Gulf Journal of Mathematics
Vol 4, Issue 3 (2016) 15-27
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT
RIEMANNIAN MANIFOLDS
MEHMET AKIF AKYOL1∗ AND YILMAZ GÜNDÜZALP2
Abstract. In this paper, we introduce hemi-slant submersions from almost
product Riemannian manifolds onto Riemannian manifolds. We give an example, investigate the geometry of foliations which are arisen from the definition
of a Riemannian submersion. We also find necessary and sufficient conditions
for a hemi-slant submersion to be totally geodesic.
1. Introduction
The theory of smooth maps between Riemannian manifolds has been widely
studied in Riemannian geometry. Such maps are useful for comparing geometric
structures between two manifolds. In this point of view, the study of Riemannian submersions between Riemannian manifolds was initiated by O’Neill [21] and
Gray [12], see also [8] and [34]. Riemannian submersions have several applications in mathematical physics. Indeed, Riemannian submersions have their
applications in the Yang-Mills theory ([6], [33]), Kaluza-Klein theory ([7], [16]),
supergravity and superstring theories ([17], [20]), etc. Later such submersions
were considered between manifolds with differentiable structures, see [8]. Furthermore, we have the following submersions: semi-Riemannian submersion and
Lorentzian submersion [8], Riemannian submersion [12], almost Hermitian submersion [32], contact-complex submersion [19], quaternionic submersion [18], etc.
Recently, B. Şahin [26] introduced the notion of anti-invariant Riemannian submersions which are Riemannian submersions from almost Hermitian manifolds
such that the vertical distributions are anti-invariant under the almost complex
structure of the total manifold. Besides there are many other notions related
with that of anti-invariant Riemannian submersions. see:([1], [2], [4], [5], [9],
[10], [11], [13], [14], [15], [22], [23], [24], [25], [28], [29], [30]). In particular, B.
Şahin [27] introduced the notion of semi-invariant Riemannian submersions and
slant submersions when the base manifold is an almost Hermitian manifold. He
showed that such submersions have rich geometric properties and they are useful
for investigating the geometry of the total space. On the other hand, as a generalization of semi-invariant submersions and slant submersions, Taştan, Şahin and
Date: Received: Mar 10, 2016; Accepted: May 2, 2016.
∗
Corresponding author.
2010 Mathematics Subject Classification. Primary 53C15; Secondary 53C40.
Key words and phrases. Hemi-slant submersion, Almost product Riemannian manifold, Riemannian submersion.
15
16
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
Yanan [31] introduced the notion of hemi-slant submersions. They showed that
such submersions have rich geometric properties and they are useful for investigating the geometry of the total space. The present work, we define and study
the notion of hemi-slant submersions from almost product Riemannian manifolds.
The paper is organized as follows. In section 2, we recall some notions needed for
this paper. In section 3, we define hemi-slant submersions from an almost product Riemannian manifold onto a Riemannian manifold. We also investigate the
geometry of leaves of the distributions. Finally we give necessary and sufficient
conditions for such submersions to be totally geodesic.
2. Preliminaries
In this section, we define almost product Riemannian manifolds, recall the
notion of Riemannian submersions between Riemannian manifolds and give a
brief review of basic facts of Riemannian submersions.
Let M be a m-dimensional manifold with a tensor F of a type (1,1) such that
F 2 = I, (F 6= I).
(2.1)
Then, we say that M is an almost product manifold with almost product structure
F. We put
1
1
P = (I + F ), Q = (I − F ).
2
2
Then we get
P + Q = I, P 2 = P, Q2 = Q, P Q = QP = 0, F = P − Q.
Thus P and Q define two complementary distributions P and Q. We easily see
that the eigenvalues of F are +1 or −1. If an almost product manifold M admits
a Riemannian metric g such that
g(F X, F Y ) = g(X, Y )
(2.2)
for any vector fields X and Y on M, then M is called an almost product Riemannian manifold, denoted by (M, g, F ). Denote the Levi-Civita connection on M with
M
respect to g by ∇ . Then, M is called a locally product Riemannian manifold
M
[34] if F is parallel with respect to ∇ , i.e.,
M
∇X F = 0, X ∈ Γ(T M ).
