I am trying to use regex to extract a certain syntax, in my case something like "10.100" or "20.111", in which 2 numbers are separated by dot(.) . So if I provide "a 10.100", it will extract 10.100 from the string. If I provide "a 10.100 20.101", it will extract 10.100 and 20.101.
Until now I have tried to use
preg_match('/^.*([0-9]{1,2})[^\.]([0-9]{1,4}).*$/', $message, $array);
but still no luck. Please provide any suggestion because I don't have strong regex knowledge. Thanks.
You may use
\b[0-9]{1,2}\.[0-9]{1,4}\b
See the regex demo.
Details:
\b - a leading word boundary[0-9]{1,2} - 1 or 2 digits\. - a dot[0-9]{1,4} - 1 to 4 digits\b - a trailing word boundary.If you do not care about the whole word option, just remove \b. Also, to match just 1 or more digits, you may use + instead of the limiting quantifiers. So, perhaps
[0-9]+\.[0-9]+
will also work for you.
See a PHP demo:
$re = '/[0-9]+\.[0-9]+/';
$str = 'I am trying to use regex to extract a certain syntax, in my case something like "10.100" or "20.111", in which 2 numbers are separated by dot(.) . So if I provide "a 10.100", it will extract 10.100 from the string. If I provide "a 10.100 20.101", it will extract 10.100 and 20.101.';
preg_match_all($re, $str, $matches);
print_r($matches[0]);
Output:
Array
(
[0] => 10.100
[1] => 20.111
[2] => 10.100
[3] => 10.100
[4] => 10.100
[5] => 20.101
[6] => 10.100
[7] => 20.101
)
\d? Just out of curiosity.
\d will match non-ASCII digits if /u modifier is used. I understand it is not the case here, but since \d may change the scope of chars it can match depending on a modifier, I'd rather use a verbose way to describe the chars to match. It is common to use [0-9] to avoid ambiguity.
Commented
May 4, 2017 at 10:54
\b is a word boundary, and it requires a start of string or a char other then a letter, digit or _ before the first digit matched with [0-9]{1,2}. The second \b requires the end of string or the character other than letter/digit/_ after the last digit matched with [0-9]{1,4}. If you do not use the word boundaries, you will match 12.3456 in 09876512.3456789999. If you plan to match 12.34 in abc12.34xyz you need to use (?<![0-9])[0-9]{1,2}\.[0-9]{1,4}(?![0-9]).
Commented
May 5, 2017 at 4:57
Regex: /\d+(?:\.\d+)/
1.
\d+for matching digits one or more.2.
(?:\.\d+)for matching digits followed by.like.1234
<?php
ini_set('display_errors', 1);
$string='a 10.100 20.101';
preg_match_all('/\d+(?:\.\d+)/', $string, $array);
print_r($array);
Output:
Array
(
[0] => Array
(
[0] => 10.100
[1] => 20.101
)
)
2345.334567.
Commented
May 4, 2017 at 10:20
\d+\.\d+ is equal here (with no modifiers) to [0-9]+\.[0-9]+.
Commented
May 4, 2017 at 10:26
[0-9]{2}\.[0-9]{3} then it might got wrong or match with some other.. Lets the OP decide which answer he likes, But your answer is best among once.. I know wiktor..
Commented
May 4, 2017 at 10:31
$decimals = "10.5 100.50 10.250";
preg_match_all('/\b[\d]{2}\.\d+\b/', $decimals, $output);
print_r($output);
Output:
Array
(
[0] => 10.5
[1] => 10.250
)
