f or all x E G. As before, we have set ~‘2, = {(x. t) E Lb :
q>(?c,t) > 0) and R, = ((x, 1) E D : q~(x, t) = 0). The unknown intcrfacc S
between 0, and a,, is the primary difficulty in the problem.
It is approrpiate to obtain a weak formulation of the problem (2.4)--(2. i 0).
This is necessary cvcn with smooth data because the free boundary S ma)
vary in a discontinuous manner and it is also convenient because it casts the
problem into the form of an evolution equation in Hilbert space. Thus we
first compute i?u/iit ---&I in the sense of distributions on L?. For each te?,t
function ~1E C;:‘(Q) WC obtain
+ !’ WP . (N, ,a”*,N,,,) + USC- 1) N,) V’.
‘S
We have assumed that the interface S and the restrictions of (u and < to 0,
and to s2, are sufficiently smooth to apply Gauss’ theorem. This calculation
shows tha.t
in P’(Q) if and only if (2.6), (2.7) and (2.8) hold. From these remarks we
obtain the following weak or generalized formulation of the two-component
Stefan problem: given T > 0 and the non-negative functions J, . ,f! on .(;! and
6
Dl BENEDETTO
AND
SHOWAI>TIIII
f3,,, v,,,,,to on G with {,, E H(vo), find a non-negative triple of functions which
satisfy
&H ‘(0, T; L’(G)),
(D=(bl+LH)-’
e(o) = 4,
v, E L’(O, T; If;(G)),
(u)
and
40) = b+, -t a,
t’ E H’(0, T; H-‘(G)),
(2.1 1)
in
L*(O, T; L’(G)),
(2.12)
in
f,*(O, T; H-‘(G)),
(2.13)
in
L’(O, T; H,!,(G)),
(2.14)
in
L*(G).
(2.15)
Certainly a smooth solution of (2.1 l)-(2.15) for which the level set S is a
smooth manifold necessarily satisfies (2.4t(2.10).
Remarks. The condition b > 0 arises later in the discussion of properties
of solutions so we briefly indicate the significance of this assumption. The
constant b is a measure of the storage capacity of the second component and
it depends on the type of material and also the percentage present in the
second component. Similarly, the constant L is determined by the type and
percentage of this material in the second component of the medium. The
essential interest here is in the change of phase phenomenon so we are
concerned with the case of a sufficient percentage of the second component
material being present to permit L > 0. The corresponding physically
significant case is that of b > 0; otherwise we would be considering the
unlikely case of a material with positive latent heat of fusion but with null
heat capacity. Neventheless, most of our results to follow are obtained from
the wcakcr assumptions that L > 0 and b > 0.
The type of the problem we have called degenerate parabolic. In the
system of partial differential equations (2.1) with k = 0 it is of interest to
consider the case of b = 0 11, 7 J; one can then reduce it to the single partial
differential equation
which is of pseudo-parabolic type 16, 221. This is distinctly not the case for
the free-boundary problem considered here. An elimination of 0 from (2.12),
(2.13) leads to the evolution equation
(alh)~+$(u+uyl-(nlh)dy?)-dy?=S,+f;+(a/h)~.
(2.16)
:
A FREE-BOUNDARY PROBLEM
The pairs of equations (2.14), (2.16) gives an equation for q which is of
second order in time-derivatives, definitely not pseudo-parabolic unless both
h = 0 and L = 0. Thus. even in the case of h = 0 where the local description
of the problem contains a pseudo-parabolic equation (cf. (2.4) and (2.6) in
rZ,), the fret-boundary problem with I, > 0 is not of this type. Problems
where the phase is dctcrmincd
by the first component can be
pseudoparabolic; see 110, 18 I.
3. EXISTENCE AND UNIQUENESS OF T‘W: WEAK SOLUIION
We shall prove that the weak formulation of the Stcfan problem (2.1 I b(2.15) is well-posed. This will be achieved by showing that the problem
corresponds to an evolution equation whose solutions are determined by a
nonlinear semigroup of contractions and that the generator nf this semigroup
is a subgradicnt operator.
The existence and uniqueness of a gencralizcd solution of the Stcfan
problem is contained in the following.
TI IHC)I<I;M 1. Let u and /I be maximal monotone graphs on /I j x
let j and lc be proper convex lower-semi-contirzuous functions
subgrudients are given by +j = a ’ and 2li =/I’ I. tls,s~r~ze
u,, E L l(G),
“m”) E L ‘(Gj,
v,, E L’(G) n H l(G)>
./; E L2(0, 7-t L2(G))?