(2.3)
Let (M, g) and (N, g ′ ) be two Riemannian manifolds. A surjective C ∞ −map
π : M → N is a C ∞ −submersion if it has maximal rank at any point of M.
Putting Vx = kerπ∗x , for any x ∈ M, we obtain an integrable distribution V,
which is called vertical distribution and corresponds to the foliation of M determined by the fibres of π. The complementary distribution H of V, determined by
the Riemannian metric g, is called horizontal distribution. A C ∞ −submersion
π : M → N between two Riemannian manifolds (M, g) and (N, g ′ ) is called a
Riemannian submersion if, at each point x of M, π∗x preserves the length of the
horizontal vectors. A horizontal vector field X on M is said to be basic if X is
π−related to a vector field X ′ on N. It is clear that every vector field X ′ on N
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT RIEMANNIAN MANIFOLDS 17
has a unique horizontal lift X to M and X is basic.
We recall that the sections of V, respectively H, are called the vertical vector
fields, respectively horizontal vector fields. A Riemannian submersion π : M → N
determines two (1, 2) tensor fields T and A on M, by the formulas:
M
M
T (E, F ) = TE F = H∇VE VF + V∇VE HF
(2.4)
and
M
M
A(E, F ) = AE F = V∇HE HF + H∇HE HF
(2.5)
ˆV W;
∇V W = T V W + ∇
(2.6)
for any E, F ∈ Γ(T M ), where V and H are the vertical and horizontal projections
(see [8]). From (2.4) and (2.5), one can obtain
M
M
M
∇V X = TV X + H(∇V X);
M
M
∇X V = V(∇X V ) + AX V ;
M
⊥
M
∇X Y = AX Y + H(∇X Y ),
(2.7)
(2.8)
(2.9)
for any X, Y ∈ Γ((kerπ∗ ) ) and V, W ∈ Γ(kerπ∗ ). Moreover, if X is basic then
M
M
H(∇V X) = V(∇X V ) = AX V.
(2.10)
We note that for U, V ∈ Γ(kerπ∗ ), TU V coincides with the second fundamental
form of the immersion of the fibre submanifolds and for X, Y ∈ Γ((kerπ∗ )⊥ ),
AX Y = 12 V[X, Y ] reflecting the complete integrability of the horizontal distribution H. It is known that A is alternating on the horizontal distribution:
AX Y = −AY X, for X, Y ∈ Γ((kerπ∗ )⊥ ) and T is symmetric on the vertical
distribution: TU V = TV U, for U, V ∈ Γ(kerπ∗ ).
We now recall the following result which will be useful for later.
Lemma 2.1. (see [8],[21]). If π : M → N is a Riemannian submersion and
X, Y basic vector fields on M, π−related to X ′ and Y ′ on N, then we have the
following properties
(1) H[X, Y ] is a basic vector field and π∗ H[X, Y ] = [X ′ , Y ′ ] ◦ π;
M
N
M
N
(2) H(∇X Y ) is a basic vector field π−related to (∇X ′ Y ′ ), where ∇ and ∇
are the Levi-Civita connection on M and N ;
(3) [E, U ] ∈ Γ(kerπ∗ ), for any U ∈ Γ(kerπ∗ ) and for any basic vector field E.
Let (M, gM ) and (N, gN ) be Riemannian manifolds and π : M → N is a smooth
map. Then the second fundamental form of π is given by
(∇π∗ )(X, Y ) = ∇π∗ X π∗ Y − π∗ (∇X Y )
(2.11)
for X, Y ∈ Γ(T M ), where we denote conveniently by ∇ the Levi-Civita connections of the metrics gM and gN . Recall that π is called a totally geodesic map if
(∇π∗ )(X, Y ) = 0 for X, Y ∈ Γ(T M ) [3]. It is known that the second fundamental
form is symmetric.
18
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
3. Hemi-slant submersions
In this section, we define hemi-slant submersions from an almost product Riemannian manifold onto a Riemannian manifold, investigate the integrability of
distributions and obtain a necessary and sufficient condition for such submersions
to be totally geodesic map.
