Skip to main content
Notice removed Authoritative reference needed by User X
Bounty Ended with KReiser's answer chosen by User X
edited title
Link
User X
  • 1.1k
  • 6
  • 15

Blow up Understanding blowups at a nonreduced pointloci

Notice added Authoritative reference needed by User X
Bounty Started worth 100 reputation by User X
added 513 characters in body
Source Link
User X
  • 1.1k
  • 6
  • 15

Blowing up at a reduced subscheme is geometrically clear to me: it is just like blowing up at a reduced point, and point on the exceptional divisor corresponds to different directions oftangent lines through the base point. However, I always have problem understanding blowing up at a nonreduced subscheme. Is it a geometric way to see it as the reduced cases?

As examples, I would like to ask the following questions:

  1. Consider the blow upblowup of $\mathbb A^2$ at a double point $x={\rm Spec}(k[x,y]/(x^2,y))$. What is the exceptional divisor? Is it isomorphic to $\mathbb P^1$? Is the blowup smooth? (I guess both answers are negativeBy the comment of mtrying46, the exceptional divisor is $\mathbb P^1$ but the blow up is not smooth)
  2. Suppose $Y$ is theConsider that first blow up of $X$$\mathbb A^2$ at $Z\subset X$one point and both $X,Y$ are smooth. If we know every fiberthen blow up at one point in the exceptional divisor of $Z$ is isomorphic to some $\mathbb P^m$,the blowup. The composition can we conclude thatbe seen as blow up once $Z$(at a nonreduced center). Then what is reducedthe center?

From the two examples above, it seems that blowup at nonreduced center will either result in singularity or central fiber not being projective space. I would like to know whether this is true in general. That is:

  1. Suppose $Y$ is the blow up of $X$ at $Z\subset X$ and both $X,Y$ are smooth. If we know every fiber of $Z$ is isomorphic to some $\mathbb P^m$, can we conclude that $Z$ is reduced?

Everything is over $\mathbb C$. Any comments will be very helpful!

Blowing up at a reduced subscheme is geometrically clear to me: it is just like blowing up at a reduced point, and point on the exceptional divisor corresponds to different directions of the base point. However, I always have problem understanding blowing up at a nonreduced subscheme. Is it a geometric way to see it as the reduced cases?

As examples, I would like to ask the following questions:

  1. Consider the blow up $\mathbb A^2$ at a double point $x={\rm Spec}(k[x,y]/(x^2,y))$. What is the exceptional divisor? Is it isomorphic to $\mathbb P^1$? Is the blowup smooth? (I guess both answers are negative)
  2. Suppose $Y$ is the blow up of $X$ at $Z\subset X$ and both $X,Y$ are smooth. If we know every fiber of $Z$ is isomorphic to some $\mathbb P^m$, can we conclude that $Z$ is reduced?

Everything is over $\mathbb C$. Any comments will be very helpful!

Blowing up at a reduced subscheme is geometrically clear to me: it is just like blowing up at a reduced point, and point on the exceptional divisor corresponds to different tangent lines through the base point. However, I always have problem understanding blowing up at a nonreduced subscheme. Is it a geometric way to see it as the reduced cases?

As examples, I would like to ask the following questions:

  1. Consider the blowup of $\mathbb A^2$ at a double point $x={\rm Spec}(k[x,y]/(x^2,y))$. What is the exceptional divisor? Is it isomorphic to $\mathbb P^1$? Is the blowup smooth? (By the comment of mtrying46, the exceptional divisor is $\mathbb P^1$ but the blow up is not smooth)
  2. Consider that first blow up $\mathbb A^2$ at one point and then blow up at one point in the exceptional divisor of the blowup. The composition can be seen as blow up once (at a nonreduced center). Then what is the center?

From the two examples above, it seems that blowup at nonreduced center will either result in singularity or central fiber not being projective space. I would like to know whether this is true in general. That is:

  1. Suppose $Y$ is the blow up of $X$ at $Z\subset X$ and both $X,Y$ are smooth. If we know every fiber of $Z$ is isomorphic to some $\mathbb P^m$, can we conclude that $Z$ is reduced?

Everything is over $\mathbb C$. Any comments will be very helpful!

Source Link
User X
  • 1.1k
  • 6
  • 15

Blow up at a nonreduced point

Blowing up at a reduced subscheme is geometrically clear to me: it is just like blowing up at a reduced point, and point on the exceptional divisor corresponds to different directions of the base point. However, I always have problem understanding blowing up at a nonreduced subscheme. Is it a geometric way to see it as the reduced cases?

As examples, I would like to ask the following questions:

  1. Consider the blow up $\mathbb A^2$ at a double point $x={\rm Spec}(k[x,y]/(x^2,y))$. What is the exceptional divisor? Is it isomorphic to $\mathbb P^1$? Is the blowup smooth? (I guess both answers are negative)
  2. Suppose $Y$ is the blow up of $X$ at $Z\subset X$ and both $X,Y$ are smooth. If we know every fiber of $Z$ is isomorphic to some $\mathbb P^m$, can we conclude that $Z$ is reduced?

Everything is over $\mathbb C$. Any comments will be very helpful!