11i
and
whose
I<(v,,j E I, ’ (Gj,
.f; E L yo, 7’; ti -- j(G)),
and that the domain ?[,!I is equal to II-?.Then there exists a unique quadrup!e
of’functions which sati@
u E .H’(O, T: L’(G)),
v E H’(0, i’-; H ‘(C)j.
6,E L ‘(0, 7’; L’(G)),
q E L’(O, T; H;,(Gj).
$ -- dy? -t- h(p - 0) ==J1
in
u E u(e),
a.e. in n,
(3.4)
v(0) = v.
a.e. in G.
(3.5)
there is a pair
O,, E l.“(Gj,
q. E H:,(G) f’br which
u(0) = U”,
(a)
(3.1)
l[ in addition
2’ E P(v)
L..‘(O, 7’; H--‘(G)).
(3.3)
8
DI BBNEDE’TTO
AND
SHOWALTER
u(, E u(B,J and v, E /l(tp,,) a.e. in G, and ifs, E H’(0, 7’; L2(G)),f2 E H’(0, T,
H-‘(G)), then
+
SE
E .Lcn(O, T; L*(G)),
0 E L*‘(O, T; L*(G)),
L”“(O, T; H-‘(G)),
cpE L’“(0, T; H:,(G)).
(b) If in addition a(O) 3 0, p(O) 3 0 und each of the functions f, , fi,
u0 and v,, is non-negative, then each of u, v, 8 and q is non-negative.
Prooj
Let V be the product space L’(G) x HA(G) which has the dual
V*=L*(G)xH
‘(G). DefineREY(V,
V*) by
NV) = J(. (4 u, - u*)(v, - v*) -t vu, . Vl!*J,
u = lu, 3U?],
L'= Iv,,u*] E v.
Renorm V with the equivalent norm (&.4(u))‘! so that B : V+ V” is the
corresponding Riesz isomorphism of the Hilbert space V onto its dual. Note
that B is given in Q’(G) in the form
B([u,,u21) = Ih(u,- uz>,
h(u,- u,)-41,
Iu,,&I E v.
Next we consider the function J : V” + 114
U (+c.o } defined by
4~) = j, i (Au ,>+ W2))
if
u,EL’,j(u,)EL’,
4.4
UZEL’nH-‘,
EL’,
otherwise, u = [u,, u2 ) E V’“.
=+a3
From 13, pp. 115, 123 1 we find that J is a proper, convex and lower-semicontinuous function on V”. Furthermore, the subgradient ofJ is determined
as follows:
g E iq.4)
with
g= Ig,,g,l
and
u = Iu, 3u*l
in
I/:‘:
if and only if for some u = IL),, v21 E V we have
g = B(v)
and
VI E au,>?
v2 E ak(u,)
a.e. in G.
These computations are immediate from the corresponding results of 13] on
the components of V”.
A FREE-BOUNDARY
9
PROBLEM
It is useful to characterize U explicitly as a composition of operators in
Q”(G). Thus we define A : V+ V* by A = ICY]: that is,
u EA(o)
with
U- Iu,.u~]
E p
and
z’ = [ 21’, 1!21E C’
if and only if U, E a(~,) and U? E /?(u,) a.e. in 6. (Note that A .- ’ is the
subgradient of J computed from the Banach space V* to its dual Vi:* == k
and YI is the corresponding subgradient of the conjugate of J ( 11 I. j From t,hc
computations above WC have the representation i;J = B 0 R --’ as desired.
Given the subgradient operator t/J on the Hilbert space P, it is well
known 12, 31 that the initial-value problem
qp
$- ijJ(w(t))
a.e.
-f(t),
1 E. IO, T1,
w(0) = I$‘()
has a unique
SE L’(0, T; Pi;)
J’E. H’(0, I’; V”)
remarks, with
SW == I.f;(t),.f:!(r)
(3.6)
solution IV E H’(0, T, V’) whenever w,) E dam(J) and
are given.