Definition 3.1. Let (M, gM , F ) be an almost product Riemannian manifold and
(N, gN ) a Riemannian manifold. A Riemannian submersion π : (M, gM , F ) →
(N, gN ) is called a hemi-slant submersion if the vertical distribution kerπ∗ of π
admits two orthogonal complementary distributions Dθ and D⊥ such that Dθ is
slant and D⊥ is anti-invariant, i.e, we have
kerπ∗ = Dθ ⊕ D⊥ .
(3.1)
In this case, the angle θ is called the hemi-slant angle of the submersion. Suppose the dimension of distribution of D⊥ (resp. Dθ ) is m1 (resp. m2 ). Then we
easily see the following particular cases.
(a) If m2 = 0, then M is an anti-invariant submersion [10].
(b) If m1 = 0 and θ = 0, then M is an invariant submersion [11].
(c) If m1 = 0 and θ 6= 0, π2 , then M is a proper slant submersion with slant
angle θ [11].
(d) If θ = π2 , then M is an anti-invariant submersion.
(e) If m1 6= 0 and θ = 0, then M is an semi-invariant submersion.
We say that the hemi-slant submersion π : (M, gM , F ) → (N, gN ) is proper if
⊥
D 6= {0} and θ 6= 0, π2 . As we have seen from above argument, anti-invariant
submersions, semi-invariant submersions and slant submersions are all examples
of hemi-slant submersions. Now, we present an example of proper hemi-slant
submersions in locally product Riemannian manifolds and demonstrate that the
method presented in this paper is effective. Note that given an Euclidean space
R8 with coordinates (x1 , ..., x8 ), we can canonically choose an almost product
structure F on R8 as follows:
F (a1 , a2 , a3 , a4 , a5 , a6 , a7 , a8 ) = (−a2 , −a1 , a4 , a3 , −a6 , −a5 , a8 , a7 ),
where a1 , ..., a8 ∈ R.
Example 3.2. Let π be a submersion defined by
π:
R8
−→
R4
8
7 x6√
, +x
).
(x1 , ..., x8 )
(x1 cos α − x4 sin α, x2 sin β − x3 cos β, x5√+x
2
2
Then it follows that
kerπ∗ = span{V1 = sin α∂x1 + cos α∂x4 , V2 = cos β∂x2 + sin β∂x3 ,
and
V3 = −∂x5 + ∂x7 , V4 = −∂x6 + ∂x8 }
(kerπ∗ )⊥ = span{H1 = cos α∂x1 − sin α∂x4 , H2 = sin β∂x2 − cos β∂x3 ,
1
1
H3 = √ (∂x5 + ∂x7 ), H4 = √ (∂x6 + ∂x8 )}.
2
2
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT RIEMANNIAN MANIFOLDS 19
Thus it follows that Dθ = span{V1 , V2 } with the slant angle cos θ = sin(β − α)
and D⊥ = span{V3 , V4 }. Also by direct computations, we get
g(H1 , H1 ) = g ′ (π∗ H1 , π∗ H1 ) and g(H2 , H2 ) = g ′ (π∗ H2 , π∗ H2 ),
g(H3 , H3 ) = g ′ (π∗ H3 , π∗ H3 ) and g(H4 , H4 ) = g ′ (π∗ H4 , π∗ H4 )
which show that π is a Riemannian submersion. Thus π is a proper hemi-slant
submersion.
Let π be a hemi-slant submersion from an almost product Riemannian manifold
(M, gM , F ) onto a Riemannian manifold (N, gN ). Then for V ∈ Γ(ker π∗ ), we put
V = PV + QV,
(3.2)
F V = φV + ωV,
(3.3)
where PV ∈ Dθ and QV ∈ D⊥ and write
where φV ∈ Γ(kerπ∗ ) and ωV ∈ Γ((ker π∗ )⊥ ). Also, for any X ∈ Γ((ker π∗ )⊥ ),
we have
F X = BX + CX,
(3.4)
⊥
where BX ∈ Γ(kerπ∗ ) and CX ∈ Γ((kerπ∗ ) ). We denote the complementary distribution to ωDθ ⊕ F D⊥ in (ker π∗ )⊥ by µ. It is invariant distribution of (kerπ∗ )⊥
with respect to F. Then, the horizontal distribution (kerπ∗ )⊥ is decomposed as
(ker π∗ )⊥ = ωDθ ⊕ F D⊥ ⊕ µ.
