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Given f (x) = √ x 4 + 1 = (x 4 + 1) 1/2 , we have f (x) = 2x 3 (x 4 + 1) −1/2. Thus, f (4x) dx = 1 4 f (4x) + C = 1 4 {2(4x) 3 [(4x) 4 + 1] −1/2 } + C = 32x 3 √ 256x 4 + 1 + C.
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