Electronic Journal of Graph Theory and Applications 11 (1) (2023), 49–64
On (F, H)-sim-magic labelings of graphs
Yeva Fadhilah Asharia , A.N.M. Salmana,b , Rinovia Simanjuntak∗,a,b ,
Andrea Semaničová-Feňovčı́kovác , Martin Bačac
Combinatorial Mathematics Research Group, Faculty of Mathematics and Natural Sciences,
Institut Teknologi Bandung, Indonesia
b Center for Research Collaboration on Graph Theory and Combinatorics, Indonesia
c Department of Applied Mathematics and Informatics, Technical University in Košice, Slovakia
a
[email protected],
[email protected],
[email protected],
[email protected],
[email protected]
∗ corresponding author
Abstract
A simple graph G(V, E) admits an H-covering if every edge in G belongs to a subgraph of G
isomorphic to H. In this case, G is called H-magic if there exists a bijective function f : V ∪
E → {1, 2, . . . , |VP| + |E|}, such that for every subgraph H ′ of G isomorphic to H, wtf (H ′ ) =
P
e∈E(H ′ ) f (e) is constant. Moreover, G is called H-supermagic if f : V (G) →
v∈V (H ′ ) f (v) +
{1, 2, . . . , |V |}. This paper generalizes the previous labeling by introducing the (F, H)-sim-(super)
magic labeling. A graph admitting an F -covering and an H-covering is called (F, H)-sim-(super)
magic if there exists a function f that is F -(super)magic and H-(super)magic at the same time.
We consider such labelings for two product graphs: the join product and the Cartesian product. In
particular, we establish a sufficient condition for the join product G + H to be (K2 + H, 2K2 + H)sim-supermagic and show that the Cartesian product G × K2 is (C4 , H)-sim-supermagic, for H
isomorphic to a ladder or an even cycle. Moreover, we also present a connection between an
α-labeling of a tree T and a (C4 , C6 )-sim-supermagic labeling of the Cartesian product T × K2 .
Keywords: H-covering, H-(super)magic, (F, H)-sim-(super)magic, join product, Cartesian product
Mathematics Subject Classification: 05C70, 05C76, 05C78
DOI: 10.5614/ejgta.2023.11.1.5
Received: 2 July 2022,
Revised: 6 January 2023,
Accepted: 4 February 2023.
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1. Introduction
The graphs considered in this paper are finite and simple. Let G be a graph, with the vertex
set V (G) and the edge set E(G). The cardinalities of V (G) and E(G) are called the order and the
size of G, respectively. A labeling f of G is a map that assigns certain elements of G to positive
or non-negative integers. In this paper, we consider a total labeling of G as a bijective function
f : V (G) ∪ E(G) → {1, 2, . . . , |V (G)|
P + |E(G)|}. Under a total labeling f , the weight of a
vertex v ∈ V (G) is wtf (v) = f (v) + vw∈E(G) f (vw) and the weight of an edge vw ∈ E(G) is
wtf (vw) = f (v) + f (vw) + f (w).
Simanjuntak et al. [27] introduced an (a, d)-edge-antimagic total labeling ((a, d)-EAT) as a
total labeling f where the set of edge-weights {wtf (vw)|vw ∈ E(G)} constitutes a set of an
arithmetic progression {a, a + d, . . . , a + (|E(G)| − 1)d} for two integers a > 0 and d ≥ 0.
When d = 0, the (a, 0)-edge(vertex)-antimagic labeling was previously known as the edge-magic
total labeling (EMT) and was introduced by Kotzig and Rosa [15] in 1970. When G has EMT
or (a, d)-EAT labelings and the corresponding f labeling has the property f (V (G)) = {1, 2, . . . ,
|V (G)|}, we say that G is super edge-magic total (SEMT) or super (a, d)-edge-antimagic total
((a, d)-SEAT), respectively.
Another variation of magic labeling called vertex-magic total labeling was introduced by MacDougal et al. [17]. A vertex-magic total labeling (VMT) of G is a total labeling where there exists
a positive integer k such that the vertex-weight wtf (v) = k for every vertex v of G. If
{wtf (v)|v ∈ V (G)} = {a, a + d, . . . , a + (|V (G)| − 1)d} for two integers a > 0 and d ≥ 0, the labeling f of G is called (a, d)-vertex-antimagic total labeling ((a, d)-VAT), that was first introduced
by Bača et al. [3]. Comprehensive surveys about the existence of magic and antimagic graphs can
be found in [4, 5, 11, 29].
In 2005, as an extension of the edge-magic total labeling, Gutiérez and Lladó [12] introduced an
H-magic labeling of a graph. A graph G admits an H-covering if every edge in E(G) belongs to a
subgraph of G isomorphic to a given graph H. A total labeling
f of G is an
PH-magic labeling
P
f
(v)
+
if there exists a positive integer k such that wt(H ′ ) =
e∈E(H ′ ) f (e) = k
v∈V (H ′ )
′
for every subgraph H of G isomorphic to H. In this case, G is called an H-magic graph. If
f (V ) = {1, 2, . . . , |V (G)|}, then G is said to be an H-supermagic graph. Current results on
H-magic labelings can be seen in the survey [11].
In 2005, Exoo et al. [9] asked whether there exists a labeling of a graph that is simultaneously
vertex-magic and edge-magic and called such labeling totally magic. Subsequently, in 2005, Bača
et al. [6] extended a similar question for (a, d)-EAT labeling and (a, d)-VAT labelings; and defined
the totally antimagic total (TAT) labeling.