(3.5)
From (3.3), (3.4) and (3.5) we have
φDθ = Dθ , φD⊥ = {0}, BωDθ = Dθ , BF D⊥ = D⊥ .
On the other hand, using (3.3), (3.4) and the fact that F 2 = I, we obtain
φ2 + Bω = I, C 2 + ωB = I, ωφ + Cω = 0, BC + φB = 0.
Then by using (2.6), (2.7), (3.3) and (3.4) we get
(∇U φ)V = BTU V − TU ωV
M
(3.6)
(∇U ω)V = CTU V − TU φV
M
(3.7)
for U, V ∈ Γ(ker π∗ ), where
and
ˆ U φV − φ∇
ˆ UV
(∇U φ)V = ∇
M
M
ˆ U V.
(∇U ω)V = AωV U − ω ∇
The proof of the following theorem is exactly the same as that one for hemi-slant
submersions, see Theorem 3.4 of [22]. So, we omit it.
Theorem 3.3. Let π be a Riemannian submersion from a locally product Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then π is
a hemi-slant submersion if and only if there exists a constant [0, 1] and a distribution D on kerπ∗ such that
(a) D = {V ∈ kerπ∗ | φ2 V = λV },
(b) for any W ∈ ker π∗ orthogonal to D, we have φW = 0.
20
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
Moreover, in this case λ = cos2 θ, where θ is the slant angle of π.
Thus, from Theorem 3.3, for any Z ∈ Dθ , we conlude that
φ2 Z = cosθ Z.
(3.8)
On the other hand, for any Z, W ∈ Dθ , using (2.1), (3.3) and (3.8), we get
gM (φZ, φW ) = cos2 θgM (Z, W ).
(3.9)
Also, using (2.1), (3.3) and (3.8), we find
gM (ωZ, ωW ) = sin2 θgM (Z, W ).
(3.10)
Next, we easily have the following lemma:
Lemma 3.4. Let (M, gM , F ) be a locally product Riemannian manifold and (N, gN )
a Riemannian manifold. Let π : (M, gM , F ) → (N, gN ) be a hemi-slant submersion. Then we have
(a)
M
M
AX BY + H∇X CY = CH∇X Y + ωAX Y
M
M
V∇X BY + AX CY = BH∇X Y + φAX Y,
(b)
ˆ UV
TU φV + AωV U = CTU V + ω ∇
ˆ U φV + TU ωV = BTU V + φ∇
ˆ U V,
∇
(c)
M
M
AX φU + H∇U ωV = CAX U + ωV∇X U
M
M
V∇X φU + AX ωU = BAX U + φV∇X U,
for X, Y ∈ Γ((ker π∗ )⊥ ) and U, V ∈ Γ(ker π∗ ).
We now examine the integrability conditions for the anti-invariant distribution
D⊥ and the slant distribution Dθ .
Theorem 3.5. Let π be a purely hemi-slant submersion from a locally product
Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then the
anti-invariant distribution D⊥ is integrable if and only if we have
gN ((∇π∗ )(U, F V ) − (∇π∗ )(V, F U ), CZ) = gM (TU F V − TV F U, BZ)
for U, V ∈ Γ(D⊥ ) and Z ∈ Γ(Dθ ).
Proof. For U, V ∈ Γ(D⊥ ) and Z ∈ Γ(Dθ ), using (2.1), (2.2) and (3.4), we get
M
M
M
gM ([U, V ], Z) = gM (∇U F V, φZ) + gM (∇U F V, ωZ) − gM (∇V F U, φZ)
M
− gM (∇V F U, ωZ).
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT RIEMANNIAN MANIFOLDS 21
Since π is a hemi-slant submersion, from (2.7) and (2.11), we get
M
gM ([U, V ], Z) = gM (TU F V, φZ) + gN (π∗ (∇U F V ), π∗ ωZ) − gM (TV F U, φZ)
M
− gN (π∗ (∇V F U ), ωZ)
= gM (TU F V − TV F U, φZ) + gN ((∇π∗ )(V, F U ) − (∇π∗ )(U, F V ), ωZ)
which proves assertion.