Furthermore,
if
HJ(,E dom(&/)
and
then this solution satisfies dw/dt E I;“-(& T: Ye). These
the identifications
iv(t) = lu(t), U(Z)/ E V*, M’,,= Iz;(,, cc,/J and
/O(l), q(l)1 = B -‘(j-(f)
- w’(r)) E A ‘(w(t)),
show that (3.6) is equivalent to (3.1 k(3.5 j and thereby establish all but (b)
of Theorem 1. For the proof of (b) we first change the data as follows: (I)
Set j(s) =,i(O) for s < 0 and leave the values as originally given for s > 0;
thus dam(a) c IO, +a). (ii) Add to p(s) the quantity s for those s < 0 and
leave the values as originally given for s > 0; thus B is strictly monotone on
( .--co, 0 1. Since ug is non-negative the hypotheses of Theorem I still hold so
there is exactly one solution of (3.1b(3.5) with the modified data; WCdenote
it by U, c, 0, w as before. Since the domain of u contains only non-negative
numbers, it follows that 0 > 0. Our plan is to show that the remaining three
functions are non-negative.
Next we consider Eq. (3.3) written with right side M’-t.f, and initial
condition ZJ~being non-negative. This equation is of independent. interest.
LEMMA P. Let A = h -A be the indicled Kiesz map of’ the IIilbert space
H:(G) nto its dual, H ‘(G), und let H ‘(6) hat!e the scalur-product
corresponding to A. Lel y be u maximal monotone graph on 1-tx IFi which
conlnins the origin und whose range is all of IF?.
(a)
The operator A 0 y is maximal
monotone on W’(G)
with rhe
10
domain
DI RENEDETTO
(c E H--’ f-l L’:
AND
SHOWAI,TER
there is u ~1E H:,(G)
with q(x) E y(v(x))
ax.
XEG}.
(b)
1 > 0.
y’C=
(JEH--‘(x):f>O},
then [I-tk4
oy]
‘(C)c-Cforevcry
Prooj: Part (a) follows from Theorem 17 of 131, where it is shown that
A o y is a subgradient on H- ‘(G). To verify (b), let (I -,i-AA 0 v)(v) =f in
H ‘(G) with J> 0. By truncation and regularization we obtain a sequence
j;, E L’(G)n
C”(G)n
C with S,,-J’ in H--‘(G). Since A 0 y is maximal
monotone, the corresponding sequence u,! = [I t AA o 1~1 ‘fl converges to 21
in H-‘(G).
From Proposition 5 of 151 it follows that each II,, E C, so WC
have u E C.
Let F be a maximal monotone operator on a Hilbert space H; let
v,, E dam(F) and fE L’(0, 1’; H). Then there exists a unique Ice& solution
of the initial-value problem 12, p. 64 ]
f + F(v) 3f
on 10,TI,
v(0) = V”.
By a weak solution we mean a uniform limit of strong solutions L’,,
corresponding to data vi and f,, with v G+ vg and j;, --$fin H and L ‘(0, T, Ii),
respectively. This existence result is proved by choosing the sequences above
with each VI; E dam(F) and each f, a step-function with values from the
range of .j- 12, p. 65 1.
LEMMA
2. Let C be a closed cone in H. Ij’ tiOE C, f’(t) E C jtir all
tE IO,?‘], und if[l+AF]-‘(C)cCj
br all A.> 0, then the weak solution ~1
(?f (3.7) satisjies t)(t) E C jbr all t E (0, T].
ProoJ By the preckding remarks it suffices to consider the case of
v,, E dam(F) and a step-function f given on a partition 0 = a, < .a. < a, = T
by f =yi E C on [a,-, , ai). The solution is given inductively by v(0) = vu
and v(f) = Si(t - aJ ~(a,) on [ai-, , ui], where Si is the semigroup generated
-(F - yi).
By
12, Proposition
4.5 ] it suffices to show
by
[T + A.(I; - yi)l ’ (C) c C, for then we have v(t) E C for all I E 10, r1. Thus,
let x= II+A(F-yi)]-‘4
7 with y E C and A > 0. It follows directly that
x = (f + A.F)-’ (Ayi + y). Since AJ!~+ y E C we have x E C and we are done.
To obtain II > 0 in (3.3) we apply Lemma 1 with 1’=/I ’ and then apply
Lemma 2 with F =A o y. Since /? is strictly monotone on (-a, 01 it follows
from (3.4) that rp > 0. Finally, writing u as the sum of its positive and
negative parts, u = u ’ - U-, we obtain, from (3.2),
A FKEE-ROUNDARY
i. I
PROBLEM
Since u and 19have the same sign and /ZCJJ
+J; is nonnegative, the right side
is non-positive so u- = 0. Thus all four of U, L’, 0, q are non-negative. II.
follows that this quadruple is a solution of the original problem without the
modified data. By uniqueness this is the solution of the original problem and
(b) is established.
