On Poisson structures arising from a Lie group
action
arXiv:1906.10789v1 [math.DG] 26 Jun 2019
G. M. Beffa and E. L. Mansfield
Abstract
We investigate some infinite dimensional Lie algebras and their associated
Poisson structures which arise from a Lie group action on a manifold.
If G is a Lie group, g its Lie algebra and M is a manifold on which G
acts, then the set of smooth maps from M to g has at least two Lie algebra structures, both satisfying the required property to be a Lie algebroid.
We may then apply a construction by Marle to obtain a Poisson bracket on
the set of smooth real or complex valued functions on M × g∗ . In this paper, we investigate these Poisson brackets. We show that the set of examples
include the standard Darboux symplectic structure and the classical Lie Poisson brackets, but is a strictly larger class of Poisson brackets than these. Our
study includes the associated Hamiltonian flows and their invariants, canonical maps induced by the Lie group action, and compatible Poisson structures.
Our approach is mainly computational and we detail numerous examples.
The Lie brackets from which our results derive, arose from the consideration of connections on bundles with zero curvature and constant torsion.
We give an alternate derivation of the Lie bracket which will be suited to
applications to Lie group actions for applications not involving a Riemannian
metric. We also begin a study of the infinite dimensional Poisson brackets
which may be obtained by considering a central extension of the Lie algebras.
1
Introduction
A recent study on post-Lie algebras by Munthe–Kaas et al [16], notes in passing
the construction of two distinct Lie algebra brackets [ , ] and J , K on the vector
space of maps from a manifold M to a Lie algebra g. The second bracket depends
on a Lie group action on the manifold, G × M → M , where g is the Lie algebra
of G. It is also noted that both brackets make the space of sections of the trivial
bundle M × g, denoted here by A1 (M, M × g), into a Lie algebroid, which means
that the Lie brackets have a Leibnitz-like property. Meanwhile, a study of the
differential calculus which is possible on Lie Algebroids, by Marle, [15], shows how
one may construct a Poisson structure on a different but related vector space to
A1 (M, M × g). Linear Poisson structures associated to a Lie algebroid were first
considered in [3].
In the first part of this paper, we study the Poisson structures so generated by
the second bracket on A1 (M, M × g). If the group action is trivial, the standard
1
Lie Poisson structure on the dual of the Lie algebra is obtained, while if the group
action is translation in the coordinates on the manifold, then the standard Darboux
symplectic structure is obtained. We discuss canonical actions for our Poisson
bracket and compare examples of the Hamiltonian flows they generate with those of
the associated Lie Poisson bracket. If the Lie group action is, in some neighbourhood
on the manifold, free and regular, so that we have, locally, a moving frame, we
analyse the Hamiltonian systems further, in terms of the frame and the invariants
of the action on M . Examples include nonlinear actions of the orthogonal group
and of SL(2).
We show that if the group G acts on M using two different actions, then the
two Poisson structures are generically compatible if, and only if, the actions differ
by a translation at the infinitesimal level.
The post-Lie agebras studied in [16] arise in the context of Riemanninan manifolds with zero curvature but constant torsion. To expand the range of examples and perhaps extend our results to discrete spaces, we introduce a product in
A1 (M, M ×G), the set of section of the trivial bundle G×M , that gives it the structure of local Lie group. We show that A1 (M, M × g) with the second Lie bracket is
the Lie algebra of this local Lie group, thus providing a geometric interpretation of
J , K, and a description of the symplectic leaves of its associated Lie-Poisson bracket
as its coadjoint orbits.
We close the paper with a preliminary study of the infinite dimensional LiePoisson brackets defined by these Lie algebra brackets. In particular, we assume
that M = S 1 or R and we show that the standard cocycle used to describe central
extensions of C ∞ (M, g) is also a cocycle when we consider the second bracket, J , K
instead of the pointwise bracket. This allow us to define the central extension of
the new algebra. We also describe a natural compatible Poisson companion to this
central extension. The study of possible applications to the integrability of PDEs
will appear elsewhere.
1.1
Basic notions
While the content of this section might be elementary to members of some pure
mathematical communities, this paper was inspired by [10] and our intended audience comprises the computational and application-driven mathematical communities. Thus, we include some basic definitions, and always with a computational
angle.
A Lie group G is a group which is also a manifold, such that the operations of
taking products and inverses are smooth maps. We consider Lie group actions on
manifolds.
Definition 1.1. If M is a manifold and G a Lie group, then we say that the map
G × M → M,
(g, z) 7→ g · z (left),
is a left Lie group action if
h · (g · z)) = (hg) · z
2
g ·R z (right)
or a right Lie group action if
h ·R (g ·R z)) = (gh) ·R z
Given that our paper is computationally oriented, in all our calculations we will
assume local coordinates z = (z1 , . . . , zp ) on M , and so we may take M to be an
open neighbourhood of Rp for some integer p ≥ 1.
If G × M → M is a left action, then the induced map on the set of functions
f : M → R, given by
(g ·R f )(z) = f (g · z),
is a right action, since h ·R (g ·R f )(z) = h ·R (f (g · z)) = f (g · (h · z)) = f ((gh) · z),
and vice versa.
The Lie algebra g associated to a Lie group G is the vector space Te G, that is,
the tangent space to G at the identity element e ∈ G, which we take to be defined
in the standard way, as equivalence classes of smooth curves passing through e
(see Hirsch [7]). Given v ∈ Te G = g, there is a distinguished representative curve,
denoted as t 7→ exp(tv) ∈ G and called the exponential of the vector v. We refer to
[2, 14] for the standard details.
It is well known that the space g has a Lie bracket, [ , ] : g × g → g obtained
via a double differentiation of the conjugation(g, h) → ghg −1 . In the case of a
matrix Lie group, the Lie bracket on g is the standard Lie matrix bracket given by
[X, Y ] = XY − Y X. Given co-ordinates g = g(a1 , . . . , ar ) on G near the identity,
with e = g(0, . . . 0) and matching basis of Te G given (as equivalence classes of
curves) by
v1 = [g(t, 0, . . . , 0)], v2 = [g(0, t, 0, . . . , 0)], . . . , vr = [g(0, . . . , 0, t)]
(1)
we may calculate the bracket table for the Lie algebra with respect to this basis.
This yields a skew-symmetric bracket table, B = B(v), where v = (v1 , v2 , . . . vr ),
given by Bi,j = [vi , vj ]. Notice that the entries of B are Lie algebra elements.
A Lie group action on a manifold M yields a representation of the Lie algebra
in X(M ), the vector space of vector fields on M . Let Tz M be the tangent space of
M at the point z ∈ M . Then for v ∈ Te G = g define the vector Xv (z) ∈ Tz M by
X(v)(z) =
d
dt
t=0
exp(tv) · z ∈ Tz M.
(2)
The vector field X(v), given by
X(v) : M → T M,
z 7→ X(v)(z)
(3)
is called the infinitesimal vector field associated to the vector v ∈ g.
Given co-ordinates z = (z 1 , z 2 , . . . , z p ) on M , and a basis {vi | i = 1, . . . r} of g,
we will write X(vk ) as Xk for simplicity, with
X d
ℓ
Xk =
(4)
(exp(tvk ) · z) ∂zℓ
dt
t=0
ℓ
3
where (exp(tvk ) · z)ℓ denotes the ℓ-th coordinate of exp(tvk ) · z. Thus, there is a
p × r matrix of infinitesimals, Φ, for the Lie group action, so that the infinitesimal
vector fields can be written as
∂z 1
X1
..
T .
(5)
. = Φ .. .
∂z p
Xr
Definition 1.2. We say that the infinitesimal vector fields Xk , k = 1, . . . , r defined
in Equation (4) are associated to the basis vk , k = 1, . . . r of g.
P
Clearly, if v =
ck vk , then
X(v) =
d
dt
t=0
exp(t
X
ck vk ) · z =
X
ck
d
dt
t=0
exp(tvk ) · z =
X
ck X k .
(6)
In our examples, we will always use infinitesimal vector fields associated to a
basis of the Lie algebra calculated using coordinates near the identity of G, as in
Equation (1).
Example 1.3. Consider the Lie group SL(2),
a b
ad − bc = 1
SL(2) = g(a, b, c, d) =
c d
acting on M = R ∪ {∞} as
au + b
cu + d
g(a, b, c, d) · u =
∞
cu + d 6= 0
(7)
cu + d = 0
together with g(a, b, c, d) · ∞ = a/c. For g(a, b, c, d) close to the identity, we have
that d = (1 + bc)/a and so the Lie algebra is
0 0
0 1
1 0
, vb =
sl(2) = va =
.
(8)
, vc =
1 0
0 0
0 −1
R
For the action in Equation (7), we have
d
d
X(va ) =
exp(tva ) · u ∂u =
dt t=0
dt
et u
t=0 e−t
and similarly
X(vb ) = ∂u ,
X(vc ) = −u2 ∂u .
Hence the matrix of infinitesimals is
Φ=u
a b
c
2u 1 −u2
4
∂u = 2u∂u
It is instructive to compare the bracket tables for the two representations of sl(2).
We have
[, ]
X(va )
X(vb )
X(vc )
X(va )
0
−2X(vb ) 2X(vc )
0
−X(va )
X(vb ) 2X(vb )
0
X(vc ) −2X(vc ) X(va )
[ , ] va
vb
vc
va
0
2vb −2vc
va
vb −2vb 0
2vc −va
0
vc
where the bracket on the left is the standard matrix bracket, while the bracket on the
right is the standard conmutator of vector fields, [X, Y ](f ) = X(Y (f )) − Y (X(f )).
Hence the isomorphism from the matrix representation of sl(2) to that in terms of
the infinitesimal vector fields is
v 7→ −X(v).
The Adjoint action of a Lie group on its Lie algebra plays a key role in all our
calculations. For a matrix Lie group, the left Adjoint action is defined as conjugation
(g, x) 7→ Ad(g)x = gxg −1 .
G × g → g,
(9)
Ad(g) is an invertible linear map from g to itself and defines a representation of G
in gl(g).