Motivated by the two notions above, it is interesting to ask a similar question by considering the
subgraph covering in G. Suppose that G simultaneously admits an F -covering and an H-covering.
We propose a new notion of a labeling called an (F, H)-sim-magic labeling as a bijective function
f : V (G) ∪ E(G) → {1, 2, . . . , |V (G)| + |E(G)|} where there exist two positive integers kF and
kH (not necessarily the same) such that
X
X
wtf (F ′ ) =
f (v) +
f (e) = kF
v∈V (F ′ )
e∈E(F ′ )
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On (F, H)-simultaneously-magic labelings of graphs
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and
wtf (H ′ ) =
X
f (v) +
v∈V (H ′ )
X
f (e) = kH ,
e∈E(H ′ )
for each subgraph F ′ of G isomorphic to F and each subgraph H ′ of G isomorphic to H. We
say that G is (F, H)-sim-magic. Furthermore, if f (V (G)) = {1, 2, . . . , |V (G)|}, G is said to be
(F, H)-sim-supermagic.
The simplest example of a (F, H)-sim-magic graph can be deduced from previously known
H-magic labelings. For odd m and n at least three, the disjoint union of m cycles mCn is both
SEMT [10] and Cn -supermagic [1, 18]. Although the Cn -supermagic labelings described in [1, 18]
are not SEMT, the SEMT labeling of 3C3 described in [10] is also C3 -supermagic (see Figure 1).
This implies that 3C3 is (K2 , C3 )-sim-supermagic.
Figure 1. A (K2 , C3 )-sim-supermagic graph.
An interesting fact for (F, H)-sim-magic labeling is that although a graph is both F -magic and
H-magic, such a graph does not need to be (F, H)-sim-magic. An example is the fan Fn with
vertex-set V (Fn ) = {vi |0 ≤ i ≤ n} and edge-set E(Fn ) = {vi vi+1 |1 ≤ i ≤ n − 1} ∪ {v0 vi |1 ≤
i ≤ n}. It is known that, for every n ≥ 3, Fn is EMT (see [28]) and C3 -supermagic (see [21]).
However, for every n ≥ 3, Fn is not (K2 , C3 )-sim-magic as stated in the following theorem.
Theorem 1.1. Let n ≥ 3 be a positive integer. A fan Fn is not (K2 , C3 )-sim-magic.
Proof. Suppose that Fn is a (K2 , C3 )-sim-magic graph and let f be a (K2 , C3 )-sim-magic labeling
of Fn with a magic constant pair (k1 , k2 ). Consider the weights of two C3 cycles v0 v1 , v1 v2 , v2 v0
and v0 v2 , v2 v3 , v3 v0 . As these weights are equal, we have
2
X
f (vi ) + f (v0 v1 ) + f (v1 v2 ) + f (v2 v0 ) =
i=0
3
X
f (vi ) + f (v0 v2 ) + f (v2 v3 ) + f (v3 v0 ),
i=1
and so
f (v1 ) + f (v1 v0 ) + f (v1 v2 ) = f (v3 ) + f (v2 v3 ) + f (v0 v3 ).
(1)
Adding f (v0 ) to both sides of Equation (1) and using the fact that all edges have the same edge
weight, we obtain f (v1 v2 ) = f (v2 v3 ), a contradiction.
In this paper, we study simultaneous labelings for two product graphs: the join product and
Cartesian product graphs. In particular, we investigate a sufficient condition for the join product
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graph G + H to be (K2 + H, 2K2 + H)-sim-supermagic (Section 3). We construct (C4 , H)-simsupermagic labelings for the Cartesian product G × K2 , where H is isomorphic to a ladder or an
even cycle (Section 4). Finally, in the last section, we provide relationships between an α-labeling
of a tree T and a (C4 , C6 )-sim-supermagic labeling of the Cartesian product T × K2 .
Throughout the paper, we shall use the following definitions and notations. The degree of a
vertex v is denoted by deg(v). For a connected graph H, a graph G is H-free if G does not contain
H as a subgraph. Notations for some classes of graphs can be seen in Table 1.
Table 1. Classes of graphs
Notation
Cn
Kn
K1,n
Pn
Sn1 ,n2 ,...,nk
Notes
A cycle on n vertices, n ≥ 3.
A complete graph on n vertices, n ≥ 1.
A star with one internal vertex and n leaves, n ≥ 2.
A path on n vertices, n ≥ 2.
A caterpillar is a graph derived from a path Pk , k ≥ 2, where
for i ∈ {1, 2, ..., k}, each vi ∈ V (Pk ) is adjacent to ni ≥ 0 additional leaves.
2. Balanced and Anti Balanced Multisets
A multiset is a generalization of a set where repetition of elements is allowed. Let a and b be
two integers. We use the notation [a, b] to define the set of consecutive integers {a, a + 1, . . . , b}.
So [a, b] = ∅, if a > b. For an integer
k, thePaddition k + [a, b] means [a + k, b + k] and for a
P
multiset of integers Y , we denote x∈Y x by Y . Let x be an element of a multiset Y . Then, the
multiplicity of x, denoted by U
mY (x), is the number of occurrences of x in Y . Let X and Y be two
multisets. AU
multiset sum X Y is a union of X and Y , where mX U Y (x)
U = mX (x) + mY (x) for
each x ∈ X Y . For example, if X = {a} and Y = {a, a, b}, then, X Y = {a, a, a, b}.
