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Energy Dissipated by Damper Infinitesimal Derivation

If we consider a damper (dashpot) element that exerts a force opposite the direction of motion proportional to the velocity, i.e. $$ \vec{F} = -c \vec{v}$$ Therefore, we can consider an infinitesimal ...
Jacob Ivanov's user avatar
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3 answers
211 views

What does it mean in terms of energy if power is increasing with time? [closed]

Recently I have been studying work and energy and in this chapter I encountered with the term power. In terms of work power is written as $dW/dt$. So I have a doubt that suppose power is increasing. ...
Sim's user avatar
  • 37
1 vote
2 answers
82 views

Is it possible to lift an object from rest with constant power?

This is inspired by the following question. Consider some object which I want to lift from rest with a constant power throughout the whole process; the power I apply when lifting the object from rest ...
user256872's user avatar
  • 6,641
0 votes
3 answers
167 views

Power and work contradiction

A body is starting from rest. A force is acting on it for a short period of time. In that given time, power delivered to it at any instance $t$ is given $$P = F \cdot v_1 = ma \cdot v_1 = mv_1^2/t,$$ ...
Priyesha Jha's user avatar
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1 answer
1k views

Infinitesimal work

I am a newbie in Physics (Senior on highschool) and our teacher wrote in a proof $$\dfrac{dK}{dt}=\dfrac{dW}{dt},$$ where $K$ is the Kinetic energy of a body and $W$ is the Work. So now that I am ...
Andreas Ch.'s user avatar
4 votes
2 answers
3k views

Why dont you take derivative of force in definition of power ? P=F.v

The derivative of work is $\bf F\cdot v .$ $$P(t)= \frac{\mathrm dW}{\mathrm dt}= \mathbf{F\cdot v}=-\frac{\mathrm dU}{\mathrm dt}\;.$$ But why not $$\frac{\mathrm{d}\mathbf{F}}{\mathrm{d}t}\cdot \...
Joe's user avatar
  • 105