The Adjoint action of G on vector fields can be defined by viewing the action
by g as a diffeomorphism of M . This group of diffeomorphisms is a Lie group and
its algebra can be identified with vector fields on M . The left Adjoint action on
vector fields is then defined as
Ad(g)(X)(z) = T g ◦ X(g −1 z)
Ad(g) : Tz M → Tg·z M,
so that the following diagram commutes,
Tg
TM → TM
X↑
↑ Ad(g)(X)
g·
M → M
In coordinates,
if we write ∇z = (∂z1 , ∂z2 , . . . , ∂zp )T then we have that for a vector
P
field X =
fj (z)∂zk = f (z)T ∇z
T
Ad(g)(X) = T g f (g
=
−1
T
· z)∇z |g−1 ·z = f (g
∂ (g −1 · z)
∂z
−1
−1
f (g −1 · z)
· z)
!T
∂ (g −1 · z)
∂z
−T
∇z
∇z
The representation of the Adjoint linear action on the coefficients f is thus given by
f (z) 7→
∂ (g −1 · z)
∂z
5
−1
f (g −1 · z).
(10)
We have that if X(v) is the field generated by v ∈ g, then Ad(g)(X(v)) =
X(Ad(g)(v)). Indeed, we have for X = X(vk ) that
Ad(g)(X(vk )) = T g ◦ X ◦ g −1 (z)
d
= T g dt
=
d
dt
=
d
dt
t=0
exp(tvk ) · g −1 · z
t=0
g exp(tvk )g −1 · z
t=0
exp(t(gvk g −1 )) · z
= X(Ad(g)(vk )).
The result then follows by linearity.
Given a basis vk , k = 1, . . . , r of g, we know that the Adjoint of a vector
P in g is a
linear
combination
of
these
basis
vectors.
Using
Equation
(4),
if
Ad(g)(
f k vk ) =
P
vk Ad(g)fj , where Ad(g) is the matrix representation
ofP
Ad(g), we have for the
P
associated infinitesimal vector fields that Ad(g) fk Xk =
Xk Ad(g)fj or
ΦT ∇z 7→ AdT (g)ΦT ∇z .
(11)
Combining this with Equation (10) yields
−1
∂ (g −1 · z)
Φ(g −1 · z) = Φ(z)Ad(g).
∂z
(12)
We now illustrate that using associated infinitesimal vector fields leads to the
same matrix representation of the Adjoint matrix Ad(g),
Example 1.3 (cont.) For the action in equation (7), recall
Φ=u
We have
g(a, b, c, d)
−1
du − b
,
·u=
−cu + a
a b
c
2u 1 −u2 .
∂(g −1 · u)
∂u
−1
∂
∂
= (−cu + a)2
∂u
∂u
so that, for example
Ad(g)(Xa ) = 2(du − b)(−cu + a)∂u = (ad + bc)Xa − 2abXb + 2cdXc .
The complete calculation gives
Xa
ad + bc −2ab 2cd
Xa
a2
−c2 Xb = Ad(g)T ΦT ∂u
ΦT ∂u = Xb 7→ −ac
Xc
bd
−b2
d2
Xc
where, as above, this defines the matrix Ad(g).
Let’s set
α β
a b
∈g
∈ G,
x(α, β, δ) =
g=
δ −α
c d
6
(13)
e δ),
e the expression defining α
e δ.
e We can
into Ad(g)(x) = gxg −1 = x(e
α, β,
e, β,
compare the Adjoint action above with that on the matrix representation of sl(2),
given in equation (8), observing that
α
e
ad + bc −ac db
α
α
βe = −2ab
a2 −b2 β = Ad(g) β
2cd
−c2 d2
δ
δ
δe
which is precisely the same matrix representation previously obtained.
Definition 1.4. Let C ∞ (M, R) denote the set of smooth real-valued functions on
M . A Poisson bracket is a map,
{ , } : C ∞ (M, R) × C ∞ (M, R) → C ∞ (M, R),
(F, G) 7→ {F, G}
is called a Poisson bracket if for all a, b ∈ R, F , G H ∈ C ∞ (M, R)
1. {F, G} = −{G, F } (skew-symmetry)
2. {aF + bG, H} = a{F, H} + b{G, H}, (bilinearity)
3. 0 = {F, {G, H}} + {G, {H, F }} + {H, {F, G}} (Jacobi identity)
4. {F, GH} = {F, G}H + G{F, H} (Leibnitz identity)
Given co-ordinates z = (z 1 , . . . z p ) on M , then viewing these co-ordinates z k as
functions on M , we may define the Poisson structure matrix Λ for the Poisson
bracket as
Λ = (Λij ),
Λij = {z i , z j }.
If M = g∗ , then M has a distinguished Poisson
bracket. Specifically, let {v1 , . . . vr } be a basis of g,
in g∗ so that θi (vj ) = δij . If f ∈ C ∞ (g∗ ), we define
at ξ ∈ g∗ , and we denote it by δξ f (or δf (ξ)) as the
bracket called the Lie Poisson
and {θ1 , . . . , θr } its dual basis
the variational derivative of f
element of g such that
d
|ǫ=0 f (ξ + ǫν) = ν(δξ f )
dǫ
for all ν ∈ g∗ .
Define the Lie Poisson bracket on C ∞ (g∗ ) by the formula
{f, g}(ξ) = ξ ([δξ f, δξ g]) .
P
Assume P
δξ f =
i vi ∂i f , where ∂i f are defined by this relationship. Then, if
k
[vi , vj ] = k cij vk , the Lie-Poisson bracket can be written as
!
X
{f, g}(ξ) = ξ
cki,j vk ∂i f ∂j g ,
(14)
i,j,k
or
{f, g}(θk ) =
X
i,j
7
cki,j ∂i f ∂j g.
Denote by ξi ,i = 1, . . . r the linear coordinate functions on g∗ representing vi , i =
1, . . . r, thinking of vi as the dual to θi , so that ξi (ξ) = vi (ξ); we say in this case
that the basis {ξi } is associated to the basis {vi }. Then
X
(15)
{ξi , ξj }(θk ) = cki,j or {ξi , ξj } =
cki,j ξk which is the bracket in g.
k
We now note the following two interesting facts which we will use in the sequel. The first is a well-known change of variable in our computationally oriented
notation. Let Ad(g) be the matrix representation of the adjoint action as in (12).
If the Adjoint action on the Lie Algebra is given in matrix form as (v1 , . . . , vr ) 7→
(v1 , . . . , vr )Ad(g) then the induced action on g∗∗ is given by
ξ 7→ ξAd(g).
(16)
where ξ = (ξ1 , . . . , ξr ) and the ξi are coordinates on g∗ .
Proposition 1.5 (The induced Adjoint action on the Lie Poisson structure). Let
G a Lie group with dim G = r, with g its Lie algebra, and with g∗∗ having basis
ξ1 , . . . , ξr , viewed as coordinates on g∗ associated to the basis of g, v1 , . . . , vr . Using
these coordinates, let the Lie Poisson structure matrix for g∗ be denoted as Λ = Λ(ξ).
1. The Lie Poisson structure matrix transforms as
Λ(ξAd(g)) = Ad(g)T Λ(ξ)Ad(g).
2. The infinitesimal matrix for the co-Adjoint action on g∗ is the negative of the
Lie Poisson structure matrix.
Proof.
1. The first result is a direct linear algebra consequence of (15) and (16).
2. Let g(t) = exp(tvi ). Then from the definition of the Adjoint action, we have
d
dt
t=0
Ad(exp(tvi ))vj =
=
=
d
dt
exp(tvi )vj exp(−tvi )
t=0
[v
Pi , vjν]
ν cij vν
By (16), the same transformation rules apply, namely
d
dt
t=0
Ad(exp(tvi ))ξj =
X
cνij ξν = {ξi , ξj },
as described in (15). By definition of the infinitesimal matrix,
(ΦT )ij =
d
dt
t=0
Ad(exp(tvi ))ξj = {ξi , ξj }
giving Φij = {ξj , ξi } = −{ξi , ξj } as required.
8
.
2
Poisson brackets on Lie algebroids
If E is a bundle with base space M and fibre g, we denote the space of sections
of E as A1 (M, E), following Marle [15]. Notice that A1 (M, M × g) is isomorphic
to C ∞ (M, g). As all our calculations are local, so that the subtleties of global
obstructions do not arise in this paper, we will restrict to the trivial case.
2.1
Two Lie algebra structures in C ∞ (M, g)
We recall two definitions of Lie brackets on C 1 (M, g), given in [16].
Definition 2.1 (The first Lie bracket). Let x, y : M → g ∈ C 1 (M, g) and let [ , ]
denote the Lie bracket on g. Then we define the first, pointwise Lie bracket on
C 1 (M, g), to be
[x, y](z) = [x(z), y(z)].
(17)
Remark 2.2. Notice that if we use the representation of the Lie algebras as infinitesimal vector fields, that is, as first order operators, then the bilinear property
for this first bracket
P
P
P i
[ xi (z)vi , y j (z)vj ] =
x (z)y j (z)[vi , vj ]
still applies, even though this representation is not linear with respect to multiplication of functions. For this reason when calculating this first bracket, we will be
using a (faithful) matrix representation. It should be noted that the isomorphism
between the two representations is
v 7→ −X(v).
A second Lie bracket may be defined in terms of a given Lie group action,
G × M → M . Let v1 , . . . , vr be a basis of g, and X(vi ) = Xi , i = 1, . . . , r, their
infinitesimal vector fields. We write these as
(X1 , . . . , Xr )T = Φ(z)T ∇z
where Φ is the matrix of infinitesimals given P
in Equation (5).
Now let x : M → g, be given by x(z) =
xj (z)vj . We define the vector field
ρ(x) on M to be
X
ρ(x)(z) = X(x(z)) =
xj (z)Xj = (Φx)T (z)∇z .
(18)
P j
Next, given a second map y : M → g, y =
y vj , define
X
Lρ(x) y =
ρ(x)(y j )vj
(19)
the component-wise Lie derivative of y along the vector field ρ(x). We note that
Lρ(x) is a derivation on C 1 (M, g).
We are now in a position to define a second Lie bracket.
9
Definition 2.3 (The second Lie bracket). If the action of G on M is a left action,
then we define the second Lie bracket on A1 (M, g), to be
Jx, yK = Lρ(x) y − Lρ(y) x − [x, y]
(20)
where the final summand is the first, point wise Lie bracket defined above. If the
action of G on M is a right action, we define the bracket to be
Jx, yK = −Lρ(x) y + Lρ(y) x − [x, y].
(21)
The Jacobi identity may be verified using the interpretation of this bracket in
§4 as the Lie bracket associated to a certain local Lie group.
Remark 2.4. If the action of G on M is a right action, (g, z) 7→ g ·R z, we can
convert it to be a left action by considering g · z = g −1 ·R z. This reverses the sign
of Φ and in this sense, the two definitions, (20) and (21), are consistent.