We shall utilize the notions of a k-balanced partition of a multiset introduced by Maryati et
al. [19] and a (k, δ)-anti balanced partition of a multiset introduced by Inayah et al. [13] to construct labelings in Sections 3 and 4. Let k and δ be two positive integers, and X be a multiset
containing positive integers. X is said to be (k, δ)-anti balanced if there exist k subsets of X, say
U
, ki=1 Xi = X, and for each i ∈ [1, k−1],
X 1 , X2 , . . . P
, Xk , such that for every i ∈ [1, k], |Xi | = |X|
k
P
Xi+1 − Xi = δ. For every i ∈ [1, k], Xi is called
P a (k, δ)-anti balanced subset of X. In the
case that there exists a positive integer θ such that Xi = θ for every i ∈ [1, k], then X is called
k-balanced with Xi s as k-balanced subsets of X.
Lemma 2.1. [18] Let x, y, and k be three integers, where 1 ≤ x < y and k > 1. If X = [x, y] and
P
(x + y) for every i ∈ [1, k].
|X| is a multiple of 2k, then X is k-balanced with Xi = |X|
2k
Lemma 2.2. Let x and k be positive integers, k ≥ 2. If
(
[x, x + 2k − 1],
for odd k;
X=
k
[x, x + 2k] \ {x + 2 }, for even k,
P
then X is (k, 1)-anti balanced with Xi = 2x + i + 3 k2 for every i ∈ [1, k].
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On (F, H)-simultaneously-magic labelings of graphs
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Y.F. Ashari et al.
+ 2(1 − (i mod 2)) k2
Proof. For each i ∈ [1, k], define Xi = {ai , bi }, where ai = x − 1 + i+1
2
k i
k
Uk
i
and
b
=
x
+
+
+
2(i
mod
2)
.
Thus,
i=1 X
2
2
2
P
P
Pi = X and we have |Xi | = 2 and
k
Xi = 2x + i + 3 2 for each i ∈ [1, k]. Since Xi+1 − Xi = 1 for every i ∈ [1, k − 1], X
is a (k, 1)-anti balanced.
Lemma 2.3. Let
Px and k be positive integers, k ≥ 2. If X = [x, x + 2k − 1], then X is (k, 2)-anti
balanced with Xi = 2(x + i − 1) + k for every i ∈ [1, k].
Uk
Proof.
P Define Xi = {x − 1 + i, x + i + k − 1} for each i ∈ [1, k]. Hence, i=1 Xi = X, |Xi | = 2,
and
Xi =
P
P 2(x + i − 1) + k for every i ∈ [1, k]. We have that X is (k, 2)-anti balanced since
Xi+1 − Xi = 2 for every i ∈ [1, k − 1].
3. Labelings for Join Product Graphs
Let G ∪ H denote the disjoint union of G and H. Then, the join product G + H of two disjoint
graphs G and H is the graph G ∪ H together with all the edges joining vertices of G and vertices
of H. The study of H-magicness of join product graphs has been conducted for some particular
families of graphs, as summarized in Table 2.
Table 2. Known join product graphs which are H-magic
Join product
P n + K1 , n ≥ 3
Cn + K1 , n odd, n ≥ 5
n even, n ≥ 4
C n + K1 , n ≥ 3
K1,n + K1 , n ≥ 3
nK2 + K1 , n ≥ 2
H
C3
C4
C3
C3
C4
C3
C3
Reference
Ngurah et al. [21] and Ovais et al. [22]
Ovais et al. [22]
Lladó and Moragas [16]
Roswitha et al. [25]
Semaničová-Feňovčı́ková et al. [26]
Ngurah et al. [21]
Lladó and Moragas [16]
The following theorem provides a sufficient condition for the join product graph G + H to be
(K2 + H, 2K2 + H)-sim-supermagic.
Theorem 3.1. Let G and H be two connected graphs such that G admits a 2K2 -covering and
G + H contains exactly |E(G)| subgraphs isomorphic to K2 + H. If G is SEMT, then G + H is
(K2 + H, 2K2 + H)-sim-supermagic.
Proof. Let g be a super edge-magic total (SEMT) labeling of G with the magic constant mg . Let
V (G) = {vi |vi = g −1 (i) and i ∈ [1, p]}, V (H) = {ui |i ∈ [1, r]}, E(G) = {ei |i ∈ [1, q]}, and
E(H) = {ki |i ∈ [1, s]}. Hence, |V (G)| = p, |E(G)| = q, |V (H)| = r, |E(H)| = s. Thus,
V (G + H) = V (G) ∪ V (H) and E(G + H) = E(G) ∪ E(H) ∪ {ui vj |i ∈ [1, r] and j ∈ [1, p]}.
Consider Y = [1, p + q + r + s + p r] as the set of all labels of vertices and edges in G + H.
Then, we divide the proof into three cases.
Case 1. r is even.
Partition Y into five subsets, namely A = [1, r], B = r +[1, p], C = (r +p)+[1, p r], D = (r +p+
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On (F, H)-simultaneously-magic labelings of graphs
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p r)+[1, q] and E = (r+p+p r+q)+[1,
r is even, |C| is a multiple of 2p. By Lemma 2.1,
P s]. Since
pr
we have that C is p-balanced with Ci = 2p (r + p + 1 + r + p + pr) = 21 r(p(r + 2) + 2r + 1)
for each i ∈ [1, p].