Remarks. The essential point in the first part of the proof of Theorem i
is to reduce the problem to the evolution equation (3.6) whose solutjon is kiac
pair 1u(r), o(t) 1 of “enthalpy” functions associated with the weak solution. St
is this sense in which enthalpy is the natural variahle for the problem.
For the special case of.f? E L’(O, 7’;,L2(G)) we can give an alternate proof
of part (b) of Theorem 1 as follows. Approximate /3 by a smooth fi, for
which the corresponding solutions [U,,, on] can be shown to be non-negative
by direct L’-estimates on (3.2) and (3.3). Then using methods of 191 we can
let II --t co to obtain the non-negativity of Iu, c 1. Iiowevcr, the proof given
above permits the more general data of the existence result, and we also
obtain the corresponding the corresponding w&known non.-negativity result
for the abstract porous media equation
in H -j(G), where h > 0 and 7 is maximal monotone. We could not find this
result in the literature.
The evolution equation (3.6) is of the form
B ’ is positive self-adjoint and A.-’ is maximal monotone
from a
Hilbert space to its dual. Various generalizations and related equations have
been discussed in 14, 6, 9, 10, 15, 16, 20, 21 1.
wllcrc
4.
BOUNDEDNI’SS
AND CONTINUITY
OF THE
Wt:.?r~ SOLLJTWN
We shall prove that the “temperatures” tl and CJIin the weak solution are
bounded when the data in the problem are bounded. WC also give sufficient
conditions for 0 and C+J
to be continuous. These results arc obtained in the
following special case of Theorem 1 which contains the weak formulation of
the one-phase two-component Stcfan problem.
‘rIIEOREM
lhe following:
2. In addition to the conditions qf ‘I%rorem I(b) M’IZ~SSLMC
12
DI BENEDETTO
AND
SHOWALTER
(i)
(ii)
There is a number a > 0 such that r > as for all r E a(s);
(iii)
the initial data and forcing terms are essentially bounded: Us,,
and.f, ,.f, E L “(0). Then the functions u, v, I!?,v are bounded on
the maximal monotone /I is of the form ,9 = bI + LH, where I is
the identity, H is the Heaviside graph and both b and L are non-negative;
v,, E L”‘(G)
R.
(a) If in addition we have (rl - r,l > a Is, --’ s2/ for all r, E a(~,)
and rz E a(q), and if the functions u0 and lif,(., t) dt are un[formly
(H6lder) continuous on G, then 8 is uniformly (respective!y. Hiilder)
continuous on 0.
(b) J7 b > 0 and q,, is uniformly
un[formly continuous on D.
continuous
on G. then cp is
Let u, v, 8, ~0be the solution of (3. I )-(3.5); by assumption (ii) we
Prooj
may write ZI= brp -I- L<, <E H(p), in a. For each c > 0 we consider the
Steklov averages
where q and 19are extended as y(O), e(O), respectively, on (--6, 0). It is
known that lim,.+, qC= q (etc.) in L’(0, T, H:(G)) 114,p. 85 1.By integrating
(3.3) over [t _- C,t 1 we obtain
= ho,(t) + (l/c) [’ f;(s) ds.
“f--C
We shall apply this to (q(f) - k)’ , integrate over (0, f) x G where the
superscript plus denotes the positive part of the indicated function in H:,(G)
and the number k is chosen by
k = Max Ilq+llr,d~cG,;
+ II~~11~~~~~)
+ $ (IIf, lIr.,ha,rjj
+ 2 IlhlLd(
-
and take the limit as c 1 0. To this end we obtain
.I
d(t)W) - k)+ = i IlW) - k) ’ /I:,w;)-- t lib+,-..-k) ’ ll:w;,
0 ci
limR--0JJ
and the last term vanishes since k > )/v. l)r,2(C;j:
(r(t) - at - e)NP(t) - k) + > (T(t) -- lNPW - w ‘- = 0
A FREE-BOUNDARY
since k > 0 and T(r) E
H(q(fj);
PROBLEM
and
_. f’ [ (h I(u, -- k)’ 1’ $- h&p-k)
-0-c;
’ +- lV(ci, .-- k)
1’)”
Thus we obtain
‘This leads immediately to the estimate
k j’ j (q - k) -‘- t j; I,; /(p -- k) ’ /’
0 c;
Next we estimate the first term on the right side of (4.1). integrate (3.2)
over (0, I) and use (i) and 0 > 0 to obtain
(4.2,)
From (4.2) it easily follows that
NOW apply this to (q~--. k) ’ and integrate to obtain
.I .