Remark 2.5. As we have defined this bracket, in coordinates, it is important to
note that the same coordinates on G near the identity e ∈ G are used to obtain
both the basis vectors of the (faithful) representation g and the infinitesimal vector
fields.
Remark 2.6. It can be seen that if the group action is trivial, that is, g · z = z
for all g ∈ G, then we recover the negative of the pointwise bracket, (17) which is
consistent with our choice of the matrix representation to calculate that bracket.
2.2
A Lie algebroid structure on C ∞ (M, g)
I’ve removed all mention of A1 from here now. The Lie brackets of the previous
subsection make A1 (M, M × g) ≃ C ∞ (M, g) into a Lie algebroid .
Definition 2.7 (Lie algebroid). We say that C 1 (M, g) is a Lie algebroid if there is
a bundle map ρ, that is, a map preserving the base point, called the anchor map,
ρ : C 1 (M, g) → X(M )
where X(M ) is the set of smooth vector fields on M , such that for x, y ∈ C 1 (M, g),
and f : M → R a smooth map,
Jx, f yK = f Jx, yK + Lρ(x) (f ) y.
(22)
Remark 2.8. The definition implies that
ρ (Jx, yK) = [ρ(x), ρ(y)]
where the bracket on the right is the bracket of vector fields in X(M ). In other
words, the anchor map is a Lie algebra homomorphism from C 1 (M, g) to X(M ),
which preserves the base point, (cf. [12]).
10
Indeed, consider
Jz, Jx, f yKK = Jz, f Jx, yK + Lρ(x) (f ) yK
= Jz, f Jx, yK + Jz, Lρ(x) (f ) yK
= f Jz, Jx, yKK + Lρ(z) (f ) Jx, yK + Lρ(x) (f ) Jz, yK + Lρ(z) (Lρ(x) (f ))y
applying Equation (22) to each summand. Similarly, we have,
Jx, Jz, f yKK = f Jx, Jz, yKK + Lρ(x) (f ) Jz, yK + Lρ(z) (f ) Jx, yK + Lρ(x) (Lρ(z) (f ))y
and further, we have,
JJx, zK, f yK = f JJx, zK, yK + Lρ(Jx,yK) (f ) y.
Applying the Jacobi identity in the form,
Jx, Jz, f yKK − Jz, Jx, f yKK = JJx, zK, f yK
yields the result,
Lρ(x) (Lρ(z) (f )) − Lρ(z) (Lρ(x) (f )) = Lρ(Jx,zK) (f )
as desired.
The anchor map allows a bundle E to be viewed as a proxy for T (M ). A great
deal more can be said, indeed the anchor map allows for proxy Lie derivatives,
exterior derivatives and many other constructions, [15].
The pointwise Lie bracket (17) makes C ∞ (M, g) a Lie algebroid with a zero
anchor map. The second Lie bracket, (20) or (21), makes C ∞ (M, g) a Lie algebroid
with the anchor map being precisely ρ(x), Equation (18), and hence the reason for
our choice of notation.
In the examples which follow, we use the standard coordinate names arising in
the applications.
Example 2.9. We set M = R with coordinate labelled as t, and G = (R, +), that,
the real numbers under addition, with the group action being
ǫ · t = t + ǫ.
Then the Lie algebra is g = R with the trivial Lie bracket and the single infinitesimal
vector field is ∂t . Hence for x : M → g, ρ(x) = x(t)∂t and thus for x, y : M → g,
we have
Jx, yK = xyt − yxt .
The proof of the Jacobi identity is straightforward given the maps into g are commuting scalars.
Example 1.3 (cont.) Recall the projective action of SL(2) on M = R given in
Equation (7) and the Lie algebra sl(2) given in Equation (8).
11
A map x : M → g takes the form
u 7→ x(u) =
x1 (u) x2 (u)
x3 (u) −x1 (u)
.
Given two such maps x, y we have
ρ(x)y 1 (u) ρ(x)y 2 (u)
Lρ(x) y =
ρ(x)y 3 (u) −ρ(x)y 1 (u)
where
ρ(x) = 2ux1 (u) + x2 (u) − u2 x3 (u) ∂u .
It can be verified directly that the second bracket (20), given explicitly in this
case using the standard matrix representation as,
1
yu yu2
1
2
2 3
Jx, yK = (2ux (u) + x (u) − u x (u))
yu3 −yu1
1
xu x2u
(23)
1
2
2 3
− (2uy (u) + y (u) − u y (u))
1
xu −xu
−x(u)y(u) + y(u)x(u).
satisfies the Jacobi identity.
Example 2.10. We consider G = SE(2) = SO(2) ⋉ R2 . A matrix representation
of G = SE(2) is
cos θ − sin θ a
g(θ, a, b) = sin θ cos θ b
0
0
1
so that the Lie algebra is
0 −α β
se(2) = αvθ + βva + δvb = α 0 δ | α, β, δ ∈ R
0 0 0
where this defines vθ , va and vb . We consider the standard, left linear action of
SE(2) on M = R2 with coordinates x and y, given as
a
x
cos θ − sin θ
x
.
(24)
+
=
g(θ, a, b) ·
b
y
sin θ cos θ
y
The infinitesimal vector fields are
X(vθ ) = −y∂x + x∂y ,
X(va ) = ∂x ,
X(vb ) = ∂y .
A map χ : M → se(2), is then χ(x, y) = χ1 (x, y)vθ + χ2 (x, y)va + χ3 (x, y)vb .
We have that
ρ(χ) = χ1 (x, y) (x∂y − y∂x ) + χ2 (x, y)∂x + χ3 (x, y)∂y
12
so that
Jχ, ηK = (χ1 (x∂y − y∂x ) + χ2 ∂x + χ3 ∂y ) η
− (η 1 (x∂y − y∂x ) + η 2 ∂x + η 3 ∂y ) χ
−χη + ηχ
where the operators act component-wise. It is straightforward to verify this bracket
satisfies the Jacobi identity.
Example 2.11. We consider the standard action of SO(3), the special orthogonal group in dimension 3, acting linearly on R3 . With respect to the standard
coordinates, (x, y, z) on R3 , the infinitesimal vector fields can be taken to be
X(vxy ) = x∂y − y∂x
X(vyz ) = y∂z − z∂y
X(vzx ) = z∂x − x∂z
This implicitly defines three coordinates
spect to these coordinates, the matching
0
0 −1 0
0
1 0 0 ,
vxy =
vyz =
0
0 0 0
on SO(3) near the identity, and with rebasis of the Lie algebra so(3) is
0 0 1
0 0
0 −1 ,
vzx = 0 0 0 .
−1 0 0
1 0
A map χ : R3 → so(3) takes the form χ(x, y, z) = χxy (x, y, z)vxy + χyz (x, y, z)vyz +
χzx (x, y, z)vzx , and
ρ(χ) = χxy X(vxy ) + χyz X(vyz ) + χzx X(vzx ).
Given two maps χ, η : R3 → so(3), then
Jχ, ηK = ρ(χ)η − ρ(η)χ − χη + ηχ
defines a Lie bracket. It is straightforward to verify this bracket satisfies the Jacobi
identity.
2.3
Poisson structures arising from Lie algebroids
We now outline the construction of a Poisson structure based on a result in Marle
[15]. The relation between the dual of vector bundles and Poisson structures can
also be found in [1], [4] and [13]. Because our approach is local and computational,
we continue to restrict to the case of the trivial bundle, M × g.
Consider the bundle E ∗ = M × g∗ where g∗ is the dual of g. For each smooth
section x ∈ C ∞ (M, g) we associate the smooth function
ϕx : E ∗ → R,
ϕx (z, θ) = θ(x(z)).
Now let z = (z 1 , . . . , z p ) be coordinates on M and let ξ = (ξ 1 , . . . , ξ r ) be coordinates
on g∗ .
13
Definition 2.12 (Section and function associated to a function on E ∗ ). Let η :
E ∗ → R. We say the section xη ∈ C ∞ (M, g) and the function fη : M → R are
associated to η at the point (z, ξ), if
dη = d(ϕx + f ◦ π),
where π is the projection on E ∗ .
Associated sections and functions are not unique and always exist. In applying
this definition to our class of examples, the associated sections and functions can
be taken to be constant and linear, respectively. The following result derives from
applying a more general result, appearing in the course of the proof of [15] Theorem
5.3.2, to our class of Lie Algebroids.
Theorem 2.13 (Poisson structure on E ∗ ). Let E be a vector bundle, a Lie algebroid
with anchor map ρ and Lie bracket [ , ]. There exists a Poisson bracket on E ∗ such
that
{ϕx1 , ϕx2 } = ϕ[x1 ,x2 ] .
Furthermore, given two functions on E ∗ , say η1 and η2 , let x1 , f1 and x2 , f2 be the
sections and functions associated to η1 and η2 respectively. The Poisson bi-vector
associated to {, } is given by
Λ(z, ξ)(η1 , η2 ) = ϕ[x1 ,x2 ] (z, ξ) + Lρ(x1 ) (f2 )(z) − Lρ(x2 ) (f1 )(z).
Despite the non-uniqueness of the associated sections and functions, Λ is uniquely
defined.
The calculation of the Poisson structure associated to any given Lie algebroid
∗
E is straightforward, as we will now demonstrate.
Example 1.3 (continued).
Assume the coordinates on g∗ are ξ = (ξ 1 , ξ 2 , ξ 3 ). Consider the functions η1 and
η2 on M × g∗ such that xi : M → g are the constant maps,
1
βi βi2
xi (u) =
βi3 −βi1
and the associated functions to be linear, f1 (u) = α1 u, f2 (u) = α2 u. Since the maps
xi are constant, we have Jx1 , x2 K = −[x1 , x2 ], the standard matrix bracket in sl(2),
and
Lρ(x1 ) (f2 (u)) = α2 (2uβ11 + β12 − u2 β13 )
Lρ(x2 ) (f1 (u)) = α1 (2uβ21 + β22 − u2 β23 )
ϕ[x1 ,x2 ] (u, ξ) = − ((β11 β22 − β12 β21 ) 2ξ 2 + (β11 β23 − β13 β21 ) (−2ξ 3 )
Finally, we have
+ (β12 β23 − β13 β22 ) ξ 1 )
α2
0
2u
1
−u2
2
3
β21
−2u
0
2ξ
−2ξ
α1 β11 β12 β13
Λ(u, ξ)(η1 , η2 ) = −
−1 −2ξ 2 0
ξ 1 β22
2
3
1
β23
u
2ξ
−ξ
0
T
= − α1 β1 [Λ] α2 β2
14
where this defines the skew-symmetric matrix, [Λ].
