Summing column that is grouped - SQL

Question

I have a query:

SELECT
 date,
 COUNT(o.row_number)FILTER (WHERE o.row_number > 1 AND date_ddr IS NOT NULL AND telephone_number <> 'Anonymous' ) repeat_calls_24h
  (
  SELECT
  telephone_number,
  date_ddr,
  ROW_NUMBER() OVER(PARTITION BY ddr.telephone_number ORDER BY ddr.date) row_number,
  FROM
  table_a
  )o
GROUP BY 1

Generating the following table:

date	Repeat calls_24h
17/09/2022	182
18/09/2022	381
19/09/2022	81
20/09/2022	24
21/09/2022	91
22/09/2022	110
23/09/2022	231

What can I add to my query to provide a sum of the previous three days as below?:

date	Repeat calls_24h	Repeat Calls 3d
17/09/2022	182
18/09/2022	381
19/09/2022	81	644
20/09/2022	24	486
21/09/2022	91	196
22/09/2022	110	225
23/09/2022	231	432

Thanks

Answer 1

We can do it using lag.

select  "date"
       ,"Repeat calls_24h"
       ,"Repeat calls_24h" + lag("Repeat calls_24h") over(order by "date") + lag("Repeat calls_24h", 2) over(order by "date") as "Repeat Calls 3d"
from    t

date	Repeat calls_24h	Repeat Calls 3d
2022-09-17	182	null
2022-09-18	381	null
2022-09-19	81	644
2022-09-20	24	486
2022-09-21	91	196
2022-09-22	110	225
2022-09-23	231	432

Fiddle