Talk:Monty Hall problem

Latest comment: 14 hours ago by EEng in topic It needs a better explanation
Former featured articleMonty Hall problem is a former featured article. Please see the links under Article milestones below for its original nomination page (for older articles, check the nomination archive) and why it was removed.
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Article milestones
DateProcessResult
May 3, 2005Peer reviewReviewed
June 25, 2005Featured article candidatePromoted
January 29, 2007Featured article reviewKept
May 18, 2008Featured article reviewKept
June 13, 2011Featured article reviewDemoted
Current status: Former featured article

50/50

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Ignorant Monty / Monty Fall - current explanation is incomplete

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The table currently describes "Ignorant Monty" solution as "switching wins 50%". However, in this variant, switching and staying are indifferent (when a goat has been revealed by chance by Ignorant Monty) and both in fact win 50%. Suggest that table be updated to state that "switching or staying both win 50%". This is given already in the citation for that Variant, if you read the second page of https://en.wikipedia.org/wiki/Monty_Hall_problem#CITEREFRosenthal2005a 2600:8801:17E2:0:30D0:6149:CBE5:D00B (talk) 17:15, 19 November 2024 (UTC)Reply

The completely unnecessary long-winded discussion mainly confuses readers

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This article is much more confusing than enlightening.

Instead of straighforwardly explaining the problem and its correct solution, it goes into all manner of alternative theories.

Furthermore, the illustrated explanation contains statements "Probability = 1/6", "Probability = 1/3", "Probability = 1/3", "Probability = 1/6",

without ever stating what these numbers are the probabilities of.

That is very unclear writing.

I hope someone familiar with this subject will fix this.

It needs a better explanation

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Gaining more knowledge change conditional probabilities.

P(Door 1 | Door 3 unknown) < P(Door 1 | Not Door 3)

01:10, 8 December 2024 (UTC) Tuntable (talk) 01:10, 8 December 2024 (UTC)Reply