Theorem 3.6. Let π be a purely hemi-slant submersion from a locally product
Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then the
slant distribution Dθ is integrable if and only if we have
gM (TW ωφZ − TZ ωφW , U ) = gN ((∇π∗ )(Z, ωW ) − (∇π∗ )(W, ωZ), F U )
for Z, W ∈ Γ(Dθ ) and U ∈ Γ(D⊥ ).
Proof. For Z, W ∈ Γ(Dθ ) and U ∈ Γ(D⊥ ), using (2.1), (2.2) and (3.4), we get
M
M
M
gM ([Z, W ], U ) = gM (∇Z ωW, F U ) + gM (∇Z F φW, U ) − gM (∇W ωZ, F Z)
M
− gM (∇W F φZ, U ).
If we take into account that π is a hemi-slant submersion, then from (2.7), (2.11)
and (3.9), we get
M
M
M
gM ([Z, W ], U ) = gN (π∗ (∇Z ωW ), π∗ F U ) + cos2 θgM (∇Z W, U ) + gM (∇Z ωφW , U )
M
M
M
− gN (π∗ (∇W ωZ), π∗ F U ) − cos2 θgM (∇W Z, U ) − gM (∇W ωφZ, U )
= gN ((∇π∗ )(W, ωZ) − (∇π∗ )(Z, ωW ), F U ) + cos2 θgM ([Z, W ], U )
+ gM (TZ ωφW − TW ωφZ, U )
or
sin2 θgM ([Z, W ], U ) = gN ((∇π∗ )(W, ωZ) − (∇π∗ )(Z, ωW ), F U )
+ gM (TZ ωφW − TW ωφZ, U )
which proves assertion.
Now, we investigate the geometry of the leaves of the distributions D⊥ and Dθ .
Theorem 3.7. Let π be a purely hemi-slant submersion from a locally product
Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then D⊥
defines a totally geodesic foliation on M if and only if
gN ((∇π∗ )(U, F V ), π∗ ωZ) = gM (TU V, ωφZ)
and
gN ((∇π∗ )(U, F V ), π∗ CX) = gM (TU F V, BZ)
for U, V ∈ Γ(D⊥ ), Z ∈ Γ(Dθ ) and X ∈ Γ((kerπ∗ )⊥ ).
Proof. From the definition of a hemi-slant submersion, it follows that the antiinvariant distribution D⊥ defines a totally geodesic foliation on M if and only
22
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
M
M
if gM (∇U V, Z) = 0 and gM (∇U V, X) = 0 for U, V ∈ Γ(D⊥ ), Z ∈ Γ(Dθ ) and
X ∈ Γ((kerπ∗ )⊥ ), from (2.1) and (2.2), we get
M
M
M
gM (∇U V, Z) = gM (∇U V, F φZ) + gM (∇U F V, ωZ).
Since π is a hemi-slant submersion, using (2.6), (2.11) and (3.9) we get
M
M
M
M
gM (∇U V, Z) = gM (∇U V, cos2 θZ) + gM (∇U V, ωφZ) + gN (π∗ (∇U F V ), π∗ ωZ)
or
M
sin2 θgM (∇U V, Z) = gM (TU V, ωφZ) − gN ((∇π∗ )(U, F V ), π∗ ωZ).
(3.11)
On the other hand, by using (3.4) we have
M
M
M
gM (∇U V, X) = gM (∇U F V, BX) + gM (∇U F V, CX).
If we take into account that π is a hemi-slant submersion, then by using (2.7)
and (2.11) we get
M
gM (∇U V, X) = gM (TU F V, BZ) − gN ((∇π∗ )(U, F V ), π∗ CX).
(3.12)
Thus proof follows from (3.11) and (3.12).
For the leaves of Dθ we have the following result.
Theorem 3.8. Let π be a purely hemi-slant submersion from a locally product
Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then Dθ
defines a totally geodesic foliation on M if and only if
gN ((∇π∗ )(Z, ωW ), π∗ F U ) = gM (TZ ωφW, U )
and
gN ((∇π∗ )(Z, ωφW ), π∗ X) + gN ((∇π∗ )(Z, ωW ), π∗ CX) = gM (TZ BX, ωW )
for Z, W ∈ Γ(Dθ ), U ∈ Γ(D⊥ ) and X ∈ Γ((kerπ∗ )⊥ ).