Next, label the vertices and edges in G+H by total labeling f as defined in the following steps.
For each i ∈ [1, r], f (ui ) = i.
For each i ∈ [1, p], f (vi ) = i + r.
For each j ∈ [1, p] and i ∈ [1, r], f (ui vj ) = mi , where mi ∈ Cj .
For each ei ∈ E(G) and i ∈ [1, q], f (ei ) = g(ei ) + r + pr.
For each ki ∈ E(H) and i ∈ [1, s], f (ki ) = mi , where mi ∈ E and no two distinct edges in
E(H) are assigned the same number.
S
S
S
Thus, we get ri=1 {f (ui )} = A, pi=1 {f (vi )} = B, pj=1 {f (ui vj )|i ∈ [1, r]} = C, {f (vi vj )|vi vj ∈
E(G)} = D, and {f (ui uj )|ui uj ∈ E(H)} = E. Clearly, f is a bijective function from V (G +
H) ∪ E(G + H) to Y .
Let F be a subgraph of G + H isomorphic to K2 + H. It is clear that F contains exactly
one edge of E(G), say vx vy for some distinct x, y ∈ [1, p]. Then, V (F ) = V (H) ∪ {vx , vy } and
E(F ) = E(H) ∪ {vx vy } ∪ {ui vj |j ∈ {x, y}, i ∈ [1, r]}. Thus,
1.
2.
3.
4.
5.
wtf (F ) =
r
X
f (ui ) + f (vx ) + f (vy ) +
i=1
X
f (e) + f (vx vy ) +
[f (ui vx ) + f (ui vy )]
i=1
e∈E(H)
= [g(vx ) + g(vy ) + g(vx vy )] + 3r + pr +
r
X
1
r(r
2
+ 1) + s(r + p + pr + q) +
s
X
i
i=1
+r(p(r + 2) + 2r + 1).
Since [g(vx ) + g(vy ) + g(vx vy )] = mg , we see that wtf (F ) is independent of F .
Now, let F ′ be a subgraph of G + H isomorphic to 2K2 + H. It is clear that F ′ contains
two
P
P
non-adjacent edges of E(G). Then, wtf (F ′ ) = 2wtf (F ) −
e∈E(H) f (e) . So,
u∈V (H) f (u) +
′
′
wtf (F ) is independent of F .
Case 2. r is odd and p is odd.
Partition Y into five subsets, namely A = [1, r], B = r + [1, 2p], C = (r + 2p) + [1, p(r − 1)],
D = (r + p +P
p r) + [1, q], and E = (r + p + p r + q) + [1, s]. By Lemma 2.2, B is (p, 1)-anti
balanced with Bi = 2(r + 1) + 3 p2 +Pi for every i ∈ [1, p]. Since g is an injective function,
g −1 (i) = vi for every i ∈ [1, p]. This gives Bi = 2(r + 1) + 3⌊ p2 ⌋ + i = 2(r + 1) + 3⌊ p2 ⌋ + g(vi )
for every i ∈ [1, p]. The cardinality of C is a multiple of 2p. By Lemma 2.1, C is p-balanced with
P
(r + 2p + 1 + r + 2p + p(r − 1)) = 12 (r − 1)(2r + 3p + pr + 1) for every i ∈ [1, p].
Ci = p(r−1)
2p
Next, label the vertices and edges in G+H by total labeling f as defined in the following steps.
1. For each i ∈ [1, r], f (ui ) = i.
2. For each i ∈ [1, p], f (vi ) = min{x|x ∈ Bi }.
3. For each i ∈ [1, p], f (u1 vi ) = bi , where bi ∈ Bi \ {f (vi )}.
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4. For each j ∈ [1, p] and i ∈ [2, r], f (ui vj ) = mi , where mi ∈ Cj .
5. For each ei ∈ E(G) and i ∈ [1, q], f (ei ) = g(ei ) + r + pr.
6. For each ki ∈ E(H) and i ∈ [1, s], ki = mi , where mi ∈ E and no two distinct edges are
assigned the same number.
S
S
S
Thus, we get ri=1 {f (ui )} = A, pi=1 {f (vi ), f (u1 vi )} = B, pj=1 {f (ui vj )| i ∈ [2, r]} = C,
{f (vi vj )|vi vj ∈ E(G)} = D, and {f (ui uj )|ui uj ∈ E(H)} = E. Clearly, f is a bijective function
from V (G + H) ∪ E(G + H) to Y .
Let F be a subgraph of G + H isomorphic to K2 + H. It is clear that F contains exactly
one edge of E(G), say vx vy for some distinct x, y ∈ [1, p]. Then, V (F ) = V (H) ∪ {vx , vy } and
E(F ) = E(H) ∪ {vx vy } ∪ {ui vj |j ∈ {x, y}, i ∈ [1, r]}. Thus,
wtf (F ) =
r
X
i=1
f (ui ) + f (vx ) + f (vy ) +
X
e∈E(H)
f (e) + f (vx vy ) +
r
X
[f (ui vx ) + f (ui vy )]
i=1
= [g(vx ) + g(vy ) + g(vx vy )] + 4(r + 1) + 6 p2 + r + pr + 21 r(r + 1)
+s(r + p + pr + q) + 12 s(s + 1) + (r − 1)(2r + 3p + pr + 1).