From this example, we see that the Poisson bracket on E ∗ can be defined as
follows: given functions F, G : E ∗ → R, we define
{F, G} =
Fu Fξ1 Fξ2 Fξ3
[Λ]
Gu Gξ1 Gξ2 Gξ3
T
Indeed, skew-symmetry and the Liebnitz rule are self-evident, while it is straightforward to check the Jacobi identity
{F {G, H}} + {G, {H, F }} + {H, {F, G}} = 0.
Looking more closely at the above example, we see that the matrix [Λ] has a
striking structure, indeed, we have
0
2u
1
−u2
!
2
3
0
Φ
−2u
0
2ξ
−2ξ
=
[Λ] =
(25)
−1 −2ξ 2 0
ξ1
−ΦT Λ(sl(2)∗ )
0
u2 2ξ 3 −ξ 1
where Φ is the matrix of infinitesimals, and Λ(g∗ ) is the structure matrix for standard Lie Poisson bracket on g∗ in its matrix representation.
The following result is immediate from Theorem 2.13.
Theorem 2.14 (Poisson structure on M × g∗ ). Let G × M → M be a left action
of the Lie group G on the manifold M , with matrix of infinitesimals, Φ. Suppose
coordinates on M are denoted as z and coordinates on g∗ are denoted as ξ. Let
Λ(g∗ ) be the bi-vector for the Lie Poisson bracket on g∗ , in its matrix representation
deriving from the same coordinates on G as used to obtain Φ. Then
0
Φ
∇z H
T
T
∇ξ F
{F, H} = ∇z F
(26)
−ΦT Λ(g∗ )
∇ξ H
is a Poisson bracket on C ∞ (M × g∗ , R). If the action is a right action, then
∇z H
0
−Φ
T
T
∇ξ F
{F, H} = ∇z F
∇ξ H
ΦT Λ(g∗ )
(27)
is a Poisson bracket on M × g∗ .
Remark 2.15. In the sequel, we denote the Poisson structure matrices in either
case as [Λ].
The set of examples covered by this theorem include both the canonical Darboux
and the Lie Poisson brackets. If the Lie group action is trivial, that is, g · z = z
for all g ∈ G, then the matrix of infinitesimals is identically zero, and we have
only the Lie Poisson structure on g∗ . Meanwhile, if the Lie group action consists of
translations, then we recover the standard Darboux structure, as in the following
Corollary.
15
Corollary 2.16. If G = Rr = M , and the action is (ǫ, z) 7→ z +ǫ, or in coordinates,
(ǫ1 , . . . , ǫr ) · (z1 , . . . , zr ) = (ǫ1 + z1 , . . . , ǫr + zr )
then
[Λ] =
where Ir is the r × r identity matrix.
0 Ir
−Ir 0
Proof. For this action, Φ is the identity matrix, while the Lie Poisson matrix is
zero, as the Lie algebra is abelian.
We now show that the Poisson structure given by Theorem 2.14 obtained from
linear actions of matrix Lie groups are isomorphic to the Lie Poisson brackets of
their semi-direct products. We begin with an example.
Example 2.17. It is simpler to show the result beginning with the contragredient
linear action of G, and to use the standard matrix representation of the semi-direct
product. Hence we take the action of SL(2) on M = R2 to be,
(g, (x, y)T ) 7→ g −T (x, y)T
so that the matrix of infinitesimals for the given action is
Φ=
Then the Poisson structure given
0
0
Λ=
x
0
y
x
y
a
b
c
−x 0 −y
.
y −x 0
by Theorem (2.14) is
0 −x
0
−y
0
y
−x
0
2
y
0
2ξ −2ξ 3
.
x −2ξ 2 0
ξ1
0 2ξ 3 −ξ 1
0
(28)
We now compare this with the standard Lie Poisson matrix for the Lie algebra of
SL(2) ⋉ R2 . We use the standard matrix representation for this Lie algebra, given
by
vc 0
vb 0
0 e1
0 e2
va 0
w1 =
, v̄c =
, w2 =
, v̄b =
, v̄a =
0 0
0 0
0 0
0 0
0 0
where e1 = (1, 0)T , e2 = (0, 1)T , and va , vb and vc are given in Equation (8). The
Lie bracket table with respect to this basis is
v̄a
v̄b
v̄c
[ , ] w1 w2
w1 0
0
−w1
0
−w2
0
w2 −w1
0
w2 0
v̄a w1 −w2
0
2v̄b −2v̄c
0
w1 −2v̄b
0
v̄a
v̄b
v̄c w2
0
2v̄c −v̄a
0
16
It can be seen that if the coefficient functions corresponding to v̄a , v̄b and v̄c are ξ 1 ,
ξ 2 and ξ 3 and those corresponding to w1 and w2 are x and y respectively, then the
Poisson structure matrix for this Lie algebra will be identical to that in (28).
Remark 2.18. We note that in both the example and in the proof which follows,
we could have started with the action on Rn to be (g, v) 7→ gv and then shown that
the Poisson structure obtained was the same as that for Lie Poisson bracket using
the contragredient representation of the semi-direct product.
Lemma 2.19. If G ⊂ GL(n, R) is a Lie group, then the Poisson structure given
by Theorem (2.14) for the action
G × R n → Rn ,
(g, v) 7→ g −T v
is isomorphic to the Lie Poisson structure on the dual of the Lie algebra of G ⋉ Rn .
Proof. Let (z 1 , · · · , z n )T be coordinates on Rn and let v1 ,. . . vr be a basis of the
Lie algebra g of G. Then, since we take the contragredient action, the matrix of
infinitesimals is the n × r matrix
Φ(z) = −v1T (z 1 , · · · , z n )T , · · · , −vrT (z 1 , · · · , z n )T
and the Poisson structure matrix arising from this action is then
0
Φ(z)
,
Λ=
−Φ(z)T Λ(g∗ )
(29)
Let us denote the semi-direct product as H = G⋉R, with (g, z)⋉(h, w) = (gh, gw+
z). The Lie Algebra h of H has a representation in gl(n + 1) with basis
vi 0
0 ej
wj =
| i = 1, . . . r, j = 1, . . . , n
, v̄i =
0 0
0 0
where ej = (0, . . . , 0, 1, 0, . . . 0)T where the non-zero component is in the jth place.
We have that [wi , wj ] = 0 while
X
X
[wj , v̄i ] = −
(vi )kj wk =
−viT jk wk .
k
k
P
P
Further, if [vi , vj ] = ℓ cℓij vℓ then [v̄i , v̄j ] = ℓ cℓij v̄ℓ . If we take the coefficient
function corresponding to v̄i to be ξ i , i = 1, . . . r and the coefficient function corresponding to wj to be z j , j = 1, . . . n then the Lie-Poisson bracket on h∗ will have
for its structure matrix, that of Equation (29).
Further examples of Theorem 2.14 will be given in §3.1.
17
2.4
A canonical group action
We next describe an action of G on M × g∗ which is canonical for the Poisson
brackets in Theorem 2.14, that is, they define diffeomorphisms that preserve the
Poisson bracket.
We first recall our remarks concerning the Adjoint action from §1.1. The Adjoint
action of G on g, for matrix groups and its associated matrix Lie algebra, is given
by conjugations
G × g → g,
(g, v) 7→ Ad(g)(x) = gvg −1 ,
and this induces the map on the associated basis {ξ1 , ξ2 , . . . , ξr } of g∗∗ , given by
ξ 7→ e
ξ = ξAd(g)
where ξ = (ξ1 , ξ2 , . . . , ξr ). Further,
recall the Lie–Poisson matrix Λ(g∗ ) depends
P k
∗
on ξ, specifically, Λ(g )ij =
cij ξk . Writing Λ(g∗ ) = Λ(g∗ )(ξ) to make clear this
dependence, we have
Λ(g∗ )(e
ξ) = Ad(g)T Λ(g∗ )(ξ)Ad(g)
(30)
by Proposition 1.5.
Theorem 2.20. Suppose coordinates on M are denoted as z, so that the group
action is written as z 7→ g · z, and coordinates on g∗ are denoted as ξ. Then the
action of the Lie group on M × g∗ given by
G × (M × g∗ ) → M × g∗ ,
g · (z, ξ) = g −1 · z, ξAd(g)
is canonical for the Poisson bracket (26).
Proof. Write g −1 · z = ze. Then by the chain rule,
−T
∂e
z
∇z
∇z 7→ ∇ze =
∂z
and similarly, since the action on ξ is linear,
∇ξ 7→ (Ad(g))−1 ∇ξ .
Denote by D the Jacobian matrix in
−T
∂ (g −1 ·z )
∇
∇z
0
z
∂z
.
7→
∇ξ
∇ξ
−1
0
Ad(g)
Next, we recall Equation (12),
−1
∂ (g −1 · z)
Φ(g −1 · z) = Φ(z)Ad(g)
∂z
while Λ(g∗ ) transforms as in Equation (30).
It is then straightforward to check that
0
Φ(z)
0
Φ(g −1 · z)
T
D=
D
−Φ(z) Λ(g∗ )(ξ)
−Φ(g −1 · z) Λ(g∗ )(ξAd(g))
as required.
18
The result is straightforward to verify in the examples.
Example 1.3 (cont.) We have for the inverse projective action, u 7→ (du −
b)/(−cu + a) with ad − bc = 1 that ∂u 7→ (cu − a)−2 ∂u . It can be verified directly that for the Poisson structure matrix in (25),
2u
1
−u2
0
−2u
0
2ξ 2 −2ξ 3
[Λ](u, ξ) =
2
−1 −2ξ
0
ξ1
2ξ 3 −ξ 1
0
u2
we have that
[Λ](g
−1
· u, ξAd(g)) =
(cu − a)−2
0
0
Ad(g)
T
[Λ](u, ξ)
(cu − a)−2
0
0
Ad(g)
where Ad(g) is given in (13).
Remark 2.21. Lemma 2.19 shows that linear actions of a Lie group G give rise to
Lie Poisson brackets associated with a semidirect product, G ⋉ Rn for some n. In
this case, there is a larger group of canonical group actions given by Adjoint action
of the full semidirect product, using Proposition 1.5, rather than just that of the G
component.
3
Compatible Poisson structures
Given that a Lie group G can act on a manifold M using different actions, a natural
question to investigate would be to study the relation between different brackets
coming from different actions.
Definition 3.1. We say two Poisson brackets, { , }1 and { , }2 are compatible if
{ , } := { , }1 + { , }2
is also a Poisson bracket.
