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Translation for "a new element" #131

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mernst opened this issue May 6, 2017 · 0 comments
Open

Translation for "a new element" #131

mernst opened this issue May 6, 2017 · 0 comments
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@mernst
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mernst commented May 6, 2017

The documentation for Commons Math's SparseGradient.multiply is

    /** Compute this × a.
     * @param a element to multiply
     * @return a new element representing this × a
     * @throws NullArgumentException if {@code a} is {@code null}.
     */

The translated postcondition is result.equals(a).
This expression is type-correct, but the documentation says that the return value is fresh, so this should be translated into (!result.equals(this)) && (!result.equals(a)).
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@mernst @albertogoffi