Timeline for Why does cudaMalloc() use pointer to pointer?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 12, 2016 at 13:27 | comment | added | Íhor Mé | So in simple terms, you pass a pointer a to pointer to future array, because you want the method to change that pointer and not an array as you would usually. | |
| Dec 5, 2015 at 19:51 | history | edited | Robert Crovella | CC BY-SA 3.0 |
deleted 1 character in body
|
| Dec 5, 2015 at 19:45 | history | edited | Robert Crovella | CC BY-SA 3.0 |
fix link
|
| Apr 6, 2015 at 14:58 | history | edited | Robert Crovella | CC BY-SA 3.0 |
improve formatting
|
| Feb 8, 2014 at 17:40 | history | edited | Robert Crovella | CC BY-SA 3.0 |
added 9 characters in body
|
| Feb 8, 2014 at 17:34 | history | edited | Robert Crovella | CC BY-SA 3.0 |
modified to clarify usage of "reference"
|
| Nov 16, 2012 at 12:04 | audit | Low quality answers | |||
| Nov 16, 2012 at 12:04 | |||||
| Nov 13, 2012 at 23:00 | vote | accept | rhyc | ||
| Oct 17, 2012 at 19:39 | history | edited | njuffa | CC BY-SA 3.0 |
edited body
|
| Oct 17, 2012 at 15:08 | comment | added | rhyc | Ahh, I see. I got mixed up with the return value and pass by reference... thanks! | |
| Oct 17, 2012 at 14:54 | history | answered | Robert Crovella | CC BY-SA 3.0 |