Proof. The slant distribution Dθ defines a totally geodesic foliation on M if and
M
M
only if gM (∇Z W, U ) = 0 and gM (∇Z W, X) = 0 for Z, W ∈ Γ(Dθ ), U ∈ Γ(D⊥ )
and X ∈ Γ((kerπ∗ )⊥ ), from (2.1) and (2.2), we get
M
M
M
gM (∇Z W, U ) = gM (∇Z F φW, U ) + gM (∇Z ωW, F U ).
Since π is a hemi-slant submersion, using (2.6), (2.11) and (3.9), we obtain
M
M
M
M
gM (∇Z W, U ) = gM (∇Z cos2 θW, U ) + gM (∇Z ωφW, U ) + gN (π∗ (∇Z ωW ), π∗ F U )
or
M
sin2 θgM (∇Z W, U ) = gM (TZ ωφW, U ) − gN ((∇π∗ )(Z, ωW ), π∗ F U ).
(3.13)
On the other hand, by using (3.3) and (3.4) we get
M
M
M
M
gM (∇Z W, X) = gM (∇Z φW, F X) + gM (∇Z ωW, BX) + gM (H∇Z ωW, CX).
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT RIEMANNIAN MANIFOLDS 23
Using (2.6), (2.7), (3.3), (3.9) and if we take into account that π is a hemi-slant
submersion, we obtain
M
M
M
g(∇Z W, X) = cos2 θgM (∇Z W, X) + gN (π∗ (∇Z ωφW ), π∗ X)
M
+ gM (TZ ωW, BX) + gN (π∗ (∇Z ωW ), CX)
or
M
sin2 θg(∇Z W, X) = gM (TZ ωW, BX) + gN ((∇π∗ )(Z, ωφW ), π∗ X)
(3.14)
+ gN ((∇π∗ )(Z, ωW ), π∗ CX).
Thus proof follows from (3.13) and (3.14).
From Theorem 3.7 and Theorem 3.8, we have the following result.
Theorem 3.9. Let π : (M, gM , F ) −→ (N, gN ) be a purely hemi-slant submersion
from a locally product Riemannian manifold (M, gM , F ) onto a Riemannian manifold (N, gN ). Then the fibers of π are the locally product Riemannian manifold of
leaves of D⊥ and Dθ if and only if
gN ((∇π∗ )(U, F V ), π∗ ωZ) = gM (TU V, ωφZ)
and
gN ((∇π∗ )(Z, ωφW ), π∗ X) + gN ((∇π∗ )(Z, ωW ), π∗ CX) = gM (TZ BX, ωW )
for any U, V ∈ Γ(D⊥ ), Z, W ∈ Γ(Dθ ) and X ∈ Γ((kerπ∗ )⊥ ).
For the geometry of leaves of the horizontal distribution ((kerπ∗ )⊥ ), we have
the following theorem.
Theorem 3.10. Let π : (M, gM , F ) −→ (N, gN ) be a purely hemi-slant submersion from a locally product Riemannian manifold (M, gM , F ) onto a Riemannian
manifold (N, gN ). Then the distribution (kerπ∗ )⊥ defines a totally geodesic foliation on M if and only if
M
M
AX1 BX2 + H∇X1 CX2 ∈ Γ(F D⊥ ⊕ µ), V∇X1 BX2 + AX1 CX2 ∈ Γ(D⊥ )
for any X1 , X2 ∈ Γ((kerπ∗ )⊥ ).
Proof. Since M is a locally product Riemannian manifold, from (2.1) and (2.2)
M
M
we have ∇X1 X2 = F ∇X1 F X2 for X1 , X2 ∈ Γ((kerπ∗ )⊥ ). Using (2.8), (2.9) and
(3.4) we have
M
M
∇X1 X2 = F (AX1 BX2 + V∇X1 BX2 )
M
+ F (H∇X1 CX2 + AX1 CX2 ).
Then by using (3.3) and (3.4) we get
M
M
∇X1 X2 = BAX1 BX2 + CAX1 BX2 + φV∇X1 BX2
M
M
M
+ ωV∇X1 BX2 + BH∇X1 CX2 + CH∇X1 CX2
+ φAX1 CX2 + ωAX1 CX2 .
