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Convergence of infinite series generated by inverse Syracuse functions

NOTE: While this question was inspired by me playing with the Collatz Conjecture, it is not related to the Collatz Conjecture directly. If I should remove the tag, please let me know. Define: $N = \{n ...
SlipEternal's user avatar
  • 10.5k
3 votes
1 answer
201 views

An argument that the value of m in a Collatz conjecture 2-cycle is subject to the same constraints as for a 1-cycle.

Question: Is the reasoning of the following argument valid? Objective: To derive a constraint on the permissible number of total divisions by 2, here referred to as $m$, for a Collatz 2-cycle ...
Joe B.'s user avatar
  • 343
8 votes
1 answer
468 views

Is there a way to predict periodic behavior in Collatz conjecture 1-cycles?

This is a recreational math question. If I use the equation for the smallest element in a 1-cycle,$$X_1 = \frac{3^n-2^n}{2^m-3^n}$$ with $n*ln_23 < m < n*ln_23 +1$, peak values of this function ...
Joe B.'s user avatar
  • 343
7 votes
2 answers
254 views

Collatz-like problem involving prime factors

Unfortunately I am not well-versed in LaTeX so I will try my best to keep this looking presentable. As an overview, I was investigating a variation of the Collatz conjecture: Define $f(1) = 1$ Then, ...
B Kosta's user avatar
  • 156
2 votes
1 answer
335 views

A question about mathematical reasoning regarding observations in Collatz conjecture 1-cycles

This is a question about the use of empirical observations to guide strategies in constructing mathematical proofs. It uses prior discussions of 1-cycles in the Collatz conjecture as a model. In a ...
Joe B.'s user avatar
  • 343
23 votes
2 answers
1k views

Collatz conjecture but with $n^2-1$ instead of $3n+1.$ Does the sequence starting with $13$ go to infinity?

Let's consider the following variant of Collatz $(3n+1) : $ If $n$ is odd then $n \to n^2-1.$ $1\to 0.$ $3\to 8\to 1\to 0.$ $5\to 24\to 3\to 0.$ $7\to 48\to 3\to 0.$ $9\to 80\to 5\to 0.$ $11\to 120\to ...
Adam Rubinson's user avatar
5 votes
0 answers
144 views

Collatz Related? Are there any generalized rules for the following?

Following up on my last question, Last Question. I have also noticed the following: If $x \bmod 5=0$ : execute $x/5$, or elseIf $x$ ends in $1$ : execute $(x⋅2)+3$, or elseif $x$ ends in $3$ : execute ...
Isaac Brenig's user avatar
  • 1,425
0 votes
0 answers
290 views

Jacobsthal numbers occurring in reduced cobweb plot for the Collatz Problem

I have been working on the Collatz problem for a while now, and have made this efficient cobweb plot function for it, where it automatically does all the dividing by two and always returns an odd ...
CJ B's user avatar
  • 35
2 votes
1 answer
320 views

Where is the flaw in my logic in this collatz conjecture idea?

Using this article from math stack exchange ( open problem - What does proving the Collatz Conjecture entail? - Mathematics Stack Exchange fourth answer down that starts "I think, for the ...
McMac Music's user avatar
5 votes
0 answers
1k views

Generating (almost?) all odd numbers for the 3n + 1 problem [closed]

The 3n + 1 problem The $3n + 1$ problem can be described as a set of simple rules. For any positive integer apply the following two rules: If the number is even: divide by 2 If the number is odd: ...
Roy van Rijn's user avatar
1 vote
1 answer
232 views

These equations can generate integers that have the same total stopping time in the Collatz Conjecture. Has this been discovered?

Conjecture #1: $a_(x,y)=(1/3)(2^{(2y+7)-2x)}(5(4^{x})-2)$ Generates positive even integers with a total stopping time S where $S=2y+13$, y is the set of all natural numbers and x is the set of all ...
Tylersamuels643's user avatar
0 votes
1 answer
182 views

Are there specific total stopping times that are finite for the collatz conjecture? [closed]

For example, are there only certain groups of numbers that have a total stopping time of 6 or 30?
Tylersamuels643's user avatar
0 votes
0 answers
161 views

Finding the stopping times or steps for positive integers in the Collatz conjecture using a formula

Is it possible to find a closed-form $a_n$ for some positive integers and use another formula to find the number of steps for all of those integers? If so, can you find multiple closed forms? For ...
Tylersamuels643's user avatar
2 votes
2 answers
229 views

Smallest element of cycle of length $k$ in Collatz 3x+1 map?

In studies of the Collatz conjecture, what research has asserted the existence of a $k$-length cycle and drawn conclusions about its smallest element $m$? In particular, about the behavior of $m$ as $...
PtH's user avatar
  • 1,164
1 vote
2 answers
779 views

Smallest number of a hypothetical second Collatz Cycle

Update/warning: The explaination below contains some obvious errors. These errors have been worked on and turned this research into: Generating (almost?) all odd numbers for the 3n + 1 problem Most ...
Roy van Rijn's user avatar
2 votes
1 answer
75 views

(More efficiently) solving for residue classes $\pmod {2^A}$?

This is in context to a detail for the generalized Collatz-problem (generalized to various multipliers, like 3x+1, 5x+1, 7x+1, ... ,mx+1, ...) I am currently looking at the 11x+1 problem , and as a ...
Gottfried Helms's user avatar
1 vote
2 answers
937 views

Repeating cycles in the $3n-1$ problem

While tracking sequences beginning with 1-to-3 digit integers, I have found 3 different repeating cycles in the $3n-1$ problem (similar to the Collatz Conjecture). They are 1, 2, 1..., 5, 14, 7, 20, ...
Aidan F. Pierce's user avatar
3 votes
3 answers
3k views

$5n+1$, $3n-1$ problem, smallest repeating cycle and Collatz conjecture

Among the Collatz conjecture we have other "similar" problems that are solved and have repeating cycles. $5n+1$ has the repeating cycle $13, 66, 33, 166, 83, 416, 208, 104, 52, 26$, with a length of $...
Bojan Vasiljević's user avatar
1 vote
2 answers
687 views

$N \equiv 3 (\textrm{mod } 4)$ and Collatz conjecture

Can the Collatz conjecture also be interpreted as behaviour, transformation of number of form $N\equiv 3(\textrm{mod }4)$ to the form of $N\equiv 1(\textrm{mod }4)$ Because integers of the form $N\...
Bojan Vasiljević's user avatar