14
Dl BENEDETTO
AND SHOWALTER
Note that
so we have from above
j’ j O(cp
-- k)’ &J:
0G
II@- kc+Il:‘(G,
If we use (4.3) in (4.1) we obtain
Thus, if 0 < I < a/2h, then by our choice of k the right side is non-positive
and the left side is necessarily zero.
In summary, we have shown that with k as given above we have
for a.c. I E [0, a/2h I. The first is immediate from our preceding calculations,
the second follows from (4.2) and the third is obtained from (4.2) and
Gronwall’s inequality. From the dependence of k on the data it is clear that
the estimates (4.4) on G x (0. u/2h) can be extended to give a bound on u, 0
and q on all of Q in a finite number of steps.
In order to prove (a) we first consider the functions
@,(x,0 = j-i rp(x,s) ds,
0(x, 2)= j' 0(.x,s) ds.
0
A FREE-BOKJNDARY
PROHLEM
Integrate (3.3) to see that @ is a weak solution of
Tf h > 0 then from 114, Theorem 1.1, p” 419 / wc conclude that @ is
uniformly Hdlder continuous on 0. If b = 0 then from 113, Theorem 14.1,
p. 201 1 WC conclude that @ is uniformly Hijlder continuous on G, unifurmi!;
in t E 10, 7’1. Since cpis bounded, Q, is trivially Lipschitz in t. Thus it foiknvs
that @ is uniformly HGlder continuous on R.
Next we integrate (3.2) to get
u(x, I) + j; h(O(x, s) -- cp(x, s)) ds -= f’/;(x:
-0
s) ds -I- u,,(x).
By taking the difference of this identity at x = .Y, , .x2 E G we obta.in
- @(x2.t - j”.f,(.Y,,s) ds -- U(,(XJ.
. (I
(45j
Ry our assumptions in (a) the left side of (4.5) bounds the quantity
a / B(x, , t) - 0(x7, t)l and the function
has a modulus of continuity
have
a(.) which is independent of I E 10, 7’1, so we
a I@, , t) -- 0(x, ) t)l < h 1’ I@, , s) - H(.x2, s)l ds + IS(X, -- x>)~
a0
By Gronwall’s inequality it follows that 19 has the same tr~od~~lus
of
continuity, cr. in X. From (3.2) follows the uniform Lipschitz continuity in i
of u and then the assumption in (a) shows that 0 is uniformly Lipschitz in 1.
This finishes the proof of (a).
16
DIBENEDETTO
AND SHOWALTER
The proof of (b) is an immediate corollary of [S, Theore 5.3, p. 691. The
point is that q is an essentially bounded weak solution of
with +/at
p. 501 I.
E L’(B).
This last inclusion follows from b > 0; see [9 1 or 114,
Remarks. The boundary aG of the region G is assumed to satisfy
‘Condition A” of 1131 in both (a) and (b) of Theorem 2. That is, there is a
pair of positive numbers a, and 8, such that for any sphere B,. with center on
i!G of radius Y < u,, and for any component 6, of the intersection
G,. = B,n G it follows that mes(G,.) < (1 - 0,) mes(B,). Without such a
restriction on the smootness of the boundary of G we obtain local or interior
continuity results as above.
It is not known whether cp is continuous in Q in the case h = 0.
5. ADDITIONAL
PROPERTIES OF THE WEAK SOLUTION
Under rather general conditions on the data in the weak formulation of
our problem it follows that the positivity set of the enthalpy u is increasing
with time. This is equal to the positivity set of the temperature ql. An
example shows this containment may be proper.
The preceding properties of the weak solution will be obtained in part
from the following comparison result.
LEMMA 3. Suppose t, < I’ and for each 1E It,,, TI we are given a pair
y,(t, a), y,(t, a) oJgraphs on R X r? such that y2(t, .) is monotone and
for each s, E y,(t, r) there exists an s2E yz(t, r) for which
s,<s,.
(5.1)
Let the pair of absolutely continuous functions u, , u2 : It,,, T] + IIi satisjj~
ul(b) G u2(~d and
for a.e. 1E It,,, T]. Then u,(t) < u2(t) for I, < t < T.