Since [g(vx ) + g(vy ) + g(vx vy )] = mg , we see that wtf (F ) is independent on the choosing of F .
Now, let F ′ be a subgraph of G + H isomorphic to 2K2 + H. It is clear that F ′ contains
two
P
P
′
non-adjacent edges of E(G). Thus, wtf (F ) = 2wtf (F ) −
e∈E(H) f (e) . So,
v∈V (H) f (v) +
wtf (F ′ ) is independent of F ′ .
Case 3. r is odd and p is even.
Partition Y into five subsets, A = [1, r − 1] ∪ {r + p2 }, B = [r, r + 2p] \ {r + p2 }, C = (r + 2p) +
[1, p (r − 1)], D = (r + pP
+ p r) + [1, q], and E = (r + p + pr + q) + [1, s]. By Lemma 2.2, B is
p
⌋ for each i ∈ [1, p]. Since g is an injective function,
(p, 1)-anti balanced with Bi = 2r + i + 3⌊
2
P
−1
g (i) = vi for every i ∈ [1, p]. Therefore, Bi = 2r + 3⌊ p2 ⌋ + i = 2r + 3⌊ p2 ⌋ + g(vi ) for every
i ∈ [1, p].
Now,
of C is a multiple of 2p. By Lemma 2.1, we have that C is p-balanced
P the cardinality
p(r−1)
with Ci = 2p (r + 2p + 1 + r + 2p + pr) = 21 (r − 1)(2r + 3p + pr + 1) for every i ∈ [1, p].
Next, label the vertices and edges in G + H by the total labeling f defined in the following
steps.
For each i ∈ [2, r], f (ui ) = i − 1, and f (u1 ) = r + p2 .
For each i ∈ [1, p], f (vi ) = min{x|x ∈ Bi }.
For each i ∈ [1, p], f (u1 vi ) = bi , where bi ∈ Bi \ {f (vi )}.
For each j ∈ [1, p] and i ∈ [2, r], f (ui vj ) = mi , where mi ∈ Cj .
For each ei ∈ E(G) and i ∈ [1, q], f (ei ) = g(ei ) + r + pr.
For each ki ∈ E(H) and i ∈ [1, s], f (ki ) = mi , where mi ∈ E and no two distinct edges are
assigned the same number.
S
S
S
Then, ri=1 {f (ui )} = A, pi=1 {f (vi ), f (u1 vi )} = B, pj=1 {f (ui vj )|i ∈ [2, r]} = C, {f (vi vj )|vi vj ∈
E(G + H)} = D and {f (ui uj )|ui uj ∈ E(G + H)} = E. Clearly, f is a bijective function from
V (G + H) ∪ E(G + H) to Y .
1.
2.
3.
4.
5.
6.
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Let F be a subgraph of G + H isomorphic to K2 + H. Then F contains exactly one edge of
E(G), say vx vy for some distinct x, y ∈ [1, p]. Then, F has the form V (F ) = V (H) ∪ {vx , vy }
and E(F ) = E(H) ∪ {vx vy } ∪ {ui vj |j ∈ {x, y}, i ∈ [1, r]}. Thus,
wtf (F ) =
r
X
f (ui ) + f (vx ) + f (vy ) +
i=1
= [g(vx ) + g(vy ) + g(vx vy )] +
X
e∈E(H)
r
X
i+
i=2
+2r2 + rs + qs + 4r.
f (e) + f (vx vy ) +
r
X
f (ui vx ) +
i=1
s
X
r
X
f (ui vy )
i=1
i + p r2 + r(s + 3) + s −
i=1
5
2
+6
p
2
Since [g(vx ) + g(vy ) + g(vx vy )] = mg , we see that wtf (F ) is independent on the choosing of F .
′
Now, let F ′ be a subgraph of G + H isomorphic
P to 2K2 + H.PF contains two non-adjacent
′
edges of E(G). Thus, wtf (F ′ ) = 2wtf (F ) −
e∈E(H) f (e) . So, wtf (F ) is
v∈V (H) f (v) +
independent of F ′ .
An example of the labeling depicted in the proof of Theorem 3.1 can be seen in Figure 2 where
a (K5 , 2K2 + C3 )-sim-supermagic labeling of S2,0,0,2 + C3 is presented.
Figure 2. A (K5 , 2K2 + C3 )-sim-supermagic labeling of S2,0,0,2 + C3
The following corollary is a consequence of Theorem 3.1 with H = K1 .
Corollary 3.1. Let G be a C3 -free connected graph containing a P5 . If G is SEMT graph, then
G + K1 is (C3 , 2K2 + K1 )-sim-supermagic.
This corollary enlarges the classes of graphs known to be C3 -supermagic; since up to date, only
the following join product graphs were known to be C3 -supermagic: Pn +K1 , Cn +K1 , K1,n +K1 ,
and nK2 + K1 , where n ≥ 3 [16, 21, 22, 25].
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4. Labelings for Cartesian Product Graphs
The Cartesian product of two graphs G and H, denoted by G × H, is a graph whose vertex
set is V (G) × V (H) = {(u, v)|u ∈ V (G), u ∈ V (H)} and for which two vertices (u1 , v1 ) and
(u2 , v2 ) are adjacent if and only if either u1 u2 ∈ E(G) and v1 = v2 or v1 v2 ∈ E(H) and u1 = u2 .
