Timeline for Rees Algebra Isomorphism $A[xt, yt] \cong A[X, Y] / (yX - xY)$
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Apr 25 at 20:44 | comment | added | 領域展開 | @Mohan Can you provide some reference for these ? Thank you. | |
| Apr 25 at 18:47 | comment | added | Mohan | One has a natural surjective map $A[X,Y]/(yX-xY)\to A[xt,yt]$. So, suffices to show this map is injective. Inverting a non-zero divisor if this map is injective, so is the original map. | |
| Apr 24 at 12:51 | history | edited | 領域展開 | CC BY-SA 4.0 |
edited title
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| Apr 24 at 12:42 | history | asked | 領域展開 | CC BY-SA 4.0 |