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Henry
  • 163.9k
  • 9
  • 131
  • 271

Hints:

  • Note for example $n^3-3n+2 = (n-1)(n^2-n-2) = (n-1)(n+1)(n-2)$. You can factorise completely to a product of terms like $(n-1)$ and $(n+2)$. Do that
  • How many powers of $5$ must the product have?
  • How many powers of $3$? How many powers of $2$? Note for example that one of two consecutive even numbers is a multiple of $4$

Hints:

  • Note for example $n^3-3n+2 = (n-1)(n^2-n-2) = (n-1)(n+1)(n-2)$. You can factorise completely to a product of terms like $(n-1)$ and $(n+2)$. Do that
  • How many powers of $5$ must the product have?
  • How many powers of $3$? How many powers of $2$?

Hints:

  • Note for example $n^3-3n+2 = (n-1)(n^2-n-2) = (n-1)(n+1)(n-2)$. You can factorise completely to a product of terms like $(n-1)$ and $(n+2)$. Do that
  • How many powers of $5$ must the product have?
  • How many powers of $3$? How many powers of $2$? Note for example that one of two consecutive even numbers is a multiple of $4$
Source Link
Henry
  • 163.9k
  • 9
  • 131
  • 271

Hints:

  • Note for example $n^3-3n+2 = (n-1)(n^2-n-2) = (n-1)(n+1)(n-2)$. You can factorise completely to a product of terms like $(n-1)$ and $(n+2)$. Do that
  • How many powers of $5$ must the product have?
  • How many powers of $3$? How many powers of $2$?