added 4 characters in body

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edited Dec 14, 2017 at 6:19

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Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

replaced http://stackoverflow.com/ with https://stackoverflow.com/

Source Link

edited May 23, 2017 at 10:28

URL Rewriter Bot

Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

Source Link

asked Mar 31, 2016 at 13:33

Black

20k
45
183
292

Determine angle between 3 coordinates

Pictures say more then thousand words. As you can see in my screenshot i try to calculate the angle between the coordinates AB and BC, in this case the angle is obviously 90°. But how can i determine this angle with javascript code?

I found this thread and tried the accepted solution, but i always get 1.57instead of 90 like i expected. I rewrote the original function because i did not understood how to pass my parameters to it.

Please excuse my bad paint and math skills.

    function find_angle(Ax,Ay,Bx,By,Cx,Cy)
    {
        var AB = Math.sqrt(Math.pow(Bx-Ax,2)    +   Math.pow(By-Ay,2));    
        var BC = Math.sqrt(Math.pow(Bx-Cx,2)    +   Math.pow(By-Cy,2)); 
        var AC = Math.sqrt(Math.pow(Cx-Ax,2)    +   Math.pow(Cy-Ay,2));
        
        return Math.acos((BC*BC+AB*AB-AC*AC)    /   (2*BC*AB));
    }
    var angle = find_angle
                (
                    4 ,     //Ax
                    3 ,     //Ay
                    
                    4 ,     //Bx
                    2 ,     //By
                    
                    0 ,     //Cx
                    2       //Cy
                )
                
    alert ( angle );

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Determine angle between 3 coordinates