In this section, we shall study (F, H)-sim-supermagic labeling for the Cartesian product of an
arbitrary graph G with K2 . The following notations are used or vertices and edges in G × K2 For
each x ∈ V (G), let x and x′ be the corresponding vertices in the two copies of G in G × K2 , and
so xx′ ∈ E(G × K2 ). For each xy ∈ E(G), denote by xy and x′ y ′ the corresponding edges in the
two copies of G in G × K2 .
We summarize the Cartesian product graphs G × K2 known to be H-magic in Table 3.
Table 3. G × K2 that are H-magic
Cartesian product
G × K2
P m × K2
mK1,n × K2
s(Pn+1 × K2 ) ∪ k(Pn × K2 )
m(Pn × K2 )
P n × K2
P n × K2
G × K2
H
C4
C4
C4
C4
C4
C2m
P m × K2
C4
(2G) × K2
C4
Conditions and Reference
G is C4 -free and SEMT of odd size [16]
m ≥ 3 [21]
m ≥ 2 and n ≥ 1 [1]
s ≥ 1, k ≥ 1 and n ≥ 2 [1]
m ≥ 2 and n ≥ 2 [23]
n ≥ 4 and m ∈ [3, ⌊ n2 ⌋ + 1] [20]
n ≥ 4 and m ∈ [3, n − 1] [20]
G is C4 -free, SEMT and a connected (p, q)-graph
where p or q is odd [14]
G is C4 -free, connected, bipartite (with
partite sets U and V ) and G has a SEMT labeling
f such that f (U ) = [1, |U |] [14]
In [20], Ngurah et al. constructed (Pm × K2 )-supermagic labelings of the ladder Pn × K2 for
every m ∈ [3, n − 1]. A more general result by Baca et al. [7] established the following sufficient
conditions for the Cartesian product G1 × G2 to be (H × G2 )-supermagic as stated in the following
theorem. On the other hand, in [14] and [16] it was proved that if G is connected of odd order or
size, C4 -free, and SEMT, then G × K2 admits a C4 -supermagic labeling.
Theorem 4.1. [7] Let G1 be a graph of odd order p1 ≥ 3 admitting an H-covering given by t
subgraphs isomorphic to H. If G2 is a graph of even order q2 ≥ 2 and odd size p2 ≥ 3 and the
graph G1 × G2 contains exactly t subgraphs isomorphic to H × G2 , then G1 × G2 is (H × G2 )supermagic.
In the next theorem, we enlarge the classes of graphs known to be (Pm × K2 )-supermagic [20]
and extend sufficient conditions for the existence of a C4 -supermagic labeling of G × K2 [14, 16]
without considering a SEMT labeling of G. Furthermore, our result settles the remaining cases of
Theorem 4.1 for p2 = 1 and q2 = 2.
Theorem 4.2. Let G be a C4 -free connected graph of odd order p ≥ 5. If G admits a Pm -covering
for some m ∈ [3, p − 1], then G × K2 is (C4 , Pm × K2 )-sim-supermagic.
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Proof. Let p and q be the order and the size of G, respectively. Consider A = [1, 3p + 2q] as
the set of integers used to label vertices and edges in G × P2 . Now, partition A into three sets
W = [1, 2p], X = [2p + 1, P
3p], and Y = [3p +1,3p + 2q]. Since p is odd, by Lemma 2.2, W
is (p, 1)-anti balanced with
Wi = 2 + i + 3 p2 for every i ∈ [1, p]. Now, since |Y | = 2q,
P
Lemma 2.1 ensures that Y is q-balanced with
Yj = 2q
(3p + 1 + 3p + 2q) = 6p + 2q + 1 for
2q
each j ∈ [1, q].
Let g and h be bijections from V (G) to [1, p] and from E(G) to [1, q], respectively. Next, define
a total labeling f of G×K2 . For each x ∈ V (G), label x and x′ in G×K2 by the elements of Wg(x)
chosen so that f (x) < f (x′ ) and define f (xx′ ) = 3p − g(x) + 1. ForSeach xy ∈ E(G), define f as
a bijection from {xy, x′ y ′ } to Yh(xy) with f (xy) < f (x′ y ′ ). Hence, v∈V (G×K2 ) {f (v)} = W and
S
e∈E(G×K2 ) {f (e)} = X ∪Y . Consequently, f is a bijective function from V (G×K2 )∪E(G×K2 )
to A.
Since G is C4 -free, there are q subgraphs of G × K2 isomorphic to C4 . Let F be a subgraph
of G × K2 isomorphic to C4 . Then, V (F ) = {x, x′ , y, y ′ } and E(F ) = {xx′ , yy ′ , xy, x′ y ′ }, where
x, y ∈ V (G) and xy ∈ E(G). Therefore,
wtf (F ) = f (x) + f (x′ ) + f (y) + f (y ′ ) + f (xx′ ) + f (yy ′ ) + f (xy) + f (x′ y ′ )
X
X
X
=
Wg(x) +
Wg(y) + 3p − g(x) + 1 + 3p − g(y) + 1 +
Yh(xy)
p
= 12p + 6 2 + 2q + 7,
which is independent of F .