Remark 3.2. An equivalent definition is: two Poisson brackets are compatible, if
their convex linear combination is also a Poisson bracket. We will use both notions.
One can describe the condition on the infinitesimal matrices that determines
whether or not the brackets given by Theorem 2.14 are compatible.
Proposition 3.3. Let G act on M using two actions ·1 and ·2 , with infinitesimal
matrices Φ1 and Φ2 . Let Θi = ±Φi , i = 1, 2 with the sign depending on the action
being left or right. Then the two Poisson brackets defined by Theorem 2.14 using
the two actions are compatible, whenever
X
ℓ
(Θ1 − Θ2 )j,ℓ
∂(Θ1 − Θ2 )j,m
∂(Θ1 − Θ2 )i,m X 1
−
= 0,
(Θ − Θ2 )i,ℓ
∂zℓ
∂zℓ
ℓ
for any i, j, m.
19
(31)
Proof. The condition for a bracket defined by a matrix of the form (26) to be Poisson
is well known and can be found, for example, in (6.15) at [17]. If Λ(g∗ ) = (Λi,j ) is
the Poisson bi-vector, and Θ = (Θi,j ) is as in the statement, the bracket is Poisson
if
#
"
j,m
X ∂Θi,m
X ∂Λi,j
∂Θ
(32)
Θr,m −
Θj,ℓ +
Θi,ℓ = 0,
∂ξ
∂z
∂z
r
ℓ
ℓ
r
ℓ
for any i, j, m. To prove the proposition, we need to show that if we assume this
equality to be satisfied by Θ1 and Θ2 , then it will be satisfied, for example, by their
average 21 (Θ1 + Θ2 ) - with the same values of Λi,j , whenever (31) holds true. This
is shown through a straightforward calculation.
In the next theorem we solve Equation (32) and classify the types of actions
that give raise to compatible Poisson brackets.
Theorem 3.4. Assume we have two actions of a Lie group G on a manifold M ,
and let X i : g → X(M ) be the map associating to an element of g its infinitesimal
generator as in Equation (2), for the two actions i = 1, 2. Let X be the difference
vector field, namely X = X 1 − X 2 : g → X(M ). Then the Poisson brackets are
compatible if, and only if X(g) is a commutative algebra and the actions differ by
a translation.
Proof. For simplicity, let us assume that both actions are left actions (similar arguments work for the other combinations). Let {vj | j = 1, . . . , r} be the basis for g
generating both infinitesimal matrices Φi , and let Xji = X i (vj ) be the infinitesimal
generator in the vj direction whose components define the matrices Φi , i = 1, 2.
Formula (31) can be described as
1
(33)
(Xj − Xj2 )(Θ1 − Θ2 )i,m − (Xi1 − Xi2 )(Θ1 − Θ2 )j,m = 0.
Let X = X 1 − X 2 . Given that
X i = X(vi ) =
X
m
(Θ1 − Θ2 )i,m
∂
,
∂zm
condition (33) is equivalent to
[Xj1 − Xj2 , Xi1 − Xi2 ] = [Xi , Xj ] = 0
for any i, j. Thus, the Poisson brackets are compatible, if, and only if, the vector
fields {Xi } commute, as stated.
Assume that in a neighborhood of a point z the rank of {Xi } is constant and
equal ℓ, with dimM = p and dimG = r. Without loss of generality, assume {Xi }ℓi=1
are independent. Standard arguments in differential geometry tells us that there
exists a coordinate system u around z such that
Xi =
∂
,
∂ui
i = 1, . . . , ℓ,
Xj = 0,
20
j = ℓ + 1, . . . , r.
From here we conclude that
∂
, i = 1, . . . , ℓ,
Xi1 = Xi2 +
∂ui
Xi1 = Xi2 ,
j = ℓ + 1, . . . , r.
Therefore, locally around z, g ·1 u = g ·2 u + w, where w is constant (it suffices to
differentiate the difference between the two actions and prove that it is independent
of u). Thus, the actions differ by a translation in the direction of u1 , . . . , uℓ .
Notice that if the point z ∈ M is a singularity where the rank of {Xi } is less
than ℓ, then we can conclude only that
Xj =
ℓ
X
aij Xi ,
j = ℓ + 1, . . . , p,
aij = aij (uℓ+1 , . . . , up ),
i=1
so that
Xj1 = Xj2 +
ℓ
X
aij Xi = Xj2 +
i=1
If we define
bjs = Xjs −
X
r
X
i=1
ℓ
X
aij Xis ,
aij (Xi1 − Xi2 ),
s = 1, 2,
j = ℓ + 1, . . . , p.
j = ℓ + 1, . . . , p,
i=1
bj1 = X
bj2 , but these are not infinitesimal generators in general and we cannot
then X
conclude anything in terms of the group actions.
Example 3.5. A simple example of two compatible Poisson brackets in our class
is given by the following two actions on the plane, so M = R2 , which differ by a
translation action;
g ·1 x = exp(λ)x + µy
g ·1 y = y
The matrix representation of the Lie
exp(λ)
0
G=
0
g ·2 x = exp(λ)x + µy + ǫ
g ·2 x = y + δ
group is
µ ǫ
1 δ
, | λ, µ, ǫ, δ ∈ R .
0 1
If the Poisson structure matrices for each action are denoted [Λ1 ] and [Λ2 ] respectively, then their convex linear sum leads to a one parameter family of Poisson
structure matrices,
0
0
x
y
k 0
0
0
0
0
0 k
2
−x 0
0
ξ
ξ3 0
[Λ] =
2
3 .
−y
0
−ξ
0
0
ξ
−k 0 −ξ 3 0
0 0
0 −k 0 −ξ 3 0 0
It is readily checked that the Jacobi identity holds for this bracket, for all k.
21
3.1
The resulting Hamiltonian systems
We now consider Hamiltonian systems given by associated to the Poisson structure
given by Theorem 2.14. For a Hamiltonian function H = H(z, ξ), we have the
Hamiltonian system given by
!
Φ
0
ż
Hz
.
(34)
=
Hξ
−ΦT
Λ(g∗ )
ξ˙
Example 3.6. We consider a nonlinear action of SO(3) on R2 , given in ([9], Example 7.1). If we set the coordinates on R2 to be (x, y) then the infinitesimal vector
fields are given by
X1 = y∂x − x∂y
X2 = 21 (1 + x2 − y 2 ) ∂x + xy∂y
X3 = xy∂x + 21 (1 − x2 + y 2 ) ∂y .
The Poisson structure matrix is
0
0
y
0
0
−x
−y
x
0
Λ=
1
− (1 + x2 − y 2 )
−xy
ξ3
2
1
2
2
−xy
− 2 (1 − x + y ) −ξ 2
xy
1
(1 − x2 + y 2 )
2
ξ2
−ξ 1
0
(35)
The Jacobi identity can be checked directly. In Figure 1 we show orbits of the
Hamiltonian system with
1
2
(1 + x2 − y 2 )
xy
−ξ 3
0
ξ1
H = 51 (x2 + y 2 ) + 2(ξ 1 )2 − (ξ 2 )2 + 3(ξ 3 )2
and the Poisson structure Λ given in (35), with the unbroken curves, while the
3
dashed line in the second plot is for H = 2ξ 1 ξ 2 − (ξ 3 ) and the Lie-Poison structure,
Λ(so(3)∗ ).
We can consider the Hamiltonian equations in terms of the Lie group action, at
some given point (z0 , ξ0 ). Since the negative of Λ(g∗ ) is the matrix of infinitesimals
for the induced Adjoint action of G on g∗ by Proposition 1.5 (2), we have the
following result.
Proposition 3.7. If H = H(z, ξ) is an invariant of the Lie group action,
(z, ξ) 7→ (g −1 ·z, ξAd(g))
that is, H(g −1 · z, Ad(g)T ξ) = H(z, ξ) for all g ∈ G, then for the Hamiltonian flow,
Equation (34),
ξ̇ ≡ 0.
(36)
Proof. By the invariance, we have
0 = −ΦT ∇z H − Λ(g∗ )∇ξ H.
But the right hand side is exactly ξ̇ for the Hamiltonian flow.
22
Figure 1: For the Hamiltonian H = 51 (x2 + y 2 ) + 2(ξ 1 )2 − (ξ 2 )2 + 3(ξ 3 )2 , the plots
˙ T = Λ(∇z H, ∇ξ H)T with Λ given in (35) the initial data x(0) = y(0) =
for (ż, ξ)
ξ1 (0) = ξ2 (0) = ξ3 (0) = 1 are shown. In (ii), the plot for the Lie Poisson system for
so(3)∗ with H = 2(ξ 1 )2 − (xi2 )2 + 3(ξ 3 )2 , with the same initial data, is shown for
comparison with the dashed line.
(ii) t 7→ (ξ 1 (t), ξ 2 (t), ξ 3 (t))
(i) t 7→ (x(t), y(t))
Example 3.8. Consider the action of SL(2) on the extended plane given as
au + b
v
(u, v) 7→
,
cu + d (cu + d)2
where
g=
a b
c d
,
ad − bc = 1.
Then the invariants of the action
du − b
v
(u, v, ξ) 7→
,
, ξAd(g)
−cu + a (−cu + a)2
where Ad(g) is given in Equation (13), are functions of
κ1 = 4ξ12 + ξ2 ξ3 ,
κ2 =
1 2
u ξ2 − uξ1 − ξ3
v
while the Poisson structure matrix for this Lie group action, given by Theorem 2.14
is
0
0
2u
1
−u2
0
0
2v
0 −2uv
0
2ξ2 −2ξ3
[Λ] =
−2u −2v
.
−1
0 −2ξ2 0
ξ1
u2 2uv 2ξ3 −ξ1
0
It is readily checked that for the Hamiltonian H = H(κ1 , κ2 ), Proposition 3.7 holds.
We can also understand the first set of equations, by comparing them to an
infinitesimal action. Fix the point (z0 , ξ) ∈ M × g∗ . If we set g∇ξ H (ǫ) to be a
23
smooth path in G with g(0) = e satisfying
g∇ξ H ′ (0) =
then we have that
ż
3.2
z=z0 ,ξ=ξ0
=
r
X
Hξi (z0 , ξ0 )vi ,
i=1
d
dǫ
ǫ=0
g∇ξ H (ǫ) · z0 .
