1894 Rhode Island gubernatorial election

The 1894 Rhode Island gubernatorial election was held on April 4, 1894. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 53.15% of the vote.

1894 Rhode Island gubernatorial election

← 1893 April 4, 1894 1895 →
 
Nominee Daniel Russell Brown David S. Baker
Party Republican Democratic
Popular vote 29,157 22,650
Percentage 53.15% 41.29%

County results
Brown:      50–60%      60–70%

Governor before election

Daniel Russell Brown
Republican

Elected Governor

Daniel Russell Brown
Republican

General election

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Candidates

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Major party candidates

  • Daniel Russell Brown, Republican
  • David S. Baker, Democratic

Other candidates

  • Henry B. Metcalf, Prohibition
  • Charles G. Baylor, Socialist Labor
  • Henry A. Burlingame, People's

Results

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1894 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Daniel Russell Brown (incumbent) 29,157 53.15%
Democratic David S. Baker 22,650 41.29%
Prohibition Henry B. Metcalf 2,241 4.09%
Socialist Labor Charles G. Baylor 592 1.08%
Populist Henry A. Burlingame 223 0.41%
Majority 6,507
Turnout
Republican hold Swing

References

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  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 19, 2020.