Moreover, as G admits a Pm -covering for some m ∈ [3, p − 1], we have that G × K2 admits
a (Pm × K2 )-covering. Let H = x1 x2 . . . xm be a subgraph of G isomorphic to Pm . For each H,
denote by H ′ = x′1 x′2 . . . x′m the corresponding subgraph in G′ . Thus, for each H, we obtain H ′′
with V (H ′′ ) = {x1 , x2 , . . . , xm , x′1 , x′2 , . . . , x′m } and E(H ′′ ) = E(H) ∪ E(H ′ ) ∪ {xx′ |x ∈ V (H)}
as the corresponding subgraph in G × K2 isomorphic to Pm × K2 . We can verify that there are
exactly t subgraphs of G × K2 isomorphic to Pm × K2 , where t is the number of subgraphs
isomorphic to Pm in G. Thus,
X
X
X
X
X
wtf (H ′′ ) =
f (v) +
f (v) +
f (e) +
f (e) +
f (vv ′ )
v∈V (H)
=
X
v∈V (H ′ )
′
[f (v) + f (v )] +
v∈V (H)
=
=3m
p
2
′
[f (e) + f (e )] +
X
v∈V (H)
[3p − g(v) + 1]
v∈V (H)
e∈E(H)
X hX
v∈V (H)
e∈E(H ′ )
e∈E(H)
X
i
i
X
X hX
[3p − g(v) + 1]
Yh(e) +
Wg(v) +
v∈V (H)
e∈E(H)
+ 4m + 9mp + 2mq − 6p − 2q − 1,
which is independent of H ′′ . Hence, G × K2 is (C4 , Pm × K2 )-sim-supermagic.
An example of the labeling in the proof of Theorem 4.2 is depicted in Figure 3.
[20], Ngurah et al. showed that the ladder Pn × K2 is C2m -supermagic for every m ∈
In
n
[3, 2 + 1]. Then it is natural to ask for which graphs G, the Cartesian product G × K2 is
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Figure 3. A (C4 , Pm × K2 )-sim-supermagic labeling of C7 × K2 for every m ∈ [3, 6].
(C2x , C2y )-sim-supermagic for some x, y ∈ 3, n2 + 1 . We will answer this question in Theorem
4.3, but to do so, we need to recall the following notion that was first introduced by Simanjuntak et
al. [27]. An injective function f from V (G) onto the set {1, 2, . . . , |V (G)|} is called (a, d)-edgeantimagic vertex labeling ((a, d)-EAV) if the set of edge-weights {w(xy) = f (x) + f (y)|xy ∈
E(G)} = {a, a + d, . . . , a + (|E(G)| − 1)d}, where a > 0 and d ≥ 0 are two integers. A graph G
is said to be an (a, d)-edge-antimagic vertex ((a, d)-EAV) graph if G has an (a, d)-EAV labeling.
In [4], it was shown that a connected graph G that is not a tree has no (a, d)-EAV labeling for
d ̸= 1.
Lemma 4.1. [4] Let G be a connected graph that is not a tree. If G has an (a, d)-EAV labeling,
then d = 1.
The next theorem describes a construction of a (C2x , C2y )-sim-supermagic labeling of G × K2
from an (a, 2)-EAV labeling for some x, y ∈ 3, n2 + 1 . Due to Lemma 4.1, we restrict our
consideration to trees.
Theorem 4.3. Let m, n and p be positive integers where 3 ≤ m < p. Let G be a tree on p vertices
where p ≥ 5, such that G admits a Pm -covering for some m ∈ 3, n2 + 1 . If G is an (a, 2)-EAV
graph, then G × K2 is (C2x , C2y )-sim-supermagic for all x, y ∈ [2, m].
Proof. Let p and q be the order and the size of G, respectively. Let g : V (G) → {1, 2, . . . , p} be
an (a, 2)-EAV labeling of G.
Since |V (G × K2 )| = 2p and |E(G × K2 )| = p + 2q, the set of labels used to label vertices and
edges of G × K2 is A = [1, 3p + 2q]. Now, partition A into three sets W = [1, 2p],
P X = [2p + 1, 3p]
and Y = [3p + 1, 3p + 2q]. By Lemma 2.3, W is (p, 2)-anti balanced with
Wi = 2i + p for
P
every i ∈ [1, p]. According to Lemma 2.3, Y is (q, 2)-anti balanced with Yj = 6p + q + 2j for
each j ∈ [1, q].
Next, define a total labeling f of G × K2 . For each x ∈ V (G), label the corresponding vertices
x and x′ in G × K2 by the elements of Wg(x) chosen so that f (x) < f (x′ ). For each x ∈ V (G),
define f (xx′ ) = 3p + 1 − g(x). Now, for each xy ∈ E(G), label the corresponding edges xy and
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x′ y ′ in G×K2 by the elements of Yr where r = 12 (2q +a−g(x)−g(y)) such that f (xy) < f (x′ y ′ ).
It follows easily that f depends on g. Then, f is a bijective function from V (G × K2 ) ∪ E(G × K2 )
to A.