Prolongation and the use of Lie group based moving
frame coordinates
Lie group actions on manifolds may be prolonged to act on curves and surfaces
immersed in M . In particular, they may be prolonged to act on the jet bundle
over M (cf. [14]). If a Lie group action is locally effective on subsets, then the
action will become free and regular after sufficient prolongation [5], in which case
a moving frame may be defined locally. Many actions occurring in practice have
the property that a sufficient prolongation will result in the existence of a moving
frame for the action. The frame provides co-ordinates on its domain, which look
like the cartesian product of a neighbourhood of the identity e of the Lie group,
crossed with a transverse cross-section to the group orbits, which has invariants
of the group action as coordinates. We will show that the Hamiltonian systems
studied in the previous section have these invariants as constants of motion, so that
we may study the system purely in terms of the frame variables and the coordinates
of g∗ .
We recall some basic definitions and constructions; full details are given in ([14]
Ch 4).
Figure 2: If the action is free and regular on a domain U ⊂ M , then there will
be a transverse cross-section K to the orbits in U , such that the intersection of
K with the orbit through a point z, is a unique point, {k}. The unique element
σ(z) ∈ G such that σ(z) · z = k defines the frame, σ : M → G. We have both that
σ(g · z) = σ(z)g −1 for a left action, and local coordinates z = (σ(z), σ(z) · z).
5
K
all
σ(z)
4
z
3
O(z)
different
{k} = O(z)2 ∩ K
orbits
1
0
0
1
2
3
4
24
Given a left Lie group action G × M → M then a moving frame is an equivariant
map σ : M → G such that σ(g · z) = σ(z)g −1 (a right frame), or σ(g · z) = gρ(z)
(a left frame). A moving frame exists if the Lie group action is free and regular.
A (local) moving frame is usually calculated by setting the frame to be such that
σ(z) · z ∈ K where K is the locus of a set of equations, Φ(z) = 0, known as the
normalisation equations. In other words, σ satisfies Φ(σ(z) · z) = 0. The action
is free and regular if the conditions for the Implicit Function Theorem hold for
these equations. This method produces a right frame; since the Implicit Function
Theorem yields a unique solution and both h = σ(g · z) and h = σ(z)g −1 solve
Φ(h · (g · z)) = 0, they are equal. The group inverse of a right frame is a left
frame. If K is transverse to the orbits of the action, then the frame defines local
coordinates. If U is the domain of the frame, then we have
U = dom(σ) ≈ G × K,
z 7→ (σ(z), σ(z) · z),
see Figure 2 for an illustration.
It can be readily seen that for a left action and a right frame, that I(z) = σ(z)·z
is invariant, indeed, I(g · z) = σ(g · z) · (g · z) = ρ(z)g −1 (g · z) = σ(z) · z = I(z). We
denote the components of I(z) as the normalised invariants.
If we have a frame on (an open domain in) M , we can use the frame adapted
coordinates to transform the Hamiltonian equations for z into equations for the
evolution of the frame. This is what we do next.
Assume for simplicity that G is a matrix Lie group. To write down our results,
we need some notation. Let (a1 , . . . , ar ) be coordinates for G in a neighbourhood
of the identity e ∈ G, with g = g(a1 , . . . , ar ) being the group element with these
coordinates, and we assume that e = g(0, 0, . . . , 0). If we define
vi =
d
dǫ
ǫ=0
g(0, . . . , 0, ai (ǫ), 0, . . . 0)
then v1 , . . . , vr form a basis for g. Further, let the Jacobian of the map, Rg−1 :
G → G, Rg−1 (h) = hg −1 at the identity element, Te Rg−1 , be denoted by Φg .
Proposition 3.9. Assume in the domain U that there is a frame σ : U → G for
the left action of G on M . Let [Λ] be the structure matrix for the Poisson bracket
defined in (26) by the group action, and let H be a Hamiltonian function defined on
U × g∗ . In the frame adapted coordinates z 7→ (σ(z), σ(z) · z) on U , we have that the
Hamiltonian equations defined by H and Λ on the coordinates (σ(z), σ(z) · z) are
d
σ(z)
dt
= −σ(z)
d
(σ(z) · z) = 0.
dt
P ∂H
vi
∂ξi
(37)
Proof. Let (a1 , . . . , ar ) be coordinates for G in a neighbourhood of the identity e ∈
G. Let the frame in these coordinates be denoted as z 7→ (σ 1 (z), σ 2 (z), . . . , σ r (z)).
Assume the action of G on M is a left action (the results for a right action on
25
M are similar). The matrix of infinitesimals of the action of G on U is, in these
coordinates,
a . . . ar
1
σ(z)
Φσ(z)
.
Φ=
σ(z) · z
0
Then the Hamiltonian system is
0 0
σ(z)
d
0 0
σ(z) · z
=
dt
−ΦTσ(z) 0
ξ
Φσ(z)
∇σ(z) H
∇σ(z)·z H
0
∗
∇ξ H
Λ(g )
where in this equation, the use of the coordinate forms of σ(z), σ(z) · z and ξ are
implicit, to ease the notation. It is immediate that the second equation of (37)
holds. To see the first, we note, that
d
d
σ(g(ǫ) · z) =
dǫ ǫ=0
dǫ
P
so that if g ′ (0) =
αi vi then,
d
dǫ
ǫ=0
ǫ=0
σ(z)g(ǫ)−1 = −σ(z)g ′ (0)
σ(g(ǫ) · z) = −σ(z)
X
α i vi .
(38)
But by definition of Φσ(z) , we also have that this equation is equivalent to
d
dǫ
ǫ=0
(σ 1 (g(ǫ) · z), . . . , σ r (g(ǫ) · z)) = (α1 , . . . , αr )Φσ(z) .
Since the Hamiltonian equations for σ(z) are
σ 1 (z)
d .
T
.. = Φσ(z) ∇ξ H
dt
σ r (z)
(39)
(40)
we have, comparing (40), (39) and (38), that the first equation in (37) is simply a
restatement of (40).
We now illustrate these results with an example.
Example 1.3 (continued). We take the coordinate u for M = R to depend on
the independent variable v and we assume that v is invariant under the action, so
that g · v = v. The prolongation of the action is effected by the chain rule, and is
defined by
g · uv =
∂(g · u)
,
∂(g · v)
g · uvv =
∂ 2 (g · u)
,
∂(g · v)2
g · u(nv) =
∂ n (g · u)
∂(g · v)n
which, since g · v = v, yields
g · uv =
uv
,
(cu + d)2
g · uvv =
26
(cu + d)uvv − 2cu2v
(cu + d)3
and
g · uvvv =
(cu + d)2 uvvv − 6c(cu + d)uv uvv + 6c2 u3v
(cu + d)4
to give the first three prolonged actions. It can be seen that the prolonged action
on (u, uv , uvv )-space is free and regular, indeed, we may take the normalisation
equations
g · u = 0,
g · uv = 1,
g · uvv = 0
to obtain a frame σ on the domain uv > 0,
1
a= √ ,
uv
σ:
u
b = −√ ,
uv
c=
uvv
3/2
2uv
or in the standard matrix representation for SL(2),
√1
uv
uvv
3/2
2uv
σ(u, uv , uvv ) =
− √uuv
1 2u2vv −uuvv
3/2
2
uv
!
The equivariance of the frame is demonstrated by noting that
!
√1
√u
−
δ −β
uv
uv
σ(g · u, g · uv , g · uvv ) =
,
uvv
1 2u2vv −uuvv
−γ α
3/2
3/2
2
2uv
uv
g=
α β
γ δ
where αδ − βγ = 1. This equivariance then yields the matrix of infinitesimals
for the action on the frame. If we use the frame to change coordinates from z =
(u, uv , uvv , uvvv , u4v , . . . ) to
u
uvv
1
b
c
u
u
a
(σ(z), σ·z) = σ = √ , σ = − √ , σ = 3/2 , I111 = σ · uvvv , I1111 = σ · u4v , . . .
uv
uv
2uv
u
where the I1···1
= σ · unv are the normalised invariants, then the matrix of infinitesimals is (reverting to labelling the independent group parameters as a, b and c)
σa
a −σ a
Ω = b 0
c −σ b
σb
σb
−σ a
0
σc
−σ c
0
b c
σ
− 1+σ
σa
u
I111
0
0
0
u
I1111
0
0
0
...
...
...
...
It can be seen that when this matrix is inserted into the Poisson structure matrix
(26), that we obtain
d u
I = 0,
dt 111
d u
I
= 0,
dt 1111
d u
I
= 0,
dt 1···1
so that these coordinates play no role, other than as constants. Thus we obtain,
no matter how high we prolong the system, a six dimensional system for the frame
27
parameters σ a , σ b and σ c and the coordinates of sl(2)∗ , ξ1 , ξ2 and ξ3 . The Poisson
structure matrix for this six dimensional system is
0
0
0
−σ a
0
−σ b
0
0
0
σ b −σ a
0
b σc
1+σ
0
0
0
−σ c
0 − σa
(41)
Λ=
a
b
c
σ −σ
σ
0
2ξ2
−2ξ3
0 σa
0
−2ξ2
0
ξ1
b
c
1+σ σ
2ξ3 −ξ1
0
σb
0
σa
for which the Jacobi identity may be verified directly. Considering the resulting
equations for the components of σ for a resulting Hamiltonian system, σ̇ = ΩT ∇ξ H,
noting that σ d = (1 + σ b σ c )/σ a and rearranging, yields
a b
a b
H ξ1 H ξ 2
σ̇ σ̇
σ σ
=−
Hξ3 −Hξ1
σ̇ c σ̇ d
σc σd
verifying our remarks that a Lie group integrator may be used to integrate the
Hamiltonian equations for the frame.
Finally, we illustrate our results by considering the Hamiltonian,
1 2
(σ b )2
1
(σ c )2
a −4
2
2
2
2
2
H = (u + ux + uxx ) + ξ1 + ξ2 + ξ3 =
(σ ) + a 2 + 4 a 6 + ξ12 + ξ22 + ξ32 ,
5
5
(σ )
(σ )
(42)
with initial data u(0) = uv (0) = uvv (0) = ξ1 (0) = ξ2 (0) = ξ3 (0) = 1 or σ a (0) = 1,
σ b (0) = −1 and σ c (0) = 21 . We plot the results in Figure 3. It appears (to the naked
eye) that the orbit for (ξ1 (t), ξ2 (t), ξ3 (t)) runs from one periodic orbit to another,
while the orbit for the Lie Poisson system with the same initial data is periodic, so
that perhaps this orbit has split into two. In considering this system, we have made
no use of the fact that u,v uv and uvv are related by differentiation with respect
to v, and we could just as easily have called them u, u1 and u2 , simply using the
prolongation method to obtain a free and regular action and hence a frame.