24
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
M
Hence, we have ∇X1 X2 ∈ Γ((kerπ∗ )⊥ ) if and only if
M
M
M
B(AX1 BX2 + H∇X1 CX2 ) + φ(V∇X1 BX2 + AX1 CX2 ) = 0.
Thus ∇X1 X2 ∈ Γ((kerπ∗ )⊥ ) if and only if
M
M
B(AX1 BX2 + H∇X1 CX2 ) = 0 and φ(V∇X1 BX2 + AX1 CX2 ) = 0,
which completes proof.
In the sequel we are going to investigate the geometry of leaves of the vertical
distribution kerπ∗ .
Theorem 3.11. Let π : (M, gM , F ) −→ (N, gN ) be a purely hemi-slant submersion from a locally product Riemannian manifold (M, gM , F ) onto a Riemannian
manifold (N, gN ). Then the distribution (kerπ∗ ) defines a totally geodesic foliation on M if and only if
ˆ Z1 φZ2 + TZ1 ωZ2 ∈ Γ((kerπ∗ )⊥ )
TZ1 φZ2 + AωZ2 Z1 ∈ Γ(kerπ∗ ), ∇
for any Z1 , Z2 ∈ Γ(kerπ∗ ).
Proof. For any Z1 , Z2 ∈ Γ(kerπ∗ ), using (2.2), (2.6), (2.7) and (3.3) we get
M
M
∇ Z 1 Z2 = F ∇ Z 1 F Z 2
M
M
= F (∇Z1 φZ2 + ∇Z1 ωZ2 )
ˆ Z1 φZ2 + AωZ2 Z1 + TZ1 ωZ2 )
= F (TZ1 φZ2 + ∇
ˆ Z1 φZ2 + ω ∇
ˆ Z1 φZ2
= BTZ1 φZ2 + CTZ1 φZ2 + φ∇
+ BAωZ2 Z1 + CAωZ2 Z1 + φTZ1 ωZ2 + ωTZ1 ωZ2 .
From above equation, it follows that (kerπ∗ ) defines a totally geodesic foliation
if and only if
ˆ Z1 φZ2 + TZ1 ωZ2 ) = 0.
C(TZ1 φZ2 + AωZ2 Z1 ) + ω(∇
M
Thus ∇Z1 Z2 ∈ Γ(kerπ∗ ) if and only if
ˆ Z1 φZ2 + TZ1 ωZ2 ) = 0,
C(TZ1 φZ2 + AωZ2 Z1 ) = 0 and ω(∇
which completes proof.
From Theorem 3.10 and Theorem 3.11, we have the following result.
Theorem 3.12. Let π : (M, gM , F ) −→ (N, gN ) be a purely hemi-slant submersion from a locally product Riemannian manifold (M, gM , F ) onto a Riemannian
manifold (N, gN ). Then the total space M is a locally product manifold of the
leaves of (kerπ∗ )⊥ and kerπ∗ , i.e., M = M(kerπ∗ )⊥ × Mkerπ∗ , if and only if
M
and
M
AX1 BX2 + H∇X1 CX2 ∈ Γ(F D⊥ ⊕ µ), V∇X1 BX2 + AX1 CX2 ∈ Γ(D⊥ )
ˆ Z1 φZ2 + TZ1 ωZ2 ∈ Γ((kerπ∗ )⊥ )
TZ1 φZ2 + AωZ2 Z1 ∈ Γ(kerπ∗ ), ∇
for any X1 , X2 ∈ Γ((kerπ∗ )⊥ ) and Z1 , Z2 ∈ Γ(kerπ∗ ), where M(kerπ∗ )⊥ and Mkerπ∗
are leaves of the distributions (kerπ∗ )⊥ and kerπ∗ , respectively.
HEMI-SLANT SUBMERSIONS FROM ALMOST PRODUCT RIEMANNIAN MANIFOLDS 25
Now, we give necessary and sufficient conditions for a hemi-slant submersion to
be totally geodesic. The Riemannian submersion map π is called totally geodesic
map if the map π∗ is parallel with respect to ∇, i.e., ∇π∗ = 0. A geometric
interpretation of a totally geodesic map is that it maps every geodesic in the
total space into a geodesic in the base space in proportion to arc lengths.
