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3 votes
1 answer
388 views

Concerning topological manifolds: Are paracompact and connected locally euclidian Hausdorff spaces always second-countable?

There are different definitions for topological manifolds, sometimes second-countability or paracompactness are added to being locally euclidian Hausdorff. (Sometimes Hausdorff is also left out, but I ...
Samuel Adrian Antz's user avatar
3 votes
2 answers
226 views

Example of a Hausdorff topology that is homeomorphic to $\mathbb R^n$ but isn't second countable?

The definition of a topological manifold $M$ I have is: $M$ is Hausdorff. Each point of $M$ has a neighborhood that is homeomorphic to an open subset of $\mathbb{R}^n$. $M$ is second countable. ...
Makogan's user avatar
  • 3,599
1 vote
1 answer
875 views

Manifold has a countable cover by compact sets.

I was confused by Boothby's proof that a Manifold had a countable cover of compact sets. In his proof he says that as $M$ has a countable basis of open sets, we may assume that $M$ has a countable ...
Melody's user avatar
  • 2,833
1 vote
1 answer
440 views

0-manifolds are countable and discrete

Want to show every 0 -manifold is a countable and discrete space. Let M be a 0-manifold. By definition, it is second countable, Hausdorff and each point in M has a neighborhood homeomorphic to $\...
user avatar
0 votes
1 answer
4k views

$\mathbb{R}^n$ Second Countable

Lemma: Let $U$ be an open subset of $\mathbb{R}^n$ and $x \in U$ then there exists a ball with rational center $(\mathbb{Q}^n$ and rational radius containing $x,$ that is contained in $U.$ What I want ...
user avatar
3 votes
2 answers
679 views

Does partition of unity implies second countable?

Reading the definition of partition of unity: Let $A\subset \Bbb R^n$ and let $\mathcal{O}$ be an open cover of $A$. Then there is a collection $\Phi$ of $C^\infty$ functions $\varphi$ defined in an ...
user avatar
3 votes
0 answers
116 views

Why are manifolds second countable [duplicate]

A manifold is defined to be a second countable Hausdorff space that is locally homeomorphic to Euclidean space. It surprises me that second countably is a requirement here, because it surprises me ...
Stella Biderman's user avatar