4
Geometric interpretation of the second bracket
The second Lie bracket (20) was discussed in [16] in terms of a connection having
zero curvature and constant torsion. The description which follows can be described
in terms of Lie algebroid bisections (see [18]). Instead, we present a more algebraic
description, better suited to our audience.
The second bracket has a natural geometric interpretation that we proceed to
describe next. We first note there is a natural product on the group of sections
A1 (M, M × G) on M , defined by
(z, g(z)) ·nat (z, h(z)) = (z, g(z)h(z)).
28
(43)
˙T =
Figure 3: For the Hamiltonian H, given in (42), some plots for (σ̇, ξ)
Λ(∇σ H, ∇ξ H)T with Λ given in (41) and the initial data σ a (0) = 1, σ b (0) = −1,
σ c (0) = 21 , ξ1 (0) = ξ2 (0) = ξ3 (0) = 1 are shown. In Plot (i), the dashed line is for
H = ξ12 + ξ22 + ξ32 , the Lie Poisson structure Λ(sl(2)∗ ), and the same initial data.
(i) t 7→ t 7→ (ξ1 (t), ξ2 (t), ξ3 (t))
(ii) t 7→ u(t) = −σ b (t)/σ a (t)
Recall the definition of an action, Definition 1.1. Assume we have an action of
G on M given by
G×M →
M
(g, s) → λ(g, s) = g · s
One might think that this action induces a natural action of the group of sections
A1 (M, M × G) on M , defined by (g, s) → λ(g(s), s) = g(s) · s. But this is not an
action with respect to the natural product, given in Equation (43), since, if λ is,
for example, a left action, one has
(gh, s) → λ(g(s)h(s), s) = λ(g(s), λ(h(s), s))
while
(g, (h, s)) → (g, λ(h(s), s)) → λ(g(λ(h(s), s)), λ(h(s), s)).
On the other hand, we can define a different product that will give A1 (M, M × G)
a structure of local Lie group (close to the identity), and will allow us to define a
natural local action on M . If λ is a left action of G on M , define
A1 (M, G) × A1 (M, G) →
A1 (M, G),
(g(s), h(s)) → (g ∗ h)(s) = g(λ(h(s), s))h(s),
while if λ is a right action, define
A1 (M, G) × A1 (M, G) →
A1 (M, G),
(g(s), h(s)) → (g ∗ h)(s) = g(s)h(λ(g(s), s)).
Proposition 4.1. The product ∗ is associative. If e(s) is the unit section with
e(s) = e for all s ∈ M , then (e ∗ h)(s) = (h ∗ e)(s) = h(s), and in a neighborhood
29
of e ∈ A1 (M, G), with respect to the C 1 -topology in A1 (M, G), the inverse element
exists although the map g → g −1 is not smooth in general. The map
A1 (M, G) × M →
M
(g, s) → σ(g, s) = λ(g(s), s)
is an action of the formal Lie group A1 (M, G) on M , with the same parity as the
original action of G on M .
Proof. The property e ∗ h = h ∗ e = h is trivially satisfied. Associativity also follows
from
((g ∗ h) ∗ f )(s)
= (g ∗ h)(λ(f (s), s))f (s) = g(λ(h(λ(f (s), s)), λ(f (s), s))h(λ(f (s), s))f (s)
= g(λ(h(λ(f (s), s))f (s), s))h(λ(f (s), s))f (s) = g(λ((h ∗ f )(s), s))(h ∗ f )(s)
if a left action, or from
= g ∗ (h ∗ f )(s).
((g ∗ h) ∗ f )(s)
= (g ∗ h)(s)f (λ((g ∗ h)(s), s)) = g(s)h(λ(g(s), s))f (λ(g(s)h(λ(g(s), s))), s))
= g(s)h(λ(g(s), s))f (λ((h(λ(g(s), s))), λ(g(s), s))) = g(s)(h ∗ f )(λ(g(s), s))
= (g ∗ (h ∗ f ))(s)
if a right action.
Since e(s) · s = s, the finite dimensional inverse function theorem guarantees
that g(s) · s is invertible for g in a C 1 -neighborhood of e, meaning whenever
sups∈M {|g(s) − e(s)|, |Dg(s) − De(s)|}.
is small, where | · | is any metric in G (we can assume that G ⊂ GL(n)). Therefore,
the relation g ∗−1 (g(s) · s) = g −1 (s) allows us to define a ∗-inverse of g around e(s).
Finally, if the action of G is left
σ(g ∗ h, s) = λ((g ∗ h)(s), s) = λ(g(λ(h(s), s)))h(s), s)
= λ(g(λ(h(s), s)), λ(h(s), s)) = σ(g, σ(h, s)).
If the action is right
σ(g ∗ h, s) = λ((g ∗ h)(s), s) = λ(g(s)h(λ(g(s), s)), s)
= λ(h(λ(g(s), s)), λ(g(s), s)) = σ(h, σ(g, s))
and so we have an action of A1 (M, M × G) on M with the same parity as the
original.
Consider now the ∗-conjugation
A1 (M, G) × A1 (M, G) →
A1 (M, G),
(g(s), h(s)) → (g ∗ h ∗ g ∗−1 )(s)
where g ∗−1 is the (local) inverse of g with respect to the ∗ product.
30
Theorem 4.2. Assume G acts on M and denote by A1 (M, M × G) be the local
formal Lie group with operation ∗ as described in proposition 4.1. Then, the Lie
bracket of its Lie algebra A1 (M, M × g) is defined by −J K.
Notice that G is a formal Lie group, and hence we do not have a guarantee that
the operations are smooth. The reason for it is that even though g ∗−1 exists, to
guarantee the smoothness of g → g ∗−1 we will need to apply an infinite dimensional
inverse function theorem, theorems that, when they exist, require strong conditions
and thus depend very much on each individual case. For example, different arguments may be applied when either M or G is compact, (A. Schmeding, (2018)
Private communication). Nevertheless, in order to differentiate to define the associated Lie algebra, we only need to guarantee that the map gǫ → gǫ∗−1 is smooth,
d
|ǫ=0 gǫ = v ∈ A1 (M, g). This is
for a one-parameter family gǫ such that g0 = e and dǫ
guaranteed by the standard finite dimensional inverse function theorem under the
hypothesis of proposition 4.1.
Proof. Assume G acts on the left on M , and let h(ǫ, s) be a curve in A1 (M, M × G)
d
with h(0, s) = e and dǫ
|ǫ=0 h(ǫ, s) = x(s) ∈ A1 (M, M × g). If we differentiate
g ∗ h ∗ g ∗−1 (s) = g ([h(g ∗−1 (s) · s)] · g ∗−1 (s) · s) h(g ∗−1 (s) · s)g ∗−1 (s) with respect to
ǫ at ǫ = 0, we obtain the ∗-Adjoint action of A1 (M, G) on A1 (M, g), given by
A1 (M, G) × A1 (M, g) →
(g(s), x(s)) →
A1 (M, g),
g(g ∗−1 (s) · s)x(g ∗−1 (s) · s)g ∗−1 (s)
+TR g ∗−1 (s) LX(x(g∗−1 (s)·s)) g )(g ∗−1 (s) · s),
where TR g(s) denotes the derivative of the right multiplication by g(s). Notice
that g(s) ∗ g ∗−1 (s) = g(g ∗−1 (s) · s)g ∗−1 (s) = e, and so g(g ∗−1 (s) · s) = (g ∗−1 )−1 (s).
Therefore, the ∗-Adjoint is given by
Ad∗ (g)(x)(s) = Ad((g ∗−1 )−1 (s))(x(g ∗−1 (s)·s))+TR g ∗−1 (s) LX(x(g∗−1 (s)·s)) g )(g ∗−1 (s)·s).
Next, assume we differentiate in the direction of g(s). Let g(ǫ, s) be a curve in
| (s) = y(s) ∈ A1 (M, M × g).
A1 (M, M × G) such that g(0, s) = e for all s and dg
dǫ ǫ=0
Using that g ∗−1 ∗ g = e and so g ∗−1 (ǫ, g(ǫ, s) · s) = g −1 (ǫ, s), differentiating both
sides we get
∂g ∗−1
∂g ∗−1
∗−1
|ǫ=0 (s) + LX(y) (g (0, s)) =
|ǫ=0 (s) = −y(s)
∂ǫ
∂ǫ
since g(0, s) = e implies that g ∗−1 (0, s) = e also. We have
d
|ǫ=0 Ad((g ∗−1 )−1 (s))(x(g ∗−1 (s) · s)) = [y(s), x(s)] − (LX(y) x)(s),
dǫ
while, since g(0, s) is constant, all the terms in
d
|ǫ=0 TR g ∗−1 (s) LX(x(g∗−1 (s)·s)) g )(g ∗−1 (s) · s)
dǫ
31
will vanish due to the Lie derivative of g being zero as ǫ = 0, except for the one
involving differentiation of g, namely
∂g
LX(x(s)) |ǫ=0 (s) = LX(x(s)) y.
∂ǫ
Therefore, the adjoint action of A1 (M, g) on itself (the Lie bracket), is given by
A1 (M, g) × A1 (M, g) →
A1 (M, g),
(y(s), x(s)) → [y, x] − LX(y) x + LX(x) y = −Jy, xK
A similar process proves the case of a right action of G on M .
Remark 4.3. It is worth remarking that the structure of ∗-Lie group is not global
in general and ∗-inverses might not exist even if g(s) is C 0 -close to e(s). Indeed,
it suffices to consider a left action of G on M , and a right moving frame for the
action associated to a cross section C. That is g(s), s ∈ M satisfies g(s) · s ∈ C
and g(f · s) = g(s)f −1 , for all s and all f ∈ G. In general moving frames might
only exist locally, but on the neighborhood where they exist, one would have that
(g ∗ h)(s) = g(h(s) · s)h(s) = g(s)h−1 (s)h(s) = g(s), for any h(s) ∈ A1 (M, G). That
is, g has no ∗-inverse.
5
Infinite dimensional Poisson brackets
In this chapter we will assume that M = S 1 or R. The study of the possible
applications of the second bracket to the study of completely integrable PDEs is
under way in this case. Still, preliminary results point at a possible use and we are
including them here, in our last section. In particular, we are able to prove that the
standard cocycle used to construct a central extension of the algebra C ∞ (S 1 , g) is
also a cocycle when we consider g endowed with the second bracket, rather than the
first. Furthermore, standard arguments allow us to define a companion bracket to
the Lie-Poisson bracket associated to J , K. These companions are often associated
to bi-Hamiltonian structures for well known completely integrable PDEs (e.g. KdV
in the case of g = sl(2, R)). We are currently studying under which conditions this
Hamiltonian pencil can be used to integrate PDE’s.
