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2 votes
1 answer
70 views

Does the equation of eigenvalues tell the equation of the matrix?

If $\lambda$'s (eigenvalues) satisfy an polynomial equation, can I derive the same equation for the matrix? To be specific, if I have $\lambda^2 = 1$, can I get $A^2 = I$? I know the converse is ...
Black Pan's user avatar
0 votes
0 answers
68 views

An $n\times n$ matrix, $n\ge 2$ with characteristic polynomial $x^{n-2}(x^2-1)$ [duplicate]

$A$ is an $n\times n$ matrix, $n\ge 2$ with characteristic polynomial $x^{n-2}(x^2-1)$. Then, which of the following is true? $A^n=A^{n-2}$ rank of $A$ is $2$ rank of $A$ is atleast $2$ there are ...
Dumbest person on earth's user avatar
3 votes
3 answers
84 views

How to find ${\rm rank}(2I_n-A)$ where A is a square matrix of size $n$ and $A^3 - 6A^2 + 12A = 0_n$?

I think the rank has to be $n$ since anything else would be impossible to prove with so little information about the matrix. $$\det(2I_n-A) = -P_A(2) = -\det(A - 2I_n) \ .$$ So, if I can show the ...
theo2003's user avatar
11 votes
1 answer
351 views

If square matrices $A^2 + B^2 = 2AB$, then prove that $p_A(x) = p_B(x)$

Original problem statement: Let $A, B \in M_n(\mathbb{C})$ such that $A^2 + B^2 = 2AB$. Prove that for any $x \in \mathbb{C}$: $$det(A - xI_n) = det(B-xI_n)$$ Now the first observation, the equality ...
D. Petrov's user avatar
  • 851
2 votes
1 answer
51 views

Proof of a polynomial matrix equation

Consider a $2 \times 2$ matrix $$ A= \left[\begin{array}{c} 2 & 7\\ 1 & 8\end{array}\right] $$ For this matrix, or for any $2 \times 2$ matrix $A$, why does $A^2 - \mbox{tr}(A) \cdot A + \det(...
Nazmul Hasan Shipon's user avatar
1 vote
0 answers
58 views

Characteristic polynomial equation for a matrix of a special form

While studying linear algebra, I became interested in the characteristic polynomial. I identified several types of matrices that interest me and made a system of equations for them. I am trying to ...
anatoly's user avatar
  • 95
4 votes
3 answers
1k views

Can an $n \times n$ matrix satisfy an $n$ degree polynomial equation other than its characteristic polynomial equation?

Can an $n \times n$ matrix satisfy an $n$ degree polynomial equation other than its characteristic polynomial equation? I was curious if the characteristic polynomial equation is the only $n$ degree ...
Aspirant's user avatar
2 votes
2 answers
122 views

Compute a matrix $P$ such that $P$ satisfies $3I+P+P^2=\left(\begin{smallmatrix}3&0&0\\3&6&0\\0&0&6\end{smallmatrix}\right)$

Question: Compute a matrix $P$ such that the matrix $P$ satisfies $3I + P + P^2 = \begin{pmatrix} 3 & 0 & 0\\ 3 & 6 & 0 \\ 0 & 0 & 6 \end{pmatrix}$ Attempt: First, I simplify ...
Edward's user avatar
  • 65
1 vote
2 answers
733 views

How to show that $det(AB-xI)=det(BA-xI)$ ,for any $x\in \mathbb F$.

There is a problem in Hoffmann Kunze: Show that $AB$ and $BA$ have the same characteristic polynomials,where $A,B$ are both $n\times n$ matrices in $\mathbb F$. If $A$ or $B$ is invertible it can be ...
Kishalay Sarkar's user avatar
2 votes
2 answers
125 views

Find all $n$ for which there exist A, B, matrices of size n with real entries, such that $A^2B-BA^2=A$.

Find all positive integers $n$ for which there exist two square matrices of size $n$, with real entries, shall we denote them by A and B, such that $A^2B-BA^2=A$ and $A\neq O_n$ and $B\neq O_n$. So ...
Parallelism Alert's user avatar
3 votes
0 answers
129 views

About the characteristic equation of a square matrix (Cayley-Hamilton theorem)

Take, for example, $A$ of order $2 \times 2$. The characteristic equation comes to be $$A^2 - (\text{tr}(A)) A + \det (A) = 0 $$ But is this the only quadratic equation that this matrix satisfies? ...
aryan bansal's user avatar
  • 1,953
5 votes
2 answers
198 views

$ A^2 - B^2 = I_{2n+1} \implies det(AB-BA)=0 $ where A,B are complex matrices of odd size

Let $A, B$ be square matrices (with complex entries) of size $2n+1$, where $n$ is a positive integer. I need help proving the following: $$A^2 - B^2 = I_{2n+1} \implies det(AB-BA)=0 $$ I've tried ...
Parallelism Alert's user avatar