Theorem 3.13. Let π : (M, gM , F ) −→ (N, gN ) be a hemi-slant submersion from
a locally product Riemannian manifold (M, gM , F ) onto a Riemannian manifold
(N, gN ). π is a totally geodesic map if and only if
M
ωTU1 ωV1 + CH∇U1 ωV1 = 0,
ˆ V φW + TV ωW ) = 0,
C(TU φW + AωW V ) + ω(∇
ˆ V BX + TV CX) = 0,
C(TV BX + ACX V ) + ω(∇
for any U1 , V1 ∈ Γ(D1 ), W ∈ Γ(D2 ), U ∈ Γ(kerπ∗ ) and X ∈ Γ((kerπ∗ )⊥ ).
Proof. For X1 , X2 ∈ Γ((kerπ∗ )⊥ ), since π is a Riemannian submersion, from
(2.11) we obtain
(∇π∗ )(X1 , X2 ) = 0.
⊥
For U1 , V1 ∈ Γ(D ), using (2.3) and (2.11) we have
M
(∇π∗ )(U1 , V1 ) = −π∗ (F ∇U1 ωV1 ).
Then from (2.6) we arrive at
M
(∇π∗ )(U1 , V1 ) = −π∗ (F (TU1 ωV1 + H∇U1 ωV1 )).
Using (3.3) and (3.4) in above equation we obtain
M
M
(∇π∗ )(U1 , V1 ) = −π∗ (φTU1 ωV1 + ωTU1 ωV1 + BH∇U1 ωV1 + CH∇U1 ωV1 ).
M
Since φTU1 ωV1 + BH∇U1 ωV1 ∈ Γ(kerπ∗ ), we derive
M
(∇π∗ )(U1 , V1 ) = −π∗ (ωTU1 ωV1 + CH∇U1 ωV1 ).
Then, since π is a linear isomorphism between (kerπ∗ )⊥ and T M , (∇π∗ )(U1 , V1 ) =
0 if and only if
M
(3.15)
ωTU1 ωV1 + CH∇U1 ωV1 = 0.
For U ∈ Γ(kerπ∗ ) and W ∈ Γ(Dθ ), using (2.3), (2.11) and (3.3), we have
M
(∇π∗ )(U, W ) = ∇πU π∗ W − π∗ (∇U W )
M
= −π∗ (F ∇U F W )
M
Then from (2.7) we arrive at
= −π∗ (F ∇U (φW + ωW )).
ˆ V φW ) + F (AωW V + TV ωW )).
(∇π∗ )(U, W ) = −π∗ (F (TU φW + ∇
Using (3.3) and (3.4) in above equation we obtain
ˆ V φW + ω ∇
ˆ V φW )
(∇π∗ )(U, W ) = −π∗ ((BTU φW + CTU φW ) + (φ∇
+ (BAωW V + CAωW V ) + (φTV ωW + ωTV ωW )).
26
MEHMET AKIF AKYOL, YILMAZ GÜNDÜZALP
Thus (∇π∗ )(V, W ) = 0 if and only if
ˆ V φW + TV ωW ) = 0.
C(TU φW + AωW V ) + ω(∇
(3.16)
On the other hand, using (2.3), (2.6), (2.7) and (3.4) for any V ∈ Γ(kerπ∗ ) and
X ∈ Γ((kerπ∗ )⊥ ), we get
M
(∇π∗ )(V, X) = ∇πV π∗ X − π∗ (∇V X)
M
= −π∗ (F ∇V F X)
M
= −π∗ (F ∇V (BX + CX))
ˆ V BX + ω ∇
ˆ V BX
= −π∗ (BTV BX + CTV BX + φ∇
+ BACX V + CACX V + φTV CX + ωTV CX).
Thus (∇π∗ )(V, X) = 0 if and only if
ˆ V BX + TV CX) = 0.
C(TV BX + ACX V ) + ω(∇
The result then follows from (3.15), (3.16) and (3.17).
(3.17)
Acknowledgement. The authors would like to express their warm thanks to
the referee for his/her valuable comments and suggestions.
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1
Faculty of Science and Arts, Department of Mathematics, University of
Bingöl, 12000, Bingöl, TURKEY
E-mail address:
[email protected]
2
Faculty of Science and Arts, Department of Mathematics, University of
Dicle, 21280, Diyarbakır, TURKEY
E-mail address:
[email protected]