Since G admits a Pm -covering for some m ∈ 3, n2 + 1 , G × K2 admits C2z -covering for
every z ∈ [2, m]. Let H = x1 x2 . . . xz be a subgraph of G isomorphic to Pz for an arbitrary
z ∈ [2, m]. For each H, denote by H ′ = x′1 x′2 . . . x′z the corresponding subgraph in G′ . Thus,
for each H, we obtain H ′′ as the corresponding subgraph in G × K2 isomorphic to C2z where
V (H ′′ ) = V (H) ∪ V (H ′ ) and E(H ′′ ) = E(H) ∪ E(H ′ ) ∪ {x1 x′1 , xz x′z }. We can verify that there
are exactly t subgraphs of G × K2 isomorphic to C2z , where t is the number of subgraphs in G
isomorphic to Pz . Thus,
X
X
X
X
wtf (H ′′ ) =
f (v) +
f (v) +
f (uv) +
f (uv) + f (x1 x′1 ) + f (xz x′z )
v∈V (H)
=
X
v∈V (H ′ )
[f (v) + f (v ′ )] +
v∈V (H)
=
X hX
v∈V (H)
uv∈E(H)
X
uv∈E(H ′ )
[f (uv) + f (u′ v ′ )] + 3p + 1 − g(x1 ) + 3p + 1 − g(xz )
uv∈E(H)
i
Wg(v) +
X X
uv∈E(H)
Y 1 (2q+a−g(u)−g(v)) + 6p + 2 − g(x1 ) − g(xz )
2
= 7zp + 3zq − 3q + az − a + 2,
which is independent of H ′′ .
Therefore, G × K2 is (C2x , C2y )-sim-supermagic for all x, y ∈ [2, m].
An example of the labeling in Theorem 4.3 can be seen in Figure 4.
Figure 4. A (C4 , C2m )-sim-supermagic labeling of P6 × K2 for m = 3 and 4
Note that the preceding theorem enlarges the classes of graphs known to be C2m -supermagic,
as stated in Table 3. For instance, since every path Pn was shown to be (3, 2)-EAV [27], an
immediate consequence of Theorem 4.3 is that the ladder Pn × K2 is (C4 , C2m )-sim-supermagic
for every m ∈ [3, ⌊ n2 ⌋ + 1].
In [2], Bača and Barrientos described a connection between an α-labeling and an (a, 2)-EAV
labeling of graphs. An injective mapping f : V (G) → [0, |E(G)|] is said to be graceful labeling if
|f (x)−f (y)| are distinct for each xy ∈ E(G). A graceful labeling f is called an α-labeling if there
exists an integer λ such that for each edge xy either f (x) ≤ λ < f (y) or f (y) ≤ λ < f (x) [24].
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A graph G that admits an α-labeling is said to be an α-graph. From the definition of α-labeling, it
follows that an α-graph is necessarily bipartite.
Let {A, B} be the natural bipartition of the vertex set of an α-graph. Bača and Barrientos [2]
presented the following theorem.
Theorem 4.4. [2] A tree T is a (3, 2)-EAV graph if and only if T is an α-graph and ||A|−|B|| ≤ 1,
where {A, B} is the natural bipartition of the vertex set of T .
Theorem 4.3 together with Theorem 4.4 implies the relationship between an α-labeling of a
tree T and a (C4 , C6 )-sim-supermagic labeling of the Cartesian product T × K2 . Let n ≥ 2 be a
positive integer and let T be an α-tree and ||A| − |B|| ≤ 1, where {A, B} is the natural bipartition
of the vertex set of T . It is clear that T × K2 admits a C4 -covering and a C6 -covering only if T is
not isomorphic to a star.
Corollary 4.1. Let T be an α-tree not isomorphic to a star on at least five vertices and let ||A| −
|B|| ≤ 1, where {A, B} is the natural bipartition of the vertex set of T . Then T × K2 is (C4 , C6 )sim-supermagic.
Figure 5 illustrates a (C4 , C6 )-sim-supermagic labeling of product graph S2,1,0,1 × K2 .
Figure 5. A (C4 , C6 )-sim-supermagic labeling of S2,1,0,1 × K2 .
A perfect matching of a graph is a matching (i.e., an independent edge set) in which every
vertex of the graph is incident to exactly one edge of the matching. Brankovic et al. [8] posed the
following conjecture for α-trees.
Conjecture 1. [8] All trees with maximum degree three and a perfect matching have an α-labeling.
Consider a tree T with a perfect matching. Since T is bipartite, by a perfect matching in T , we
have a natural bipartition of the vertex-set of T , namely A and B, such that ||A| − |B|| ≤ 1. As a
direct consequence of Corollary 4.1 and Conjecture 1, the following holds.
Theorem 4.5. Let T be a tree on at least five vertices that are not isomorphic to a star, with a
maximum degree three and containing a perfect matching. If Conjecture 1 is true, then T × K2 is
(C4 , C6 )-sim-supermagic.
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Although all our results in this section are restricted to trees, the proof of Theorem 7 in [16]
implied that Cn × K2 is (C4 , C2m )-sim-supermagic for each odd n ≥ 5 and m = 2. Thus, it is
interesting to seek conditions such that a Cartesian product of a non-tree graph G with K2 admits
a (C4 , C2m )-sim-supermagic labeling.
Acknowledgement
Y.F. Ashari is supported by the PKPI/Sandwich-like-PMDSU Scholarship funded by the Indonesian Ministry of Research and Technology. Salman is supported by ”Program Penelitian dan
Pengabdian kepada Masyarakat-Institut Teknologi Bandung” (P3MI-ITB). R. Simanjuntak is supported by Penelitian Dasar Unggulan Perguruan Tinggi 2021-2023 No. 2/E1/KP.PTNBH/2021
funded by Indonesian Ministry of Education, Culture, Research and Technology. A. SemaničováFeňovčı́ková and M. Bača are supported by the Slovak Research and Development Agency under
contract No. APVV-19-0153.
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