I'm trying to generate a function declaration using a macro
/* goal: generate int f(int a, float b) */
template<typename P>
struct ptype;
template<typename P>
struct ptype<void(P)> { typedef P type; };
#define NAMEe
#define COMMAe
#define COMMA ,
#define NAME(N) N PARAMS
#define PARAMS(P, ...) COMMA ## __VA_ARGS__ P NAME ## __VA_ARGS__
#define PARAM_ITER(P) P NAME
#define PROTO(R, N, P) \
ptype<void R>::type N (PARAM_ITER P (,e))
PROTO((int), f, (int)(a)(float)(b));
It will iteratively process the next (name)
or (type)
by NAME
or PARAMS
respectively, with the ...
having an empty macro argument. But GCC complains with
prototype.hpp:20:35: warning: ISO C99 requires rest arguments to be used
And clang complains with
ptype<void (int)>::type f (int aprototype.hpp:20:1: warning: varargs argument missing, but tolerated as an extension [-pedantic]
I think this happens because of the following
#define FOO(X, ...)
FOO(A);
Because I'm not passing an argument for the ...
or each of those (name)
or (type)
. Is there any simple work around I can apply?
I've now used a technique similar to the technique used by @James to find the length of a parameter list. If as second argument, instead of O
, ONT
is passed, I will print the comma and NAME
. The following is the final solution:
/* goal: generate void f(int a, float b) */
template<typename P>
struct ptype;
template<typename P>
struct ptype<void(P)> { typedef P type; };
#define TYPE_DO(X) X
#define TYPE_DONT(X)
#define TYPE_MAYBE(X, A, ...) TYPE_D ## A (X)
#define COMMA_DO ,
#define COMMA_DONT
#define COMMA_MAYBE(A, B, ...) COMMA_D ## B
#define NAME_DO NAME
#define NAME_DONT
#define NAME_MAYBE(A, B, ...) NAME_D ## B
#define NAME(N) N PARAMS
#define PARAMS(...) COMMA_MAYBE(__VA_ARGS__,O,O) TYPE_MAYBE(__VA_ARGS__,O,O) \
NAME_MAYBE(__VA_ARGS__,O,O)
#define PARAM_ITER(P) P NAME
#define PROTO(R, N, P) \
ptype<void R>::type N (PARAM_ITER P (D,ONT))
Test:
#define STR1(X) #X
#define STR(X) STR1(X)
int main() {
// prints correctly
std::cout << STR(PROTO((int), f, (int)(a)(float)(b)));
}