5.1
Central extensions
a central extension of a Lie algebra g is given by g ⊕ R, with the standard algebra
structure and the Lie bracket
[(x, l), (y, t)] = ([x, y], β(x, y)).
(44)
where the map
β :g×g→R
is skew-symmetric, bilinear, and satisfies what is known as a cocycle condition,
β(w1 , [w2 , w3 ]) + β(w2 , [w3 , w1 ]) + β(w3 , [w1 , w2 ]) = 0.
32
Under these conditions, (44) does indeed define a Lie bracket, being bilinear, skewsymmetric and satisfying the Jacobi identity. Any linear map θ : g → R defines
a central extension, with β(x, y) = θ([x, y]). Such extensions are called trivial, or
coboundaries.
The dual to this Lie algebra can be identified with g∗ ⊕ R, and the action on
the central extension is defined as
(ξ, l)(x, t) = ξ(x) + lt.
5.1.1
Lie-Poisson bracket for a central extension
Assume F and H are two functions on g∗ ⊕ R. The variational derivative of F and
H are given using the relation
d
|ǫ=0 F ((ξ, t) + ǫ(ν, r)) = (ν, r)(δξ F, δt F ) = ν(δξ F ) + rδt F
dǫ
for all ν ∈ g∗ , and where ξ ∈ g∗ and δξ F ∈ g, δt F ∈ R. The Lie-Poisson bracket is
thus defined as
{F, H}(ξ, r) = (ξ, r) ([(δξ F, δt F ), (δξ H, δt H)]) = ξ([δξ F, δξ H]) + rβ(δξ F, δξ H). (45)
Notice that once we fix r, we have a Poisson bracket on g∗ . It is known that the
r-family of Poisson brackets are all equivalent, except for r = 0. It is customary
to assume that r = −1, or r = 1, depending on the case, but we can choose any
constant.
5.1.2
First bracket
Assume that the bracket in our algebra is the standard commutator, [, ], and assume
that g is semisimple so that we can identify g and g∗ using the trace inner product,
assuming that they have a representation as matrices. That is, if ξ ∈ g∗ , then there
exists xξ ∈ g, such that
ξ(x) = tr(xξ x)
for all x ∈ g. If we consider, for example, M = S 1 and smooth sections C ∞ (S 1 , g)
and C ∞ (S 1 , g)∗ instead finite dimensional algebras, the inner product would be
Z
tr(xξ x).
ξ(x) =
M
Instead of S 1 we could choose smooth functions on R vanishing at infinity, or other
conditions that will ensure that boundary conditions during integration will vanish.
Let us denote by s the coordinates in M (S 1 or R). It is known that β defined as
Z
tr(xys )
β(x, y) =
M
is a cocycle for our first bracket. In this case, the Poisson structure (45) becomes
{F, H}1 (ξ, r) = ξ([δξ F, δξ H]) + rβ(δξ F, δξ H)
33
=
Z
ξ
tr x [δξ F, δξ H] + rδξ F (δξ H)s ds =
M
If we choose r = −1, then we have
Z
tr
{F, H}1 (ξ, r) =
M
Z
tr
M
xξ , δξ F − r(δξ F )s δξ H ds.
(δξ F )s + xξ , δξ F δξ H ds.
(46)
Since this is true for all H, the Hamiltonian vector field for F can be identified
with
(δξ F )s + xξ , δξ F and the Hamiltonian evolutions with (xξ )t = (δξ F )s + xξ , δξ F .
5.1.3
Second bracket
Proposition 5.1. The map β is also a cocycle when C ∞ (S 1 , g) is endowed with the
second bracket J , K.
Proof. It suffices to show that
β(Jy, zK, x) + β(Jz, xK, y) + β(Jx, yK, z) = 0
and, since β is a cocycle for the first bracket, that
Z
tr(ρ(y)(z)xs −ρ(z)(y)xs )+tr(ρ(z)(x)ys −ρ(x)(z)ys )+tr(ρ(x)(y)zs −ρ(y)(x)zs ) = 0.
M
Now, if dimM = 1, we have that ρ(x)(y) = ρ̂(x, s)ys , for some scalar ρ̂(x, s). This
implies that the above integrand is equal to
tr(ρ̂(y, s)zs xs − ρ̂(z, s)ys xs + ρ̂(z, s)xs ys − ρ̂(x, s)zs ys + ρ̂(x, s)ys zs − ρ̂(y, s)xs zs )
= tr (ρ̂(y, s)[zs , xs ] + ρ̂(z, s)[xs , ys ] + ρ̂(x, s)[ys , zs ])
= ρ̂(y, s)tr([zs , xs ]) + ρ̂(z, s)tr([xs , ys ]) + ρ̂(x, s)tr([ys , zs ]) = 0
since the trace of the commutator vanishes.
Notice that the scalar ρ̂(x, s) is linear in x. Therefore, since g is semisimple, we
can write it as
ρ̂(x, s) = tr(xE(s))
(47)
for some matrix E(s) ∈ g depending on s ∈ M . Notice also that the inner product
defined by the trace is not invariant under the Adjoint action associated to J , K. This
fact will cause the appearance of extra terms in a typical Hamiltonian evolution.
Using that β is also a cocycle for J , K, we can write the Lie-Poisson structure
associated to the central extension of J , K as
Z
{F, H}(ξ, r) =
tr xξ [[δξ F, δξ H]] + rδξ F (δξ H)s ds
M
=
=
Z
Z
M
M
tr xξ ([δξ F, δξ H] + tr(δξ F E(s))(δξ H)s − tr(δξ HE(s))(δξ F )s ) + rδξ F (δξ H)s ds.
tr [xξ , δξ F ]δξ H + tr((δξ F )E)xξ (δξ H)s − tr((δξ H)E)xξ (δξ F )s + rδξ F (δξ H)s ds
34
=α
Z
2π
tr
0
[xξ , δξ F ] − r(δξ F )s − tr((δξ F )E)xξ
Finally, we have
s
δξ H − tr((δξ H)E)xξ (δξ F )s ds
tr tr((δξ H)E)xξ (δξ F )s = tr(E(δξ H))tr xξ (δξ F )s = tr(tr xξ (δξ F )s E(δξ H)).
From here, the bracket can be written as
Z 2π
q
tr xξ , δξ F ] − r(δξ F )s − tr((δξ F )E)xξ s − tr xξ (δξ F )s E δξ H ds
{F, H}(ξ, r) = α
0
(48)
and so, if r = −1, the Hamiltonian vector field can be identified with the element
of the algebra on the left and the Hamiltonian evolution would be
(xξ )t = (δξ F )s + [xξ , δξ F ] − tr((δξ F )E)xξ s − tr xξ (δξ F )s E.
The following result is known for general Lie algebras, but we reproduce the
proof to make the paper self-contained.
Theorem 5.2. Consider the bracket
Z
{F, H}0 (ξ) = α
2π
0
tr xξ0 Jδξ F, δξ HK ds,
(49)
where ξ0 ∈ g∗ is constant. The bracket (49) is Poisson and compatible with (48) for
any value of the central parameter r and any choice of ξ0 .
Proof. First of all, recall that the second variation of a functional F (ξ) defined on
g∗ is a symmetric bilinear form on g∗ , which we will denote by D2 F (ξ)(∗, ∗). In that
sense, D2 F (ξ)(η, ∗) is a linear map on g∗ , and can be identified with an element of
(g∗ )∗ = g, as follows
ν(D2 F (ξ)(η, ∗)) = D2 F (ξ)(η, ν) = η(D2 F (ξ)(ν, ∗))
for any ξ, η, ν ∈ g∗ . To make calculations easier to read, let us denote
ν(x) = hν, xi
for any ν ∈ g∗ , x ∈ g. In that case, the bracket can be written as
Z 2π
hξ0 , Jδξ F, δξ HKids.
{F, H}0 (ξ) = α
0
Since J , K is a Lie bracket, we have that
DJδξ F, δξ HK(ξ)(η) = JD2 F (ξ)(η, ∗), δξ HK + Jδξ F, D2 H(ξ)(η, ∗)K.
Therefore
Z
Z 2π
hη, δξ {F, H}0 ids =
0
2π
0
hξ0 , JD2 F (ξ)(η, ∗), δξ HK + Jδξ F, D2 H(ξ)(η, ∗)Kids
35
=
Z
2π
0
=
=
∗
Z
Z
hJδξ H, ξ0 K∗ , D2 F (η, ∗)i − hJδξ F, ξ0 K∗ , D2 H(ξ)(η, ∗)ids
2π
0
0
2π
D2 F (η, Jδξ H, ξ0 K∗ ) − D2 H(ξ)(η, Jδξ F, ξ0 K∗ ) ds
hη, D2 F (Jδξ H, ξ0 K∗ , ∗) − D2 H(ξ)(Jδξ F, ξ0 K∗ , ∗)ids
where J , K is the dual of J , K. From here we conclude that
δξ {F, H}0 = D2 F (Jδξ H, ξ0 K∗ , ∗) − D2 H(ξ)(Jδξ F, ξ0 K∗ , ∗).
We can now calculate Jacobi’s identity. If F, G, H are three functionals on A1 (M, g∗ ),
we have
Z 2π
Z 2π
hJδξ G, ξ0 K∗ , δξ {F, H}0 ids
hξ0 , Jδξ {F, H}0 , δξ GKids = α
{{F, H}0 , G}0 (ξ) = α
0
0
=α
=α
Z
Z
2π
0
hJδξ G, ξ0 K∗ , D2 F (Jδξ H, ξ0 K∗ , ∗) − D2 H(ξ)(Jδξ F, ξ0 K∗ , ∗)ids
2π
0
D2 F (Jδξ H, ξ0 K∗ , Jδξ G, ξ0 K∗ ) − D2 H(ξ)(Jδξ F, ξ0 K∗ , Jδξ G, ξ0 K∗ )ds.
Using the symmetry of the second variation, we can conclude that the circular sum
of this expression vanishes. A similar calculation shows that the sum of (48) and
(49) is also Poisson (notice that adding both brackets merely translates xξ to xξ +xξ0
in the expression of (48), so the proof that the sum is Poisson is almost identical to
that of (48) being Poisson).
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