ProoJ: Suppose there is a t2 E (t,, T] such that u&&> u2(t2). Define
I, = lubjl E [t,, T] : u,(t) < u,(t)} and note that u,(t,) = u,(t,) and u,(t) >
u2(t) for all I E It,, t,l. For each t E [li, 1,1 for which -u:(t) E y,(t, u,(t))
A FREE-BOUNDARY
i 7
PRODI.EM
there is by (5.1) an s(f) E I’~(& U,(I)) with s(l) < ---u;(t). For SLICII a E WC
obtain
04(l) - G(t>>tu,(t)- u,(t)) < (44 -- M)>(~~,@)- U*!f))
and this last quantity is non-positive because ~~(1,.) is monotone. Thus the
function (u,(tj -- u,(t))* has a non-positive derivative on [r,. f2 1. it therefore
vanishes on It,, f?] and this contradicts the choice of tz.
Suppose we are in the situation of Theorem l(b). For a.e. x’ E G the
function uz(l) E U(X, t) is an absolutely continuous solution of (3.2). In order
to apply Lemma 3 to (3.2), (3.4), define
)qt, 11)= ha -I(u) ---hrp(x.1) --./;(x,rj.
y,(l? 24)= (h/a) u + -ji(X, t),
WC will assume u > 0 and that
for each r > 0 there exists an s E LT ‘(Y) such that US < r.
(5.2)
This implies that (5.1) holds for our choice of y,, y:. L.et U, be the solution
of
g(t) + (h/a) u,(t) =J;(A 0,
with ~,(t,,) = U(X, t,,). From
following.
0 < t ,< 7;
Lemma 3 we obtain the first part of the
THEOREM3. Jtz addition to the conditions of 7’heorern J(b) hl!e MSLU~~
there is UN a > 0 j’or which (5.2) holds. Therz the ,first component q,f’ the
solulio~z qf’ (3.1 t(3.5) satiA$es
qx,
1) > e- (h:o)lr-
f,,l , u(x,
t,,) i- if
“‘fi(,.c, s) ds,
e-- I!~.‘~l~~f-10
0 < t,, < t < 7;
(5.3)
for almost every x E G. Thus the set S,?(u) E (x E G : u(x, E) > O} is
increasing with t. Furthermore? the set S ‘(u) z {(x, t) E Q : u(x, t) > 0 j
contains the interior of S ’ (f,) and
u{S~-(ql):O<t<l,}C1S,~(U),
O<l,<T.
(S.4)
Prooj: The inequality (5.3) follows from the preceding remarks and it
immediately implies the monotonicity of Si (u) and the inclusion of the
interior of S ‘-(s,) in S’(U). We verify (5.4). Let x1 G?S,‘,(U), that is..
for all O< t<:~,. ‘Thus
u(xI, t,)=:O, so by (5.3) we have u(x,, t)=O
iiu(x,, /)/at = 0 for 0 < t < 1,. From (5.2) we obtain (see below) 0(x,, t) =: 0
18
DIBENEDETTO
for 0 < I < t, so (3.2) implies &,
for all 0 < t < 1,.
COROLLARY.
Proof.
AND SHOWALTEH
, t) = 0 for 0 < t < t,. That is, x, & S:(q)
In the situation qf Theorem 2(b) M’e have S+(rpj c S ’ (u).
Since v, is continuous this follows from (5.4).
Remarks. The condition (5.2) is actually equivalent to the assumption (i)
in Theorem 2: r > as for all (s, r) E 0~.To see this, note that if (so, r,)) E u
with r,, < as,, then we can choose r, = (1/2)(r0 + as,J > 0 and from (5.2) a
s, with (s,,r,)Ea
and as,<r,.
But then s, < (1/2)(r,,/a + s,J < sg and
contradicting
the
monotonicity
of LT.Thus (5.2) implies that. all of (1
rl > ro,
lies above the graph of r = as.
As a consequence of the above remark it follows from (3.4) that U(X, t) >
a@, I), hence S l.(0) c S+(U). If in addition we have a(O) = (O}, then
s k (fq = s+ (2.4).
In the case of our original problem, (2.1 lb(2.15),
we have S ’ (q) c
S ’ (8): Thus 6, > 0 in the region Q+ where the water is completely melted.
The following
example shows that we do not necessarily have
s+((o)=s’(e).
Define B(t) = em.‘, a, = 0 and v(f) = 1 - em-’ for t > 0. This
EXAMPLE.
triple of non-negative functions is the solution of (2.11) - (2.15) with
L=a=h=
1 and arbitrary b>O,f,=f,=O,
and BO= I, ~o=<o=O. This
solution is independent of x E G. In the thermal conduction model of
Section 2, this example corresponds to the situation wherein a small amount
of heat uniformly distributed in the first component is all absorbed as latent
heat to convert the second component from solid ice to water at temperature
equal to zero.
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