Timeline for Prime dividing the binomial coefficients
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 21, 2022 at 21:30 | comment | added | Nikifuj908 | Sweet solution. It expands to a nice proof by induction as well. | |
| Jul 16, 2011 at 17:22 | comment | added | Steven Sam | @Gadi, if you're worried about cancellation, you can work with the field Z/p(x,y), where x and y are transcendentals. | |
| Jul 15, 2011 at 16:10 | vote | accept | Gadi A | ||
| Jul 15, 2011 at 16:10 | |||||
| Jul 15, 2011 at 1:32 | comment | added | Gerry Myerson | @Gadi, the intermediate coefficients may not all be divisible by $q$, but they are all divisible by $p$, so the equation holds in any field of characteristic $p$. | |
| Jul 14, 2011 at 19:14 | comment | added | Gadi A | However, I'm not sure if it proves what I asked (although the identity above is what I was really after). How it shows that all the intermediate coefficients are divisible by q? They might have simply canceled each other out. | |
| Jul 14, 2011 at 19:13 | comment | added | Gadi A | Ok, I got it, your solution is quite elegant. Thanks! | |
| Jul 14, 2011 at 19:13 | vote | accept | Gadi A | ||
| Jul 14, 2011 at 19:14 | |||||
| Jul 14, 2011 at 18:49 | comment | added | Gadi A | Can you elaborate what you mean by "repeat"? | |
| Jul 14, 2011 at 17:51 | history | answered | Steven Sam | CC BY-SA 3.0 |