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Deriving smoothing kernels

I'm watching a video on smoothed particle hydrodynamics it just blindly claims that these smoothing kernels are pretty good. $$W(r-r_b,h)\equiv\dfrac{315}{64\pi h^9}\left(h^2-|r-r_b|^2\right)^3$$ $$\...
ScottishTapWater's user avatar
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0 answers
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What do equations involving infinitesimals say?

I am reading this note on the Bernoulli equations with the following derivations: I am struggling to find a calculus based meaning for the above equations involving the infinitesimal $\delta V$: I ...
kid111's user avatar
  • 101
1 vote
1 answer
122 views

Fluid mechanics - Particular derivative

I've got a problem in MHD where I need to develop the following derivative (where $\vec{B}$ is the magnetic field and $\rho$ the density, both are functions of $(\vec{r},t))$: $$ \frac{\mathrm{d}}{\...
Michael's user avatar
  • 11
1 vote
2 answers
125 views

Partial derivative in hydrostatic equilibrium in star

In a simple model, a gaseous, non-rotating star consists of many thin, concentric spherical shells with radius $r$ and mass $\text{d}m$. The total mass of the shells within radius $r$ is $m$. The ...
gamma1954's user avatar
  • 1,169
0 votes
1 answer
78 views

Particle paths - the distance moved by a particle in a velocity field

This question is is context to particle paths. Particle paths are trajectories of a given particle in the velocity field: $$\boldsymbol{u}(\boldsymbol{x},t)$$ A particle location at position $\...
Jack Jack's user avatar
  • 187
0 votes
1 answer
835 views

Relationship Between Differentiation in Two Frames

In section 10.3 of Principles of Ideal-Fluid Aerodynamics by Karamcheti, he writes the following: $\qquad$ Denote by $K_1$ a reference frame fixed with respect to the moving body. We shall denote ...
eball's user avatar
  • 149
6 votes
2 answers
5k views

What does $(\mathbf{u}\cdot\nabla)\mathbf{u}$ mean in the Navier-Stokes equation?

I am studying the Navier-Stokes equations and I have the equation in the form: $$\rho \dfrac{\partial{\mathbf{u}}}{\partial{t}} + \rho (\mathbf{u}\cdot\nabla)\mathbf{u} - \mu\nabla^2\mathbf{u} + \...
Ayisha Mahmudova's user avatar