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What is the difference between the potential energy and potential function in quantum mechanics?

In quantum mechanics, we study particles in various systems, such as an infinite potential well, a finite potential well, potential barriers, potential steps, harmonic oscillators, and so on. In all ...
Dinesh Katoch's user avatar
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0 answers
140 views

Applications of infinite square well/particle in a box

I know of only two instances where the infinite square well is an adequate model for experimental behaviour: the absorption wavelengths of cyanine dyes, and extremely small semiconductors to which ...
Jackalope's user avatar
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0 votes
1 answer
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Negative potential infinite square well

A 1D finite square well is generally defined either by \begin{equation} V(x)=\begin{cases} 0\qquad -a\leqslant x\leqslant a\\ V_0\qquad \text{otherwise} \end{cases} \tag{1} \end{equation} or \begin{...
Herr Feinmann's user avatar
4 votes
2 answers
170 views

Is classical physics crucial for quantum physics?

When we solve Schrödinger equation we start by determine what is the potential $V(r,t)$. This usually done by looking at the problem from classical point of view, find $V(r,t)$ using classical physics ...
ziv's user avatar
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0 votes
1 answer
911 views

Probability to find a particle inside a finite potential well

Supoose we have a repuslive potential well ($+V_0$) and, if a particle of energy $E(>V_0)$ is incident toward it, then it will feel repulsion, so intuitively the probability of finding particle ...
Barry's user avatar
  • 362
2 votes
2 answers
2k views

Meaning of the term $V(x)$ in the Schrodinger equation [closed]

I'm new to quantum mechanics and I am currently trying to understand finite potential well (although my question is not specific to finite potential well ). In the Schrodinger equation, many texts ...
prananna's user avatar
0 votes
1 answer
2k views

Why do we always require the potentials to be bounded from below?

Why do we always require the potentials $V(x)$ (both in classical and quantum mechanics) to be bounded from below i.e., require that $V(x)$ should not go to $-\infty$ as $x\rightarrow \pm \infty$? ...
SRS's user avatar
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1 vote
1 answer
301 views

Possibility of defining "Path-dependent" potentials

Yes, I know the title seems stupid since the most important property of potential is that it's actually path independent. But I have a point. I just want to know is it possible to define a function ...
Hamed.Begloo's user avatar
1 vote
1 answer
3k views

How can energy be negative in a finite square well?

Say if the potential $V(x) < 0$ in the well but the sides or the scattered states its zero potential, anyways How is that the energy in the well is less than zero? Is it because the potential is ...
Cleo's user avatar
  • 359